Effect of Dielectric Charging and Discharging of Capacitor
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NEET DIGITAL LIBRARY
Capacitance

165977 The dielectric constant of air is

1 $8.9 \times 10^{-12} \mathrm{C}^{2} \mathrm{~N}^{-1} \mathrm{~m}^{-2}$
2 1
3 infinite
4 None of these
[CG PET- 2012]
Capacitance

165978 Calculate the area of the plates of a one farad parallel plate capacitor if separation between plates is $1 \mathrm{~mm}$ and plates are in vacuum

1 $18 \times 10^{8} \mathrm{~m}^{2}$
2 $0.3 \times 10^{8} \mathrm{~m}^{2}$
3 $1.3 \times 10^{8} \mathrm{~m}^{2}$
4 $1.13 \times 10^{8} \mathrm{~m}^{2}$
[BITSAT-2009]
Capacitance

165979 The capacity of parallel plate condenser is $5 \mu \mathrm{F}$. When a glass plate is placed between the plates of the condenser, its potential difference reduces of $1 / 8$ of the original value. The magnitude of relative dielectric constant of glass is

1 4
2 6
3 7
4 8
[AP EAMCET (22.09.2020) Shift-II]
Capacitance

165981 In a parallel plate capacitor the separation between plates is $3 x$. This separation is filled by two layers of dielectrics, in which one layer has thickness $x$ and dielectric constant $3 k$, the other layer is of thickness $2 x$ and dielectric constant $5 \mathrm{k}$. If the plates of the capacitor are connected to a battery, then the ratio of potential difference across the dielectric layers is

1 $\frac{1}{2}$
2 $\frac{4}{3}$
3 $\frac{3}{5}$
4 $\frac{5}{6}$
[AP EAMCET (21.04.2019) Shift-I]
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Capacitance

165977 The dielectric constant of air is

1 $8.9 \times 10^{-12} \mathrm{C}^{2} \mathrm{~N}^{-1} \mathrm{~m}^{-2}$
2 1
3 infinite
4 None of these
[CG PET- 2012]
Capacitance

165978 Calculate the area of the plates of a one farad parallel plate capacitor if separation between plates is $1 \mathrm{~mm}$ and plates are in vacuum

1 $18 \times 10^{8} \mathrm{~m}^{2}$
2 $0.3 \times 10^{8} \mathrm{~m}^{2}$
3 $1.3 \times 10^{8} \mathrm{~m}^{2}$
4 $1.13 \times 10^{8} \mathrm{~m}^{2}$
[BITSAT-2009]
Capacitance

165979 The capacity of parallel plate condenser is $5 \mu \mathrm{F}$. When a glass plate is placed between the plates of the condenser, its potential difference reduces of $1 / 8$ of the original value. The magnitude of relative dielectric constant of glass is

1 4
2 6
3 7
4 8
[AP EAMCET (22.09.2020) Shift-II]
Capacitance

165981 In a parallel plate capacitor the separation between plates is $3 x$. This separation is filled by two layers of dielectrics, in which one layer has thickness $x$ and dielectric constant $3 k$, the other layer is of thickness $2 x$ and dielectric constant $5 \mathrm{k}$. If the plates of the capacitor are connected to a battery, then the ratio of potential difference across the dielectric layers is

1 $\frac{1}{2}$
2 $\frac{4}{3}$
3 $\frac{3}{5}$
4 $\frac{5}{6}$
[AP EAMCET (21.04.2019) Shift-I]
For More Updates join with Us
Capacitance

165977 The dielectric constant of air is

1 $8.9 \times 10^{-12} \mathrm{C}^{2} \mathrm{~N}^{-1} \mathrm{~m}^{-2}$
2 1
3 infinite
4 None of these
[CG PET- 2012]
Capacitance

165978 Calculate the area of the plates of a one farad parallel plate capacitor if separation between plates is $1 \mathrm{~mm}$ and plates are in vacuum

1 $18 \times 10^{8} \mathrm{~m}^{2}$
2 $0.3 \times 10^{8} \mathrm{~m}^{2}$
3 $1.3 \times 10^{8} \mathrm{~m}^{2}$
4 $1.13 \times 10^{8} \mathrm{~m}^{2}$
[BITSAT-2009]
Capacitance

165979 The capacity of parallel plate condenser is $5 \mu \mathrm{F}$. When a glass plate is placed between the plates of the condenser, its potential difference reduces of $1 / 8$ of the original value. The magnitude of relative dielectric constant of glass is

1 4
2 6
3 7
4 8
[AP EAMCET (22.09.2020) Shift-II]
Capacitance

165981 In a parallel plate capacitor the separation between plates is $3 x$. This separation is filled by two layers of dielectrics, in which one layer has thickness $x$ and dielectric constant $3 k$, the other layer is of thickness $2 x$ and dielectric constant $5 \mathrm{k}$. If the plates of the capacitor are connected to a battery, then the ratio of potential difference across the dielectric layers is

1 $\frac{1}{2}$
2 $\frac{4}{3}$
3 $\frac{3}{5}$
4 $\frac{5}{6}$
[AP EAMCET (21.04.2019) Shift-I]
NEET DIGITAL LIBRARY
Capacitance

165977 The dielectric constant of air is

1 $8.9 \times 10^{-12} \mathrm{C}^{2} \mathrm{~N}^{-1} \mathrm{~m}^{-2}$
2 1
3 infinite
4 None of these
[CG PET- 2012]
Capacitance

165978 Calculate the area of the plates of a one farad parallel plate capacitor if separation between plates is $1 \mathrm{~mm}$ and plates are in vacuum

1 $18 \times 10^{8} \mathrm{~m}^{2}$
2 $0.3 \times 10^{8} \mathrm{~m}^{2}$
3 $1.3 \times 10^{8} \mathrm{~m}^{2}$
4 $1.13 \times 10^{8} \mathrm{~m}^{2}$
[BITSAT-2009]
Capacitance

165979 The capacity of parallel plate condenser is $5 \mu \mathrm{F}$. When a glass plate is placed between the plates of the condenser, its potential difference reduces of $1 / 8$ of the original value. The magnitude of relative dielectric constant of glass is

1 4
2 6
3 7
4 8
[AP EAMCET (22.09.2020) Shift-II]
Capacitance

165981 In a parallel plate capacitor the separation between plates is $3 x$. This separation is filled by two layers of dielectrics, in which one layer has thickness $x$ and dielectric constant $3 k$, the other layer is of thickness $2 x$ and dielectric constant $5 \mathrm{k}$. If the plates of the capacitor are connected to a battery, then the ratio of potential difference across the dielectric layers is

1 $\frac{1}{2}$
2 $\frac{4}{3}$
3 $\frac{3}{5}$
4 $\frac{5}{6}$
[AP EAMCET (21.04.2019) Shift-I]
Join With Us for More Updates