A Number of neutrons For $\quad{ }_{34} \mathrm{Se}^{74}=74-34=40$ ${ }_{31} \mathrm{Ga}^{71}=71-31=40$ It is a isotones because $\mathrm{Se}$ and $\mathrm{Ga}$ have same (equal) number of neutrons.
BITSAT-2019
NUCLEAR PHYSICS
147979
The average number of prompt neutrons produced per fission of $\mathrm{U}^{235}$ is
1 more than 5
2 4 to 5
3 2 to 3
4 1 to 2
Explanation:
C The reaction, ${ }_{92} \mathrm{U}^{235}+{ }_{0} \mathrm{n}^{1} \rightarrow{ }_{56} \mathrm{Ba}^{144}+{ }_{36} \mathrm{Kr}^{89}+3{ }_{0} \mathrm{n}^{1}+200 \mathrm{MeV}$ Hence, the average neutrons produced is 2.5 . It is between 2 to 3 .
CG PET- 2005
NUCLEAR PHYSICS
148010
In an atom bomb, the energy is released because of the ?
1 chain reaction of neutrons and ${ }_{92} \mathrm{U}^{238}$
2 chain reaction of neutrons and ${ }_{92} \mathrm{U}^{235}$
3 chain reaction of neutrons and ${ }_{92} U^{236}$
4 chain reaction of neutrons and ${ }_{92} \mathrm{U}^{240}$
Explanation:
B The energy is released because of the chain reaction of neutrons and ${ }_{92} \mathrm{U}^{235}$. The nuclear reaction- ${ }_{0} \mathrm{n}^{1}+{ }_{92} \mathrm{U}^{235} \rightarrow{ }_{36} \mathrm{Ba}^{141}+{ }_{56} \mathrm{Kr}^{92}+3{ }_{0} \mathrm{n}^{1}+\mathrm{Q}$
AIIMS-2001
NUCLEAR PHYSICS
148056
In carbon- nitrogen nuclear fusion cycle, protons are fused to form a helium nucleus, positrons and release some energy. The number of protons fused and the number of positrons released in this process respectively are:
1 4,4
2 4,2
3 2,4
4 4,6
Explanation:
B According to question, $4_{1} \mathrm{H}^{1} \rightarrow{ }_{2} \mathrm{He}^{4}+2\left({ }_{1} \mathrm{e}^{0}\right)+\mathrm{Q}$ Hence, 4 protons are fused and produced 2 positrons.
AP EAMCET(Medical)-2002
NUCLEAR PHYSICS
148061
The overall process of carbon-nitrogen fusion cycle results in fusion of four protons to yield the helium nucleus and two
1 Positron
2 electron
3 neutron
4 proton
Explanation:
A Reaction of carbon cycle is $\underset{\text { Hydrogen }}{4 \mathrm{H}^{1}} \rightarrow \underset{\text { Helium }}{\mathrm{He}^{4}}+\underset{\text { Positron }}{2\left({ }_{+1} \mathrm{e}^{0}\right)}+2 v+\text { energy }$ So, the two positron are released.
A Number of neutrons For $\quad{ }_{34} \mathrm{Se}^{74}=74-34=40$ ${ }_{31} \mathrm{Ga}^{71}=71-31=40$ It is a isotones because $\mathrm{Se}$ and $\mathrm{Ga}$ have same (equal) number of neutrons.
BITSAT-2019
NUCLEAR PHYSICS
147979
The average number of prompt neutrons produced per fission of $\mathrm{U}^{235}$ is
1 more than 5
2 4 to 5
3 2 to 3
4 1 to 2
Explanation:
C The reaction, ${ }_{92} \mathrm{U}^{235}+{ }_{0} \mathrm{n}^{1} \rightarrow{ }_{56} \mathrm{Ba}^{144}+{ }_{36} \mathrm{Kr}^{89}+3{ }_{0} \mathrm{n}^{1}+200 \mathrm{MeV}$ Hence, the average neutrons produced is 2.5 . It is between 2 to 3 .
CG PET- 2005
NUCLEAR PHYSICS
148010
In an atom bomb, the energy is released because of the ?
1 chain reaction of neutrons and ${ }_{92} \mathrm{U}^{238}$
2 chain reaction of neutrons and ${ }_{92} \mathrm{U}^{235}$
3 chain reaction of neutrons and ${ }_{92} U^{236}$
4 chain reaction of neutrons and ${ }_{92} \mathrm{U}^{240}$
Explanation:
B The energy is released because of the chain reaction of neutrons and ${ }_{92} \mathrm{U}^{235}$. The nuclear reaction- ${ }_{0} \mathrm{n}^{1}+{ }_{92} \mathrm{U}^{235} \rightarrow{ }_{36} \mathrm{Ba}^{141}+{ }_{56} \mathrm{Kr}^{92}+3{ }_{0} \mathrm{n}^{1}+\mathrm{Q}$
AIIMS-2001
NUCLEAR PHYSICS
148056
In carbon- nitrogen nuclear fusion cycle, protons are fused to form a helium nucleus, positrons and release some energy. The number of protons fused and the number of positrons released in this process respectively are:
1 4,4
2 4,2
3 2,4
4 4,6
Explanation:
B According to question, $4_{1} \mathrm{H}^{1} \rightarrow{ }_{2} \mathrm{He}^{4}+2\left({ }_{1} \mathrm{e}^{0}\right)+\mathrm{Q}$ Hence, 4 protons are fused and produced 2 positrons.
