NEWTON'S LAWS OF MOTION
Laws of Motion

270351 A ropeis stretched between two boats at rest. A sailor in the first boat pulls the rope with a constant force of 100N. First boat with the sailor has a mass of \(250 \mathrm{~kg}\) where as the mass of second boat is double of this mass. If the initial distance between the boats was \(100 \mathrm{~m}\), the time taken for two boats to meet each other in seconds (neglect water resistance between boats and water)

1 13.8
2 18.3
3 3.18
4 31.8
Laws of Motion

270352 In order to raise a block of mass\(100 \mathrm{~kg}\) a man of mass \(60 \mathrm{~kg}\) fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with an acceleration \(\frac{5 g}{4}\) relative to rope. The tension in the rope is \(\left(g=10 \mathrm{~ms}^{-2}\right)\)

1 \(1432 \mathrm{~N}\)
2 \(928 \mathrm{~N}\)
3 \(1218 \mathrm{~N}\)
4 \(642 \mathrm{~N}\)
Laws of Motion

270353 In the pulley-block arrangement shown infigure.Find the relation between acceleration of block \(A\) and \(B\).

1 \(\mathrm{a}_{B}=-3 \mathrm{a}_{\mathrm{A}}\)
2 \(a_{B}=-a_{A}\)
3 \(a_{B}=-2 a_{A}\)
4 \(a_{B}=-4 a_{A}\)
Laws of Motion

270354 Three equal weights\(A, B\) and \(C\) of mass \(2 \mathrm{~kg}\) each are hanging on a string passing over a fixed frictionless pulley as shown in the fig. The tension in the string connecting weights \(B\) and \(C\) is

1 zero
2 \(13 \mathrm{~N}\)
3 \(3.3 \mathrm{~N}\)
4 \(19.6 \mathrm{~N}\)
Laws of Motion

270355 In the figure show\(n a_{3}=6 \mathrm{~m} / \mathrm{s}^{2}\) (downwards) and \(a_{2}=4 m / s^{2}\) (upwards). Find acceleration of ![original image](https://cdn.mathpix.com/snip/images/ShDtY6kwSV3KBvBKalOk6vfrgt6t-fhV-zm2_4Mgfnw.original.fullsize.png)

1 \(1 \mathrm{~m} / \mathrm{sec}^2\) upwards
2 \(2 \mathrm{~m} / \mathrm{sec}^2\) upwards
3 \(1 \mathrm{~m} / \mathrm{sec}^2\) downwards
4 \(42 \mathrm{~m} / \mathrm{sec}^2\) downwards
Laws of Motion

270351 A ropeis stretched between two boats at rest. A sailor in the first boat pulls the rope with a constant force of 100N. First boat with the sailor has a mass of \(250 \mathrm{~kg}\) where as the mass of second boat is double of this mass. If the initial distance between the boats was \(100 \mathrm{~m}\), the time taken for two boats to meet each other in seconds (neglect water resistance between boats and water)

1 13.8
2 18.3
3 3.18
4 31.8
Laws of Motion

270352 In order to raise a block of mass\(100 \mathrm{~kg}\) a man of mass \(60 \mathrm{~kg}\) fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with an acceleration \(\frac{5 g}{4}\) relative to rope. The tension in the rope is \(\left(g=10 \mathrm{~ms}^{-2}\right)\)

1 \(1432 \mathrm{~N}\)
2 \(928 \mathrm{~N}\)
3 \(1218 \mathrm{~N}\)
4 \(642 \mathrm{~N}\)
Laws of Motion

270353 In the pulley-block arrangement shown infigure.Find the relation between acceleration of block \(A\) and \(B\).

1 \(\mathrm{a}_{B}=-3 \mathrm{a}_{\mathrm{A}}\)
2 \(a_{B}=-a_{A}\)
3 \(a_{B}=-2 a_{A}\)
4 \(a_{B}=-4 a_{A}\)
Laws of Motion

270354 Three equal weights\(A, B\) and \(C\) of mass \(2 \mathrm{~kg}\) each are hanging on a string passing over a fixed frictionless pulley as shown in the fig. The tension in the string connecting weights \(B\) and \(C\) is

