Effect of Dielectric Charging and Discharging of Capacitor
Capacitance

165982 A capacitor is made of flat plate of area $A$ and a second plate of stair-like structure as sown in the figure. The area of each stair is $\frac{\mathrm{A}}{3}$ and the height is $d$. the capacitance of the arrangement is

1 $\frac{\varepsilon_{0} \mathrm{~A}}{3 \mathrm{~d}}$
2 $\frac{6 \varepsilon_{0} \mathrm{~A}}{11 \mathrm{~d}}$
3 $\frac{3 \varepsilon_{0} \mathrm{~A}}{\mathrm{~d}}$
4 $\frac{11 \varepsilon_{0} \mathrm{~A}}{18 \mathrm{~d}}$
Capacitance

165983 One plate of a parallel palate capacitor is connected to a spring as shown in the figure. The area of each plate of the capacitor is $A$ and the distance between the plate is $d$, when the battery is not connected and the spring is unscratched. After connecting the battery, in the steady state the distance between the plates is $0.75 \mathrm{~d}$, then the force constant of the spring is

1 $\frac{3}{8} \frac{\varepsilon_{0} \mathrm{~V}^{2} \mathrm{~A}}{\mathrm{~d}^{3}}$
2 $\frac{8}{3} \frac{\varepsilon_{0} \mathrm{~V}^{2} \mathrm{~A}}{\mathrm{~d}^{3}}$
3 $\frac{9}{32} \frac{\varepsilon_{0} \mathrm{~V}^{2} \mathrm{~A}}{\mathrm{~d}^{3}}$
4 $\frac{32}{9} \frac{\varepsilon_{0} \mathrm{~V}^{2} \mathrm{~A}}{\mathrm{~d}^{3}}$
Capacitance

165984 The plates of a parallel plate capacitor are charges upto $100 \mathrm{~V}$. A $2 \mathrm{~mm}$ thick insulator sheet is inserted between the plates. Then to maintain the same potential difference, the distance between the plates is increased by $\mathbf{1 . 6}$ $\mathrm{mm}$. The dielectric constant of the insulator is

1 6
2 8
3 5
4 4
Capacitance

165985 A parallel plate capacitor has a capacity $80 \times$ $10^{-6} \mathrm{~F}$, when air is present between its plates. The space between the plates is filled with a dielectric slab of dielectric constant 20 . The capacitor is now connected to a battery of $30 \mathrm{~V}$ by wires. The dielectric slab is then removed. Then, the charge passing through the wire is

1 $12 \times 10^{-3} \mathrm{C}$
2 $25.3 \times 10^{-3} \mathrm{C}$
3 $120 \times 10^{-3} \mathrm{C}$
4 $45.6 \times 10^{-3} \mathrm{C}$
Capacitance

165982 A capacitor is made of flat plate of area $A$ and a second plate of stair-like structure as sown in the figure. The area of each stair is $\frac{\mathrm{A}}{3}$ and the height is $d$. the capacitance of the arrangement is

1 $\frac{\varepsilon_{0} \mathrm{~A}}{3 \mathrm{~d}}$
2 $\frac{6 \varepsilon_{0} \mathrm{~A}}{11 \mathrm{~d}}$
3 $\frac{3 \varepsilon_{0} \mathrm{~A}}{\mathrm{~d}}$
4 $\frac{11 \varepsilon_{0} \mathrm{~A}}{18 \mathrm{~d}}$
Capacitance

165983 One plate of a parallel palate capacitor is connected to a spring as shown in the figure. The area of each plate of the capacitor is $A$ and the distance between the plate is $d$, when the battery is not connected and the spring is unscratched. After connecting the battery, in the steady state the distance between the plates is $0.75 \mathrm{~d}$, then the force constant of the spring is

1 $\frac{3}{8} \frac{\varepsilon_{0} \mathrm{~V}^{2} \mathrm{~A}}{\mathrm{~d}^{3}}$
2 $\frac{8}{3} \frac{\varepsilon_{0} \mathrm{~V}^{2} \mathrm{~A}}{\mathrm{~d}^{3}}$
3 $\frac{9}{32} \frac{\varepsilon_{0} \mathrm{~V}^{2} \mathrm{~A}}{\mathrm{~d}^{3}}$
4 $\frac{32}{9} \frac{\varepsilon_{0} \mathrm{~V}^{2} \mathrm{~A}}{\mathrm{~d}^{3}}$
Capacitance

165984 The plates of a parallel plate capacitor are charges upto $100 \mathrm{~V}$. A $2 \mathrm{~mm}$ thick insulator sheet is inserted between the plates. Then to maintain the same potential difference, the distance between the plates is increased by $\mathbf{1 . 6}$ $\mathrm{mm}$. The dielectric constant of the insulator is

1 6
2 8
3 5
4 4
Capacitance

165985 A parallel plate capacitor has a capacity $80 \times$ $10^{-6} \mathrm{~F}$, when air is present between its plates. The space between the plates is filled with a dielectric slab of dielectric constant 20 . The capacitor is now connected to a battery of $30 \mathrm{~V}$ by wires. The dielectric slab is then removed. Then, the charge passing through the wire is

1 $12 \times 10^{-3} \mathrm{C}$
2 $25.3 \times 10^{-3} \mathrm{C}$
3 $120 \times 10^{-3} \mathrm{C}$
4 $45.6 \times 10^{-3} \mathrm{C}$
Capacitance

