DisplacementCurrent
Electromagnetic Wave

155465 In a plane electromagnetic wave travelling in free space, the electric field component oscillated sinusoidally at a frequency of 2.0× 1010 Hz and amplitude 48Vm1. Then the amplitude of oscillating magnetic field is : (Speed of light in free space =3×108 m s1 )

1 1.6×108 T
2 1.6×107 T
3 1.6×106 T
4 1.6×109 T
Electromagnetic Wave

155467 Match List I with List II
| List-I | | List-II | |
| :--- | :--- | :--- | :--- |
| A. | Gauss's Law in \lt br> Electrostatics | 1. | fEdl=dϕBdt |
| B. | Faraday's law | 2. | fBdA=0 |
| C. | Gauss's Law in \lt br> Magnetism | 3. | fBdl=μ0ic+μ0ε0dϕEdt |
| D. | Ampere- \lt br> Maxwell Law | 4. | fEds=qε0 |
Choose the correct answer from the options given below :

1 A-1, B-2, C-3, D-4
2 A-4, B-1, C-2, D-3
3 A-3, B-4, C-1, D-2
4 A-2, B-3, C-4, D-1
Electromagnetic Wave

155468 In a plane EM wave the electric field oscillates sinusoidally at a frequency of 30MHz and amplitude 150 V/m. Identify the correct expression of B assuming the wave is propagating along x-axis and is oscillating along y-axis.

1 5×107sin[x36×10+7t]z^T
2 5×107sin[π(x56×10+7t)]z^T
3 5×107sin[π(x103×10+7t)]z^T
4 5×107sin[π(2x56×10+8t)]zT^
Electromagnetic Wave

155474 The wavelength of electromagnetic waves of frequency 5×1014 Hz is (in angstrom) is

1 5000
2 3500
3 6200
4 6000
Electromagnetic Wave

155477 If ε0 and μ0 represent the permittivity and permittivity of vacuum and ε and μ represent the permittivity and permeability of medium, then refractive index of the medium is given by

1 ε0μ0εμ
2 εμε0μ0
3 μ0ε0ε
4 μ0ε0μ
Electromagnetic Wave

155465 In a plane electromagnetic wave travelling in free space, the electric field component oscillated sinusoidally at a frequency of 2.0× 1010 Hz and amplitude 48Vm1. Then the amplitude of oscillating magnetic field is : (Speed of light in free space =3×108 m s1 )

1 1.6×108 T
2 1.6×107 T
3 1.6×106 T
4 1.6×109 T
Electromagnetic Wave

155467 Match List I with List II
| List-I | | List-II | |
| :--- | :--- | :--- | :--- |
| A. | Gauss's Law in \lt br> Electrostatics | 1. | fEdl=dϕBdt |
| B. | Faraday's law | 2. | fBdA=0 |
| C. | Gauss's Law in \lt br> Magnetism | 3. | fBdl=μ0ic+μ0ε0dϕEdt |
| D. | Ampere- \lt br> Maxwell Law | 4. | fEds=qε0 |
Choose the correct answer from the options given below :

1 A-1, B-2, C-3, D-4
2 A-4, B-1, C-2, D-3
3 A-3, B-4, C-1, D-2
4 A-2, B-3, C-4, D-1
Electromagnetic Wave

155468 In a plane EM wave the electric field oscillates sinusoidally at a frequency of 30MHz and amplitude 150 V/m. Identify the correct expression of B assuming the wave is propagating along x-axis and is oscillating along y-axis.

1 5×107sin[x36×10+7t]z^T
2 5×107sin[π(x56×10+7t)]z^T
3 5×107sin[π(x103×10+7t)]z^T
4 5×107sin[π(2x56×10+8t)]zT^
Electromagnetic Wave

155474 The wavelength of electromagnetic waves of frequency 5×1014 Hz is (in angstrom) is

1 5000
2 3500
3 6200
4 6000
Electromagnetic Wave

155477 If ε0 and μ0 represent the permittivity and permittivity of vacuum and ε and μ represent the permittivity and permeability of medium, then refractive index of the medium is given by

1 ε0μ0εμ
2 εμε0μ0
3 μ0ε0ε
4 μ0ε0μ
Electromagnetic Wave

155465 In a plane electromagnetic wave travelling in free space, the electric field component oscillated sinusoidally at a frequency of 2.0× 1010 Hz and amplitude 48Vm1. Then the amplitude of oscillating magnetic field is : (Speed of light in free space =3×108 m s1 )

1 1.6×108 T
2 1.6×107 T
3 1.6×106 T
4 1.6×109 T
Electromagnetic Wave

155467 Match List I with List II
| List-I | | List-II | |
| :--- | :--- | :--- | :--- |
| A. | Gauss's Law in \lt br> Electrostatics | 1. | fEdl=dϕBdt |
| B. | Faraday's law | 2. | fBdA=0 |
| C. | Gauss's Law in \lt br> Magnetism | 3. | fBdl=μ0ic+μ0ε0dϕEdt |
| D. | Ampere- \lt br> Maxwell Law | 4. | fEds=qε0 |
Choose the correct answer from the options given below :

1 A-1, B-2, C-3, D-4
2 A-4, B-1, C-2, D-3
3 A-3, B-4, C-1, D-2
4 A-2, B-3, C-4, D-1
Electromagnetic Wave

155468 In a plane EM wave the electric field oscillates sinusoidally at a frequency of 30MHz and amplitude 150 V/m. Identify the correct expression of B assuming the wave is propagating along x-axis and is oscillating along y-axis.