1 zero
2 \(13 \mathrm{~N}\)
3 \(3.3 \mathrm{~N}\)
4 \(19.6 \mathrm{~N}\)
Laws of Motion

270355 In the figure show\(n a_{3}=6 \mathrm{~m} / \mathrm{s}^{2}\) (downwards) and \(a_{2}=4 m / s^{2}\) (upwards). Find acceleration of ![original image](https://cdn.mathpix.com/snip/images/ShDtY6kwSV3KBvBKalOk6vfrgt6t-fhV-zm2_4Mgfnw.original.fullsize.png)

1 \(1 \mathrm{~m} / \mathrm{sec}^2\) upwards
2 \(2 \mathrm{~m} / \mathrm{sec}^2\) upwards
3 \(1 \mathrm{~m} / \mathrm{sec}^2\) downwards
4 \(42 \mathrm{~m} / \mathrm{sec}^2\) downwards
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Laws of Motion

270351 A ropeis stretched between two boats at rest. A sailor in the first boat pulls the rope with a constant force of 100N. First boat with the sailor has a mass of \(250 \mathrm{~kg}\) where as the mass of second boat is double of this mass. If the initial distance between the boats was \(100 \mathrm{~m}\), the time taken for two boats to meet each other in seconds (neglect water resistance between boats and water)

1 13.8
2 18.3
3 3.18
4 31.8
Laws of Motion

270352 In order to raise a block of mass\(100 \mathrm{~kg}\) a man of mass \(60 \mathrm{~kg}\) fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with an acceleration \(\frac{5 g}{4}\) relative to rope. The tension in the rope is \(\left(g=10 \mathrm{~ms}^{-2}\right)\)

1 \(1432 \mathrm{~N}\)
2 \(928 \mathrm{~N}\)
3 \(1218 \mathrm{~N}\)
4 \(642 \mathrm{~N}\)
Laws of Motion

270353 In the pulley-block arrangement shown infigure.Find the relation between acceleration of block \(A\) and \(B\).

1 \(\mathrm{a}_{B}=-3 \mathrm{a}_{\mathrm{A}}\)
2 \(a_{B}=-a_{A}\)
3 \(a_{B}=-2 a_{A}\)
4 \(a_{B}=-4 a_{A}\)
Laws of Motion

270354 Three equal weights\(A, B\) and \(C\) of mass \(2 \mathrm{~kg}\) each are hanging on a string passing over a fixed frictionless pulley as shown in the fig. The tension in the string connecting weights \(B\) and \(C\) is

1 zero
2 \(13 \mathrm{~N}\)
3 \(3.3 \mathrm{~N}\)
4 \(19.6 \mathrm{~N}\)
Laws of Motion

270355 In the figure show\(n a_{3}=6 \mathrm{~m} / \mathrm{s}^{2}\) (downwards) and \(a_{2}=4 m / s^{2}\) (upwards). Find acceleration of ![original image](https://cdn.mathpix.com/snip/images/ShDtY6kwSV3KBvBKalOk6vfrgt6t-fhV-zm2_4Mgfnw.original.fullsize.png)

1 \(1 \mathrm{~m} / \mathrm{sec}^2\) upwards
2 \(2 \mathrm{~m} / \mathrm{sec}^2\) upwards
3 \(1 \mathrm{~m} / \mathrm{sec}^2\) downwards
4 \(42 \mathrm{~m} / \mathrm{sec}^2\) downwards
Laws of Motion

270351 A ropeis stretched between two boats at rest. A sailor in the first boat pulls the rope with a constant force of 100N. First boat with the sailor has a mass of \(250 \mathrm{~kg}\) where as the mass of second boat is double of this mass. If the initial distance between the boats was \(100 \mathrm{~m}\), the time taken for two boats to meet each other in seconds (neglect water resistance between boats and water)

1 13.8
2 18.3
3 3.18
4 31.8
Laws of Motion

270352 In order to raise a block of mass\(100 \mathrm{~kg}\) a man of mass \(60 \mathrm{~kg}\) fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with an acceleration \(\frac{5 g}{4}\) relative to rope. The tension in the rope is \(\left(g=10 \mathrm{~ms}^{-2}\right)\)

