283496
Which of the following effects could not be observed for sound waves in air?
1 Interference
2 Refraction
3 Polarization
4 Diffraction
Explanation:
: Polarisation :- The action of restricting the vibration of a transverse wave completely or partially one direction is called polarization. Only transverse waves can be polarised because its particles is vibrating perpendicular to the direction of propagation. Diffraction :- It is defined as the bending of waver around the corner when a wave encounters an obstacle.
COMEDK 2011
WAVE OPTICS
283500
Which of the following statement is false?
1 Sound and light wave exhibit interference.
2 Sound and light wave exhibit diffraction.
3 Light wave exhibit polarization while sound wave does not.
4 Sound wave exhibit polarization while light does not.
Explanation:
: Diffraction of light is the Phenomenon of pending of light around corners of an obstacle or aperture in the path of light. Polarization It is property of transverse waves that define the orientation of oscillation of the wave. Sound is a longitudinal wave. longitudinal wave cannot be polarized because their particles vibrate in the some direction that wave travels. so sound waves cannot undergo polarization.
COMEDK 2012
WAVE OPTICS
283506
The condition for obtaining secondary maxima in the diffraction pattern due to single slit is
1 a \(\sin \theta=n \lambda\)
2 \(\sin \theta=(2 n-1) \frac{\lambda}{2}\)
3 \(a \sin \theta=(2 n-1) \lambda\)
4 \(a \sin \theta=\frac{\mathrm{n} \lambda}{2}\)
Explanation:
: The condition to obtain secondary maxima in the diffraction pattern due to single slit is given by the formula \(\operatorname{asin} \theta=(2 n-1) \frac{\lambda}{2}\) Where, \(\mathrm{a}=\) width of the slit \(\mathrm{n}=\) order of maxima \(\lambda=\) wavelength of the incident light.
AIIMS-2014
WAVE OPTICS
283508
In a single slit diffraction experiment, the width of the slit is made double its original width. Then the central maximum of the diffraction pattern will become.
1 broader and brighter
2 narrower and fainter
3 narrower and brighter
4 broader and fainter
Explanation:
: From the angular width of the central maximum is given by, \(\beta=\frac{2 \mathrm{D} \lambda}{\mathrm{a}}\) Here \(\mathrm{a}\) is the width of the slit and \(\lambda\) is the wavelength if the value of a becomes doubled then the angular width of the central maximum decrease to half it previous value. This implies that the central maximum becomes much sharper moreover if \(\mathrm{a}\) is doubled, the intensity of the central maximum becomes four times. Therefore, the central maximum becomes much narrower and brighter.
283496
Which of the following effects could not be observed for sound waves in air?
1 Interference
2 Refraction
3 Polarization
4 Diffraction
Explanation:
: Polarisation :- The action of restricting the vibration of a transverse wave completely or partially one direction is called polarization. Only transverse waves can be polarised because its particles is vibrating perpendicular to the direction of propagation. Diffraction :- It is defined as the bending of waver around the corner when a wave encounters an obstacle.
COMEDK 2011
WAVE OPTICS
283500
Which of the following statement is false?
1 Sound and light wave exhibit interference.
2 Sound and light wave exhibit diffraction.
3 Light wave exhibit polarization while sound wave does not.
4 Sound wave exhibit polarization while light does not.
Explanation:
: Diffraction of light is the Phenomenon of pending of light around corners of an obstacle or aperture in the path of light. Polarization It is property of transverse waves that define the orientation of oscillation of the wave. Sound is a longitudinal wave. longitudinal wave cannot be polarized because their particles vibrate in the some direction that wave travels. so sound waves cannot undergo polarization.
COMEDK 2012
WAVE OPTICS
283506
The condition for obtaining secondary maxima in the diffraction pattern due to single slit is
1 a \(\sin \theta=n \lambda\)
2 \(\sin \theta=(2 n-1) \frac{\lambda}{2}\)
3 \(a \sin \theta=(2 n-1) \lambda\)
4 \(a \sin \theta=\frac{\mathrm{n} \lambda}{2}\)
Explanation:
: The condition to obtain secondary maxima in the diffraction pattern due to single slit is given by the formula \(\operatorname{asin} \theta=(2 n-1) \frac{\lambda}{2}\) Where, \(\mathrm{a}=\) width of the slit \(\mathrm{n}=\) order of maxima \(\lambda=\) wavelength of the incident light.
AIIMS-2014
WAVE OPTICS
283508
In a single slit diffraction experiment, the width of the slit is made double its original width. Then the central maximum of the diffraction pattern will become.
1 broader and brighter
2 narrower and fainter
3 narrower and brighter
4 broader and fainter
Explanation:
: From the angular width of the central maximum is given by, \(\beta=\frac{2 \mathrm{D} \lambda}{\mathrm{a}}\) Here \(\mathrm{a}\) is the width of the slit and \(\lambda\) is the wavelength if the value of a becomes doubled then the angular width of the central maximum decrease to half it previous value. This implies that the central maximum becomes much sharper moreover if \(\mathrm{a}\) is doubled, the intensity of the central maximum becomes four times. Therefore, the central maximum becomes much narrower and brighter.
