283515
A single slit is used to observe diffraction pattern with red light. On replacing the red light with violet light the diffraction pattern would :
1 remain unchanged
2 become narrower
3 become broader
4 disappear
Explanation:
: The diffraction pattern is given as b \(\sin \theta=\mathrm{n} \lambda\) Since the wavelength of violet light is less than that of red light so if red light is replace by violet light the diffraction pattern becomes narrower.
BCECE-2005
WAVE OPTICS
283517
A plane wavefront of wavelength \(\lambda\) is incident on a single slit of width \(b\). What is the angular width for secondary maximum?
1 \(\frac{\lambda}{2 b}\)
2 \(\frac{\lambda}{\mathrm{b}}\)
3 \(\frac{2 \lambda}{\mathrm{b}}\)
4 \(\frac{\mathrm{b}}{\lambda}\)
Explanation:
: We know that, Fringe width \((\beta)=\frac{\lambda D}{d}\) and \(\theta=\frac{\beta}{D}\) \(\therefore \quad \theta=\frac{\lambda}{\mathrm{d}}\) Width of single slit \(=\mathrm{b}\) So, \(\theta=\frac{\lambda}{\mathrm{b}}\)
MHT-CET 2011
WAVE OPTICS
283518
Light is incident at an angle \(i\) on a glass slab. The reflected ray is completely polarised. The angle of refraction is
1 \(90^{\circ}-\mathrm{i}\)
2 \(180^{\circ}-\mathrm{i}\)
3 \(90^{\circ}+\mathrm{i}\)
4 \(\mathrm{i}\)
Explanation:
: When a beam of unpolarised light reflected from a transparent medium (refractive index \(\mu\) ). The refracted light is completely plane polarised of a certain angle of incidence is called polarization angle (i). \(\angle \mathrm{i}+\angle \mathrm{r}=90^{\circ}\) \(\angle \mathrm{r}=90-\angle \mathrm{i}\)
MHT-CET 2010
WAVE OPTICS
283520
When an unpolarised light of intensity \(I_0\) is incident on a polarising sheet, the intensity of the light which does not get transmitted is
1 \(\frac{1}{2} I_0\)
2 \(\frac{1}{4} I_0\)
3 zero
4 \(\mathrm{I}_0\)
Explanation:
: We know that, \(\mathrm{I}=\mathrm{I}_{\mathrm{o}} \cos ^2 \theta\) Intensity of polarized light \(=\frac{I_o}{2}\) \(\therefore\) Intensity of untransmitted light \(=\mathrm{I}_{\mathrm{o}}-\frac{\mathrm{I}_{\mathrm{o}}}{2}=\frac{\mathrm{I}_{\mathrm{o}}}{2}\)
MHT-CET 2008
WAVE OPTICS
283521
When exposed to sunlight, thin films of oil on water often exhibit brilliant colours due to the phenomenon of
1 interference
2 diffraction
3 dispersion
4 polarisation
Explanation:
: When exposed to sunlight, thin filters of oil on water often exhibit brilliant colours due to the phenomenon of interference. These colours arise due to interference of sunlight reflected from the upper and lower surface of the film.
283515
A single slit is used to observe diffraction pattern with red light. On replacing the red light with violet light the diffraction pattern would :
1 remain unchanged
2 become narrower
3 become broader
4 disappear
Explanation:
: The diffraction pattern is given as b \(\sin \theta=\mathrm{n} \lambda\) Since the wavelength of violet light is less than that of red light so if red light is replace by violet light the diffraction pattern becomes narrower.
BCECE-2005
WAVE OPTICS
283517
A plane wavefront of wavelength \(\lambda\) is incident on a single slit of width \(b\). What is the angular width for secondary maximum?
