283522
A parallel beam of fast moving electrons is incident normally on a narrow slit. A screen in placed at a large distance from the slit. If the speed of the electrons is increase, which of the following statement is correct?
1 diffraction pattern is not observed on the screen in the case of electrons
2 the angular width of the central maximum of the diffraction pattern will increase
3 the angular width of the central maximum will decrease
4 the angular width of the central maximum will remain the same
Explanation:
: Fast moving electrons creates electromagnetic waves so, the diffraction pattern will be observed. Also the angular width of the central maximum is given by \(\omega=\frac{2 \lambda}{\mathrm{a}}\) \(\mathrm{a}=\text { width of the slit }\) \(\lambda=\text { wavelength of the light. }\)When the speed of electrons will increase the frequency will increase which will result in decreasing the wavelength as the speed of light is a constant. Therefore the angular width will decreases.
VITEEE-2008
WAVE OPTICS
283533
Experiment with slit width \(0.6 \mathrm{~mm}\). If yellow light is replaced by \(\mathrm{X}\)-rays then the pattern will reveal that :
1 no diffraction pattern
2 that the central maxima narrower
3 less number of fringes
4 more number of fringes
Explanation:
: If yellow light is replaced by X-rays than no diffraction pattern will be observed because X-rays can't be seen by naked eye. Since, wavelength of X-rays is equal to 1 to \(100 \AA\) and its very-very lesser than slit width. Diffraction is obtained only when width of slit in the order of wavelength of electromagnetic wave.
Karnataka CET-2003
WAVE OPTICS
283534
Light appears to travel in straight lines because:
1 light consists of very small particles
2 the frequency of light is very small
3 the velocity of light is different for different colours
4 the wavelength of light is very small
Explanation:
: Light travel in straight line because the wavelength of light is very small. Due to small wavelength the phenomena known as diffraction is least happened in light. So, light travels in straight line.
Karnataka CET-2002
WAVE OPTICS
283535
The angular width of the central maximum of the diffraction pattern in a single slit (of width 'a') experiment, with \(\lambda\) as the wavelength of light, is
1 \(\frac{3 \lambda}{2 \mathrm{a}}\)
2 \(\frac{\lambda}{2 \mathrm{a}}\)
3 \(\frac{2 \lambda}{\mathrm{a}}\)
4 \(\frac{\lambda}{\mathrm{a}}\)
Explanation:
: The central maxima lies between the first minima on both sides. The angular width of central maxima, \(2 \theta=\frac{2 \lambda}{\mathrm{a}}\)
283522
A parallel beam of fast moving electrons is incident normally on a narrow slit. A screen in placed at a large distance from the slit. If the speed of the electrons is increase, which of the following statement is correct?
1 diffraction pattern is not observed on the screen in the case of electrons
2 the angular width of the central maximum of the diffraction pattern will increase
3 the angular width of the central maximum will decrease
4 the angular width of the central maximum will remain the same
Explanation:
: Fast moving electrons creates electromagnetic waves so, the diffraction pattern will be observed. Also the angular width of the central maximum is given by \(\omega=\frac{2 \lambda}{\mathrm{a}}\) \(\mathrm{a}=\text { width of the slit }\) \(\lambda=\text { wavelength of the light. }\)When the speed of electrons will increase the frequency will increase which will result in decreasing the wavelength as the speed of light is a constant. Therefore the angular width will decreases.
VITEEE-2008
WAVE OPTICS
283533
Experiment with slit width \(0.6 \mathrm{~mm}\). If yellow light is replaced by \(\mathrm{X}\)-rays then the pattern will reveal that :
1 no diffraction pattern
2 that the central maxima narrower
3 less number of fringes
4 more number of fringes
Explanation:
: If yellow light is replaced by X-rays than no diffraction pattern will be observed because X-rays can't be seen by naked eye. Since, wavelength of X-rays is equal to 1 to \(100 \AA\) and its very-very lesser than slit width. Diffraction is obtained only when width of slit in the order of wavelength of electromagnetic wave.
Karnataka CET-2003
WAVE OPTICS
283534
Light appears to travel in straight lines because:
1 light consists of very small particles
2 the frequency of light is very small
3 the velocity of light is different for different colours
4 the wavelength of light is very small
Explanation:
: Light travel in straight line because the wavelength of light is very small. Due to small wavelength the phenomena known as diffraction is least happened in light. So, light travels in straight line.
Karnataka CET-2002
WAVE OPTICS
283535
The angular width of the central maximum of the diffraction pattern in a single slit (of width 'a') experiment, with \(\lambda\) as the wavelength of light, is
1 \(\frac{3 \lambda}{2 \mathrm{a}}\)
2 \(\frac{\lambda}{2 \mathrm{a}}\)
3 \(\frac{2 \lambda}{\mathrm{a}}\)
4 \(\frac{\lambda}{\mathrm{a}}\)
Explanation:
: The central maxima lies between the first minima on both sides. The angular width of central maxima, \(2 \theta=\frac{2 \lambda}{\mathrm{a}}\)
283522
A parallel beam of fast moving electrons is incident normally on a narrow slit. A screen in placed at a large distance from the slit. If the speed of the electrons is increase, which of the following statement is correct?
