270486
If ' \(A\) ' is areal velocity of a planet of mass \(M\), its angular momentum is
1 \(M / A\)
2 \(2 \mathrm{MA}\)
3 \(A^{2} M\)
4 \(A M^{2}\)
Explanation:
\(\frac{d A}{d t}=\frac{L}{2 M}\)
Gravitation
270487
A planet revolves round the sun in an elliptical orbit of semi minor and semi major axes \(x\) and \(y\) respectively. Then the time period of revolution is proportional to
1 \((x+y)^{\frac{3}{2}}\)
2 \((y-x)^{\frac{3}{2}}\)
3 \(x^{\frac{3}{2}}\)
4 \(y^{\frac{3}{2}}\)
Explanation:
From Kepler's 3rd law, \(T^{2} \alpha r^{3}\)
Gravitation
270488
Let ' \(A\) ' be the area swept by the line joining the earth and the sun during Feb 2012. The area swept by the same line during the first week of that month is
1 \(A / 4\)
2 \(7 A / 29\)
3 \(A\)
4 \(7 \mathrm{~A} / 30\)
Explanation:
For 29 days - A, For 1 day - A/29,
For 1 week - 7A/29,
Gravitation
270489
A satellite moving in a circular path of radius ' \(r\) ' around earth has a time period \(T\). If its radius slightly increases by \(4 \%\), then percentage change in its time period is
270490
The time of revolution of planet \(A\) round the sun is 8 times that of another planet \(B\). The distance of planet \(A\) from the sun is how many times greater than that of the planet \(B\) from the sun
270486
If ' \(A\) ' is areal velocity of a planet of mass \(M\), its angular momentum is
1 \(M / A\)
2 \(2 \mathrm{MA}\)
3 \(A^{2} M\)
4 \(A M^{2}\)
Explanation:
\(\frac{d A}{d t}=\frac{L}{2 M}\)
Gravitation
270487
A planet revolves round the sun in an elliptical orbit of semi minor and semi major axes \(x\) and \(y\) respectively. Then the time period of revolution is proportional to
1 \((x+y)^{\frac{3}{2}}\)
2 \((y-x)^{\frac{3}{2}}\)
3 \(x^{\frac{3}{2}}\)
4 \(y^{\frac{3}{2}}\)
Explanation:
From Kepler's 3rd law, \(T^{2} \alpha r^{3}\)
Gravitation
270488
Let ' \(A\) ' be the area swept by the line joining the earth and the sun during Feb 2012. The area swept by the same line during the first week of that month is
1 \(A / 4\)
2 \(7 A / 29\)
3 \(A\)
4 \(7 \mathrm{~A} / 30\)
Explanation:
For 29 days - A, For 1 day - A/29,
For 1 week - 7A/29,
Gravitation
270489
A satellite moving in a circular path of radius ' \(r\) ' around earth has a time period \(T\). If its radius slightly increases by \(4 \%\), then percentage change in its time period is
270490
The time of revolution of planet \(A\) round the sun is 8 times that of another planet \(B\). The distance of planet \(A\) from the sun is how many times greater than that of the planet \(B\) from the sun
270486
If ' \(A\) ' is areal velocity of a planet of mass \(M\), its angular momentum is
1 \(M / A\)
2 \(2 \mathrm{MA}\)
3 \(A^{2} M\)
4 \(A M^{2}\)
Explanation:
\(\frac{d A}{d t}=\frac{L}{2 M}\)
Gravitation
270487
A planet revolves round the sun in an elliptical orbit of semi minor and semi major axes \(x\) and \(y\) respectively. Then the time period of revolution is proportional to
1 \((x+y)^{\frac{3}{2}}\)
2 \((y-x)^{\frac{3}{2}}\)
3 \(x^{\frac{3}{2}}\)
4 \(y^{\frac{3}{2}}\)
Explanation:
From Kepler's 3rd law, \(T^{2} \alpha r^{3}\)
Gravitation
270488
Let ' \(A\) ' be the area swept by the line joining the earth and the sun during Feb 2012. The area swept by the same line during the first week of that month is
