POTENTIO METER
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Current Electricity

268511 The ratio of potential gradients is\(1: 2\), the resistance of two potentiometer wires of same length are \(2 \Omega \& 4 \Omega\) respectively. The current flowing through them are in the ratio

1 \(1: 2\)
2 \(2: 1\)
3 \(1: 3\)
4 \(1: 1\)
Current Electricity

268512 The length of potentiometer wire is 100\(\mathrm{cm}\) and the emf of its standard cell is \(E\) volts. It is employed to measure the emf of a battery whose internal resistance is 0.5 ohm. If the balance point is obtained at \(I=30 \mathrm{~cm}\) from positive end, the emf of the battery is

1 \(\frac{30 E}{100.5}\)
2 \(\frac{30 E}{100-0.5}\)
3 \(\frac{30 E}{100}\)
4 \(\frac{100 E}{30}\)
Current Electricity

268513 1 ohm resistance is in series with an Ammeter which is balanced by \(75 \mathrm{~cm}\) of potentiometer wire. A standard cell of \(1.02 \mathrm{~V}\) is balanced by \(50 \mathrm{~cm}\). T he ammeter shows a reading of \(1.5 \mathrm{~A}\). The error in the ammeter reading is

1 \(0.002 \mathrm{~A}\)
2 \(0.03 \mathrm{~A}\)
3 \(1.01 \mathrm{~A}\)
4 no error
Current Electricity

268555 In an experiment with potentiometer to measure the internal resistance of a cell, when the cell is shunted by\(5 \Omega\), the null point is obtained at \(2 \mathrm{~m}\). When cell is shunted by \(20 \Omega\) the null point is obtained at \(3 \mathrm{~m}\). The internal resistance of cell is

1 \(2 \Omega\)
2 \(4 \Omega\)
3 \(6 \Omega\)
4 \(8 \Omega\)
Current Electricity

268511 The ratio of potential gradients is\(1: 2\), the resistance of two potentiometer wires of same length are \(2 \Omega \& 4 \Omega\) respectively. The current flowing through them are in the ratio

1 \(1: 2\)
2 \(2: 1\)
3 \(1: 3\)
4 \(1: 1\)
Current Electricity

268512 The length of potentiometer wire is 100\(\mathrm{cm}\) and the emf of its standard cell is \(E\) volts. It is employed to measure the emf of a battery whose internal resistance is 0.5 ohm. If the balance point is obtained at \(I=30 \mathrm{~cm}\) from positive end, the emf of the battery is

1 \(\frac{30 E}{100.5}\)
2 \(\frac{30 E}{100-0.5}\)
3 \(\frac{30 E}{100}\)
4 \(\frac{100 E}{30}\)
Current Electricity

268513 1 ohm resistance is in series with an Ammeter which is balanced by \(75 \mathrm{~cm}\) of potentiometer wire. A standard cell of \(1.02 \mathrm{~V}\) is balanced by \(50 \mathrm{~cm}\). T he ammeter shows a reading of \(1.5 \mathrm{~A}\). The error in the ammeter reading is

1 \(0.002 \mathrm{~A}\)
2 \(0.03 \mathrm{~A}\)
3 \(1.01 \mathrm{~A}\)
4 no error
Current Electricity

268555 In an experiment with potentiometer to measure the internal resistance of a cell, when the cell is shunted by\(5 \Omega\), the null point is obtained at \(2 \mathrm{~m}\). When cell is shunted by \(20 \Omega\) the null point is obtained at \(3 \mathrm{~m}\). The internal resistance of cell is

1 \(2 \Omega\)
2 \(4 \Omega\)
3 \(6 \Omega\)
4 \(8 \Omega\)
Current Electricity

268511 The ratio of potential gradients is\(1: 2\), the resistance of two potentiometer wires of same length are \(2 \Omega \& 4 \Omega\) respectively. The current flowing through them are in the ratio

1 \(1: 2\)
2 \(2: 1\)
3 \(1: 3\)
4 \(1: 1\)
Current Electricity

268512 The length of potentiometer wire is 100\(\mathrm{cm}\) and the emf of its standard cell is \(E\) volts. It is employed to measure the emf of a battery whose internal resistance is 0.5 ohm. If the balance point is obtained at \(I=30 \mathrm{~cm}\) from positive end, the emf of the battery is

1 \(\frac{30 E}{100.5}\)
2 \(\frac{30 E}{100-0.5}\)
3 \(\frac{30 E}{100}\)
4 \(\frac{100 E}{30}\)
Current Electricity

268513 1 ohm resistance is in series with an Ammeter which is balanced by \(75 \mathrm{~cm}\) of potentiometer wire. A standard cell of \(1.02 \mathrm{~V}\) is balanced by \(50 \mathrm{~cm}\). T he ammeter shows a reading of \(1.5 \mathrm{~A}\). The error in the ammeter reading is

1 \(0.002 \mathrm{~A}\)
2 \(0.03 \mathrm{~A}\)
3 \(1.01 \mathrm{~A}\)
4 no error
Current Electricity

268555 In an experiment with potentiometer to measure the internal resistance of a cell, when the cell is shunted by\(5 \Omega\), the null point is obtained at \(2 \mathrm{~m}\). When cell is shunted by \(20 \Omega\) the null point is obtained at \(3 \mathrm{~m}\). The internal resistance of cell is

1 \(2 \Omega\)
2 \(4 \Omega\)
3 \(6 \Omega\)
4 \(8 \Omega\)
Current Electricity

268511 The ratio of potential gradients is\(1: 2\), the resistance of two potentiometer wires of same length are \(2 \Omega \& 4 \Omega\) respectively. The current flowing through them are in the ratio

1 \(1: 2\)
2 \(2: 1\)
3 \(1: 3\)
4 \(1: 1\)
Current Electricity

268512 The length of potentiometer wire is 100\(\mathrm{cm}\) and the emf of its standard cell is \(E\) volts. It is employed to measure the emf of a battery whose internal resistance is 0.5 ohm. If the balance point is obtained at \(I=30 \mathrm{~cm}\) from positive end, the emf of the battery is

1 \(\frac{30 E}{100.5}\)
2 \(\frac{30 E}{100-0.5}\)
3 \(\frac{30 E}{100}\)
4 \(\frac{100 E}{30}\)
Current Electricity

268513 1 ohm resistance is in series with an Ammeter which is balanced by \(75 \mathrm{~cm}\) of potentiometer wire. A standard cell of \(1.02 \mathrm{~V}\) is balanced by \(50 \mathrm{~cm}\). T he ammeter shows a reading of \(1.5 \mathrm{~A}\). The error in the ammeter reading is

1 \(0.002 \mathrm{~A}\)
2 \(0.03 \mathrm{~A}\)
3 \(1.01 \mathrm{~A}\)
4 no error
Current Electricity

268555 In an experiment with potentiometer to measure the internal resistance of a cell, when the cell is shunted by\(5 \Omega\), the null point is obtained at \(2 \mathrm{~m}\). When cell is shunted by \(20 \Omega\) the null point is obtained at \(3 \mathrm{~m}\). The internal resistance of cell is

1 \(2 \Omega\)
2 \(4 \Omega\)
3 \(6 \Omega\)
4 \(8 \Omega\)