NEWTON'S LAWS OF MOTION
Laws of Motion

270194 An impulse is supplied to a moving object with the force at an angle\(120^{\circ}\) with the velocity vector. The angle between the impulse vector and the change in momentum vector is

1 \(120^{\circ}\)
2 \(0^{0}\)
3 \(60^{\circ}\)
4 \(240^{\circ}\)
Laws of Motion

270195 A\(20 \mathrm{~kg}\) body is pushed with a force of \(7 \mathrm{~N}\) for \(1.5 \mathrm{sec}\) then with a force of \(5 \mathrm{~N}\) for \(1.7 \mathrm{sec}\) and finally with a force of \(10 \mathrm{~N}\) for \(3 \mathrm{sec}\), the total impulse applied to the body and change in velocity will be

1 \(49 \mathrm{Ns}, 12.5 \mathrm{~ms}^{-1}\)
2 \(49 \mathrm{Ns}, 2.45 \mathrm{~ms}^{-1}\)
3 \(98 \mathrm{Ns}, 4.9 \mathrm{~ms}^{-1}\)
4 \(4.9 \mathrm{Ns}, 2.45 \mathrm{~ms}^{-1}\)
Laws of Motion

270196 A body of mass \(5 \mathrm{~kg}\) is acted upon by a net force \(F\) which varies with time \(t\) as shown in graph, then the net momentum in SI units gained by the body at the end of 10 seconds is

1 0
2 100
3 140
4 200
Laws of Motion

270197 A body is acted on by a force given by\(F=(10+2 t) N\). The impulse received by the body during the first four seconds is

1 \(40 \mathrm{~N} \mathrm{~s}\)
2 \(56 \mathrm{~N} \mathrm{~s}\)
3 \(72 \mathrm{~N} \mathrm{~s}\)
4 \(32 \mathrm{~N} \mathrm{~s}\)
Laws of Motion

270194 An impulse is supplied to a moving object with the force at an angle\(120^{\circ}\) with the velocity vector. The angle between the impulse vector and the change in momentum vector is

1 \(120^{\circ}\)
2 \(0^{0}\)
3 \(60^{\circ}\)
4 \(240^{\circ}\)
Laws of Motion

270195 A\(20 \mathrm{~kg}\) body is pushed with a force of \(7 \mathrm{~N}\) for \(1.5 \mathrm{sec}\) then with a force of \(5 \mathrm{~N}\) for \(1.7 \mathrm{sec}\) and finally with a force of \(10 \mathrm{~N}\) for \(3 \mathrm{sec}\), the total impulse applied to the body and change in velocity will be

1 \(49 \mathrm{Ns}, 12.5 \mathrm{~ms}^{-1}\)
2 \(49 \mathrm{Ns}, 2.45 \mathrm{~ms}^{-1}\)
3 \(98 \mathrm{Ns}, 4.9 \mathrm{~ms}^{-1}\)
4 \(4.9 \mathrm{Ns}, 2.45 \mathrm{~ms}^{-1}\)
Laws of Motion

270196 A body of mass \(5 \mathrm{~kg}\) is acted upon by a net force \(F\) which varies with time \(t\) as shown in graph, then the net momentum in SI units gained by the body at the end of 10 seconds is

1 0
2 100
3 140
4 200
Laws of Motion

270197 A body is acted on by a force given by\(F=(10+2 t) N\). The impulse received by the body during the first four seconds is

1 \(40 \mathrm{~N} \mathrm{~s}\)
2 \(56 \mathrm{~N} \mathrm{~s}\)
3 \(72 \mathrm{~N} \mathrm{~s}\)
4 \(32 \mathrm{~N} \mathrm{~s}\)
Laws of Motion

270194 An impulse is supplied to a moving object with the force at an angle\(120^{\circ}\) with the velocity vector. The angle between the impulse vector and the change in momentum vector is

1 \(120^{\circ}\)
2 \(0^{0}\)
3 \(60^{\circ}\)
4 \(240^{\circ}\)
Laws of Motion

270195 A\(20 \mathrm{~kg}\) body is pushed with a force of \(7 \mathrm{~N}\) for \(1.5 \mathrm{sec}\) then with a force of \(5 \mathrm{~N}\) for \(1.7 \mathrm{sec}\) and finally with a force of \(10 \mathrm{~N}\) for \(3 \mathrm{sec}\), the total impulse applied to the body and change in velocity will be

1 \(49 \mathrm{Ns}, 12.5 \mathrm{~ms}^{-1}\)
2 \(49 \mathrm{Ns}, 2.45 \mathrm{~ms}^{-1}\)
3 \(98 \mathrm{Ns}, 4.9 \mathrm{~ms}^{-1}\)
4 \(4.9 \mathrm{Ns}, 2.45 \mathrm{~ms}^{-1}\)
Laws of Motion

270196 A body of mass \(5 \mathrm{~kg}\) is acted upon by a net force \(F\) which varies with time \(t\) as shown in graph, then the net momentum in SI units gained by the body at the end of 10 seconds is

1 0
2 100
3 140
4 200
Laws of Motion

270197 A body is acted on by a force given by\(F=(10+2 t) N\). The impulse received by the body during the first four seconds is

1 \(40 \mathrm{~N} \mathrm{~s}\)
2 \(56 \mathrm{~N} \mathrm{~s}\)
3 \(72 \mathrm{~N} \mathrm{~s}\)
4 \(32 \mathrm{~N} \mathrm{~s}\)
Laws of Motion

270194 An impulse is supplied to a moving object with the force at an angle\(120^{\circ}\) with the velocity vector. The angle between the impulse vector and the change in momentum vector is

1 \(120^{\circ}\)
2 \(0^{0}\)
3 \(60^{\circ}\)
4 \(240^{\circ}\)
Laws of Motion

270195 A\(20 \mathrm{~kg}\) body is pushed with a force of \(7 \mathrm{~N}\) for \(1.5 \mathrm{sec}\) then with a force of \(5 \mathrm{~N}\) for \(1.7 \mathrm{sec}\) and finally with a force of \(10 \mathrm{~N}\) for \(3 \mathrm{sec}\), the total impulse applied to the body and change in velocity will be

1 \(49 \mathrm{Ns}, 12.5 \mathrm{~ms}^{-1}\)
2 \(49 \mathrm{Ns}, 2.45 \mathrm{~ms}^{-1}\)
3 \(98 \mathrm{Ns}, 4.9 \mathrm{~ms}^{-1}\)
4 \(4.9 \mathrm{Ns}, 2.45 \mathrm{~ms}^{-1}\)
Laws of Motion

270196 A body of mass \(5 \mathrm{~kg}\) is acted upon by a net force \(F\) which varies with time \(t\) as shown in graph, then the net momentum in SI units gained by the body at the end of 10 seconds is

1 0
2 100
3 140
4 200
Laws of Motion

270197 A body is acted on by a force given by\(F=(10+2 t) N\). The impulse received by the body during the first four seconds is

1 \(40 \mathrm{~N} \mathrm{~s}\)
2 \(56 \mathrm{~N} \mathrm{~s}\)
3 \(72 \mathrm{~N} \mathrm{~s}\)
4 \(32 \mathrm{~N} \mathrm{~s}\)