1 \(1432 \mathrm{~N}\)
2 \(928 \mathrm{~N}\)
3 \(1218 \mathrm{~N}\)
4 \(642 \mathrm{~N}\)
Laws of Motion

270353 In the pulley-block arrangement shown infigure.Find the relation between acceleration of block \(A\) and \(B\).

1 \(\mathrm{a}_{B}=-3 \mathrm{a}_{\mathrm{A}}\)
2 \(a_{B}=-a_{A}\)
3 \(a_{B}=-2 a_{A}\)
4 \(a_{B}=-4 a_{A}\)
Laws of Motion

270354 Three equal weights\(A, B\) and \(C\) of mass \(2 \mathrm{~kg}\) each are hanging on a string passing over a fixed frictionless pulley as shown in the fig. The tension in the string connecting weights \(B\) and \(C\) is

1 zero
2 \(13 \mathrm{~N}\)
3 \(3.3 \mathrm{~N}\)
4 \(19.6 \mathrm{~N}\)
Laws of Motion

270355 In the figure show\(n a_{3}=6 \mathrm{~m} / \mathrm{s}^{2}\) (downwards) and \(a_{2}=4 m / s^{2}\) (upwards). Find acceleration of ![original image](https://cdn.mathpix.com/snip/images/ShDtY6kwSV3KBvBKalOk6vfrgt6t-fhV-zm2_4Mgfnw.original.fullsize.png)

1 \(1 \mathrm{~m} / \mathrm{sec}^2\) upwards
2 \(2 \mathrm{~m} / \mathrm{sec}^2\) upwards
3 \(1 \mathrm{~m} / \mathrm{sec}^2\) downwards
4 \(42 \mathrm{~m} / \mathrm{sec}^2\) downwards
Laws of Motion

270351 A ropeis stretched between two boats at rest. A sailor in the first boat pulls the rope with a constant force of 100N. First boat with the sailor has a mass of \(250 \mathrm{~kg}\) where as the mass of second boat is double of this mass. If the initial distance between the boats was \(100 \mathrm{~m}\), the time taken for two boats to meet each other in seconds (neglect water resistance between boats and water)

1 13.8
2 18.3
3 3.18
4 31.8
Laws of Motion

270352 In order to raise a block of mass\(100 \mathrm{~kg}\) a man of mass \(60 \mathrm{~kg}\) fastens a rope to it and passes the rope over a smooth pulley. He climbs the rope with an acceleration \(\frac{5 g}{4}\) relative to rope. The tension in the rope is \(\left(g=10 \mathrm{~ms}^{-2}\right)\)

1 \(1432 \mathrm{~N}\)
2 \(928 \mathrm{~N}\)
3 \(1218 \mathrm{~N}\)
4 \(642 \mathrm{~N}\)
Laws of Motion

270353 In the pulley-block arrangement shown infigure.Find the relation between acceleration of block \(A\) and \(B\).

1 \(\mathrm{a}_{B}=-3 \mathrm{a}_{\mathrm{A}}\)
2 \(a_{B}=-a_{A}\)
3 \(a_{B}=-2 a_{A}\)
4 \(a_{B}=-4 a_{A}\)
Laws of Motion

270354 Three equal weights\(A, B\) and \(C\) of mass \(2 \mathrm{~kg}\) each are hanging on a string passing over a fixed frictionless pulley as shown in the fig. The tension in the string connecting weights \(B\) and \(C\) is

1 zero
2 \(13 \mathrm{~N}\)
3 \(3.3 \mathrm{~N}\)
4 \(19.6 \mathrm{~N}\)
Laws of Motion

270355 In the figure show\(n a_{3}=6 \mathrm{~m} / \mathrm{s}^{2}\) (downwards) and \(a_{2}=4 m / s^{2}\) (upwards). Find acceleration of ![original image](https://cdn.mathpix.com/snip/images/ShDtY6kwSV3KBvBKalOk6vfrgt6t-fhV-zm2_4Mgfnw.original.fullsize.png)

1 \(1 \mathrm{~m} / \mathrm{sec}^2\) upwards
2 \(2 \mathrm{~m} / \mathrm{sec}^2\) upwards
3 \(1 \mathrm{~m} / \mathrm{sec}^2\) downwards
4 \(42 \mathrm{~m} / \mathrm{sec}^2\) downwards