Semiconductor Electronics Material Devices and Simple Circuits
151087
Consider an n-p-n transistor amplifier in common emitter configuration. The current gain of the transistor is 100 . If the collector current changes by \(1 \mathrm{~mA}\), what will be the change in emitter current.
1 \(1.1 \mathrm{~mA}\)
2 \(1.01 \mathrm{~mA}\)
3 \(0.01 \mathrm{~mA}\)
4 \(10 \mathrm{~mA}\)
Explanation:
B Given, current gain, \(\beta=100\) \(\mathrm{I}_{\mathrm{C}}=1 \mathrm{~mA}\) \(\beta=\frac{I_C}{I_B}\) \(I_B=\frac{I_C}{\beta}\) \(\mathrm{I}_{\mathrm{B}}=\frac{1}{100}=10^{-2} \mathrm{~mA}\) We know that, \(\mathrm{I}_{\mathrm{E}}=\mathrm{I}_{\mathrm{C}}+\mathrm{I}_{\mathrm{B}}\) \(\mathrm{I}_{\mathrm{E}}=1+0.01\) \(\mathrm{I}_{\mathrm{E}}=1.01 \mathrm{~mA}\)
AIIMS-2005
Semiconductor Electronics Material Devices and Simple Circuits
151079
Assertion: In a common emitter transistor amplifier the input current is much less than the output current. Reason: The common emitter transistor amplifier has very high input impedance.
1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
3 If the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the Assertion is incorrect but the Reason is correct.
Explanation:
C In an amplifier output current is always more than input current. Amplifier has low input impedance. Hence, the assertion is correct but reason are incorrect.
AIIMS-2005
Semiconductor Electronics Material Devices and Simple Circuits
151088
The voltage gain of the following amplifier is
1 10
2 100
3 1000
4 9.9
Explanation:
B Voltage gain \(\left(A_V\right)=\frac{V_0}{V_i}\) \(\therefore \quad \mathrm{A}_{\mathrm{V}}=\frac{\mathrm{R}_0}{\mathrm{R}_{\mathrm{i}}}=\frac{100}{1}\) \(\mathrm{A}_{\mathrm{V}}=100\)
AIIMS-2005
Semiconductor Electronics Material Devices and Simple Circuits
151089
In the following common emitter configuration an npn transistor with current gain \(\beta=100\) is used. The output voltage of the amplifier will be.
1 \(10 \mathrm{mV}\)
2 \(0.1 \mathrm{~V}\)
3 \(1.0 \mathrm{~V}\)
4 \(10 \mathrm{~V}\)
Explanation:
D \(\therefore\) Voltage gain \(=\) current gain \(\times\) resistance gain \(\frac{V_o}{V_i}=\beta \times \frac{R_o}{R_i}\) \(\frac{V_o}{10^{-3} \times 10}=100 \times \frac{10}{1}\) \(V_o= 100 \times 10 \times 10^{-3} \times 10\) \(V_o= 10 \mathrm{~V}\)
Semiconductor Electronics Material Devices and Simple Circuits
151087
Consider an n-p-n transistor amplifier in common emitter configuration. The current gain of the transistor is 100 . If the collector current changes by \(1 \mathrm{~mA}\), what will be the change in emitter current.
1 \(1.1 \mathrm{~mA}\)
2 \(1.01 \mathrm{~mA}\)
3 \(0.01 \mathrm{~mA}\)
4 \(10 \mathrm{~mA}\)
Explanation:
B Given, current gain, \(\beta=100\) \(\mathrm{I}_{\mathrm{C}}=1 \mathrm{~mA}\) \(\beta=\frac{I_C}{I_B}\) \(I_B=\frac{I_C}{\beta}\) \(\mathrm{I}_{\mathrm{B}}=\frac{1}{100}=10^{-2} \mathrm{~mA}\) We know that, \(\mathrm{I}_{\mathrm{E}}=\mathrm{I}_{\mathrm{C}}+\mathrm{I}_{\mathrm{B}}\) \(\mathrm{I}_{\mathrm{E}}=1+0.01\) \(\mathrm{I}_{\mathrm{E}}=1.01 \mathrm{~mA}\)
AIIMS-2005
Semiconductor Electronics Material Devices and Simple Circuits
151079
Assertion: In a common emitter transistor amplifier the input current is much less than the output current. Reason: The common emitter transistor amplifier has very high input impedance.