1 \(\frac{\lambda}{2 b}\)
2 \(\frac{\lambda}{\mathrm{b}}\)
3 \(\frac{2 \lambda}{\mathrm{b}}\)
4 \(\frac{\mathrm{b}}{\lambda}\)
Explanation:
: We know that, Fringe width \((\beta)=\frac{\lambda D}{d}\) and \(\theta=\frac{\beta}{D}\) \(\therefore \quad \theta=\frac{\lambda}{\mathrm{d}}\) Width of single slit \(=\mathrm{b}\) So, \(\theta=\frac{\lambda}{\mathrm{b}}\)
MHT-CET 2011
WAVE OPTICS
283518
Light is incident at an angle \(i\) on a glass slab. The reflected ray is completely polarised. The angle of refraction is
1 \(90^{\circ}-\mathrm{i}\)
2 \(180^{\circ}-\mathrm{i}\)
3 \(90^{\circ}+\mathrm{i}\)
4 \(\mathrm{i}\)
Explanation:
: When a beam of unpolarised light reflected from a transparent medium (refractive index \(\mu\) ). The refracted light is completely plane polarised of a certain angle of incidence is called polarization angle (i). \(\angle \mathrm{i}+\angle \mathrm{r}=90^{\circ}\) \(\angle \mathrm{r}=90-\angle \mathrm{i}\)
MHT-CET 2010
WAVE OPTICS
283520
When an unpolarised light of intensity \(I_0\) is incident on a polarising sheet, the intensity of the light which does not get transmitted is
1 \(\frac{1}{2} I_0\)
2 \(\frac{1}{4} I_0\)
3 zero
4 \(\mathrm{I}_0\)
Explanation:
: We know that, \(\mathrm{I}=\mathrm{I}_{\mathrm{o}} \cos ^2 \theta\) Intensity of polarized light \(=\frac{I_o}{2}\) \(\therefore\) Intensity of untransmitted light \(=\mathrm{I}_{\mathrm{o}}-\frac{\mathrm{I}_{\mathrm{o}}}{2}=\frac{\mathrm{I}_{\mathrm{o}}}{2}\)
MHT-CET 2008
WAVE OPTICS
283521
When exposed to sunlight, thin films of oil on water often exhibit brilliant colours due to the phenomenon of
1 interference
2 diffraction
3 dispersion
4 polarisation
Explanation:
: When exposed to sunlight, thin filters of oil on water often exhibit brilliant colours due to the phenomenon of interference. These colours arise due to interference of sunlight reflected from the upper and lower surface of the film.
283515
A single slit is used to observe diffraction pattern with red light. On replacing the red light with violet light the diffraction pattern would :
1 remain unchanged
2 become narrower
3 become broader
4 disappear
Explanation:
: The diffraction pattern is given as b \(\sin \theta=\mathrm{n} \lambda\) Since the wavelength of violet light is less than that of red light so if red light is replace by violet light the diffraction pattern becomes narrower.
BCECE-2005
WAVE OPTICS
283517
A plane wavefront of wavelength \(\lambda\) is incident on a single slit of width \(b\). What is the angular width for secondary maximum?
