165666 A force of $10 \mathrm{~N}$ acts on a charged particle placed between two plates of a charged capacitor. If one plate of capacitor is removed, then the force acting on that particle will be

165667 Two metallic plates form a parallel plate capacitor. The distance between the plate is ' $d$ '. A metal sheet of thickness $\frac{d}{2}$ and of area equal to area of each plate is introduced between the plates. What will be the ratio of the new capacitance to the original capacitance of the capacitor?

165668 A parallel plate air capacitor has a capacitance of $8 \mathrm{pF}$. If the separation between the plates is reduced by half and the space is filled up with a material of dielectric constant 6 , then its capacitance will be.

165669 Three infinite long plane sheets of uniform charge densities $\sigma_{1}=-5 \sigma, \sigma_{2}=+2 \sigma \quad$ and $\sigma_{1}=3 \sigma$ are placed parallel to each other as shown in the figure. The electric field at point $P$ will be

165666 A force of $10 \mathrm{~N}$ acts on a charged particle placed between two plates of a charged capacitor. If one plate of capacitor is removed, then the force acting on that particle will be

165667 Two metallic plates form a parallel plate capacitor. The distance between the plate is ' $d$ '. A metal sheet of thickness $\frac{d}{2}$ and of area equal to area of each plate is introduced between the plates. What will be the ratio of the new capacitance to the original capacitance of the capacitor?

165668 A parallel plate air capacitor has a capacitance of $8 \mathrm{pF}$. If the separation between the plates is reduced by half and the space is filled up with a material of dielectric constant 6 , then its capacitance will be.

165669 Three infinite long plane sheets of uniform charge densities $\sigma_{1}=-5 \sigma, \sigma_{2}=+2 \sigma \quad$ and $\sigma_{1}=3 \sigma$ are placed parallel to each other as shown in the figure. The electric field at point $P$ will be

165666 A force of $10 \mathrm{~N}$ acts on a charged particle placed between two plates of a charged capacitor. If one plate of capacitor is removed, then the force acting on that particle will be

165667 Two metallic plates form a parallel plate capacitor. The distance between the plate is ' $d$ '. A metal sheet of thickness $\frac{d}{2}$ and of area equal to area of each plate is introduced between the plates. What will be the ratio of the new capacitance to the original capacitance of the capacitor?

165668 A parallel plate air capacitor has a capacitance of $8 \mathrm{pF}$. If the separation between the plates is reduced by half and the space is filled up with a material of dielectric constant 6 , then its capacitance will be.

165669 Three infinite long plane sheets of uniform charge densities $\sigma_{1}=-5 \sigma, \sigma_{2}=+2 \sigma \quad$ and $\sigma_{1}=3 \sigma$ are placed parallel to each other as shown in the figure. The electric field at point $P$ will be

165666 A force of $10 \mathrm{~N}$ acts on a charged particle placed between two plates of a charged capacitor. If one plate of capacitor is removed, then the force acting on that particle will be

165667 Two metallic plates form a parallel plate capacitor. The distance between the plate is ' $d$ '. A metal sheet of thickness $\frac{d}{2}$ and of area equal to area of each plate is introduced between the plates. What will be the ratio of the new capacitance to the original capacitance of the capacitor?

165668 A parallel plate air capacitor has a capacitance of $8 \mathrm{pF}$. If the separation between the plates is reduced by half and the space is filled up with a material of dielectric constant 6 , then its capacitance will be.

165669 Three infinite long plane sheets of uniform charge densities $\sigma_{1}=-5 \sigma, \sigma_{2}=+2 \sigma \quad$ and $\sigma_{1}=3 \sigma$ are placed parallel to each other as shown in the figure. The electric field at point $P$ will be