(A): 2S, 3R Absolute configuration of compound It lowest priority group in vertical line then same configuration if lowest priority group on horizontal line. Introvert configuration come is $\mathrm{R} \rightarrow \mathrm{S} \quad \mathrm{S} \rightarrow \mathrm{R}$
JEE Main 2016
GENERAL ORGANIC CHEMISTRY
232077
The absolute configuration of
1 $\mathrm{S}, \mathrm{S}$
2 R, R
3 R, S
4 $\mathrm{S}, \mathrm{R}$
Explanation:
(B): Clockwise $+4^{\text {th }}$ priority inside plane $=\mathrm{R}$ Anticlock wise $+4^{\text {th }}$ priority of the plane $=R$
AIEEE 2008
GENERAL ORGANIC CHEMISTRY
232081
Following compounds are respectively .... geometrical isomers
1 P - cis, Q - cis, R - trans
2 P - cis, Q - trans, R- trans
3 P - trans, Q - cis, R - cis
4 P - cis, Q - trans, R - cis
Explanation:
It the molecules are present in some side them it is cis type and if opposite then the compound is trans types. Hence the option (a) is correct.
VITEEE 2013
GENERAL ORGANIC CHEMISTRY
232082
Arrange the following conformational isomers of n-butane in order of their increasing potential energy
1 II \(<\) III \(<\) IV \(<\) I
2 I \(<\) IV \(<\) III \(<\) II
3 II \(<\) IV \(<\) III \(<\) I
4 I \(<\) III \(<\) IV \(<\) II
Explanation:
(D) : In [I] Anti conformation of n-butane is more stable so its energy [potential] is low because we know that stability is inversely proportional to potential energy. Then the stability order of molecule is Anti> Gauche $>$ eclipsed $>$ fully eclipsed decreasing order of stability. So the potential energy in increasing order Anti $<$ Gauche $<$ eclipsed $<$ full eclipsed $\rightarrow$ increasing order of potential energy. $\text { I }<\text { III }<\text { IV }<\text { II }$
JEE Main 2021
GENERAL ORGANIC CHEMISTRY
232084
The correct relation between the following pair of compounds is
1 Constitutional isomers
2 Enantiomers
3 Distereomers
4 None of these
Explanation:
The relationship between pair of compound is Distereomer, because it is neither identical nor mirror image of each and it have also different physical and chemical property. These are not mirror image of each other
(A): 2S, 3R Absolute configuration of compound It lowest priority group in vertical line then same configuration if lowest priority group on horizontal line. Introvert configuration come is $\mathrm{R} \rightarrow \mathrm{S} \quad \mathrm{S} \rightarrow \mathrm{R}$
JEE Main 2016
GENERAL ORGANIC CHEMISTRY
232077
The absolute configuration of
1 $\mathrm{S}, \mathrm{S}$
2 R, R
3 R, S
4 $\mathrm{S}, \mathrm{R}$
Explanation:
(B): Clockwise $+4^{\text {th }}$ priority inside plane $=\mathrm{R}$ Anticlock wise $+4^{\text {th }}$ priority of the plane $=R$
AIEEE 2008
GENERAL ORGANIC CHEMISTRY
232081
Following compounds are respectively .... geometrical isomers
1 P - cis, Q - cis, R - trans
2 P - cis, Q - trans, R- trans
3 P - trans, Q - cis, R - cis
4 P - cis, Q - trans, R - cis
Explanation:
It the molecules are present in some side them it is cis type and if opposite then the compound is trans types. Hence the option (a) is correct.