1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
3 If the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the Assertion is incorrect but the Reason is correct.
Explanation:
C In an amplifier output current is always more than input current. Amplifier has low input impedance. Hence, the assertion is correct but reason are incorrect.
AIIMS-2005
Semiconductor Electronics Material Devices and Simple Circuits
151088
The voltage gain of the following amplifier is
1 10
2 100
3 1000
4 9.9
Explanation:
B Voltage gain \(\left(A_V\right)=\frac{V_0}{V_i}\) \(\therefore \quad \mathrm{A}_{\mathrm{V}}=\frac{\mathrm{R}_0}{\mathrm{R}_{\mathrm{i}}}=\frac{100}{1}\) \(\mathrm{A}_{\mathrm{V}}=100\)
AIIMS-2005
Semiconductor Electronics Material Devices and Simple Circuits
151089
In the following common emitter configuration an npn transistor with current gain \(\beta=100\) is used. The output voltage of the amplifier will be.
1 \(10 \mathrm{mV}\)
2 \(0.1 \mathrm{~V}\)
3 \(1.0 \mathrm{~V}\)
4 \(10 \mathrm{~V}\)
Explanation:
D \(\therefore\) Voltage gain \(=\) current gain \(\times\) resistance gain \(\frac{V_o}{V_i}=\beta \times \frac{R_o}{R_i}\) \(\frac{V_o}{10^{-3} \times 10}=100 \times \frac{10}{1}\) \(V_o= 100 \times 10 \times 10^{-3} \times 10\) \(V_o= 10 \mathrm{~V}\)
Semiconductor Electronics Material Devices and Simple Circuits
151087
Consider an n-p-n transistor amplifier in common emitter configuration. The current gain of the transistor is 100 . If the collector current changes by \(1 \mathrm{~mA}\), what will be the change in emitter current.
1 \(1.1 \mathrm{~mA}\)
2 \(1.01 \mathrm{~mA}\)
3 \(0.01 \mathrm{~mA}\)
4 \(10 \mathrm{~mA}\)
Explanation:
B Given, current gain, \(\beta=100\) \(\mathrm{I}_{\mathrm{C}}=1 \mathrm{~mA}\) \(\beta=\frac{I_C}{I_B}\) \(I_B=\frac{I_C}{\beta}\) \(\mathrm{I}_{\mathrm{B}}=\frac{1}{100}=10^{-2} \mathrm{~mA}\) We know that, \(\mathrm{I}_{\mathrm{E}}=\mathrm{I}_{\mathrm{C}}+\mathrm{I}_{\mathrm{B}}\) \(\mathrm{I}_{\mathrm{E}}=1+0.01\) \(\mathrm{I}_{\mathrm{E}}=1.01 \mathrm{~mA}\)
AIIMS-2005
Semiconductor Electronics Material Devices and Simple Circuits
151079
Assertion: In a common emitter transistor amplifier the input current is much less than the output current. Reason: The common emitter transistor amplifier has very high input impedance.
1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
3 If the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the Assertion is incorrect but the Reason is correct.
Explanation:
C In an amplifier output current is always more than input current. Amplifier has low input impedance. Hence, the assertion is correct but reason are incorrect.
AIIMS-2005
Semiconductor Electronics Material Devices and Simple Circuits
151088
The voltage gain of the following amplifier is
1 10
2 100
3 1000
4 9.9
Explanation:
B Voltage gain \(\left(A_V\right)=\frac{V_0}{V_i}\) \(\therefore \quad \mathrm{A}_{\mathrm{V}}=\frac{\mathrm{R}_0}{\mathrm{R}_{\mathrm{i}}}=\frac{100}{1}\) \(\mathrm{A}_{\mathrm{V}}=100\)
AIIMS-2005
Semiconductor Electronics Material Devices and Simple Circuits
151089
In the following common emitter configuration an npn transistor with current gain \(\beta=100\) is used. The output voltage of the amplifier will be.
