266243
If the nucleus \({ }_{15}^{27} \mathrm{~A}\) has a nuclear radius of about 3.6 fm . the \({ }_{52}^{125} \mathrm{Te}\) would have its radius approximately as:
266244
The ratio of molar specific heat at constant pressure and constant volume of an ideal gas is \(9 / 7\). then the number of degree of freedom of a gas molecule is:
266246
The refractive index of a prism for a monochromatic wave is \(\sqrt{2}\), and its refracting angle is \(60^{\circ}\). for minimum deviation, the angle of incidence will be:
1 \(30^{\circ}\)
2 \(45^{\circ}\)
3 \(60^{\circ}\)
4 \(75^{\circ}\)
Explanation:
b \( \begin{aligned} & \mu=\frac{\sin \left(\frac{A+\delta_m}{2}\right)}{\sin A / 2} \\ & \Rightarrow \sqrt{2}=\frac{\sin \left(\frac{60+\delta_m}{2}\right)}{\sin \frac{60}{2}} \\ & \delta_m=30^{\circ} \end{aligned} \) Angle of incidence \(\mathrm{i}=\frac{\mathrm{A}+\delta_{\mathrm{m}}}{2}\) \[ =\frac{60+30}{2}=45^{\circ} \]
**NCERT-XII-II-239
TEST SERIES (PHYSICS FST)
266247
The magnetic force acting on a charged particle of charge \(+2 \mu \mathrm{C}\) in a magnetic field of 2 T acting in +y direction, when the particle velocity is \((2 \hat{i}+3 \hat{j}) \times 10^6 \mathrm{~ms}^{-1} \mathrm{is}:\)
1 8 N in -z direction
2 4 N in z direction
3 8 N in y direction
4 8 N in Z direction
Explanation:
d
**NCERT-XII-I-109**
TEST SERIES (PHYSICS FST)
266248
Two coherent sources produce waves of different intensities which interfere. After interference the ratio of the maximum intensity to the minimum intensity is 25. The intensity of the waves are in the ratio:
1 \(4: 1\)
2 \(25: 9\)
3 \(9: 4\)
4 \(5: 3\)
Explanation:
c \( \begin{aligned} & \frac{I_{\max }}{I_{\min }}=25 \\ & \frac{A_{\max }}{A_{\min }}=5 \\ & \frac{A_1+A_2}{A_1-A_2}=\frac{5}{1} \end{aligned} \) On solving we get \[ \frac{A_1}{A_2}=\frac{3}{2} \Rightarrow \frac{I_1}{I_2}=\left(\frac{3}{2}\right)^2=\frac{9}{4} \]
266243
If the nucleus \({ }_{15}^{27} \mathrm{~A}\) has a nuclear radius of about 3.6 fm . the \({ }_{52}^{125} \mathrm{Te}\) would have its radius approximately as:
266244
The ratio of molar specific heat at constant pressure and constant volume of an ideal gas is \(9 / 7\). then the number of degree of freedom of a gas molecule is:
266246
The refractive index of a prism for a monochromatic wave is \(\sqrt{2}\), and its refracting angle is \(60^{\circ}\). for minimum deviation, the angle of incidence will be:
1 \(30^{\circ}\)
2 \(45^{\circ}\)
3 \(60^{\circ}\)
4 \(75^{\circ}\)
Explanation:
b \( \begin{aligned} & \mu=\frac{\sin \left(\frac{A+\delta_m}{2}\right)}{\sin A / 2} \\ & \Rightarrow \sqrt{2}=\frac{\sin \left(\frac{60+\delta_m}{2}\right)}{\sin \frac{60}{2}} \\ & \delta_m=30^{\circ} \end{aligned} \) Angle of incidence \(\mathrm{i}=\frac{\mathrm{A}+\delta_{\mathrm{m}}}{2}\) \[ =\frac{60+30}{2}=45^{\circ} \]
**NCERT-XII-II-239
TEST SERIES (PHYSICS FST)
266247
The magnetic force acting on a charged particle of charge \(+2 \mu \mathrm{C}\) in a magnetic field of 2 T acting in +y direction, when the particle velocity is \((2 \hat{i}+3 \hat{j}) \times 10^6 \mathrm{~ms}^{-1} \mathrm{is}:\)
1 8 N in -z direction
2 4 N in z direction
3 8 N in y direction
