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Ray Optics

282105 Consider a glass and water interface. If a light ray incident at the glass water interface with an angle of ' $i$ ' and the ray emerges parallel to surface of water. What is refractive index of glass?

1 1

2 1.5

3

\frac{1}{\sin i}

4

\sin i

Explanation:

C: Given, incident angle $= i$
Refractive index of water $= μ_{w}$
And reflection angle at water air interface is $90^{\circ}$
![original image](https://cdn.mathpix.com/snip/images/zlF6E0qT1kf-C60oJjx9Y7ksH0IU5YHEBqvEn9gJZZE.original.fullsize.png)
$Unknown environment 'tabular'$

TS EAMCET 29.09.2020

Ray Optics

282106 A light travels through water in the breaker. The height of water column is ' $h$ '. Refractive index of water is ' $μ_{w}$ '. If $c$ is velocity of light in air, the time taken by light to travel through water will be

1

\frac{μ_{w} h}{c}

2

\frac{h}{μ_{w} c}

3

\frac{hc}{μ_{w}}

4

h μ_{w} c

Explanation:

D: We know that,
$Velocity = \frac{distance}{time}$
or time $= \frac{distance}{velocity} = \frac{h}{c / μ_{w}}$
$(\begin{aligned} ∵ μ_{w} & = \frac{c}{v} \\ v & = \frac{c}{μ_{w}} \end{aligned})$
Where, $c =$ speed of light in air
$μ_{w} = Refractive index of water$
So, time $= \frac{h μ_{w}}{c}$

MHT-CET 2020

Ray Optics

282107 Refractive index of the medium is ' $μ$ ' and wavelength is $λ$ , then which of the following proportionality relation is correct?

1

μ \propto \frac{1}{λ}

2

μ \propto λ

3

μ \propto \frac{1}{λ^{2}}

4

μ \propto λ^{2}

Explanation:

A: Given, Reflective index $= μ$ , wavelength $= λ$
We know that,
$\begin{array}{r} μ = \frac{speed of light in air}{speed of light in medium} \\ μ = \frac{c}{v} = \frac{c}{λ f} (∵ v = λ f) \\ μ \propto \frac{1}{λ} \end{array}$

MHT-CET 2020

Ray Optics

282108 Let ' $μ_{1}$ ' and ' $μ_{2}$ ' be the refractive indices of two media. ' $v_{1}$ ' and ' $v_{2}$ ' are the velocities of light in the media respectively. Which one of the following relations is TRUE?

1

μ_{2}^{2} v_{1} = μ_{1}^{2} v_{2}

2

μ_{1} v_{1} = μ_{2} v_{2}

3

μ_{2} v_{1} = μ_{1} v_{2}

4

μ_{1} v_{1}^{2} = μ_{2} v_{2}^{2}

Explanation:

B: Given, $μ_{1}$ and $μ_{2}$ be the refractive indices of two media, $v_{1}$ and $v_{2}$ are the velocities.
We know that,
$_{1} μ_{2} = \frac{μ_{2}}{μ_{1}} = \frac{speed of light in medium 1}{speed of light in medium 2} = \frac{v_{1}}{v_{2}}$
$μ_{1} v_{1} = μ_{2} v_{2}$

МНТ-СЕТ 2020

Ray Optics

282105 Consider a glass and water interface. If a light ray incident at the glass water interface with an angle of ' $i$ ' and the ray emerges parallel to surface of water. What is refractive index of glass?

1 1

2 1.5

3

\frac{1}{\sin i}

4

\sin i

Explanation:

C: Given, incident angle $= i$
Refractive index of water $= μ_{w}$
And reflection angle at water air interface is $90^{\circ}$
![original image](https://cdn.mathpix.com/snip/images/zlF6E0qT1kf-C60oJjx9Y7ksH0IU5YHEBqvEn9gJZZE.original.fullsize.png)
$Unknown environment 'tabular'$

TS EAMCET 29.09.2020

Ray Optics

282106 A light travels through water in the breaker. The height of water column is ' $h$ '. Refractive index of water is ' $μ_{w}$ '. If $c$ is velocity of light in air, the time taken by light to travel through water will be

1

\frac{μ_{w} h}{c}

2

\frac{h}{μ_{w} c}

3

\frac{hc}{μ_{w}}

4

h μ_{w} c

Explanation:

D: We know that,
$Velocity = \frac{distance}{time}$
or time $= \frac{distance}{velocity} = \frac{h}{c / μ_{w}}$
$(\begin{aligned} ∵ μ_{w} & = \frac{c}{v} \\ v & = \frac{c}{μ_{w}} \end{aligned})$
Where, $c =$ speed of light in air
$μ_{w} = Refractive index of water$
So, time $= \frac{h μ_{w}}{c}$

MHT-CET 2020

Ray Optics

282107 Refractive index of the medium is ' $μ$ ' and wavelength is $λ$ , then which of the following proportionality relation is correct?

