266239
Energy per unit volume for a capacitor having area \(A\) and seperation d kept at potential difference \(V\) is given by:
1 \(\frac{1}{2} \varepsilon_0 \frac{y^2}{d^2}\)
2 \(\frac{1}{2 \varepsilon_0} \frac{y^2}{d^2}\)
3 \(\frac{1}{2} \mathrm{CV}^2\)
4 \(\frac{Q^2}{2 e}\)
Explanation:
a Energy density \(=\frac{1}{2} \varepsilon_0 \frac{y^2}{d^2}\)
**NCERT-XII-I-74**
TEST SERIES (PHYSICS FST)
266240
A 5 ampere fuse wire can with stand a maximum power of 1 watt in the circuit: The resistance of the fuse wire is:
1 \(0.04 \Omega\)
2 \(0.20 \Omega\)
3 \(5 \Omega\)
4 \(0.4 \Omega\)
Explanation:
a \[ \begin{aligned} & P=i^2 R \\ & 1=(5)^2 \times R \\ & R=0.04 \Omega \end{aligned} \]
**NCERT-XII-I-92
TEST SERIES (PHYSICS FST)
266241
For the circuit shown with \(R_1=1.0 \Omega 2, R_2=2.00, E_1\) \(=1 \mathrm{~V}\) and \(E_2=E_3=2 \mathrm{~V}\), the potential difference between the points 'a' and 'b' is approximately (in V)
266242
Temperature coefficient of resis tance of platinum is \(4 \times 10^{-3} / \mathrm{K}\) at \(0^0 \mathrm{C}\). The temperature at which the increase in the resistance of platinum wire is \(10 \%\) of its value at \(0^{\circ} \mathrm{C}\)
1 2500 C
2 \(500^{\circ} \mathrm{C}\)
3 500 C
4 \(25^{\circ} \mathrm{C}\) SECTION-B This section will have 15 questions. Candidate can choose to attempt any 10 questions out of these 15 questions. In case if candidate attempts more than 10 questions, first 10 attempted questions will be considered for marking.
Explanation:
d \[ \begin{aligned} & R_T=R_0[1+\alpha t] \\ & 1.1 R_0=R_0[1+\alpha t] \\ & 1.1-1=4 \times 10^{-3} \times t \\ & t=25^{\circ} \mathrm{C} \end{aligned} \] SECTION-B Attempt any 10 Questions
266239
Energy per unit volume for a capacitor having area \(A\) and seperation d kept at potential difference \(V\) is given by:
1 \(\frac{1}{2} \varepsilon_0 \frac{y^2}{d^2}\)
2 \(\frac{1}{2 \varepsilon_0} \frac{y^2}{d^2}\)
3 \(\frac{1}{2} \mathrm{CV}^2\)
4 \(\frac{Q^2}{2 e}\)
Explanation:
a Energy density \(=\frac{1}{2} \varepsilon_0 \frac{y^2}{d^2}\)
**NCERT-XII-I-74**
TEST SERIES (PHYSICS FST)
266240
A 5 ampere fuse wire can with stand a maximum power of 1 watt in the circuit: The resistance of the fuse wire is:
1 \(0.04 \Omega\)
2 \(0.20 \Omega\)
3 \(5 \Omega\)
4 \(0.4 \Omega\)
Explanation:
a \[ \begin{aligned} & P=i^2 R \\ & 1=(5)^2 \times R \\ & R=0.04 \Omega \end{aligned} \]
**NCERT-XII-I-92
TEST SERIES (PHYSICS FST)
266241
For the circuit shown with \(R_1=1.0 \Omega 2, R_2=2.00, E_1\) \(=1 \mathrm{~V}\) and \(E_2=E_3=2 \mathrm{~V}\), the potential difference between the points 'a' and 'b' is approximately (in V)
266242
Temperature coefficient of resis tance of platinum is \(4 \times 10^{-3} / \mathrm{K}\) at \(0^0 \mathrm{C}\). The temperature at which the increase in the resistance of platinum wire is \(10 \%\) of its value at \(0^{\circ} \mathrm{C}\)
1 2500 C
2 \(500^{\circ} \mathrm{C}\)
3 500 C
4 \(25^{\circ} \mathrm{C}\) SECTION-B This section will have 15 questions. Candidate can choose to attempt any 10 questions out of these 15 questions. In case if candidate attempts more than 10 questions, first 10 attempted questions will be considered for marking.