AP EAMCET(Medical)-2002
NUCLEAR PHYSICS
148061
The overall process of carbon-nitrogen fusion cycle results in fusion of four protons to yield the helium nucleus and two
1 Positron
2 electron
3 neutron
4 proton
Explanation:
A Reaction of carbon cycle is $\underset{\text { Hydrogen }}{4 \mathrm{H}^{1}} \rightarrow \underset{\text { Helium }}{\mathrm{He}^{4}}+\underset{\text { Positron }}{2\left({ }_{+1} \mathrm{e}^{0}\right)}+2 v+\text { energy }$ So, the two positron are released.
A Number of neutrons For $\quad{ }_{34} \mathrm{Se}^{74}=74-34=40$ ${ }_{31} \mathrm{Ga}^{71}=71-31=40$ It is a isotones because $\mathrm{Se}$ and $\mathrm{Ga}$ have same (equal) number of neutrons.
BITSAT-2019
NUCLEAR PHYSICS
147979
The average number of prompt neutrons produced per fission of $\mathrm{U}^{235}$ is
1 more than 5
2 4 to 5
3 2 to 3
4 1 to 2
Explanation:
C The reaction, ${ }_{92} \mathrm{U}^{235}+{ }_{0} \mathrm{n}^{1} \rightarrow{ }_{56} \mathrm{Ba}^{144}+{ }_{36} \mathrm{Kr}^{89}+3{ }_{0} \mathrm{n}^{1}+200 \mathrm{MeV}$ Hence, the average neutrons produced is 2.5 . It is between 2 to 3 .
CG PET- 2005
NUCLEAR PHYSICS
148010
In an atom bomb, the energy is released because of the ?
1 chain reaction of neutrons and ${ }_{92} \mathrm{U}^{238}$
2 chain reaction of neutrons and ${ }_{92} \mathrm{U}^{235}$
3 chain reaction of neutrons and ${ }_{92} U^{236}$
4 chain reaction of neutrons and ${ }_{92} \mathrm{U}^{240}$
Explanation:
B The energy is released because of the chain reaction of neutrons and ${ }_{92} \mathrm{U}^{235}$. The nuclear reaction- ${ }_{0} \mathrm{n}^{1}+{ }_{92} \mathrm{U}^{235} \rightarrow{ }_{36} \mathrm{Ba}^{141}+{ }_{56} \mathrm{Kr}^{92}+3{ }_{0} \mathrm{n}^{1}+\mathrm{Q}$
AIIMS-2001
NUCLEAR PHYSICS
148056
In carbon- nitrogen nuclear fusion cycle, protons are fused to form a helium nucleus, positrons and release some energy. The number of protons fused and the number of positrons released in this process respectively are:
1 4,4
2 4,2
3 2,4
4 4,6
Explanation:
B According to question, $4_{1} \mathrm{H}^{1} \rightarrow{ }_{2} \mathrm{He}^{4}+2\left({ }_{1} \mathrm{e}^{0}\right)+\mathrm{Q}$ Hence, 4 protons are fused and produced 2 positrons.
AP EAMCET(Medical)-2002
NUCLEAR PHYSICS
148061
The overall process of carbon-nitrogen fusion cycle results in fusion of four protons to yield the helium nucleus and two
1 Positron
2 electron
3 neutron
4 proton
Explanation:
A Reaction of carbon cycle is $\underset{\text { Hydrogen }}{4 \mathrm{H}^{1}} \rightarrow \underset{\text { Helium }}{\mathrm{He}^{4}}+\underset{\text { Positron }}{2\left({ }_{+1} \mathrm{e}^{0}\right)}+2 v+\text { energy }$ So, the two positron are released.
A Number of neutrons For $\quad{ }_{34} \mathrm{Se}^{74}=74-34=40$ ${ }_{31} \mathrm{Ga}^{71}=71-31=40$ It is a isotones because $\mathrm{Se}$ and $\mathrm{Ga}$ have same (equal) number of neutrons.
BITSAT-2019
NUCLEAR PHYSICS
147979
The average number of prompt neutrons produced per fission of $\mathrm{U}^{235}$ is
1 more than 5
2 4 to 5
3 2 to 3
4 1 to 2
Explanation:
C The reaction, ${ }_{92} \mathrm{U}^{235}+{ }_{0} \mathrm{n}^{1} \rightarrow{ }_{56} \mathrm{Ba}^{144}+{ }_{36} \mathrm{Kr}^{89}+3{ }_{0} \mathrm{n}^{1}+200 \mathrm{MeV}$ Hence, the average neutrons produced is 2.5 . It is between 2 to 3 .
CG PET- 2005
NUCLEAR PHYSICS
148010
In an atom bomb, the energy is released because of the ?