1

μ \propto \frac{1}{λ}

2

μ \propto λ

3

μ \propto \frac{1}{λ^{2}}

4

μ \propto λ^{2}

Explanation:

A: Given, Reflective index $= μ$ , wavelength $= λ$
We know that,
$\begin{array}{r} μ = \frac{speed of light in air}{speed of light in medium} \\ μ = \frac{c}{v} = \frac{c}{λ f} (∵ v = λ f) \\ μ \propto \frac{1}{λ} \end{array}$

MHT-CET 2020

Ray Optics

282108 Let ' $μ_{1}$ ' and ' $μ_{2}$ ' be the refractive indices of two media. ' $v_{1}$ ' and ' $v_{2}$ ' are the velocities of light in the media respectively. Which one of the following relations is TRUE?

1

μ_{2}^{2} v_{1} = μ_{1}^{2} v_{2}

2

μ_{1} v_{1} = μ_{2} v_{2}

3

μ_{2} v_{1} = μ_{1} v_{2}

4

μ_{1} v_{1}^{2} = μ_{2} v_{2}^{2}

Explanation:

B: Given, $μ_{1}$ and $μ_{2}$ be the refractive indices of two media, $v_{1}$ and $v_{2}$ are the velocities.
We know that,
$_{1} μ_{2} = \frac{μ_{2}}{μ_{1}} = \frac{speed of light in medium 1}{speed of light in medium 2} = \frac{v_{1}}{v_{2}}$
$μ_{1} v_{1} = μ_{2} v_{2}$

МНТ-СЕТ 2020

Ray Optics

282105 Consider a glass and water interface. If a light ray incident at the glass water interface with an angle of ' $i$ ' and the ray emerges parallel to surface of water. What is refractive index of glass?

1 1

2 1.5

3

\frac{1}{\sin i}

4

\sin i

Explanation:

C: Given, incident angle $= i$
Refractive index of water $= μ_{w}$
And reflection angle at water air interface is $90^{\circ}$
![original image](https://cdn.mathpix.com/snip/images/zlF6E0qT1kf-C60oJjx9Y7ksH0IU5YHEBqvEn9gJZZE.original.fullsize.png)
$Unknown environment 'tabular'$

TS EAMCET 29.09.2020

Ray Optics

282106 A light travels through water in the breaker. The height of water column is ' $h$ '. Refractive index of water is ' $μ_{w}$ '. If $c$ is velocity of light in air, the time taken by light to travel through water will be

1

\frac{μ_{w} h}{c}

2

\frac{h}{μ_{w} c}

3

\frac{hc}{μ_{w}}

4

h μ_{w} c

Explanation:

D: We know that,
$Velocity = \frac{distance}{time}$
or time $= \frac{distance}{velocity} = \frac{h}{c / μ_{w}}$
$(\begin{aligned} ∵ μ_{w} & = \frac{c}{v} \\ v & = \frac{c}{μ_{w}} \end{aligned})$
Where, $c =$ speed of light in air
$μ_{w} = Refractive index of water$
So, time $= \frac{h μ_{w}}{c}$

MHT-CET 2020

Ray Optics

282107 Refractive index of the medium is ' $μ$ ' and wavelength is $λ$ , then which of the following proportionality relation is correct?

1

μ \propto \frac{1}{λ}

2

μ \propto λ

3

μ \propto \frac{1}{λ^{2}}

4

μ \propto λ^{2}

Explanation:

A: Given, Reflective index $= μ$ , wavelength $= λ$
We know that,
$\begin{array}{r} μ = \frac{speed of light in air}{speed of light in medium} \\ μ = \frac{c}{v} = \frac{c}{λ f} (∵ v = λ f) \\ μ \propto \frac{1}{λ} \end{array}$

MHT-CET 2020

Ray Optics

282108 Let ' $μ_{1}$ ' and ' $μ_{2}$ ' be the refractive indices of two media. ' $v_{1}$ ' and ' $v_{2}$ ' are the velocities of light in the media respectively. Which one of the following relations is TRUE?

