Energy Stored in Capacitor
Capacitance

165709 If the potential of a capacitor having capacity 6 $\mu \mathrm{F}$ is increased from $10 \mathrm{~V}$ to $20 \mathrm{~V}$, then increase in its energy will be

1 $4 \times 10^{-4} \mathrm{~J}$
2 $4 \times 10^{-6} \mathrm{~J}$
3 $9 \times 10^{-4} \mathrm{~J}$
4 $12 \times 10^{-6} \mathrm{~J}$
Capacitance

165710 Two identical capacitors, have the same capacitance $C$. One of them is charged to potential $V_{1}$ and the other to $V_{2}$. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is-

1 $\frac{1}{4} \mathrm{C}\left(\mathrm{V}_{1}^{2}-\mathrm{V}_{2}^{2}\right)$
2 $\frac{1}{4} \mathrm{C}\left(\mathrm{V}_{1}^{2}+\mathrm{V}_{2}^{2}\right)$
3 $\frac{1}{4} \mathrm{C}\left(\mathrm{V}_{1}-\mathrm{V}_{2}\right)^{2}$
4 $\frac{1}{4} \mathrm{C}\left(\mathrm{V}_{1}+\mathrm{V}_{2}\right)^{2}$
Capacitance

165711 A parallel plate capacitor of capacitance $C$ is connected to a battery and is charged to a potential difference $V$. Another capacitor of capacitance $2 \mathrm{C}$ is similarly charge to a potential difference $2 \mathrm{~V}$. The charging battery is now disconnected and the capacitors are connected in parallel to each other in such a way that the positive terminal of one is connected to the negative terminal of the other. The final energy of the configuration is

1 Zero
2 $\frac{3}{2} \mathrm{CV}^{2}$
3 $\frac{25}{6} \mathrm{CV}^{2}$
4 $\frac{9}{2} \mathrm{CV}^{2}$
Capacitance

165712 A $100 \mathrm{~V}$ battery is connected across the series combination of the two capacitors of $4 \mu \mathrm{F}$ and $8 \mu \mathrm{F}$. The energy stored in the series combination is

1 $0.75 \times 10^{-2} \mathrm{~J}$
2 $1.33 \times 10^{-2} \mathrm{~J}$
3 $0.5 \mathrm{~J}$
4 $1 \mathrm{~J}$
Capacitance

165709 If the potential of a capacitor having capacity 6 $\mu \mathrm{F}$ is increased from $10 \mathrm{~V}$ to $20 \mathrm{~V}$, then increase in its energy will be

1 $4 \times 10^{-4} \mathrm{~J}$
2 $4 \times 10^{-6} \mathrm{~J}$
3 $9 \times 10^{-4} \mathrm{~J}$
4 $12 \times 10^{-6} \mathrm{~J}$
Capacitance

165710 Two identical capacitors, have the same capacitance $C$. One of them is charged to potential $V_{1}$ and the other to $V_{2}$. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is-

1 $\frac{1}{4} \mathrm{C}\left(\mathrm{V}_{1}^{2}-\mathrm{V}_{2}^{2}\right)$
2 $\frac{1}{4} \mathrm{C}\left(\mathrm{V}_{1}^{2}+\mathrm{V}_{2}^{2}\right)$
3 $\frac{1}{4} \mathrm{C}\left(\mathrm{V}_{1}-\mathrm{V}_{2}\right)^{2}$
4 $\frac{1}{4} \mathrm{C}\left(\mathrm{V}_{1}+\mathrm{V}_{2}\right)^{2}$
Capacitance

165711 A parallel plate capacitor of capacitance $C$ is connected to a battery and is charged to a potential difference $V$. Another capacitor of capacitance $2 \mathrm{C}$ is similarly charge to a potential difference $2 \mathrm{~V}$. The charging battery is now disconnected and the capacitors are connected in parallel to each other in such a way that the positive terminal of one is connected to the negative terminal of the other. The final energy of the configuration is

1 Zero
2 $\frac{3}{2} \mathrm{CV}^{2}$
3 $\frac{25}{6} \mathrm{CV}^{2}$
4 $\frac{9}{2} \mathrm{CV}^{2}$
Capacitance

165712 A $100 \mathrm{~V}$ battery is connected across the series combination of the two capacitors of $4 \mu \mathrm{F}$ and $8 \mu \mathrm{F}$. The energy stored in the series combination is

1 $0.75 \times 10^{-2} \mathrm{~J}$
2 $1.33 \times 10^{-2} \mathrm{~J}$
3 $0.5 \mathrm{~J}$
4 $1 \mathrm{~J}$
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Capacitance