1 \(A / 4\)
2 \(7 A / 29\)
3 \(A\)
4 \(7 \mathrm{~A} / 30\)
Explanation:
For 29 days - A, For 1 day - A/29,
For 1 week - 7A/29,
Gravitation
270489
A satellite moving in a circular path of radius ' \(r\) ' around earth has a time period \(T\). If its radius slightly increases by \(4 \%\), then percentage change in its time period is
270490
The time of revolution of planet \(A\) round the sun is 8 times that of another planet \(B\). The distance of planet \(A\) from the sun is how many times greater than that of the planet \(B\) from the sun
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Gravitation
270486
If ' \(A\) ' is areal velocity of a planet of mass \(M\), its angular momentum is
1 \(M / A\)
2 \(2 \mathrm{MA}\)
3 \(A^{2} M\)
4 \(A M^{2}\)
Explanation:
\(\frac{d A}{d t}=\frac{L}{2 M}\)
Gravitation
270487
A planet revolves round the sun in an elliptical orbit of semi minor and semi major axes \(x\) and \(y\) respectively. Then the time period of revolution is proportional to
1 \((x+y)^{\frac{3}{2}}\)
2 \((y-x)^{\frac{3}{2}}\)
3 \(x^{\frac{3}{2}}\)
4 \(y^{\frac{3}{2}}\)
Explanation:
From Kepler's 3rd law, \(T^{2} \alpha r^{3}\)
Gravitation
270488
Let ' \(A\) ' be the area swept by the line joining the earth and the sun during Feb 2012. The area swept by the same line during the first week of that month is
1 \(A / 4\)
2 \(7 A / 29\)
3 \(A\)
4 \(7 \mathrm{~A} / 30\)
Explanation:
For 29 days - A, For 1 day - A/29,
For 1 week - 7A/29,
Gravitation
270489
A satellite moving in a circular path of radius ' \(r\) ' around earth has a time period \(T\). If its radius slightly increases by \(4 \%\), then percentage change in its time period is
270490
The time of revolution of planet \(A\) round the sun is 8 times that of another planet \(B\). The distance of planet \(A\) from the sun is how many times greater than that of the planet \(B\) from the sun
270486
If ' \(A\) ' is areal velocity of a planet of mass \(M\), its angular momentum is
1 \(M / A\)
2 \(2 \mathrm{MA}\)
3 \(A^{2} M\)
4 \(A M^{2}\)
Explanation:
\(\frac{d A}{d t}=\frac{L}{2 M}\)
Gravitation
270487
A planet revolves round the sun in an elliptical orbit of semi minor and semi major axes \(x\) and \(y\) respectively. Then the time period of revolution is proportional to
1 \((x+y)^{\frac{3}{2}}\)
2 \((y-x)^{\frac{3}{2}}\)
3 \(x^{\frac{3}{2}}\)
4 \(y^{\frac{3}{2}}\)
Explanation:
From Kepler's 3rd law, \(T^{2} \alpha r^{3}\)
Gravitation
270488
Let ' \(A\) ' be the area swept by the line joining the earth and the sun during Feb 2012. The area swept by the same line during the first week of that month is
1 \(A / 4\)
2 \(7 A / 29\)
3 \(A\)
4 \(7 \mathrm{~A} / 30\)
Explanation:
For 29 days - A, For 1 day - A/29,
For 1 week - 7A/29,
Gravitation
270489
A satellite moving in a circular path of radius ' \(r\) ' around earth has a time period \(T\). If its radius slightly increases by \(4 \%\), then percentage change in its time period is
270490
The time of revolution of planet \(A\) round the sun is 8 times that of another planet \(B\). The distance of planet \(A\) from the sun is how many times greater than that of the planet \(B\) from the sun