VITEEE 2013
GENERAL ORGANIC CHEMISTRY
232082
Arrange the following conformational isomers of n-butane in order of their increasing potential energy
1 II \(<\) III \(<\) IV \(<\) I
2 I \(<\) IV \(<\) III \(<\) II
3 II \(<\) IV \(<\) III \(<\) I
4 I \(<\) III \(<\) IV \(<\) II
Explanation:
(D) : In [I] Anti conformation of n-butane is more stable so its energy [potential] is low because we know that stability is inversely proportional to potential energy. Then the stability order of molecule is Anti> Gauche $>$ eclipsed $>$ fully eclipsed decreasing order of stability. So the potential energy in increasing order Anti $<$ Gauche $<$ eclipsed $<$ full eclipsed $\rightarrow$ increasing order of potential energy. $\text { I }<\text { III }<\text { IV }<\text { II }$
JEE Main 2021
GENERAL ORGANIC CHEMISTRY
232084
The correct relation between the following pair of compounds is
1 Constitutional isomers
2 Enantiomers
3 Distereomers
4 None of these
Explanation:
The relationship between pair of compound is Distereomer, because it is neither identical nor mirror image of each and it have also different physical and chemical property. These are not mirror image of each other
(A): 2S, 3R Absolute configuration of compound It lowest priority group in vertical line then same configuration if lowest priority group on horizontal line. Introvert configuration come is $\mathrm{R} \rightarrow \mathrm{S} \quad \mathrm{S} \rightarrow \mathrm{R}$
JEE Main 2016
GENERAL ORGANIC CHEMISTRY
232077
The absolute configuration of
1 $\mathrm{S}, \mathrm{S}$
2 R, R
3 R, S
4 $\mathrm{S}, \mathrm{R}$
Explanation:
(B): Clockwise $+4^{\text {th }}$ priority inside plane $=\mathrm{R}$ Anticlock wise $+4^{\text {th }}$ priority of the plane $=R$
AIEEE 2008
GENERAL ORGANIC CHEMISTRY
232081
Following compounds are respectively .... geometrical isomers
1 P - cis, Q - cis, R - trans
2 P - cis, Q - trans, R- trans
3 P - trans, Q - cis, R - cis
4 P - cis, Q - trans, R - cis
Explanation:
It the molecules are present in some side them it is cis type and if opposite then the compound is trans types. Hence the option (a) is correct.
VITEEE 2013
GENERAL ORGANIC CHEMISTRY
232082
Arrange the following conformational isomers of n-butane in order of their increasing potential energy
1 II \(<\) III \(<\) IV \(<\) I
2 I \(<\) IV \(<\) III \(<\) II
3 II \(<\) IV \(<\) III \(<\) I
4 I \(<\) III \(<\) IV \(<\) II
Explanation:
(D) : In [I] Anti conformation of n-butane is more stable so its energy [potential] is low because we know that stability is inversely proportional to potential energy. Then the stability order of molecule is Anti> Gauche $>$ eclipsed $>$ fully eclipsed decreasing order of stability. So the potential energy in increasing order Anti $<$ Gauche $<$ eclipsed $<$ full eclipsed $\rightarrow$ increasing order of potential energy. $\text { I }<\text { III }<\text { IV }<\text { II }$
JEE Main 2021
GENERAL ORGANIC CHEMISTRY
232084
The correct relation between the following pair of compounds is
1 Constitutional isomers
2 Enantiomers
3 Distereomers
4 None of these
Explanation:
The relationship between pair of compound is Distereomer, because it is neither identical nor mirror image of each and it have also different physical and chemical property. These are not mirror image of each other
(A): 2S, 3R Absolute configuration of compound It lowest priority group in vertical line then same configuration if lowest priority group on horizontal line. Introvert configuration come is $\mathrm{R} \rightarrow \mathrm{S} \quad \mathrm{S} \rightarrow \mathrm{R}$
JEE Main 2016
GENERAL ORGANIC CHEMISTRY
232077
The absolute configuration of
1 $\mathrm{S}, \mathrm{S}$
2 R, R
3 R, S
4 $\mathrm{S}, \mathrm{R}$
Explanation:
(B): Clockwise $+4^{\text {th }}$ priority inside plane $=\mathrm{R}$ Anticlock wise $+4^{\text {th }}$ priority of the plane $=R$
AIEEE 2008
GENERAL ORGANIC CHEMISTRY
232081
Following compounds are respectively .... geometrical isomers
1 P - cis, Q - cis, R - trans
2 P - cis, Q - trans, R- trans
3 P - trans, Q - cis, R - cis
4 P - cis, Q - trans, R - cis
Explanation:
It the molecules are present in some side them it is cis type and if opposite then the compound is trans types. Hence the option (a) is correct.
