NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Laws of Motion
270200
A\(6.0 \mathrm{~kg}\) object is suspended by a vertical string from the ceiling of an elevator which is accelerating upward at a rate of \(2.2 \mathrm{~ms}^{-2}\). the tension in the string is
1 \(11 \mathrm{~N}\)
2 \(72 \mathrm{~N}\)
3 \(48 \mathrm{~N}\)
4 \(59 \mathrm{~N}\)
Explanation:
\(\mathrm{T}=\mathrm{m}(\mathrm{g}+\mathrm{a})\)
Laws of Motion
270201
A young man of mass\(60 \mathrm{~kg}\) stands on the floor of a lift which is accelerating downwards at \(1 \mathrm{~m} / \mathrm{s}^{2}\) then the reaction of the floor of the lift on the man is (Take \(g=9.8 \mathrm{~m} / \mathrm{s}^{2}\) )
1 \(528 \mathrm{~N}\)
2 \(540 \mathrm{~N}\)
3 \(546 \mathrm{~N}\)
4 none
Explanation:
\(R=m(g-a)\)
Laws of Motion
270202
Three masses of\(16 \mathrm{~kg}, 8 \mathrm{~kg}\) and \(4 \mathrm{~kg}\) are placed in contact as shown in Figure. If a force of \(140 \mathrm{~N}\) is applied on \(4 \mathrm{~kg}\) mass, then the force on \(16 \mathrm{~kg}\) will be
1 \(140 \mathrm{~N}\)
2 \(120 \mathrm{~N}\)
3 \(100 \mathrm{~N}\)
4 \(80 \mathrm{~N}\)
Explanation:
\(F=m a, a=\frac{F}{m_{1}+m_{2}+m_{3}}\)
Laws of Motion
270203
A body of mass \(M\) is being pulled by a string of mass \(m\) with a force \(P\) applied at one end. The force exerted by the string on the body is
1 \(\frac{P m}{(M+m)}\)
2 \(\frac{P M}{(M+m)}\)
3 \(\operatorname{Pm}(M+m)\)
4 \(\frac{P}{(M-m)}\)
Explanation:
\(F=m a, a=\frac{F}{M}=\frac{F}{M+m} ; \mathrm{T}=\) Ма
270200
A\(6.0 \mathrm{~kg}\) object is suspended by a vertical string from the ceiling of an elevator which is accelerating upward at a rate of \(2.2 \mathrm{~ms}^{-2}\). the tension in the string is
1 \(11 \mathrm{~N}\)
2 \(72 \mathrm{~N}\)
3 \(48 \mathrm{~N}\)
4 \(59 \mathrm{~N}\)
Explanation:
\(\mathrm{T}=\mathrm{m}(\mathrm{g}+\mathrm{a})\)
Laws of Motion
270201
A young man of mass\(60 \mathrm{~kg}\) stands on the floor of a lift which is accelerating downwards at \(1 \mathrm{~m} / \mathrm{s}^{2}\) then the reaction of the floor of the lift on the man is (Take \(g=9.8 \mathrm{~m} / \mathrm{s}^{2}\) )
1 \(528 \mathrm{~N}\)
2 \(540 \mathrm{~N}\)
3 \(546 \mathrm{~N}\)
4 none
Explanation:
\(R=m(g-a)\)
Laws of Motion
270202
Three masses of\(16 \mathrm{~kg}, 8 \mathrm{~kg}\) and \(4 \mathrm{~kg}\) are placed in contact as shown in Figure. If a force of \(140 \mathrm{~N}\) is applied on \(4 \mathrm{~kg}\) mass, then the force on \(16 \mathrm{~kg}\) will be
1 \(140 \mathrm{~N}\)
2 \(120 \mathrm{~N}\)
3 \(100 \mathrm{~N}\)
4 \(80 \mathrm{~N}\)
Explanation:
\(F=m a, a=\frac{F}{m_{1}+m_{2}+m_{3}}\)
Laws of Motion
270203
A body of mass \(M\) is being pulled by a string of mass \(m\) with a force \(P\) applied at one end. The force exerted by the string on the body is
1 \(\frac{P m}{(M+m)}\)
2 \(\frac{P M}{(M+m)}\)
3 \(\operatorname{Pm}(M+m)\)
4 \(\frac{P}{(M-m)}\)
Explanation:
\(F=m a, a=\frac{F}{M}=\frac{F}{M+m} ; \mathrm{T}=\) Ма