1 \(10 \mathrm{mV}\)
2 \(0.1 \mathrm{~V}\)
3 \(1.0 \mathrm{~V}\)
4 \(10 \mathrm{~V}\)
Explanation:
D \(\therefore\) Voltage gain \(=\) current gain \(\times\) resistance gain \(\frac{V_o}{V_i}=\beta \times \frac{R_o}{R_i}\) \(\frac{V_o}{10^{-3} \times 10}=100 \times \frac{10}{1}\) \(V_o= 100 \times 10 \times 10^{-3} \times 10\) \(V_o= 10 \mathrm{~V}\)
NEET Test Series from KOTA - 10 Papers In MS WORD
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Semiconductor Electronics Material Devices and Simple Circuits
151087
Consider an n-p-n transistor amplifier in common emitter configuration. The current gain of the transistor is 100 . If the collector current changes by \(1 \mathrm{~mA}\), what will be the change in emitter current.
1 \(1.1 \mathrm{~mA}\)
2 \(1.01 \mathrm{~mA}\)
3 \(0.01 \mathrm{~mA}\)
4 \(10 \mathrm{~mA}\)
Explanation:
B Given, current gain, \(\beta=100\) \(\mathrm{I}_{\mathrm{C}}=1 \mathrm{~mA}\) \(\beta=\frac{I_C}{I_B}\) \(I_B=\frac{I_C}{\beta}\) \(\mathrm{I}_{\mathrm{B}}=\frac{1}{100}=10^{-2} \mathrm{~mA}\) We know that, \(\mathrm{I}_{\mathrm{E}}=\mathrm{I}_{\mathrm{C}}+\mathrm{I}_{\mathrm{B}}\) \(\mathrm{I}_{\mathrm{E}}=1+0.01\) \(\mathrm{I}_{\mathrm{E}}=1.01 \mathrm{~mA}\)
AIIMS-2005
Semiconductor Electronics Material Devices and Simple Circuits
151079
Assertion: In a common emitter transistor amplifier the input current is much less than the output current. Reason: The common emitter transistor amplifier has very high input impedance.
1 If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
2 If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
3 If the Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
5 If the Assertion is incorrect but the Reason is correct.
Explanation:
C In an amplifier output current is always more than input current. Amplifier has low input impedance. Hence, the assertion is correct but reason are incorrect.
AIIMS-2005
Semiconductor Electronics Material Devices and Simple Circuits
151088
The voltage gain of the following amplifier is
1 10
2 100
3 1000
4 9.9
Explanation:
B Voltage gain \(\left(A_V\right)=\frac{V_0}{V_i}\) \(\therefore \quad \mathrm{A}_{\mathrm{V}}=\frac{\mathrm{R}_0}{\mathrm{R}_{\mathrm{i}}}=\frac{100}{1}\) \(\mathrm{A}_{\mathrm{V}}=100\)
AIIMS-2005
Semiconductor Electronics Material Devices and Simple Circuits
151089
In the following common emitter configuration an npn transistor with current gain \(\beta=100\) is used. The output voltage of the amplifier will be.
1 \(10 \mathrm{mV}\)
2 \(0.1 \mathrm{~V}\)
3 \(1.0 \mathrm{~V}\)
4 \(10 \mathrm{~V}\)
Explanation:
D \(\therefore\) Voltage gain \(=\) current gain \(\times\) resistance gain \(\frac{V_o}{V_i}=\beta \times \frac{R_o}{R_i}\) \(\frac{V_o}{10^{-3} \times 10}=100 \times \frac{10}{1}\) \(V_o= 100 \times 10 \times 10^{-3} \times 10\) \(V_o= 10 \mathrm{~V}\)