VITEEE 2013
GENERAL ORGANIC CHEMISTRY
232082
Arrange the following conformational isomers of n-butane in order of their increasing potential energy
1 II \(<\) III \(<\) IV \(<\) I
2 I \(<\) IV \(<\) III \(<\) II
3 II \(<\) IV \(<\) III \(<\) I
4 I \(<\) III \(<\) IV \(<\) II
Explanation:
(D) : In [I] Anti conformation of n-butane is more stable so its energy [potential] is low because we know that stability is inversely proportional to potential energy. Then the stability order of molecule is Anti> Gauche $>$ eclipsed $>$ fully eclipsed decreasing order of stability. So the potential energy in increasing order Anti $<$ Gauche $<$ eclipsed $<$ full eclipsed $\rightarrow$ increasing order of potential energy. $\text { I }<\text { III }<\text { IV }<\text { II }$
JEE Main 2021
GENERAL ORGANIC CHEMISTRY
232084
The correct relation between the following pair of compounds is
1 Constitutional isomers
2 Enantiomers
3 Distereomers
4 None of these
Explanation:
The relationship between pair of compound is Distereomer, because it is neither identical nor mirror image of each and it have also different physical and chemical property. These are not mirror image of each other
(A): 2S, 3R Absolute configuration of compound It lowest priority group in vertical line then same configuration if lowest priority group on horizontal line. Introvert configuration come is $\mathrm{R} \rightarrow \mathrm{S} \quad \mathrm{S} \rightarrow \mathrm{R}$
JEE Main 2016
GENERAL ORGANIC CHEMISTRY
232077
The absolute configuration of
1 $\mathrm{S}, \mathrm{S}$
2 R, R
3 R, S
4 $\mathrm{S}, \mathrm{R}$
Explanation:
(B): Clockwise $+4^{\text {th }}$ priority inside plane $=\mathrm{R}$ Anticlock wise $+4^{\text {th }}$ priority of the plane $=R$
AIEEE 2008
GENERAL ORGANIC CHEMISTRY
232081
Following compounds are respectively .... geometrical isomers
1 P - cis, Q - cis, R - trans
2 P - cis, Q - trans, R- trans
3 P - trans, Q - cis, R - cis
4 P - cis, Q - trans, R - cis
Explanation:
It the molecules are present in some side them it is cis type and if opposite then the compound is trans types. Hence the option (a) is correct.
VITEEE 2013
GENERAL ORGANIC CHEMISTRY
232082
Arrange the following conformational isomers of n-butane in order of their increasing potential energy
1 II \(<\) III \(<\) IV \(<\) I
2 I \(<\) IV \(<\) III \(<\) II
3 II \(<\) IV \(<\) III \(<\) I
4 I \(<\) III \(<\) IV \(<\) II
Explanation:
(D) : In [I] Anti conformation of n-butane is more stable so its energy [potential] is low because we know that stability is inversely proportional to potential energy. Then the stability order of molecule is Anti> Gauche $>$ eclipsed $>$ fully eclipsed decreasing order of stability. So the potential energy in increasing order Anti $<$ Gauche $<$ eclipsed $<$ full eclipsed $\rightarrow$ increasing order of potential energy. $\text { I }<\text { III }<\text { IV }<\text { II }$
JEE Main 2021
GENERAL ORGANIC CHEMISTRY
232084
The correct relation between the following pair of compounds is
1 Constitutional isomers
2 Enantiomers
3 Distereomers
4 None of these
Explanation:
The relationship between pair of compound is Distereomer, because it is neither identical nor mirror image of each and it have also different physical and chemical property. These are not mirror image of each other
