NEET Test Series from KOTA - 10 Papers In MS WORD
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Rotational Motion
269556
A vehicle starts from rest and moves at uniform acceleration such that its velocity increases by \(3 \mathrm{~ms}^{-1}\) per every second. If diameter of wheel of that vehicle is \(60 \mathrm{~cm}\), the angular acceleration ofw heelis (in rad \(\mathbf{s}^{1}\)
1 5
2 10
3 15
4 20
Explanation:
\(\alpha=\frac{a}{r}\)
Rotational Motion
269557
Starting from rest the fly wheel of a motor attains an angular velocity of \(60 \mathrm{rad} / \mathrm{sec}\) in 5 seconds. . The angular acceleration obtained is
1 \(6 \mathrm{rad} / \mathrm{s}^{2}\)
2 \(12 \mathrm{rad} / \mathrm{s}^{2}\)
3 \(300 \mathrm{rad} / \mathrm{s}^{2}\)
4 \(150 \mathrm{rad} / \mathrm{s}^{2}\)
Explanation:
\(\alpha=\frac{a}{r}\)
Rotational Motion
269607
Two points \(P\) and \(Q\), diametrically opposite on a disc of radius \(R\) have linear velocities \(v\) and \(2 \mathrm{v}\) as shown in figure. Find the angular speed of the disc.
1 \(\frac{v}{R}\)
2 \(\frac{2 v}{R}\)
3 \(\frac{v}{2 R}\)
4 \(\frac{v}{4 R}\)
Explanation:
\(\omega=\frac{\mathrm{v}}{x}=\frac{2 \mathrm{v}}{x+2 R} ; \Rightarrow x=2 R ; \omega=\frac{\mathrm{v}}{2 R}\)
Rotational Motion
269608
Point \(A\) of rod \(A B(I=2 \mathrm{~m})\) is moved upwards against a wall with velocity \(v=2 \mathrm{~m} / \mathrm{s}\). Find angular speed of the rod at an instant when \(\theta=60^{\circ}\).
269556
A vehicle starts from rest and moves at uniform acceleration such that its velocity increases by \(3 \mathrm{~ms}^{-1}\) per every second. If diameter of wheel of that vehicle is \(60 \mathrm{~cm}\), the angular acceleration ofw heelis (in rad \(\mathbf{s}^{1}\)
1 5
2 10
3 15
4 20
Explanation:
\(\alpha=\frac{a}{r}\)
Rotational Motion
269557
Starting from rest the fly wheel of a motor attains an angular velocity of \(60 \mathrm{rad} / \mathrm{sec}\) in 5 seconds. . The angular acceleration obtained is
1 \(6 \mathrm{rad} / \mathrm{s}^{2}\)
2 \(12 \mathrm{rad} / \mathrm{s}^{2}\)
3 \(300 \mathrm{rad} / \mathrm{s}^{2}\)
4 \(150 \mathrm{rad} / \mathrm{s}^{2}\)
Explanation:
\(\alpha=\frac{a}{r}\)
Rotational Motion
269607
Two points \(P\) and \(Q\), diametrically opposite on a disc of radius \(R\) have linear velocities \(v\) and \(2 \mathrm{v}\) as shown in figure. Find the angular speed of the disc.
1 \(\frac{v}{R}\)
2 \(\frac{2 v}{R}\)
3 \(\frac{v}{2 R}\)
4 \(\frac{v}{4 R}\)
Explanation:
\(\omega=\frac{\mathrm{v}}{x}=\frac{2 \mathrm{v}}{x+2 R} ; \Rightarrow x=2 R ; \omega=\frac{\mathrm{v}}{2 R}\)
Rotational Motion
269608
Point \(A\) of rod \(A B(I=2 \mathrm{~m})\) is moved upwards against a wall with velocity \(v=2 \mathrm{~m} / \mathrm{s}\). Find angular speed of the rod at an instant when \(\theta=60^{\circ}\).
