285602
The distinguishing test betweenmethanoic acid and ethanoic acid is
1 Tollens' test
2 sodium bicarbonate test
3 litmus test
4 esterification test.
Explanation:
(a)
Methanoic acid has \(-\stackrel{\text { II }}{\mathrm{C}}-\) group as well as hydrogen attached to \(\mathrm{C}=\mathrm{O}\) group.
Therefore it can reduce Tollen's reagent.
Karnataka CET 2015
CHEMISTRY(KCET)
285603
Iodoform reaction is answered by all, except
(d) Alcohols of the type,\(\mathrm{CH}_3-\mathrm{CH}(\mathrm{OH})-\mathrm{R}\) (where, \(\mathrm{R}=\mathrm{H} /\) alkyl/aryl groups) and carbonyl compounds having \(\mathrm{H}_3 \mathrm{C}-\stackrel{\mathrm{O}}{\mathrm{C}}\)-group give iodoform reaction.
285606
The acid strength of active methylene group in
1 i \(>\) iii \(>\) ii
2 i \(>\) ii \(>\) iii
3 ii \(>\) i \(>\) iii
4 iii \(>\) i \(>\) ii
Explanation:
(c) In active methylene compound (ii), methylene\(\left(-\mathrm{CH}_2\right)\) group exists in between two strong EWGs i.e. \(\left(\mathrm{CH}_3 \mathrm{CO}-\right)\), which increases the acidity. Esters (iii) are less acidic than ketones (i) because the enolate ion produced from an ester is less stable than that produced from a ketone.
Hence,
(ii)
285602
The distinguishing test betweenmethanoic acid and ethanoic acid is
1 Tollens' test
2 sodium bicarbonate test
3 litmus test
4 esterification test.
Explanation:
(a)
Methanoic acid has \(-\stackrel{\text { II }}{\mathrm{C}}-\) group as well as hydrogen attached to \(\mathrm{C}=\mathrm{O}\) group.
Therefore it can reduce Tollen's reagent.
Karnataka CET 2015
CHEMISTRY(KCET)
285603
Iodoform reaction is answered by all, except
(d) Alcohols of the type,\(\mathrm{CH}_3-\mathrm{CH}(\mathrm{OH})-\mathrm{R}\) (where, \(\mathrm{R}=\mathrm{H} /\) alkyl/aryl groups) and carbonyl compounds having \(\mathrm{H}_3 \mathrm{C}-\stackrel{\mathrm{O}}{\mathrm{C}}\)-group give iodoform reaction.
285606
The acid strength of active methylene group in
1 i \(>\) iii \(>\) ii
2 i \(>\) ii \(>\) iii
3 ii \(>\) i \(>\) iii
4 iii \(>\) i \(>\) ii
Explanation:
(c) In active methylene compound (ii), methylene\(\left(-\mathrm{CH}_2\right)\) group exists in between two strong EWGs i.e. \(\left(\mathrm{CH}_3 \mathrm{CO}-\right)\), which increases the acidity. Esters (iii) are less acidic than ketones (i) because the enolate ion produced from an ester is less stable than that produced from a ketone.
Hence,
(ii)
285602
The distinguishing test betweenmethanoic acid and ethanoic acid is
1 Tollens' test
2 sodium bicarbonate test
3 litmus test
4 esterification test.
Explanation:
(a)
Methanoic acid has \(-\stackrel{\text { II }}{\mathrm{C}}-\) group as well as hydrogen attached to \(\mathrm{C}=\mathrm{O}\) group.
Therefore it can reduce Tollen's reagent.
Karnataka CET 2015
CHEMISTRY(KCET)
285603
Iodoform reaction is answered by all, except
(d) Alcohols of the type,\(\mathrm{CH}_3-\mathrm{CH}(\mathrm{OH})-\mathrm{R}\) (where, \(\mathrm{R}=\mathrm{H} /\) alkyl/aryl groups) and carbonyl compounds having \(\mathrm{H}_3 \mathrm{C}-\stackrel{\mathrm{O}}{\mathrm{C}}\)-group give iodoform reaction.
