270198
A unidirectional force \(F\) varying with time \(t\) as shown in the Fig. acts on a body initially at rest for a short duration \(2 T\). Then the velocity acquired by the body is
1 \(\frac{\pi F_{0} T}{4 m}\)
2 \(\frac{\pi F_{0} T}{2 m}\)
3 \(\frac{F_{0} T}{4 m}\)
4 zero
Explanation:
From \(\mathrm{O}\) to \(\mathrm{T}\), area is \((+)\) ve and from \(\mathrm{T}\) to \(2 \mathrm{~T}\), area is \((-) v e\), net area is zero, hence, no chang in momentum.
Laws of Motion
270199
If the average velocity of a body moving with uniform acceleration under the action of a force is" \(v\) " and the impulse it receives during a displacement of " \(s\) " is " \(I\) ", the constant force acting on the body is given by
1 \(\frac{I \times v}{2 s}\)
2 \(\frac{2 I \times v}{s}\)
3 \(\frac{I \times v}{s}\)
4 \(\frac{I \times s}{v}\)
Explanation:
\(J=F \times t, t=\frac{s}{v} \quad\)
Laws of Motion
270228
The momenta of a body in two perpendicular directions at anytime't' are given by \(P_{X}=2 t^{2}+6\) and \(P_{Y}=\frac{3 t^{2}}{2}+3\). The force acting on the body at \(t=2 \mathrm{sec}\) is
270229
When a force\(F\) acts on a body of mass \(m\), the acceleration produced in the body is a. If three equal forces \(F_{1}=F_{2}=F_{3}=F\) act on the same body as shown in figure the acceleration produced is
270198
A unidirectional force \(F\) varying with time \(t\) as shown in the Fig. acts on a body initially at rest for a short duration \(2 T\). Then the velocity acquired by the body is
1 \(\frac{\pi F_{0} T}{4 m}\)
2 \(\frac{\pi F_{0} T}{2 m}\)
3 \(\frac{F_{0} T}{4 m}\)
4 zero
Explanation:
From \(\mathrm{O}\) to \(\mathrm{T}\), area is \((+)\) ve and from \(\mathrm{T}\) to \(2 \mathrm{~T}\), area is \((-) v e\), net area is zero, hence, no chang in momentum.
Laws of Motion
270199
If the average velocity of a body moving with uniform acceleration under the action of a force is" \(v\) " and the impulse it receives during a displacement of " \(s\) " is " \(I\) ", the constant force acting on the body is given by
1 \(\frac{I \times v}{2 s}\)
2 \(\frac{2 I \times v}{s}\)
3 \(\frac{I \times v}{s}\)
4 \(\frac{I \times s}{v}\)
Explanation:
\(J=F \times t, t=\frac{s}{v} \quad\)
Laws of Motion
270228
The momenta of a body in two perpendicular directions at anytime't' are given by \(P_{X}=2 t^{2}+6\) and \(P_{Y}=\frac{3 t^{2}}{2}+3\). The force acting on the body at \(t=2 \mathrm{sec}\) is
270229
When a force\(F\) acts on a body of mass \(m\), the acceleration produced in the body is a. If three equal forces \(F_{1}=F_{2}=F_{3}=F\) act on the same body as shown in figure the acceleration produced is
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Laws of Motion
270198
A unidirectional force \(F\) varying with time \(t\) as shown in the Fig. acts on a body initially at rest for a short duration \(2 T\). Then the velocity acquired by the body is
1 \(\frac{\pi F_{0} T}{4 m}\)
2 \(\frac{\pi F_{0} T}{2 m}\)
3 \(\frac{F_{0} T}{4 m}\)
4 zero
Explanation:
From \(\mathrm{O}\) to \(\mathrm{T}\), area is \((+)\) ve and from \(\mathrm{T}\) to \(2 \mathrm{~T}\), area is \((-) v e\), net area is zero, hence, no chang in momentum.
Laws of Motion
270199
If the average velocity of a body moving with uniform acceleration under the action of a force is" \(v\) " and the impulse it receives during a displacement of " \(s\) " is " \(I\) ", the constant force acting on the body is given by
1 \(\frac{I \times v}{2 s}\)
2 \(\frac{2 I \times v}{s}\)
3 \(\frac{I \times v}{s}\)
4 \(\frac{I \times s}{v}\)
Explanation:
\(J=F \times t, t=\frac{s}{v} \quad\)
Laws of Motion
270228
The momenta of a body in two perpendicular directions at anytime't' are given by \(P_{X}=2 t^{2}+6\) and \(P_{Y}=\frac{3 t^{2}}{2}+3\). The force acting on the body at \(t=2 \mathrm{sec}\) is
270229
When a force\(F\) acts on a body of mass \(m\), the acceleration produced in the body is a. If three equal forces \(F_{1}=F_{2}=F_{3}=F\) act on the same body as shown in figure the acceleration produced is
270198
A unidirectional force \(F\) varying with time \(t\) as shown in the Fig. acts on a body initially at rest for a short duration \(2 T\). Then the velocity acquired by the body is
1 \(\frac{\pi F_{0} T}{4 m}\)
2 \(\frac{\pi F_{0} T}{2 m}\)
3 \(\frac{F_{0} T}{4 m}\)
4 zero
Explanation:
From \(\mathrm{O}\) to \(\mathrm{T}\), area is \((+)\) ve and from \(\mathrm{T}\) to \(2 \mathrm{~T}\), area is \((-) v e\), net area is zero, hence, no chang in momentum.
Laws of Motion
270199
If the average velocity of a body moving with uniform acceleration under the action of a force is" \(v\) " and the impulse it receives during a displacement of " \(s\) " is " \(I\) ", the constant force acting on the body is given by
1 \(\frac{I \times v}{2 s}\)
2 \(\frac{2 I \times v}{s}\)
3 \(\frac{I \times v}{s}\)
4 \(\frac{I \times s}{v}\)
Explanation:
\(J=F \times t, t=\frac{s}{v} \quad\)
Laws of Motion
270228
The momenta of a body in two perpendicular directions at anytime't' are given by \(P_{X}=2 t^{2}+6\) and \(P_{Y}=\frac{3 t^{2}}{2}+3\). The force acting on the body at \(t=2 \mathrm{sec}\) is
270229
When a force\(F\) acts on a body of mass \(m\), the acceleration produced in the body is a. If three equal forces \(F_{1}=F_{2}=F_{3}=F\) act on the same body as shown in figure the acceleration produced is