1 \(\frac{\lambda}{2 b}\)
2 \(\frac{\lambda}{\mathrm{b}}\)
3 \(\frac{2 \lambda}{\mathrm{b}}\)
4 \(\frac{\mathrm{b}}{\lambda}\)
Explanation:
: We know that, Fringe width \((\beta)=\frac{\lambda D}{d}\) and \(\theta=\frac{\beta}{D}\) \(\therefore \quad \theta=\frac{\lambda}{\mathrm{d}}\) Width of single slit \(=\mathrm{b}\) So, \(\theta=\frac{\lambda}{\mathrm{b}}\)
MHT-CET 2011
WAVE OPTICS
283518
Light is incident at an angle \(i\) on a glass slab. The reflected ray is completely polarised. The angle of refraction is
1 \(90^{\circ}-\mathrm{i}\)
2 \(180^{\circ}-\mathrm{i}\)
3 \(90^{\circ}+\mathrm{i}\)
4 \(\mathrm{i}\)
Explanation:
: When a beam of unpolarised light reflected from a transparent medium (refractive index \(\mu\) ). The refracted light is completely plane polarised of a certain angle of incidence is called polarization angle (i). \(\angle \mathrm{i}+\angle \mathrm{r}=90^{\circ}\) \(\angle \mathrm{r}=90-\angle \mathrm{i}\)
MHT-CET 2010
WAVE OPTICS
283520
When an unpolarised light of intensity \(I_0\) is incident on a polarising sheet, the intensity of the light which does not get transmitted is
1 \(\frac{1}{2} I_0\)
2 \(\frac{1}{4} I_0\)
3 zero
4 \(\mathrm{I}_0\)
Explanation:
: We know that, \(\mathrm{I}=\mathrm{I}_{\mathrm{o}} \cos ^2 \theta\) Intensity of polarized light \(=\frac{I_o}{2}\) \(\therefore\) Intensity of untransmitted light \(=\mathrm{I}_{\mathrm{o}}-\frac{\mathrm{I}_{\mathrm{o}}}{2}=\frac{\mathrm{I}_{\mathrm{o}}}{2}\)
MHT-CET 2008
WAVE OPTICS
283521
When exposed to sunlight, thin films of oil on water often exhibit brilliant colours due to the phenomenon of
1 interference
2 diffraction
3 dispersion
4 polarisation
Explanation:
: When exposed to sunlight, thin filters of oil on water often exhibit brilliant colours due to the phenomenon of interference. These colours arise due to interference of sunlight reflected from the upper and lower surface of the film.
NEET Test Series from KOTA - 10 Papers In MS WORD
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WAVE OPTICS
283515
A single slit is used to observe diffraction pattern with red light. On replacing the red light with violet light the diffraction pattern would :
1 remain unchanged
2 become narrower
3 become broader
4 disappear
Explanation:
: The diffraction pattern is given as b \(\sin \theta=\mathrm{n} \lambda\) Since the wavelength of violet light is less than that of red light so if red light is replace by violet light the diffraction pattern becomes narrower.
BCECE-2005
WAVE OPTICS
283517
A plane wavefront of wavelength \(\lambda\) is incident on a single slit of width \(b\). What is the angular width for secondary maximum?
1 \(\frac{\lambda}{2 b}\)
2 \(\frac{\lambda}{\mathrm{b}}\)
3 \(\frac{2 \lambda}{\mathrm{b}}\)
4 \(\frac{\mathrm{b}}{\lambda}\)
Explanation:
: We know that, Fringe width \((\beta)=\frac{\lambda D}{d}\) and \(\theta=\frac{\beta}{D}\) \(\therefore \quad \theta=\frac{\lambda}{\mathrm{d}}\) Width of single slit \(=\mathrm{b}\) So, \(\theta=\frac{\lambda}{\mathrm{b}}\)
MHT-CET 2011
WAVE OPTICS
283518
Light is incident at an angle \(i\) on a glass slab. The reflected ray is completely polarised. The angle of refraction is
1 \(90^{\circ}-\mathrm{i}\)
2 \(180^{\circ}-\mathrm{i}\)
3 \(90^{\circ}+\mathrm{i}\)
4 \(\mathrm{i}\)
Explanation:
: When a beam of unpolarised light reflected from a transparent medium (refractive index \(\mu\) ). The refracted light is completely plane polarised of a certain angle of incidence is called polarization angle (i). \(\angle \mathrm{i}+\angle \mathrm{r}=90^{\circ}\) \(\angle \mathrm{r}=90-\angle \mathrm{i}\)
MHT-CET 2010
WAVE OPTICS
283520
When an unpolarised light of intensity \(I_0\) is incident on a polarising sheet, the intensity of the light which does not get transmitted is
1 \(\frac{1}{2} I_0\)
2 \(\frac{1}{4} I_0\)
3 zero
4 \(\mathrm{I}_0\)
Explanation:
: We know that, \(\mathrm{I}=\mathrm{I}_{\mathrm{o}} \cos ^2 \theta\) Intensity of polarized light \(=\frac{I_o}{2}\) \(\therefore\) Intensity of untransmitted light \(=\mathrm{I}_{\mathrm{o}}-\frac{\mathrm{I}_{\mathrm{o}}}{2}=\frac{\mathrm{I}_{\mathrm{o}}}{2}\)
MHT-CET 2008
WAVE OPTICS
283521
When exposed to sunlight, thin films of oil on water often exhibit brilliant colours due to the phenomenon of
1 interference
2 diffraction
3 dispersion
4 polarisation
Explanation:
: When exposed to sunlight, thin filters of oil on water often exhibit brilliant colours due to the phenomenon of interference. These colours arise due to interference of sunlight reflected from the upper and lower surface of the film.