269556
A vehicle starts from rest and moves at uniform acceleration such that its velocity increases by \(3 \mathrm{~ms}^{-1}\) per every second. If diameter of wheel of that vehicle is \(60 \mathrm{~cm}\), the angular acceleration ofw heelis (in rad \(\mathbf{s}^{1}\)
1 5
2 10
3 15
4 20
Explanation:
\(\alpha=\frac{a}{r}\)
Rotational Motion
269557
Starting from rest the fly wheel of a motor attains an angular velocity of \(60 \mathrm{rad} / \mathrm{sec}\) in 5 seconds. . The angular acceleration obtained is
1 \(6 \mathrm{rad} / \mathrm{s}^{2}\)
2 \(12 \mathrm{rad} / \mathrm{s}^{2}\)
3 \(300 \mathrm{rad} / \mathrm{s}^{2}\)
4 \(150 \mathrm{rad} / \mathrm{s}^{2}\)
Explanation:
\(\alpha=\frac{a}{r}\)
Rotational Motion
269607
Two points \(P\) and \(Q\), diametrically opposite on a disc of radius \(R\) have linear velocities \(v\) and \(2 \mathrm{v}\) as shown in figure. Find the angular speed of the disc.
1 \(\frac{v}{R}\)
2 \(\frac{2 v}{R}\)
3 \(\frac{v}{2 R}\)
4 \(\frac{v}{4 R}\)
Explanation:
\(\omega=\frac{\mathrm{v}}{x}=\frac{2 \mathrm{v}}{x+2 R} ; \Rightarrow x=2 R ; \omega=\frac{\mathrm{v}}{2 R}\)
Rotational Motion
269608
Point \(A\) of rod \(A B(I=2 \mathrm{~m})\) is moved upwards against a wall with velocity \(v=2 \mathrm{~m} / \mathrm{s}\). Find angular speed of the rod at an instant when \(\theta=60^{\circ}\).
269556
A vehicle starts from rest and moves at uniform acceleration such that its velocity increases by \(3 \mathrm{~ms}^{-1}\) per every second. If diameter of wheel of that vehicle is \(60 \mathrm{~cm}\), the angular acceleration ofw heelis (in rad \(\mathbf{s}^{1}\)
1 5
2 10
3 15
4 20
Explanation:
\(\alpha=\frac{a}{r}\)
Rotational Motion
269557
Starting from rest the fly wheel of a motor attains an angular velocity of \(60 \mathrm{rad} / \mathrm{sec}\) in 5 seconds. . The angular acceleration obtained is
1 \(6 \mathrm{rad} / \mathrm{s}^{2}\)
2 \(12 \mathrm{rad} / \mathrm{s}^{2}\)
3 \(300 \mathrm{rad} / \mathrm{s}^{2}\)
4 \(150 \mathrm{rad} / \mathrm{s}^{2}\)
Explanation:
\(\alpha=\frac{a}{r}\)
Rotational Motion
269607
Two points \(P\) and \(Q\), diametrically opposite on a disc of radius \(R\) have linear velocities \(v\) and \(2 \mathrm{v}\) as shown in figure. Find the angular speed of the disc.
1 \(\frac{v}{R}\)
2 \(\frac{2 v}{R}\)
3 \(\frac{v}{2 R}\)
4 \(\frac{v}{4 R}\)
Explanation:
\(\omega=\frac{\mathrm{v}}{x}=\frac{2 \mathrm{v}}{x+2 R} ; \Rightarrow x=2 R ; \omega=\frac{\mathrm{v}}{2 R}\)
Rotational Motion
269608
Point \(A\) of rod \(A B(I=2 \mathrm{~m})\) is moved upwards against a wall with velocity \(v=2 \mathrm{~m} / \mathrm{s}\). Find angular speed of the rod at an instant when \(\theta=60^{\circ}\).
