DOT PRODUCT AND CROSS PRODUCT
VECTORS

268937 Three vectors satisfy the relation AB=0 and AC=0, then A is parallel to

1 C
2 B
3 B×C
4 BC
VECTORS

268939 (A×B)+(B×A) is equal to

1 2AB
2 A2B2
3 zero
4 null vector
VECTORS

268940 If C=A×B, then C is

1 parallel to A
2 parallel to B
3 perpendicular to A and parallel to B
4 perpendicular to both A and B
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
VECTORS

268937 Three vectors satisfy the relation AB=0 and AC=0, then A is parallel to

1 C
2 B
3 B×C
4 BC
VECTORS

268938 Let F be the force acting on a particle having position vector r and τ be the torque of this foce about the origin. Then (AIEEE-2003)

1 rF=0 and rτ0
2 rτ0 and Fτ=0
3 rτ0 and Fτ0
4 rτ=0 and Fτ=0
VECTORS

268939 (A×B)+(B×A) is equal to

1 2AB
2 A2B2
3 zero
4 null vector
VECTORS

268940 If C=A×B, then C is

1 parallel to A
2 parallel to B
3 perpendicular to A and parallel to B
4 perpendicular to both A and B
VECTORS

268937 Three vectors satisfy the relation AB=0 and AC=0, then A is parallel to

1 C
2 B
3 B×C
4 BC
VECTORS

268938 Let F be the force acting on a particle having position vector r and τ be the torque of this foce about the origin. Then (AIEEE-2003)

1 rF=0 and rτ0
2 rτ0 and Fτ=0
3 rτ0 and Fτ0
4 rτ=0 and Fτ=0
VECTORS

268939 (A×B)+(B×A) is equal to

1 2AB
2 A2B2
3 zero
4 null vector
VECTORS

268940 If C=A×B, then C is

1 parallel to A
2 parallel to B
3 perpendicular to A and parallel to B
4 perpendicular to both A and B
VECTORS

268937 Three vectors satisfy the relation AB=0 and AC=0, then A is parallel to

1 C
2 B
3 B×C
4 BC
VECTORS

268938 Let F be the force acting on a particle having position vector r and τ be the torque of this foce about the origin. Then (AIEEE-2003)

1 rF=0 and rτ0
2 rτ0 and Fτ=0
3 rτ0 and Fτ0
4 rτ=0 and Fτ=0
VECTORS

268939 (A×B)+(B×A) is equal to

1 2AB
2 A2B2
3 zero
4 null vector
VECTORS

268940 If C=A×B, then C is

1 parallel to A
2 parallel to B
3 perpendicular to A and parallel to B
4 perpendicular to both A and B