Junction Transistors (npn, pnp)
Semiconductor Electronics Material Devices and Simple Circuits

151067 In CE NPN transistor \(10^{10}\) electrons enter the emitter in \(10^{-6} \mathrm{~s}\) when it is connected to battery. About 5\% electrons recombine with holes in the base. The current gain of the transistor is
\(\left.\overline{(\mathrm{e}=1.6} \times 10^{-19} \mathrm{C}\right)\)

1 0.98
2 19
3 49
4 0.95
Semiconductor Electronics Material Devices and Simple Circuits

151070 The collector supply voltage in \(\mathrm{CE}\) transistor amplifier is \(10 \mathrm{~V}\). The base current is \(10 \mu \mathrm{A}\) in the absence of the signal voltage and the voltage between the collector and the emitter is \(4 \mathrm{~V}\). The current gain \((\beta)\) of a transistor is 200 , then the value of the load resistance \(R_L\)

1 \(1 \mathrm{k} \Omega\)
2 \(2 \mathrm{k} \Omega\)
3 \(3 \mathrm{k} \Omega\)
4 \(4 \mathrm{k} \Omega\)
Semiconductor Electronics Material Devices and Simple Circuits

151073 In a common base circuit, collector base voltage changes by \(0.6 \mathrm{~V}\) and collector current changes by \(0.02 \mathrm{~mA}\). Then, the output resistance is

1 \(6 \times 10^4 \Omega\)
2 \(3 \times 10^4 \Omega\)
3 \(9 \times 10^4 \Omega\)
4 \(18 \times 10^4 \Omega\)
Semiconductor Electronics Material Devices and Simple Circuits

151074 For a common emitter amplifier, the audio signal voltage across the collector resistance 2 \(\mathrm{k} \Omega\) is \(2 \mathrm{~V}\). If the current amplification factor of the transistor is \(\mathbf{2 0 0}\), and the base resistance is \(1.5 \mathrm{k} \Omega\), the input signal and base current are

1 \(0.1 \mathrm{~V}\) and \(1 \mu \mathrm{A}\)
2 \(0.15 \mathrm{~V}\) and \(10 \mu \mathrm{A}\)
3 \(0.015 \mathrm{~V}\) and \(1 \mathrm{~A}\)
4 \(0.0075 \mathrm{~V}\) and \(5 \mu \mathrm{A}\)
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Semiconductor Electronics Material Devices and Simple Circuits

151067 In CE NPN transistor \(10^{10}\) electrons enter the emitter in \(10^{-6} \mathrm{~s}\) when it is connected to battery. About 5\% electrons recombine with holes in the base. The current gain of the transistor is
\(\left.\overline{(\mathrm{e}=1.6} \times 10^{-19} \mathrm{C}\right)\)

1 0.98
2 19
3 49
4 0.95
Semiconductor Electronics Material Devices and Simple Circuits

151070 The collector supply voltage in \(\mathrm{CE}\) transistor amplifier is \(10 \mathrm{~V}\). The base current is \(10 \mu \mathrm{A}\) in the absence of the signal voltage and the voltage between the collector and the emitter is \(4 \mathrm{~V}\). The current gain \((\beta)\) of a transistor is 200 , then the value of the load resistance \(R_L\)

1 \(1 \mathrm{k} \Omega\)
2 \(2 \mathrm{k} \Omega\)
3 \(3 \mathrm{k} \Omega\)
4 \(4 \mathrm{k} \Omega\)
Semiconductor Electronics Material Devices and Simple Circuits

151073 In a common base circuit, collector base voltage changes by \(0.6 \mathrm{~V}\) and collector current changes by \(0.02 \mathrm{~mA}\). Then, the output resistance is

1 \(6 \times 10^4 \Omega\)
2 \(3 \times 10^4 \Omega\)
3 \(9 \times 10^4 \Omega\)
4 \(18 \times 10^4 \Omega\)
Semiconductor Electronics Material Devices and Simple Circuits

151074 For a common emitter amplifier, the audio signal voltage across the collector resistance 2 \(\mathrm{k} \Omega\) is \(2 \mathrm{~V}\). If the current amplification factor of the transistor is \(\mathbf{2 0 0}\), and the base resistance is \(1.5 \mathrm{k} \Omega\), the input signal and base current are

1 \(0.1 \mathrm{~V}\) and \(1 \mu \mathrm{A}\)
2 \(0.15 \mathrm{~V}\) and \(10 \mu \mathrm{A}\)
3 \(0.015 \mathrm{~V}\) and \(1 \mathrm{~A}\)
4 \(0.0075 \mathrm{~V}\) and \(5 \mu \mathrm{A}\)
Semiconductor Electronics Material Devices and Simple Circuits

