270486
If ' \(A\) ' is areal velocity of a planet of mass \(M\), its angular momentum is
1 \(M / A\)
2 \(2 \mathrm{MA}\)
3 \(A^{2} M\)
4 \(A M^{2}\)
Explanation:
\(\frac{d A}{d t}=\frac{L}{2 M}\)
Gravitation
270487
A planet revolves round the sun in an elliptical orbit of semi minor and semi major axes \(x\) and \(y\) respectively. Then the time period of revolution is proportional to
1 \((x+y)^{\frac{3}{2}}\)
2 \((y-x)^{\frac{3}{2}}\)
3 \(x^{\frac{3}{2}}\)
4 \(y^{\frac{3}{2}}\)
Explanation:
From Kepler's 3rd law, \(T^{2} \alpha r^{3}\)
Gravitation
270488
Let ' \(A\) ' be the area swept by the line joining the earth and the sun during Feb 2012. The area swept by the same line during the first week of that month is
1 \(A / 4\)
2 \(7 A / 29\)
3 \(A\)
4 \(7 \mathrm{~A} / 30\)
Explanation:
For 29 days - A, For 1 day - A/29,
For 1 week - 7A/29,
Gravitation
270489
A satellite moving in a circular path of radius ' \(r\) ' around earth has a time period \(T\). If its radius slightly increases by \(4 \%\), then percentage change in its time period is
270490
The time of revolution of planet \(A\) round the sun is 8 times that of another planet \(B\). The distance of planet \(A\) from the sun is how many times greater than that of the planet \(B\) from the sun
270486
If ' \(A\) ' is areal velocity of a planet of mass \(M\), its angular momentum is
1 \(M / A\)
2 \(2 \mathrm{MA}\)
3 \(A^{2} M\)
4 \(A M^{2}\)
Explanation:
\(\frac{d A}{d t}=\frac{L}{2 M}\)
Gravitation
270487
A planet revolves round the sun in an elliptical orbit of semi minor and semi major axes \(x\) and \(y\) respectively. Then the time period of revolution is proportional to
1 \((x+y)^{\frac{3}{2}}\)
2 \((y-x)^{\frac{3}{2}}\)
3 \(x^{\frac{3}{2}}\)
4 \(y^{\frac{3}{2}}\)
Explanation:
From Kepler's 3rd law, \(T^{2} \alpha r^{3}\)
Gravitation
270488
Let ' \(A\) ' be the area swept by the line joining the earth and the sun during Feb 2012. The area swept by the same line during the first week of that month is
1 \(A / 4\)
2 \(7 A / 29\)
3 \(A\)
4 \(7 \mathrm{~A} / 30\)
Explanation:
For 29 days - A, For 1 day - A/29,
For 1 week - 7A/29,
Gravitation
270489
A satellite moving in a circular path of radius ' \(r\) ' around earth has a time period \(T\). If its radius slightly increases by \(4 \%\), then percentage change in its time period is
270490
The time of revolution of planet \(A\) round the sun is 8 times that of another planet \(B\). The distance of planet \(A\) from the sun is how many times greater than that of the planet \(B\) from the sun
270486
If ' \(A\) ' is areal velocity of a planet of mass \(M\), its angular momentum is
1 \(M / A\)
2 \(2 \mathrm{MA}\)
3 \(A^{2} M\)
4 \(A M^{2}\)
Explanation:
\(\frac{d A}{d t}=\frac{L}{2 M}\)
Gravitation
270487
A planet revolves round the sun in an elliptical orbit of semi minor and semi major axes \(x\) and \(y\) respectively. Then the time period of revolution is proportional to
1 \((x+y)^{\frac{3}{2}}\)
2 \((y-x)^{\frac{3}{2}}\)
3 \(x^{\frac{3}{2}}\)
4 \(y^{\frac{3}{2}}\)
Explanation:
From Kepler's 3rd law, \(T^{2} \alpha r^{3}\)
Gravitation
270488