1 5×107sin[x36×10+7t]z^T
2 5×107sin[π(x56×10+7t)]z^T
3 5×107sin[π(x103×10+7t)]z^T
4 5×107sin[π(2x56×10+8t)]zT^
Electromagnetic Wave

155474 The wavelength of electromagnetic waves of frequency 5×1014 Hz is (in angstrom) is

1 5000
2 3500
3 6200
4 6000
Electromagnetic Wave

155477 If ε0 and μ0 represent the permittivity and permittivity of vacuum and ε and μ represent the permittivity and permeability of medium, then refractive index of the medium is given by

1 ε0μ0εμ
2 εμε0μ0
3 μ0ε0ε
4 μ0ε0μ
Electromagnetic Wave

155465 In a plane electromagnetic wave travelling in free space, the electric field component oscillated sinusoidally at a frequency of 2.0× 1010 Hz and amplitude 48Vm1. Then the amplitude of oscillating magnetic field is : (Speed of light in free space =3×108 m s1 )

1 1.6×108 T
2 1.6×107 T
3 1.6×106 T
4 1.6×109 T
Electromagnetic Wave

155467 Match List I with List II
| List-I | | List-II | |
| :--- | :--- | :--- | :--- |
| A. | Gauss's Law in \lt br> Electrostatics | 1. | fEdl=dϕBdt |
| B. | Faraday's law | 2. | fBdA=0 |
| C. | Gauss's Law in \lt br> Magnetism | 3. | fBdl=μ0ic+μ0ε0dϕEdt |
| D. | Ampere- \lt br> Maxwell Law | 4. | fEds=qε0 |
Choose the correct answer from the options given below :

1 A-1, B-2, C-3, D-4
2 A-4, B-1, C-2, D-3
3 A-3, B-4, C-1, D-2
4 A-2, B-3, C-4, D-1
Electromagnetic Wave

155468 In a plane EM wave the electric field oscillates sinusoidally at a frequency of 30MHz and amplitude 150 V/m. Identify the correct expression of B assuming the wave is propagating along x-axis and is oscillating along y-axis.

1 5×107sin[x36×10+7t]z^T
2 5×107sin[π(x56×10+7t)]z^T
3 5×107sin[π(x103×10+7t)]z^T
4 5×107sin[π(2x56×10+8t)]zT^
Electromagnetic Wave

155474 The wavelength of electromagnetic waves of frequency 5×1014 Hz is (in angstrom) is

1 5000
2 3500
3 6200
4 6000
Electromagnetic Wave

155477 If ε0 and μ0 represent the permittivity and permittivity of vacuum and ε and μ represent the permittivity and permeability of medium, then refractive index of the medium is given by

1 ε0μ0εμ
2 εμε0μ0
3 μ0ε0ε
4 μ0ε0μ
Electromagnetic Wave

155465 In a plane electromagnetic wave travelling in free space, the electric field component oscillated sinusoidally at a frequency of 2.0× 1010 Hz and amplitude 48Vm1. Then the amplitude of oscillating magnetic field is : (Speed of light in free space =3×108 m s1 )

1 1.6×108 T
2 1.6×107 T
3 1.6×106 T
4 1.6×109 T
Electromagnetic Wave

155467 Match List I with List II
| List-I | | List-II | |
| :--- | :--- | :--- | :--- |
| A. | Gauss's Law in \lt br> Electrostatics | 1. | fEdl=dϕBdt |
| B. | Faraday's law | 2. | fBdA=0 |
| C. | Gauss's Law in \lt br> Magnetism | 3. | fBdl=μ0ic+μ0ε0dϕEdt |
| D. | Ampere- \lt br> Maxwell Law | 4. | fEds=qε0 |
Choose the correct answer from the options given below :

1 A-1, B-2, C-3, D-4
2 A-4, B-1, C-2, D-3
3 A-3, B-4, C-1, D-2
4 A-2, B-3, C-4, D-1
Electromagnetic Wave

155468 In a plane EM wave the electric field oscillates sinusoidally at a frequency of 30MHz and amplitude 150 V/m. Identify the correct expression of B assuming the wave is propagating along x-axis and is oscillating along y-axis.

1 5×107sin[x36×10+7t]z^T
2 5×107sin[π(x56×10+7t)]z^T
3 5×107sin[π(x103×10+7t)]z^T
4 5×107sin[π(2x56×10+8t)]zT^
Electromagnetic Wave

155474 The wavelength of electromagnetic waves of frequency 5×1014 Hz is (in angstrom) is

1 5000
2 3500
3 6200
4 6000
Electromagnetic Wave

155477 If ε0 and μ0 represent the permittivity and permittivity of vacuum and ε and μ represent the permittivity and permeability of medium, then refractive index of the medium is given by

1 ε0μ0εμ
2 εμε0μ0
3 μ0ε0ε
4 μ0ε0μ