165982 A capacitor is made of flat plate of area $A$ and a second plate of stair-like structure as sown in the figure. The area of each stair is $\frac{\mathrm{A}}{3}$ and the height is $d$. the capacitance of the arrangement is

1 $\frac{\varepsilon_{0} \mathrm{~A}}{3 \mathrm{~d}}$
2 $\frac{6 \varepsilon_{0} \mathrm{~A}}{11 \mathrm{~d}}$
3 $\frac{3 \varepsilon_{0} \mathrm{~A}}{\mathrm{~d}}$
4 $\frac{11 \varepsilon_{0} \mathrm{~A}}{18 \mathrm{~d}}$
Capacitance

165983 One plate of a parallel palate capacitor is connected to a spring as shown in the figure. The area of each plate of the capacitor is $A$ and the distance between the plate is $d$, when the battery is not connected and the spring is unscratched. After connecting the battery, in the steady state the distance between the plates is $0.75 \mathrm{~d}$, then the force constant of the spring is

1 $\frac{3}{8} \frac{\varepsilon_{0} \mathrm{~V}^{2} \mathrm{~A}}{\mathrm{~d}^{3}}$
2 $\frac{8}{3} \frac{\varepsilon_{0} \mathrm{~V}^{2} \mathrm{~A}}{\mathrm{~d}^{3}}$
3 $\frac{9}{32} \frac{\varepsilon_{0} \mathrm{~V}^{2} \mathrm{~A}}{\mathrm{~d}^{3}}$
4 $\frac{32}{9} \frac{\varepsilon_{0} \mathrm{~V}^{2} \mathrm{~A}}{\mathrm{~d}^{3}}$
Capacitance

165984 The plates of a parallel plate capacitor are charges upto $100 \mathrm{~V}$. A $2 \mathrm{~mm}$ thick insulator sheet is inserted between the plates. Then to maintain the same potential difference, the distance between the plates is increased by $\mathbf{1 . 6}$ $\mathrm{mm}$. The dielectric constant of the insulator is

1 6
2 8
3 5
4 4
Capacitance

165985 A parallel plate capacitor has a capacity $80 \times$ $10^{-6} \mathrm{~F}$, when air is present between its plates. The space between the plates is filled with a dielectric slab of dielectric constant 20 . The capacitor is now connected to a battery of $30 \mathrm{~V}$ by wires. The dielectric slab is then removed. Then, the charge passing through the wire is

1 $12 \times 10^{-3} \mathrm{C}$
2 $25.3 \times 10^{-3} \mathrm{C}$
3 $120 \times 10^{-3} \mathrm{C}$
4 $45.6 \times 10^{-3} \mathrm{C}$
Capacitance

165982 A capacitor is made of flat plate of area $A$ and a second plate of stair-like structure as sown in the figure. The area of each stair is $\frac{\mathrm{A}}{3}$ and the height is $d$. the capacitance of the arrangement is

1 $\frac{\varepsilon_{0} \mathrm{~A}}{3 \mathrm{~d}}$
2 $\frac{6 \varepsilon_{0} \mathrm{~A}}{11 \mathrm{~d}}$
3 $\frac{3 \varepsilon_{0} \mathrm{~A}}{\mathrm{~d}}$
4 $\frac{11 \varepsilon_{0} \mathrm{~A}}{18 \mathrm{~d}}$
Capacitance

165983 One plate of a parallel palate capacitor is connected to a spring as shown in the figure. The area of each plate of the capacitor is $A$ and the distance between the plate is $d$, when the battery is not connected and the spring is unscratched. After connecting the battery, in the steady state the distance between the plates is $0.75 \mathrm{~d}$, then the force constant of the spring is

1 $\frac{3}{8} \frac{\varepsilon_{0} \mathrm{~V}^{2} \mathrm{~A}}{\mathrm{~d}^{3}}$
2 $\frac{8}{3} \frac{\varepsilon_{0} \mathrm{~V}^{2} \mathrm{~A}}{\mathrm{~d}^{3}}$
3 $\frac{9}{32} \frac{\varepsilon_{0} \mathrm{~V}^{2} \mathrm{~A}}{\mathrm{~d}^{3}}$
4 $\frac{32}{9} \frac{\varepsilon_{0} \mathrm{~V}^{2} \mathrm{~A}}{\mathrm{~d}^{3}}$
Capacitance

165984 The plates of a parallel plate capacitor are charges upto $100 \mathrm{~V}$. A $2 \mathrm{~mm}$ thick insulator sheet is inserted between the plates. Then to maintain the same potential difference, the distance between the plates is increased by $\mathbf{1 . 6}$ $\mathrm{mm}$. The dielectric constant of the insulator is

1 6
2 8
3 5
4 4
Capacitance

165985 A parallel plate capacitor has a capacity $80 \times$ $10^{-6} \mathrm{~F}$, when air is present between its plates. The space between the plates is filled with a dielectric slab of dielectric constant 20 . The capacitor is now connected to a battery of $30 \mathrm{~V}$ by wires. The dielectric slab is then removed. Then, the charge passing through the wire is

1 $12 \times 10^{-3} \mathrm{C}$
2 $25.3 \times 10^{-3} \mathrm{C}$
3 $120 \times 10^{-3} \mathrm{C}$
4 $45.6 \times 10^{-3} \mathrm{C}$