283515
A single slit is used to observe diffraction pattern with red light. On replacing the red light with violet light the diffraction pattern would :
1 remain unchanged
2 become narrower
3 become broader
4 disappear
Explanation:
: The diffraction pattern is given as b \(\sin \theta=\mathrm{n} \lambda\) Since the wavelength of violet light is less than that of red light so if red light is replace by violet light the diffraction pattern becomes narrower.
BCECE-2005
WAVE OPTICS
283517
A plane wavefront of wavelength \(\lambda\) is incident on a single slit of width \(b\). What is the angular width for secondary maximum?
1 \(\frac{\lambda}{2 b}\)
2 \(\frac{\lambda}{\mathrm{b}}\)
3 \(\frac{2 \lambda}{\mathrm{b}}\)
4 \(\frac{\mathrm{b}}{\lambda}\)
Explanation:
: We know that, Fringe width \((\beta)=\frac{\lambda D}{d}\) and \(\theta=\frac{\beta}{D}\) \(\therefore \quad \theta=\frac{\lambda}{\mathrm{d}}\) Width of single slit \(=\mathrm{b}\) So, \(\theta=\frac{\lambda}{\mathrm{b}}\)
MHT-CET 2011
WAVE OPTICS
283518
Light is incident at an angle \(i\) on a glass slab. The reflected ray is completely polarised. The angle of refraction is
1 \(90^{\circ}-\mathrm{i}\)
2 \(180^{\circ}-\mathrm{i}\)
3 \(90^{\circ}+\mathrm{i}\)
4 \(\mathrm{i}\)
Explanation:
: When a beam of unpolarised light reflected from a transparent medium (refractive index \(\mu\) ). The refracted light is completely plane polarised of a certain angle of incidence is called polarization angle (i). \(\angle \mathrm{i}+\angle \mathrm{r}=90^{\circ}\) \(\angle \mathrm{r}=90-\angle \mathrm{i}\)
MHT-CET 2010
WAVE OPTICS
283520
When an unpolarised light of intensity \(I_0\) is incident on a polarising sheet, the intensity of the light which does not get transmitted is
1 \(\frac{1}{2} I_0\)
2 \(\frac{1}{4} I_0\)
3 zero
4 \(\mathrm{I}_0\)
Explanation:
: We know that, \(\mathrm{I}=\mathrm{I}_{\mathrm{o}} \cos ^2 \theta\) Intensity of polarized light \(=\frac{I_o}{2}\) \(\therefore\) Intensity of untransmitted light \(=\mathrm{I}_{\mathrm{o}}-\frac{\mathrm{I}_{\mathrm{o}}}{2}=\frac{\mathrm{I}_{\mathrm{o}}}{2}\)
MHT-CET 2008
WAVE OPTICS
283521
When exposed to sunlight, thin films of oil on water often exhibit brilliant colours due to the phenomenon of
1 interference
2 diffraction
3 dispersion
4 polarisation
Explanation:
: When exposed to sunlight, thin filters of oil on water often exhibit brilliant colours due to the phenomenon of interference. These colours arise due to interference of sunlight reflected from the upper and lower surface of the film.