283496
Which of the following effects could not be observed for sound waves in air?
1 Interference
2 Refraction
3 Polarization
4 Diffraction
Explanation:
: Polarisation :- The action of restricting the vibration of a transverse wave completely or partially one direction is called polarization. Only transverse waves can be polarised because its particles is vibrating perpendicular to the direction of propagation. Diffraction :- It is defined as the bending of waver around the corner when a wave encounters an obstacle.
COMEDK 2011
WAVE OPTICS
283500
Which of the following statement is false?
1 Sound and light wave exhibit interference.
2 Sound and light wave exhibit diffraction.
3 Light wave exhibit polarization while sound wave does not.
4 Sound wave exhibit polarization while light does not.
Explanation:
: Diffraction of light is the Phenomenon of pending of light around corners of an obstacle or aperture in the path of light. Polarization It is property of transverse waves that define the orientation of oscillation of the wave. Sound is a longitudinal wave. longitudinal wave cannot be polarized because their particles vibrate in the some direction that wave travels. so sound waves cannot undergo polarization.
COMEDK 2012
WAVE OPTICS
283506
The condition for obtaining secondary maxima in the diffraction pattern due to single slit is
1 a \(\sin \theta=n \lambda\)
2 \(\sin \theta=(2 n-1) \frac{\lambda}{2}\)
3 \(a \sin \theta=(2 n-1) \lambda\)
4 \(a \sin \theta=\frac{\mathrm{n} \lambda}{2}\)
Explanation:
: The condition to obtain secondary maxima in the diffraction pattern due to single slit is given by the formula \(\operatorname{asin} \theta=(2 n-1) \frac{\lambda}{2}\) Where, \(\mathrm{a}=\) width of the slit \(\mathrm{n}=\) order of maxima \(\lambda=\) wavelength of the incident light.
AIIMS-2014
WAVE OPTICS
283508
In a single slit diffraction experiment, the width of the slit is made double its original width. Then the central maximum of the diffraction pattern will become.
1 broader and brighter
2 narrower and fainter
3 narrower and brighter
4 broader and fainter
Explanation:
: From the angular width of the central maximum is given by, \(\beta=\frac{2 \mathrm{D} \lambda}{\mathrm{a}}\) Here \(\mathrm{a}\) is the width of the slit and \(\lambda\) is the wavelength if the value of a becomes doubled then the angular width of the central maximum decrease to half it previous value. This implies that the central maximum becomes much sharper moreover if \(\mathrm{a}\) is doubled, the intensity of the central maximum becomes four times. Therefore, the central maximum becomes much narrower and brighter.
283496
Which of the following effects could not be observed for sound waves in air?
1 Interference
2 Refraction
3 Polarization
4 Diffraction
Explanation:
: Polarisation :- The action of restricting the vibration of a transverse wave completely or partially one direction is called polarization. Only transverse waves can be polarised because its particles is vibrating perpendicular to the direction of propagation. Diffraction :- It is defined as the bending of waver around the corner when a wave encounters an obstacle.
COMEDK 2011
WAVE OPTICS
283500
Which of the following statement is false?
1 Sound and light wave exhibit interference.
2 Sound and light wave exhibit diffraction.
3 Light wave exhibit polarization while sound wave does not.
4 Sound wave exhibit polarization while light does not.
Explanation:
: Diffraction of light is the Phenomenon of pending of light around corners of an obstacle or aperture in the path of light. Polarization It is property of transverse waves that define the orientation of oscillation of the wave. Sound is a longitudinal wave. longitudinal wave cannot be polarized because their particles vibrate in the some direction that wave travels. so sound waves cannot undergo polarization.
COMEDK 2012
WAVE OPTICS
283506
The condition for obtaining secondary maxima in the diffraction pattern due to single slit is
1 a \(\sin \theta=n \lambda\)
2 \(\sin \theta=(2 n-1) \frac{\lambda}{2}\)
3 \(a \sin \theta=(2 n-1) \lambda\)
4 \(a \sin \theta=\frac{\mathrm{n} \lambda}{2}\)
Explanation:
: The condition to obtain secondary maxima in the diffraction pattern due to single slit is given by the formula \(\operatorname{asin} \theta=(2 n-1) \frac{\lambda}{2}\) Where, \(\mathrm{a}=\) width of the slit \(\mathrm{n}=\) order of maxima \(\lambda=\) wavelength of the incident light.
AIIMS-2014
WAVE OPTICS
283508
In a single slit diffraction experiment, the width of the slit is made double its original width. Then the central maximum of the diffraction pattern will become.
1 broader and brighter
2 narrower and fainter
3 narrower and brighter
4 broader and fainter
Explanation:
: From the angular width of the central maximum is given by, \(\beta=\frac{2 \mathrm{D} \lambda}{\mathrm{a}}\) Here \(\mathrm{a}\) is the width of the slit and \(\lambda\) is the wavelength if the value of a becomes doubled then the angular width of the central maximum decrease to half it previous value. This implies that the central maximum becomes much sharper moreover if \(\mathrm{a}\) is doubled, the intensity of the central maximum becomes four times. Therefore, the central maximum becomes much narrower and brighter.