1 diffraction pattern is not observed on the screen in the case of electrons
2 the angular width of the central maximum of the diffraction pattern will increase
3 the angular width of the central maximum will decrease
4 the angular width of the central maximum will remain the same
Explanation:
: Fast moving electrons creates electromagnetic waves so, the diffraction pattern will be observed. Also the angular width of the central maximum is given by \(\omega=\frac{2 \lambda}{\mathrm{a}}\) \(\mathrm{a}=\text { width of the slit }\) \(\lambda=\text { wavelength of the light. }\)When the speed of electrons will increase the frequency will increase which will result in decreasing the wavelength as the speed of light is a constant. Therefore the angular width will decreases.
VITEEE-2008
WAVE OPTICS
283533
Experiment with slit width \(0.6 \mathrm{~mm}\). If yellow light is replaced by \(\mathrm{X}\)-rays then the pattern will reveal that :
1 no diffraction pattern
2 that the central maxima narrower
3 less number of fringes
4 more number of fringes
Explanation:
: If yellow light is replaced by X-rays than no diffraction pattern will be observed because X-rays can't be seen by naked eye. Since, wavelength of X-rays is equal to 1 to \(100 \AA\) and its very-very lesser than slit width. Diffraction is obtained only when width of slit in the order of wavelength of electromagnetic wave.
Karnataka CET-2003
WAVE OPTICS
283534
Light appears to travel in straight lines because:
1 light consists of very small particles
2 the frequency of light is very small
3 the velocity of light is different for different colours
4 the wavelength of light is very small
Explanation:
: Light travel in straight line because the wavelength of light is very small. Due to small wavelength the phenomena known as diffraction is least happened in light. So, light travels in straight line.
Karnataka CET-2002
WAVE OPTICS
283535
The angular width of the central maximum of the diffraction pattern in a single slit (of width 'a') experiment, with \(\lambda\) as the wavelength of light, is
1 \(\frac{3 \lambda}{2 \mathrm{a}}\)
2 \(\frac{\lambda}{2 \mathrm{a}}\)
3 \(\frac{2 \lambda}{\mathrm{a}}\)
4 \(\frac{\lambda}{\mathrm{a}}\)
Explanation:
: The central maxima lies between the first minima on both sides. The angular width of central maxima, \(2 \theta=\frac{2 \lambda}{\mathrm{a}}\)
283522
A parallel beam of fast moving electrons is incident normally on a narrow slit. A screen in placed at a large distance from the slit. If the speed of the electrons is increase, which of the following statement is correct?
1 diffraction pattern is not observed on the screen in the case of electrons
2 the angular width of the central maximum of the diffraction pattern will increase
3 the angular width of the central maximum will decrease
4 the angular width of the central maximum will remain the same
Explanation:
: Fast moving electrons creates electromagnetic waves so, the diffraction pattern will be observed. Also the angular width of the central maximum is given by \(\omega=\frac{2 \lambda}{\mathrm{a}}\) \(\mathrm{a}=\text { width of the slit }\) \(\lambda=\text { wavelength of the light. }\)When the speed of electrons will increase the frequency will increase which will result in decreasing the wavelength as the speed of light is a constant. Therefore the angular width will decreases.
VITEEE-2008
WAVE OPTICS
283533
Experiment with slit width \(0.6 \mathrm{~mm}\). If yellow light is replaced by \(\mathrm{X}\)-rays then the pattern will reveal that :
1 no diffraction pattern
2 that the central maxima narrower
3 less number of fringes
4 more number of fringes
Explanation:
: If yellow light is replaced by X-rays than no diffraction pattern will be observed because X-rays can't be seen by naked eye. Since, wavelength of X-rays is equal to 1 to \(100 \AA\) and its very-very lesser than slit width. Diffraction is obtained only when width of slit in the order of wavelength of electromagnetic wave.
Karnataka CET-2003
WAVE OPTICS
283534
Light appears to travel in straight lines because:
1 light consists of very small particles
2 the frequency of light is very small
3 the velocity of light is different for different colours
4 the wavelength of light is very small
Explanation:
: Light travel in straight line because the wavelength of light is very small. Due to small wavelength the phenomena known as diffraction is least happened in light. So, light travels in straight line.
Karnataka CET-2002
WAVE OPTICS
283535
The angular width of the central maximum of the diffraction pattern in a single slit (of width 'a') experiment, with \(\lambda\) as the wavelength of light, is
1 \(\frac{3 \lambda}{2 \mathrm{a}}\)
2 \(\frac{\lambda}{2 \mathrm{a}}\)
3 \(\frac{2 \lambda}{\mathrm{a}}\)
4 \(\frac{\lambda}{\mathrm{a}}\)
Explanation:
: The central maxima lies between the first minima on both sides. The angular width of central maxima, \(2 \theta=\frac{2 \lambda}{\mathrm{a}}\)