285606
The acid strength of active methylene group in
1 i \(>\) iii \(>\) ii
2 i \(>\) ii \(>\) iii
3 ii \(>\) i \(>\) iii
4 iii \(>\) i \(>\) ii
Explanation:
(c) In active methylene compound (ii), methylene\(\left(-\mathrm{CH}_2\right)\) group exists in between two strong EWGs i.e. \(\left(\mathrm{CH}_3 \mathrm{CO}-\right)\), which increases the acidity. Esters (iii) are less acidic than ketones (i) because the enolate ion produced from an ester is less stable than that produced from a ketone.
Hence,
(ii)
285602
The distinguishing test betweenmethanoic acid and ethanoic acid is
1 Tollens' test
2 sodium bicarbonate test
3 litmus test
4 esterification test.
Explanation:
(a)
Methanoic acid has \(-\stackrel{\text { II }}{\mathrm{C}}-\) group as well as hydrogen attached to \(\mathrm{C}=\mathrm{O}\) group.
Therefore it can reduce Tollen's reagent.
Karnataka CET 2015
CHEMISTRY(KCET)
285603
Iodoform reaction is answered by all, except
(d) Alcohols of the type,\(\mathrm{CH}_3-\mathrm{CH}(\mathrm{OH})-\mathrm{R}\) (where, \(\mathrm{R}=\mathrm{H} /\) alkyl/aryl groups) and carbonyl compounds having \(\mathrm{H}_3 \mathrm{C}-\stackrel{\mathrm{O}}{\mathrm{C}}\)-group give iodoform reaction.
285606
The acid strength of active methylene group in
1 i \(>\) iii \(>\) ii
2 i \(>\) ii \(>\) iii
3 ii \(>\) i \(>\) iii
4 iii \(>\) i \(>\) ii
Explanation:
(c) In active methylene compound (ii), methylene\(\left(-\mathrm{CH}_2\right)\) group exists in between two strong EWGs i.e. \(\left(\mathrm{CH}_3 \mathrm{CO}-\right)\), which increases the acidity. Esters (iii) are less acidic than ketones (i) because the enolate ion produced from an ester is less stable than that produced from a ketone.
Hence,
(ii)
285602
The distinguishing test betweenmethanoic acid and ethanoic acid is
1 Tollens' test
2 sodium bicarbonate test
3 litmus test
4 esterification test.
Explanation:
(a)
Methanoic acid has \(-\stackrel{\text { II }}{\mathrm{C}}-\) group as well as hydrogen attached to \(\mathrm{C}=\mathrm{O}\) group.
Therefore it can reduce Tollen's reagent.
Karnataka CET 2015
CHEMISTRY(KCET)
285603
Iodoform reaction is answered by all, except
(d) Alcohols of the type,\(\mathrm{CH}_3-\mathrm{CH}(\mathrm{OH})-\mathrm{R}\) (where, \(\mathrm{R}=\mathrm{H} /\) alkyl/aryl groups) and carbonyl compounds having \(\mathrm{H}_3 \mathrm{C}-\stackrel{\mathrm{O}}{\mathrm{C}}\)-group give iodoform reaction.
285606
The acid strength of active methylene group in
1 i \(>\) iii \(>\) ii
2 i \(>\) ii \(>\) iii
3 ii \(>\) i \(>\) iii
4 iii \(>\) i \(>\) ii
Explanation:
(c) In active methylene compound (ii), methylene\(\left(-\mathrm{CH}_2\right)\) group exists in between two strong EWGs i.e. \(\left(\mathrm{CH}_3 \mathrm{CO}-\right)\), which increases the acidity. Esters (iii) are less acidic than ketones (i) because the enolate ion produced from an ester is less stable than that produced from a ketone.
Hence,
(ii)