165709 If the potential of a capacitor having capacity 6 $\mu \mathrm{F}$ is increased from $10 \mathrm{~V}$ to $20 \mathrm{~V}$, then increase in its energy will be

1 $4 \times 10^{-4} \mathrm{~J}$
2 $4 \times 10^{-6} \mathrm{~J}$
3 $9 \times 10^{-4} \mathrm{~J}$
4 $12 \times 10^{-6} \mathrm{~J}$
Capacitance

165710 Two identical capacitors, have the same capacitance $C$. One of them is charged to potential $V_{1}$ and the other to $V_{2}$. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is-

1 $\frac{1}{4} \mathrm{C}\left(\mathrm{V}_{1}^{2}-\mathrm{V}_{2}^{2}\right)$
2 $\frac{1}{4} \mathrm{C}\left(\mathrm{V}_{1}^{2}+\mathrm{V}_{2}^{2}\right)$
3 $\frac{1}{4} \mathrm{C}\left(\mathrm{V}_{1}-\mathrm{V}_{2}\right)^{2}$
4 $\frac{1}{4} \mathrm{C}\left(\mathrm{V}_{1}+\mathrm{V}_{2}\right)^{2}$
Capacitance

165711 A parallel plate capacitor of capacitance $C$ is connected to a battery and is charged to a potential difference $V$. Another capacitor of capacitance $2 \mathrm{C}$ is similarly charge to a potential difference $2 \mathrm{~V}$. The charging battery is now disconnected and the capacitors are connected in parallel to each other in such a way that the positive terminal of one is connected to the negative terminal of the other. The final energy of the configuration is

1 Zero
2 $\frac{3}{2} \mathrm{CV}^{2}$
3 $\frac{25}{6} \mathrm{CV}^{2}$
4 $\frac{9}{2} \mathrm{CV}^{2}$
Capacitance

165712 A $100 \mathrm{~V}$ battery is connected across the series combination of the two capacitors of $4 \mu \mathrm{F}$ and $8 \mu \mathrm{F}$. The energy stored in the series combination is

1 $0.75 \times 10^{-2} \mathrm{~J}$
2 $1.33 \times 10^{-2} \mathrm{~J}$
3 $0.5 \mathrm{~J}$
4 $1 \mathrm{~J}$
Capacitance

165709 If the potential of a capacitor having capacity 6 $\mu \mathrm{F}$ is increased from $10 \mathrm{~V}$ to $20 \mathrm{~V}$, then increase in its energy will be

1 $4 \times 10^{-4} \mathrm{~J}$
2 $4 \times 10^{-6} \mathrm{~J}$
3 $9 \times 10^{-4} \mathrm{~J}$
4 $12 \times 10^{-6} \mathrm{~J}$
Capacitance

165710 Two identical capacitors, have the same capacitance $C$. One of them is charged to potential $V_{1}$ and the other to $V_{2}$. The negative ends of the capacitors are connected together. When the positive ends are also connected, the decrease in energy of the combined system is-

1 $\frac{1}{4} \mathrm{C}\left(\mathrm{V}_{1}^{2}-\mathrm{V}_{2}^{2}\right)$
2 $\frac{1}{4} \mathrm{C}\left(\mathrm{V}_{1}^{2}+\mathrm{V}_{2}^{2}\right)$
3 $\frac{1}{4} \mathrm{C}\left(\mathrm{V}_{1}-\mathrm{V}_{2}\right)^{2}$
4 $\frac{1}{4} \mathrm{C}\left(\mathrm{V}_{1}+\mathrm{V}_{2}\right)^{2}$
Capacitance

165711 A parallel plate capacitor of capacitance $C$ is connected to a battery and is charged to a potential difference $V$. Another capacitor of capacitance $2 \mathrm{C}$ is similarly charge to a potential difference $2 \mathrm{~V}$. The charging battery is now disconnected and the capacitors are connected in parallel to each other in such a way that the positive terminal of one is connected to the negative terminal of the other. The final energy of the configuration is

1 Zero
2 $\frac{3}{2} \mathrm{CV}^{2}$
3 $\frac{25}{6} \mathrm{CV}^{2}$
4 $\frac{9}{2} \mathrm{CV}^{2}$
Capacitance

165712 A $100 \mathrm{~V}$ battery is connected across the series combination of the two capacitors of $4 \mu \mathrm{F}$ and $8 \mu \mathrm{F}$. The energy stored in the series combination is

1 $0.75 \times 10^{-2} \mathrm{~J}$
2 $1.33 \times 10^{-2} \mathrm{~J}$
3 $0.5 \mathrm{~J}$
4 $1 \mathrm{~J}$