232085
Optically active compounds among the following compounds are
1 1-phenylethanol
2 2-Phenylpropan-1-ol
3 2-Phenylpropan-2-ol
4 2-Methylpropan-2-ol
Explanation:
,b) Exp:(A,B) : Optically active compound among the following is 2- phenylpropan-1-ol because it has chiral carbon. While other compound in 1-phenylethanol also has chiral carbon but in 2-phenylpropan-2-ol and 2- methylpropan-2-ol has no chiral center so, it is not optically active. In this all four structure only a \& b has chiral center and optically active.
J and K CET-(2016)
GENERAL ORGANIC CHEMISTRY
232089
There are four conformational isomers of nbutane. Eclipsed, fully eclipsed, Gauche, Staggered Arrange these isomers of n-butane in increasing order of energy.
The increasing order of stability of four conformational n-butane Fully eclipsed $<$ Eclipsed $<$ Gauche $<$ Staggered $\text { Energy } \propto \frac{1}{\text { stability }}$ Staggered $<$ Gauche $<$ Eclipsed $<$ Fully eclipsed
J and K CET-(2018
GENERAL ORGANIC CHEMISTRY
232185
In case of $R, S$ configuration the group having highest priority is
1 $-\mathrm{NO}_{2}$
2 $-\mathrm{NH}_{2}$
3 $-\mathrm{CN}$
4 $-\mathrm{OH}$
Explanation:
R ; S Configuration priority of group is given on the basis of 1.Atomic No. of an atom 2.Molecular mass of an atom 3.Expansion of molecule In this question $-\mathrm{OH}$ has high atomic number. So, the priority of $\mathrm{OH}$ is also high.
MHT CET-2018
GENERAL ORGANIC CHEMISTRY
232090
Identify the optically active cyclohexane from the given options.
1 trans-1, 3-dimethyl cyclohexane
2 cis-1, 3-dimethyl cyclohexane
3 cis-1, 4-dimethyl cyclohexane
4 trans-1, 4-dimethyl cyclohexane
Explanation:
cis and trans 1,4-dimethyl cyclohexane contain an internal symmetry plane. only two stereoisomer appear. Therefore, they both are meso compound (optically inactive). Trans 1,4 dimethyl cyclohexane In contrast to 1,4 dimethyl cyclohexane only cis 1,3 dimethyl cyclohexane contains internal plane of symmetry while trans will not. Thus cis 1,3 dimethylcyclohexane is a meso compound and tans 1,3 dimethyl cyclohexane shows optical activity. trans (1S, 3S) 1, 3-dimethyl cyclohexane In trans compound 1, 3-dimethyl cyclohexane shows optical activity because it has chiral center. Meso compound is an-optically active number of set of steroisomer at least two of which are optically active. This means that despite containg two or more stereogenic center the molecule is not chiral.
232085
Optically active compounds among the following compounds are
1 1-phenylethanol
2 2-Phenylpropan-1-ol
3 2-Phenylpropan-2-ol
4 2-Methylpropan-2-ol
Explanation:
,b) Exp:(A,B) : Optically active compound among the following is 2- phenylpropan-1-ol because it has chiral carbon. While other compound in 1-phenylethanol also has chiral carbon but in 2-phenylpropan-2-ol and 2- methylpropan-2-ol has no chiral center so, it is not optically active. In this all four structure only a \& b has chiral center and optically active.
J and K CET-(2016)
GENERAL ORGANIC CHEMISTRY
232089
There are four conformational isomers of nbutane. Eclipsed, fully eclipsed, Gauche, Staggered Arrange these isomers of n-butane in increasing order of energy.
The increasing order of stability of four conformational n-butane Fully eclipsed $<$ Eclipsed $<$ Gauche $<$ Staggered $\text { Energy } \propto \frac{1}{\text { stability }}$ Staggered $<$ Gauche $<$ Eclipsed $<$ Fully eclipsed
J and K CET-(2018
GENERAL ORGANIC CHEMISTRY
232185
In case of $R, S$ configuration the group having highest priority is
1 $-\mathrm{NO}_{2}$
2 $-\mathrm{NH}_{2}$
3 $-\mathrm{CN}$
4 $-\mathrm{OH}$
Explanation:
R ; S Configuration priority of group is given on the basis of 1.Atomic No. of an atom 2.Molecular mass of an atom 3.Expansion of molecule In this question $-\mathrm{OH}$ has high atomic number. So, the priority of $\mathrm{OH}$ is also high.
MHT CET-2018
GENERAL ORGANIC CHEMISTRY
232090
Identify the optically active cyclohexane from the given options.
1 trans-1, 3-dimethyl cyclohexane
2 cis-1, 3-dimethyl cyclohexane
3 cis-1, 4-dimethyl cyclohexane
4 trans-1, 4-dimethyl cyclohexane
Explanation:
cis and trans 1,4-dimethyl cyclohexane contain an internal symmetry plane. only two stereoisomer appear. Therefore, they both are meso compound (optically inactive). Trans 1,4 dimethyl cyclohexane In contrast to 1,4 dimethyl cyclohexane only cis 1,3 dimethyl cyclohexane contains internal plane of symmetry while trans will not. Thus cis 1,3 dimethylcyclohexane is a meso compound and tans 1,3 dimethyl cyclohexane shows optical activity. trans (1S, 3S) 1, 3-dimethyl cyclohexane In trans compound 1, 3-dimethyl cyclohexane shows optical activity because it has chiral center. Meso compound is an-optically active number of set of steroisomer at least two of which are optically active. This means that despite containg two or more stereogenic center the molecule is not chiral.