4 8 N in Z direction
Explanation:
d
**NCERT-XII-I-109**
TEST SERIES (PHYSICS FST)
266248
Two coherent sources produce waves of different intensities which interfere. After interference the ratio of the maximum intensity to the minimum intensity is 25. The intensity of the waves are in the ratio:
1 \(4: 1\)
2 \(25: 9\)
3 \(9: 4\)
4 \(5: 3\)
Explanation:
c \( \begin{aligned} & \frac{I_{\max }}{I_{\min }}=25 \\ & \frac{A_{\max }}{A_{\min }}=5 \\ & \frac{A_1+A_2}{A_1-A_2}=\frac{5}{1} \end{aligned} \) On solving we get \[ \frac{A_1}{A_2}=\frac{3}{2} \Rightarrow \frac{I_1}{I_2}=\left(\frac{3}{2}\right)^2=\frac{9}{4} \]
266243
If the nucleus \({ }_{15}^{27} \mathrm{~A}\) has a nuclear radius of about 3.6 fm . the \({ }_{52}^{125} \mathrm{Te}\) would have its radius approximately as:
266244
The ratio of molar specific heat at constant pressure and constant volume of an ideal gas is \(9 / 7\). then the number of degree of freedom of a gas molecule is:
266246
The refractive index of a prism for a monochromatic wave is \(\sqrt{2}\), and its refracting angle is \(60^{\circ}\). for minimum deviation, the angle of incidence will be:
1 \(30^{\circ}\)
2 \(45^{\circ}\)
3 \(60^{\circ}\)
4 \(75^{\circ}\)
Explanation:
b \( \begin{aligned} & \mu=\frac{\sin \left(\frac{A+\delta_m}{2}\right)}{\sin A / 2} \\ & \Rightarrow \sqrt{2}=\frac{\sin \left(\frac{60+\delta_m}{2}\right)}{\sin \frac{60}{2}} \\ & \delta_m=30^{\circ} \end{aligned} \) Angle of incidence \(\mathrm{i}=\frac{\mathrm{A}+\delta_{\mathrm{m}}}{2}\) \[ =\frac{60+30}{2}=45^{\circ} \]
**NCERT-XII-II-239
TEST SERIES (PHYSICS FST)
266247
The magnetic force acting on a charged particle of charge \(+2 \mu \mathrm{C}\) in a magnetic field of 2 T acting in +y direction, when the particle velocity is \((2 \hat{i}+3 \hat{j}) \times 10^6 \mathrm{~ms}^{-1} \mathrm{is}:\)
1 8 N in -z direction
2 4 N in z direction
3 8 N in y direction
4 8 N in Z direction
Explanation:
d
**NCERT-XII-I-109**
TEST SERIES (PHYSICS FST)
266248
Two coherent sources produce waves of different intensities which interfere. After interference the ratio of the maximum intensity to the minimum intensity is 25. The intensity of the waves are in the ratio:
1 \(4: 1\)
2 \(25: 9\)
3 \(9: 4\)
4 \(5: 3\)
Explanation:
c \( \begin{aligned} & \frac{I_{\max }}{I_{\min }}=25 \\ & \frac{A_{\max }}{A_{\min }}=5 \\ & \frac{A_1+A_2}{A_1-A_2}=\frac{5}{1} \end{aligned} \) On solving we get \[ \frac{A_1}{A_2}=\frac{3}{2} \Rightarrow \frac{I_1}{I_2}=\left(\frac{3}{2}\right)^2=\frac{9}{4} \]
266243
If the nucleus \({ }_{15}^{27} \mathrm{~A}\) has a nuclear radius of about 3.6 fm . the \({ }_{52}^{125} \mathrm{Te}\) would have its radius approximately as:
266244
The ratio of molar specific heat at constant pressure and constant volume of an ideal gas is \(9 / 7\). then the number of degree of freedom of a gas molecule is:
266246
The refractive index of a prism for a monochromatic wave is \(\sqrt{2}\), and its refracting angle is \(60^{\circ}\). for minimum deviation, the angle of incidence will be:
1 \(30^{\circ}\)
2 \(45^{\circ}\)
3 \(60^{\circ}\)
4 \(75^{\circ}\)
Explanation:
b \( \begin{aligned} & \mu=\frac{\sin \left(\frac{A+\delta_m}{2}\right)}{\sin A / 2} \\ & \Rightarrow \sqrt{2}=\frac{\sin \left(\frac{60+\delta_m}{2}\right)}{\sin \frac{60}{2}} \\ & \delta_m=30^{\circ} \end{aligned} \) Angle of incidence \(\mathrm{i}=\frac{\mathrm{A}+\delta_{\mathrm{m}}}{2}\) \[ =\frac{60+30}{2}=45^{\circ} \]
**NCERT-XII-II-239
TEST SERIES (PHYSICS FST)
266247
The magnetic force acting on a charged particle of charge \(+2 \mu \mathrm{C}\) in a magnetic field of 2 T acting in +y direction, when the particle velocity is \((2 \hat{i}+3 \hat{j}) \times 10^6 \mathrm{~ms}^{-1} \mathrm{is}:\)
1 8 N in -z direction
2 4 N in z direction
3 8 N in y direction
4 8 N in Z direction
Explanation:
d
**NCERT-XII-I-109**
TEST SERIES (PHYSICS FST)
266248
Two coherent sources produce waves of different intensities which interfere. After interference the ratio of the maximum intensity to the minimum intensity is 25. The intensity of the waves are in the ratio:
1 \(4: 1\)
2 \(25: 9\)
3 \(9: 4\)
4 \(5: 3\)
Explanation:
c \( \begin{aligned} & \frac{I_{\max }}{I_{\min }}=25 \\ & \frac{A_{\max }}{A_{\min }}=5 \\ & \frac{A_1+A_2}{A_1-A_2}=\frac{5}{1} \end{aligned} \) On solving we get \[ \frac{A_1}{A_2}=\frac{3}{2} \Rightarrow \frac{I_1}{I_2}=\left(\frac{3}{2}\right)^2=\frac{9}{4} \]
266243
If the nucleus \({ }_{15}^{27} \mathrm{~A}\) has a nuclear radius of about 3.6 fm . the \({ }_{52}^{125} \mathrm{Te}\) would have its radius approximately as:
266244
The ratio of molar specific heat at constant pressure and constant volume of an ideal gas is \(9 / 7\). then the number of degree of freedom of a gas molecule is:
266246
The refractive index of a prism for a monochromatic wave is \(\sqrt{2}\), and its refracting angle is \(60^{\circ}\). for minimum deviation, the angle of incidence will be:
1 \(30^{\circ}\)
2 \(45^{\circ}\)
3 \(60^{\circ}\)
4 \(75^{\circ}\)
Explanation:
b \( \begin{aligned} & \mu=\frac{\sin \left(\frac{A+\delta_m}{2}\right)}{\sin A / 2} \\ & \Rightarrow \sqrt{2}=\frac{\sin \left(\frac{60+\delta_m}{2}\right)}{\sin \frac{60}{2}} \\ & \delta_m=30^{\circ} \end{aligned} \) Angle of incidence \(\mathrm{i}=\frac{\mathrm{A}+\delta_{\mathrm{m}}}{2}\) \[ =\frac{60+30}{2}=45^{\circ} \]
**NCERT-XII-II-239
TEST SERIES (PHYSICS FST)
266247
The magnetic force acting on a charged particle of charge \(+2 \mu \mathrm{C}\) in a magnetic field of 2 T acting in +y direction, when the particle velocity is \((2 \hat{i}+3 \hat{j}) \times 10^6 \mathrm{~ms}^{-1} \mathrm{is}:\)
1 8 N in -z direction
2 4 N in z direction
3 8 N in y direction
4 8 N in Z direction
Explanation:
d
**NCERT-XII-I-109**
TEST SERIES (PHYSICS FST)
266248
Two coherent sources produce waves of different intensities which interfere. After interference the ratio of the maximum intensity to the minimum intensity is 25. The intensity of the waves are in the ratio:
1 \(4: 1\)
2 \(25: 9\)
3 \(9: 4\)
4 \(5: 3\)
Explanation:
c \( \begin{aligned} & \frac{I_{\max }}{I_{\min }}=25 \\ & \frac{A_{\max }}{A_{\min }}=5 \\ & \frac{A_1+A_2}{A_1-A_2}=\frac{5}{1} \end{aligned} \) On solving we get \[ \frac{A_1}{A_2}=\frac{3}{2} \Rightarrow \frac{I_1}{I_2}=\left(\frac{3}{2}\right)^2=\frac{9}{4} \]