Let ' \(A\) ' be the area swept by the line joining the earth and the sun during Feb 2012. The area swept by the same line during the first week of that month is
1 \(A / 4\)
2 \(7 A / 29\)
3 \(A\)
4 \(7 \mathrm{~A} / 30\)
Explanation:
For 29 days - A, For 1 day - A/29,
For 1 week - 7A/29,
Gravitation
270489
A satellite moving in a circular path of radius ' \(r\) ' around earth has a time period \(T\). If its radius slightly increases by \(4 \%\), then percentage change in its time period is
270490
The time of revolution of planet \(A\) round the sun is 8 times that of another planet \(B\). The distance of planet \(A\) from the sun is how many times greater than that of the planet \(B\) from the sun
270486
If ' \(A\) ' is areal velocity of a planet of mass \(M\), its angular momentum is
1 \(M / A\)
2 \(2 \mathrm{MA}\)
3 \(A^{2} M\)
4 \(A M^{2}\)
Explanation:
\(\frac{d A}{d t}=\frac{L}{2 M}\)
Gravitation
270487
A planet revolves round the sun in an elliptical orbit of semi minor and semi major axes \(x\) and \(y\) respectively. Then the time period of revolution is proportional to
1 \((x+y)^{\frac{3}{2}}\)
2 \((y-x)^{\frac{3}{2}}\)
3 \(x^{\frac{3}{2}}\)
4 \(y^{\frac{3}{2}}\)
Explanation:
From Kepler's 3rd law, \(T^{2} \alpha r^{3}\)
Gravitation
270488
Let ' \(A\) ' be the area swept by the line joining the earth and the sun during Feb 2012. The area swept by the same line during the first week of that month is
1 \(A / 4\)
2 \(7 A / 29\)
3 \(A\)
4 \(7 \mathrm{~A} / 30\)
Explanation:
For 29 days - A, For 1 day - A/29,
For 1 week - 7A/29,
Gravitation
270489
A satellite moving in a circular path of radius ' \(r\) ' around earth has a time period \(T\). If its radius slightly increases by \(4 \%\), then percentage change in its time period is
270490
The time of revolution of planet \(A\) round the sun is 8 times that of another planet \(B\). The distance of planet \(A\) from the sun is how many times greater than that of the planet \(B\) from the sun
270486
If ' \(A\) ' is areal velocity of a planet of mass \(M\), its angular momentum is
1 \(M / A\)
2 \(2 \mathrm{MA}\)
3 \(A^{2} M\)
4 \(A M^{2}\)
Explanation:
\(\frac{d A}{d t}=\frac{L}{2 M}\)
Gravitation
270487
A planet revolves round the sun in an elliptical orbit of semi minor and semi major axes \(x\) and \(y\) respectively. Then the time period of revolution is proportional to
1 \((x+y)^{\frac{3}{2}}\)
2 \((y-x)^{\frac{3}{2}}\)
3 \(x^{\frac{3}{2}}\)
4 \(y^{\frac{3}{2}}\)
Explanation:
From Kepler's 3rd law, \(T^{2} \alpha r^{3}\)
Gravitation
270488
Let ' \(A\) ' be the area swept by the line joining the earth and the sun during Feb 2012. The area swept by the same line during the first week of that month is
1 \(A / 4\)
2 \(7 A / 29\)
3 \(A\)
4 \(7 \mathrm{~A} / 30\)
Explanation:
For 29 days - A, For 1 day - A/29,
For 1 week - 7A/29,
Gravitation
270489
A satellite moving in a circular path of radius ' \(r\) ' around earth has a time period \(T\). If its radius slightly increases by \(4 \%\), then percentage change in its time period is
270490
The time of revolution of planet \(A\) round the sun is 8 times that of another planet \(B\). The distance of planet \(A\) from the sun is how many times greater than that of the planet \(B\) from the sun