Explanation:
d \[ \begin{aligned} & R_T=R_0[1+\alpha t] \\ & 1.1 R_0=R_0[1+\alpha t] \\ & 1.1-1=4 \times 10^{-3} \times t \\ & t=25^{\circ} \mathrm{C} \end{aligned} \] SECTION-B Attempt any 10 Questions
266239
Energy per unit volume for a capacitor having area \(A\) and seperation d kept at potential difference \(V\) is given by:
1 \(\frac{1}{2} \varepsilon_0 \frac{y^2}{d^2}\)
2 \(\frac{1}{2 \varepsilon_0} \frac{y^2}{d^2}\)
3 \(\frac{1}{2} \mathrm{CV}^2\)
4 \(\frac{Q^2}{2 e}\)
Explanation:
a Energy density \(=\frac{1}{2} \varepsilon_0 \frac{y^2}{d^2}\)
**NCERT-XII-I-74**
TEST SERIES (PHYSICS FST)
266240
A 5 ampere fuse wire can with stand a maximum power of 1 watt in the circuit: The resistance of the fuse wire is:
1 \(0.04 \Omega\)
2 \(0.20 \Omega\)
3 \(5 \Omega\)
4 \(0.4 \Omega\)
Explanation:
a \[ \begin{aligned} & P=i^2 R \\ & 1=(5)^2 \times R \\ & R=0.04 \Omega \end{aligned} \]
**NCERT-XII-I-92
TEST SERIES (PHYSICS FST)
266241
For the circuit shown with \(R_1=1.0 \Omega 2, R_2=2.00, E_1\) \(=1 \mathrm{~V}\) and \(E_2=E_3=2 \mathrm{~V}\), the potential difference between the points 'a' and 'b' is approximately (in V)
266242
Temperature coefficient of resis tance of platinum is \(4 \times 10^{-3} / \mathrm{K}\) at \(0^0 \mathrm{C}\). The temperature at which the increase in the resistance of platinum wire is \(10 \%\) of its value at \(0^{\circ} \mathrm{C}\)
1 2500 C
2 \(500^{\circ} \mathrm{C}\)
3 500 C
4 \(25^{\circ} \mathrm{C}\) SECTION-B This section will have 15 questions. Candidate can choose to attempt any 10 questions out of these 15 questions. In case if candidate attempts more than 10 questions, first 10 attempted questions will be considered for marking.
Explanation:
d \[ \begin{aligned} & R_T=R_0[1+\alpha t] \\ & 1.1 R_0=R_0[1+\alpha t] \\ & 1.1-1=4 \times 10^{-3} \times t \\ & t=25^{\circ} \mathrm{C} \end{aligned} \] SECTION-B Attempt any 10 Questions
NEET Test Series from KOTA - 10 Papers In MS WORD
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TEST SERIES (PHYSICS FST)
266239
Energy per unit volume for a capacitor having area \(A\) and seperation d kept at potential difference \(V\) is given by:
1 \(\frac{1}{2} \varepsilon_0 \frac{y^2}{d^2}\)
2 \(\frac{1}{2 \varepsilon_0} \frac{y^2}{d^2}\)
3 \(\frac{1}{2} \mathrm{CV}^2\)
4 \(\frac{Q^2}{2 e}\)
Explanation:
a Energy density \(=\frac{1}{2} \varepsilon_0 \frac{y^2}{d^2}\)
**NCERT-XII-I-74**
TEST SERIES (PHYSICS FST)
266240
A 5 ampere fuse wire can with stand a maximum power of 1 watt in the circuit: The resistance of the fuse wire is:
1 \(0.04 \Omega\)
2 \(0.20 \Omega\)
3 \(5 \Omega\)
4 \(0.4 \Omega\)
Explanation:
a \[ \begin{aligned} & P=i^2 R \\ & 1=(5)^2 \times R \\ & R=0.04 \Omega \end{aligned} \]
**NCERT-XII-I-92
TEST SERIES (PHYSICS FST)
266241
For the circuit shown with \(R_1=1.0 \Omega 2, R_2=2.00, E_1\) \(=1 \mathrm{~V}\) and \(E_2=E_3=2 \mathrm{~V}\), the potential difference between the points 'a' and 'b' is approximately (in V)
266242
Temperature coefficient of resis tance of platinum is \(4 \times 10^{-3} / \mathrm{K}\) at \(0^0 \mathrm{C}\). The temperature at which the increase in the resistance of platinum wire is \(10 \%\) of its value at \(0^{\circ} \mathrm{C}\)
1 2500 C
2 \(500^{\circ} \mathrm{C}\)
3 500 C
4 \(25^{\circ} \mathrm{C}\) SECTION-B This section will have 15 questions. Candidate can choose to attempt any 10 questions out of these 15 questions. In case if candidate attempts more than 10 questions, first 10 attempted questions will be considered for marking.
Explanation:
d \[ \begin{aligned} & R_T=R_0[1+\alpha t] \\ & 1.1 R_0=R_0[1+\alpha t] \\ & 1.1-1=4 \times 10^{-3} \times t \\ & t=25^{\circ} \mathrm{C} \end{aligned} \] SECTION-B Attempt any 10 Questions