151067 In CE NPN transistor \(10^{10}\) electrons enter the emitter in \(10^{-6} \mathrm{~s}\) when it is connected to battery. About 5\% electrons recombine with holes in the base. The current gain of the transistor is
\(\left.\overline{(\mathrm{e}=1.6} \times 10^{-19} \mathrm{C}\right)\)

1 0.98
2 19
3 49
4 0.95
Semiconductor Electronics Material Devices and Simple Circuits

151070 The collector supply voltage in \(\mathrm{CE}\) transistor amplifier is \(10 \mathrm{~V}\). The base current is \(10 \mu \mathrm{A}\) in the absence of the signal voltage and the voltage between the collector and the emitter is \(4 \mathrm{~V}\). The current gain \((\beta)\) of a transistor is 200 , then the value of the load resistance \(R_L\)

1 \(1 \mathrm{k} \Omega\)
2 \(2 \mathrm{k} \Omega\)
3 \(3 \mathrm{k} \Omega\)
4 \(4 \mathrm{k} \Omega\)
Semiconductor Electronics Material Devices and Simple Circuits

151073 In a common base circuit, collector base voltage changes by \(0.6 \mathrm{~V}\) and collector current changes by \(0.02 \mathrm{~mA}\). Then, the output resistance is

1 \(6 \times 10^4 \Omega\)
2 \(3 \times 10^4 \Omega\)
3 \(9 \times 10^4 \Omega\)
4 \(18 \times 10^4 \Omega\)
Semiconductor Electronics Material Devices and Simple Circuits

151074 For a common emitter amplifier, the audio signal voltage across the collector resistance 2 \(\mathrm{k} \Omega\) is \(2 \mathrm{~V}\). If the current amplification factor of the transistor is \(\mathbf{2 0 0}\), and the base resistance is \(1.5 \mathrm{k} \Omega\), the input signal and base current are

1 \(0.1 \mathrm{~V}\) and \(1 \mu \mathrm{A}\)
2 \(0.15 \mathrm{~V}\) and \(10 \mu \mathrm{A}\)
3 \(0.015 \mathrm{~V}\) and \(1 \mathrm{~A}\)
4 \(0.0075 \mathrm{~V}\) and \(5 \mu \mathrm{A}\)
Semiconductor Electronics Material Devices and Simple Circuits

151067 In CE NPN transistor \(10^{10}\) electrons enter the emitter in \(10^{-6} \mathrm{~s}\) when it is connected to battery. About 5\% electrons recombine with holes in the base. The current gain of the transistor is
\(\left.\overline{(\mathrm{e}=1.6} \times 10^{-19} \mathrm{C}\right)\)

1 0.98
2 19
3 49
4 0.95
Semiconductor Electronics Material Devices and Simple Circuits

151070 The collector supply voltage in \(\mathrm{CE}\) transistor amplifier is \(10 \mathrm{~V}\). The base current is \(10 \mu \mathrm{A}\) in the absence of the signal voltage and the voltage between the collector and the emitter is \(4 \mathrm{~V}\). The current gain \((\beta)\) of a transistor is 200 , then the value of the load resistance \(R_L\)

1 \(1 \mathrm{k} \Omega\)
2 \(2 \mathrm{k} \Omega\)
3 \(3 \mathrm{k} \Omega\)
4 \(4 \mathrm{k} \Omega\)
Semiconductor Electronics Material Devices and Simple Circuits

151073 In a common base circuit, collector base voltage changes by \(0.6 \mathrm{~V}\) and collector current changes by \(0.02 \mathrm{~mA}\). Then, the output resistance is

1 \(6 \times 10^4 \Omega\)
2 \(3 \times 10^4 \Omega\)
3 \(9 \times 10^4 \Omega\)
4 \(18 \times 10^4 \Omega\)
Semiconductor Electronics Material Devices and Simple Circuits

151074 For a common emitter amplifier, the audio signal voltage across the collector resistance 2 \(\mathrm{k} \Omega\) is \(2 \mathrm{~V}\). If the current amplification factor of the transistor is \(\mathbf{2 0 0}\), and the base resistance is \(1.5 \mathrm{k} \Omega\), the input signal and base current are

1 \(0.1 \mathrm{~V}\) and \(1 \mu \mathrm{A}\)
2 \(0.15 \mathrm{~V}\) and \(10 \mu \mathrm{A}\)
3 \(0.015 \mathrm{~V}\) and \(1 \mathrm{~A}\)
4 \(0.0075 \mathrm{~V}\) and \(5 \mu \mathrm{A}\)