270200
A\(6.0 \mathrm{~kg}\) object is suspended by a vertical string from the ceiling of an elevator which is accelerating upward at a rate of \(2.2 \mathrm{~ms}^{-2}\). the tension in the string is
1 \(11 \mathrm{~N}\)
2 \(72 \mathrm{~N}\)
3 \(48 \mathrm{~N}\)
4 \(59 \mathrm{~N}\)
Explanation:
\(\mathrm{T}=\mathrm{m}(\mathrm{g}+\mathrm{a})\)
Laws of Motion
270201
A young man of mass\(60 \mathrm{~kg}\) stands on the floor of a lift which is accelerating downwards at \(1 \mathrm{~m} / \mathrm{s}^{2}\) then the reaction of the floor of the lift on the man is (Take \(g=9.8 \mathrm{~m} / \mathrm{s}^{2}\) )
1 \(528 \mathrm{~N}\)
2 \(540 \mathrm{~N}\)
3 \(546 \mathrm{~N}\)
4 none
Explanation:
\(R=m(g-a)\)
Laws of Motion
270202
Three masses of\(16 \mathrm{~kg}, 8 \mathrm{~kg}\) and \(4 \mathrm{~kg}\) are placed in contact as shown in Figure. If a force of \(140 \mathrm{~N}\) is applied on \(4 \mathrm{~kg}\) mass, then the force on \(16 \mathrm{~kg}\) will be
1 \(140 \mathrm{~N}\)
2 \(120 \mathrm{~N}\)
3 \(100 \mathrm{~N}\)
4 \(80 \mathrm{~N}\)
Explanation:
\(F=m a, a=\frac{F}{m_{1}+m_{2}+m_{3}}\)
Laws of Motion
270203
A body of mass \(M\) is being pulled by a string of mass \(m\) with a force \(P\) applied at one end. The force exerted by the string on the body is
1 \(\frac{P m}{(M+m)}\)
2 \(\frac{P M}{(M+m)}\)
3 \(\operatorname{Pm}(M+m)\)
4 \(\frac{P}{(M-m)}\)
Explanation:
\(F=m a, a=\frac{F}{M}=\frac{F}{M+m} ; \mathrm{T}=\) Ма
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
Laws of Motion
270200
A\(6.0 \mathrm{~kg}\) object is suspended by a vertical string from the ceiling of an elevator which is accelerating upward at a rate of \(2.2 \mathrm{~ms}^{-2}\). the tension in the string is
1 \(11 \mathrm{~N}\)
2 \(72 \mathrm{~N}\)
3 \(48 \mathrm{~N}\)
4 \(59 \mathrm{~N}\)
Explanation:
\(\mathrm{T}=\mathrm{m}(\mathrm{g}+\mathrm{a})\)
Laws of Motion
270201
A young man of mass\(60 \mathrm{~kg}\) stands on the floor of a lift which is accelerating downwards at \(1 \mathrm{~m} / \mathrm{s}^{2}\) then the reaction of the floor of the lift on the man is (Take \(g=9.8 \mathrm{~m} / \mathrm{s}^{2}\) )
1 \(528 \mathrm{~N}\)
2 \(540 \mathrm{~N}\)
3 \(546 \mathrm{~N}\)
4 none
Explanation:
\(R=m(g-a)\)
Laws of Motion
270202
Three masses of\(16 \mathrm{~kg}, 8 \mathrm{~kg}\) and \(4 \mathrm{~kg}\) are placed in contact as shown in Figure. If a force of \(140 \mathrm{~N}\) is applied on \(4 \mathrm{~kg}\) mass, then the force on \(16 \mathrm{~kg}\) will be
1 \(140 \mathrm{~N}\)
2 \(120 \mathrm{~N}\)
3 \(100 \mathrm{~N}\)
4 \(80 \mathrm{~N}\)
Explanation:
\(F=m a, a=\frac{F}{m_{1}+m_{2}+m_{3}}\)
Laws of Motion
270203
A body of mass \(M\) is being pulled by a string of mass \(m\) with a force \(P\) applied at one end. The force exerted by the string on the body is
1 \(\frac{P m}{(M+m)}\)
2 \(\frac{P M}{(M+m)}\)
3 \(\operatorname{Pm}(M+m)\)
4 \(\frac{P}{(M-m)}\)
Explanation:
\(F=m a, a=\frac{F}{M}=\frac{F}{M+m} ; \mathrm{T}=\) Ма
