165665
A slab of dielectric constant $K$ has the same cross-sectional area as the plates of a parallel plate capacitor and thickness $\frac{3}{4} \mathrm{~d}$, where $\mathbf{d}$ is the separation of the plates. The capacitance of the capacitor when the slab is inserted between the plates will be:
(Given $\mathrm{C}_{0}=$ capacitance of capacitor with air as medium between plates.)
165665
A slab of dielectric constant $K$ has the same cross-sectional area as the plates of a parallel plate capacitor and thickness $\frac{3}{4} \mathrm{~d}$, where $\mathbf{d}$ is the separation of the plates. The capacitance of the capacitor when the slab is inserted between the plates will be:
(Given $\mathrm{C}_{0}=$ capacitance of capacitor with air as medium between plates.)
165665
A slab of dielectric constant $K$ has the same cross-sectional area as the plates of a parallel plate capacitor and thickness $\frac{3}{4} \mathrm{~d}$, where $\mathbf{d}$ is the separation of the plates. The capacitance of the capacitor when the slab is inserted between the plates will be:
(Given $\mathrm{C}_{0}=$ capacitance of capacitor with air as medium between plates.)
165665
A slab of dielectric constant $K$ has the same cross-sectional area as the plates of a parallel plate capacitor and thickness $\frac{3}{4} \mathrm{~d}$, where $\mathbf{d}$ is the separation of the plates. The capacitance of the capacitor when the slab is inserted between the plates will be:
(Given $\mathrm{C}_{0}=$ capacitance of capacitor with air as medium between plates.)