232085
Optically active compounds among the following compounds are
1 1-phenylethanol
2 2-Phenylpropan-1-ol
3 2-Phenylpropan-2-ol
4 2-Methylpropan-2-ol
Explanation:
,b) Exp:(A,B) : Optically active compound among the following is 2- phenylpropan-1-ol because it has chiral carbon. While other compound in 1-phenylethanol also has chiral carbon but in 2-phenylpropan-2-ol and 2- methylpropan-2-ol has no chiral center so, it is not optically active. In this all four structure only a \& b has chiral center and optically active.
J and K CET-(2016)
GENERAL ORGANIC CHEMISTRY
232089
There are four conformational isomers of nbutane. Eclipsed, fully eclipsed, Gauche, Staggered Arrange these isomers of n-butane in increasing order of energy.
The increasing order of stability of four conformational n-butane Fully eclipsed $<$ Eclipsed $<$ Gauche $<$ Staggered $\text { Energy } \propto \frac{1}{\text { stability }}$ Staggered $<$ Gauche $<$ Eclipsed $<$ Fully eclipsed
J and K CET-(2018
GENERAL ORGANIC CHEMISTRY
232185
In case of $R, S$ configuration the group having highest priority is
1 $-\mathrm{NO}_{2}$
2 $-\mathrm{NH}_{2}$
3 $-\mathrm{CN}$
4 $-\mathrm{OH}$
Explanation:
R ; S Configuration priority of group is given on the basis of 1.Atomic No. of an atom 2.Molecular mass of an atom 3.Expansion of molecule In this question $-\mathrm{OH}$ has high atomic number. So, the priority of $\mathrm{OH}$ is also high.
MHT CET-2018
GENERAL ORGANIC CHEMISTRY
232090
Identify the optically active cyclohexane from the given options.
1 trans-1, 3-dimethyl cyclohexane
2 cis-1, 3-dimethyl cyclohexane
3 cis-1, 4-dimethyl cyclohexane
4 trans-1, 4-dimethyl cyclohexane
Explanation:
cis and trans 1,4-dimethyl cyclohexane contain an internal symmetry plane. only two stereoisomer appear. Therefore, they both are meso compound (optically inactive). Trans 1,4 dimethyl cyclohexane In contrast to 1,4 dimethyl cyclohexane only cis 1,3 dimethyl cyclohexane contains internal plane of symmetry while trans will not. Thus cis 1,3 dimethylcyclohexane is a meso compound and tans 1,3 dimethyl cyclohexane shows optical activity. trans (1S, 3S) 1, 3-dimethyl cyclohexane In trans compound 1, 3-dimethyl cyclohexane shows optical activity because it has chiral center. Meso compound is an-optically active number of set of steroisomer at least two of which are optically active. This means that despite containg two or more stereogenic center the molecule is not chiral.
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GENERAL ORGANIC CHEMISTRY
232085
Optically active compounds among the following compounds are
1 1-phenylethanol
2 2-Phenylpropan-1-ol
3 2-Phenylpropan-2-ol
4 2-Methylpropan-2-ol
Explanation:
,b) Exp:(A,B) : Optically active compound among the following is 2- phenylpropan-1-ol because it has chiral carbon. While other compound in 1-phenylethanol also has chiral carbon but in 2-phenylpropan-2-ol and 2- methylpropan-2-ol has no chiral center so, it is not optically active. In this all four structure only a \& b has chiral center and optically active.
J and K CET-(2016)
GENERAL ORGANIC CHEMISTRY
232089
There are four conformational isomers of nbutane. Eclipsed, fully eclipsed, Gauche, Staggered Arrange these isomers of n-butane in increasing order of energy.
The increasing order of stability of four conformational n-butane Fully eclipsed $<$ Eclipsed $<$ Gauche $<$ Staggered $\text { Energy } \propto \frac{1}{\text { stability }}$ Staggered $<$ Gauche $<$ Eclipsed $<$ Fully eclipsed
J and K CET-(2018
GENERAL ORGANIC CHEMISTRY
232185
In case of $R, S$ configuration the group having highest priority is
1 $-\mathrm{NO}_{2}$
2 $-\mathrm{NH}_{2}$
3 $-\mathrm{CN}$
4 $-\mathrm{OH}$
Explanation:
R ; S Configuration priority of group is given on the basis of 1.Atomic No. of an atom 2.Molecular mass of an atom 3.Expansion of molecule In this question $-\mathrm{OH}$ has high atomic number. So, the priority of $\mathrm{OH}$ is also high.
MHT CET-2018
GENERAL ORGANIC CHEMISTRY
232090
Identify the optically active cyclohexane from the given options.
1 trans-1, 3-dimethyl cyclohexane
2 cis-1, 3-dimethyl cyclohexane
3 cis-1, 4-dimethyl cyclohexane
4 trans-1, 4-dimethyl cyclohexane
Explanation:
cis and trans 1,4-dimethyl cyclohexane contain an internal symmetry plane. only two stereoisomer appear. Therefore, they both are meso compound (optically inactive). Trans 1,4 dimethyl cyclohexane In contrast to 1,4 dimethyl cyclohexane only cis 1,3 dimethyl cyclohexane contains internal plane of symmetry while trans will not. Thus cis 1,3 dimethylcyclohexane is a meso compound and tans 1,3 dimethyl cyclohexane shows optical activity. trans (1S, 3S) 1, 3-dimethyl cyclohexane In trans compound 1, 3-dimethyl cyclohexane shows optical activity because it has chiral center. Meso compound is an-optically active number of set of steroisomer at least two of which are optically active. This means that despite containg two or more stereogenic center the molecule is not chiral.