1 chain reaction of neutrons and ${ }_{92} \mathrm{U}^{238}$
2 chain reaction of neutrons and ${ }_{92} \mathrm{U}^{235}$
3 chain reaction of neutrons and ${ }_{92} U^{236}$
4 chain reaction of neutrons and ${ }_{92} \mathrm{U}^{240}$
Explanation:
B The energy is released because of the chain reaction of neutrons and ${ }_{92} \mathrm{U}^{235}$. The nuclear reaction- ${ }_{0} \mathrm{n}^{1}+{ }_{92} \mathrm{U}^{235} \rightarrow{ }_{36} \mathrm{Ba}^{141}+{ }_{56} \mathrm{Kr}^{92}+3{ }_{0} \mathrm{n}^{1}+\mathrm{Q}$
AIIMS-2001
NUCLEAR PHYSICS
148056
In carbon- nitrogen nuclear fusion cycle, protons are fused to form a helium nucleus, positrons and release some energy. The number of protons fused and the number of positrons released in this process respectively are:
1 4,4
2 4,2
3 2,4
4 4,6
Explanation:
B According to question, $4_{1} \mathrm{H}^{1} \rightarrow{ }_{2} \mathrm{He}^{4}+2\left({ }_{1} \mathrm{e}^{0}\right)+\mathrm{Q}$ Hence, 4 protons are fused and produced 2 positrons.
AP EAMCET(Medical)-2002
NUCLEAR PHYSICS
148061
The overall process of carbon-nitrogen fusion cycle results in fusion of four protons to yield the helium nucleus and two
1 Positron
2 electron
3 neutron
4 proton
Explanation:
A Reaction of carbon cycle is $\underset{\text { Hydrogen }}{4 \mathrm{H}^{1}} \rightarrow \underset{\text { Helium }}{\mathrm{He}^{4}}+\underset{\text { Positron }}{2\left({ }_{+1} \mathrm{e}^{0}\right)}+2 v+\text { energy }$ So, the two positron are released.
A Number of neutrons For $\quad{ }_{34} \mathrm{Se}^{74}=74-34=40$ ${ }_{31} \mathrm{Ga}^{71}=71-31=40$ It is a isotones because $\mathrm{Se}$ and $\mathrm{Ga}$ have same (equal) number of neutrons.
BITSAT-2019
NUCLEAR PHYSICS
147979
The average number of prompt neutrons produced per fission of $\mathrm{U}^{235}$ is
1 more than 5
2 4 to 5
3 2 to 3
4 1 to 2
Explanation:
C The reaction, ${ }_{92} \mathrm{U}^{235}+{ }_{0} \mathrm{n}^{1} \rightarrow{ }_{56} \mathrm{Ba}^{144}+{ }_{36} \mathrm{Kr}^{89}+3{ }_{0} \mathrm{n}^{1}+200 \mathrm{MeV}$ Hence, the average neutrons produced is 2.5 . It is between 2 to 3 .
CG PET- 2005
NUCLEAR PHYSICS
148010
In an atom bomb, the energy is released because of the ?
1 chain reaction of neutrons and ${ }_{92} \mathrm{U}^{238}$
2 chain reaction of neutrons and ${ }_{92} \mathrm{U}^{235}$
3 chain reaction of neutrons and ${ }_{92} U^{236}$
4 chain reaction of neutrons and ${ }_{92} \mathrm{U}^{240}$
Explanation:
B The energy is released because of the chain reaction of neutrons and ${ }_{92} \mathrm{U}^{235}$. The nuclear reaction- ${ }_{0} \mathrm{n}^{1}+{ }_{92} \mathrm{U}^{235} \rightarrow{ }_{36} \mathrm{Ba}^{141}+{ }_{56} \mathrm{Kr}^{92}+3{ }_{0} \mathrm{n}^{1}+\mathrm{Q}$
AIIMS-2001
NUCLEAR PHYSICS
148056
In carbon- nitrogen nuclear fusion cycle, protons are fused to form a helium nucleus, positrons and release some energy. The number of protons fused and the number of positrons released in this process respectively are:
1 4,4
2 4,2
3 2,4
4 4,6
Explanation:
B According to question, $4_{1} \mathrm{H}^{1} \rightarrow{ }_{2} \mathrm{He}^{4}+2\left({ }_{1} \mathrm{e}^{0}\right)+\mathrm{Q}$ Hence, 4 protons are fused and produced 2 positrons.
AP EAMCET(Medical)-2002
NUCLEAR PHYSICS
148061
The overall process of carbon-nitrogen fusion cycle results in fusion of four protons to yield the helium nucleus and two
1 Positron
2 electron
3 neutron
4 proton
Explanation:
A Reaction of carbon cycle is $\underset{\text { Hydrogen }}{4 \mathrm{H}^{1}} \rightarrow \underset{\text { Helium }}{\mathrm{He}^{4}}+\underset{\text { Positron }}{2\left({ }_{+1} \mathrm{e}^{0}\right)}+2 v+\text { energy }$ So, the two positron are released.