1

μ_{2}^{2} v_{1} = μ_{1}^{2} v_{2}

2

μ_{1} v_{1} = μ_{2} v_{2}

3

μ_{2} v_{1} = μ_{1} v_{2}

4

μ_{1} v_{1}^{2} = μ_{2} v_{2}^{2}

Explanation:

B: Given, $μ_{1}$ and $μ_{2}$ be the refractive indices of two media, $v_{1}$ and $v_{2}$ are the velocities.
We know that,
$_{1} μ_{2} = \frac{μ_{2}}{μ_{1}} = \frac{speed of light in medium 1}{speed of light in medium 2} = \frac{v_{1}}{v_{2}}$
$μ_{1} v_{1} = μ_{2} v_{2}$

МНТ-СЕТ 2020

Ray Optics

282105 Consider a glass and water interface. If a light ray incident at the glass water interface with an angle of ' $i$ ' and the ray emerges parallel to surface of water. What is refractive index of glass?

1 1

2 1.5

3

\frac{1}{\sin i}

4

\sin i

Explanation:

C: Given, incident angle $= i$
Refractive index of water $= μ_{w}$
And reflection angle at water air interface is $90^{\circ}$
![original image](https://cdn.mathpix.com/snip/images/zlF6E0qT1kf-C60oJjx9Y7ksH0IU5YHEBqvEn9gJZZE.original.fullsize.png)
$Unknown environment 'tabular'$

TS EAMCET 29.09.2020

Ray Optics

282106 A light travels through water in the breaker. The height of water column is ' $h$ '. Refractive index of water is ' $μ_{w}$ '. If $c$ is velocity of light in air, the time taken by light to travel through water will be

1

\frac{μ_{w} h}{c}

2

\frac{h}{μ_{w} c}

3

\frac{hc}{μ_{w}}

4

h μ_{w} c

Explanation:

D: We know that,
$Velocity = \frac{distance}{time}$
or time $= \frac{distance}{velocity} = \frac{h}{c / μ_{w}}$
$(\begin{aligned} ∵ μ_{w} & = \frac{c}{v} \\ v & = \frac{c}{μ_{w}} \end{aligned})$
Where, $c =$ speed of light in air
$μ_{w} = Refractive index of water$
So, time $= \frac{h μ_{w}}{c}$

MHT-CET 2020

Ray Optics

282107 Refractive index of the medium is ' $μ$ ' and wavelength is $λ$ , then which of the following proportionality relation is correct?

1

μ \propto \frac{1}{λ}

2

μ \propto λ

3

μ \propto \frac{1}{λ^{2}}

4

μ \propto λ^{2}

Explanation:

A: Given, Reflective index $= μ$ , wavelength $= λ$
We know that,
$\begin{array}{r} μ = \frac{speed of light in air}{speed of light in medium} \\ μ = \frac{c}{v} = \frac{c}{λ f} (∵ v = λ f) \\ μ \propto \frac{1}{λ} \end{array}$

MHT-CET 2020

Ray Optics

282108 Let ' $μ_{1}$ ' and ' $μ_{2}$ ' be the refractive indices of two media. ' $v_{1}$ ' and ' $v_{2}$ ' are the velocities of light in the media respectively. Which one of the following relations is TRUE?

1

μ_{2}^{2} v_{1} = μ_{1}^{2} v_{2}

2

μ_{1} v_{1} = μ_{2} v_{2}

3

μ_{2} v_{1} = μ_{1} v_{2}

4

μ_{1} v_{1}^{2} = μ_{2} v_{2}^{2}

Explanation:

B: Given, $μ_{1}$ and $μ_{2}$ be the refractive indices of two media, $v_{1}$ and $v_{2}$ are the velocities.
We know that,
$_{1} μ_{2} = \frac{μ_{2}}{μ_{1}} = \frac{speed of light in medium 1}{speed of light in medium 2} = \frac{v_{1}}{v_{2}}$
$μ_{1} v_{1} = μ_{2} v_{2}$

МНТ-СЕТ 2020