Capacitance
Capacitance

165601 Capacity of parallel plate capacitor is $10 \mu \mathrm{F}$, when gap between plates is $8 \mathrm{~cm}$, then what will be its capacity if gap is reduced to $4 \mathrm{~cm}$ ?

1 $10 \mu \mathrm{F}$
2 $40 \mu \mathrm{F}$
3 $20 \mu \mathrm{F}$
4 $30 \mu \mathrm{F}$
Capacitance

165602 Two metal spheres of capacitance $C_{1}$ and $C_{2}$ carry some charges. They are put in contact and then separated. The final charges $Q_{1}$ and $Q_{2}$ on them will satisfy

1 $\frac{Q_{1}}{Q_{2}}<\frac{C_{1}}{C_{2}}$
2 $\frac{\mathrm{Q}_{1}}{\mathrm{Q}_{2}}=\frac{\mathrm{C}_{1}}{\mathrm{C}_{2}}$
3 $\frac{Q_{1}}{Q_{2}}>\frac{C_{1}}{C_{2}}$
4 $\frac{\mathrm{Q}_{1}}{\mathrm{Q}_{2}}=\frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}$
Capacitance

165603 A parallel plate capacitor with air between the plates has a capacitance of $9 \mathrm{pF}$. The separation between the plates is $d$. The space between the plates is now filled with two dielectrics constant $K_{1}=3$ and thickness $d / 3$ while the other one has dielectric constant $K_{2}=$ 6 and thickness 2d/3. Capacitance of the capacitor is now

1 $1.8 \mathrm{pF}$
2 $45 \mathrm{pF}$
3 $40.5 \mathrm{pF}$
4 $20.25 \mathrm{pF}$
Capacitance

165604 Two metal plates having potential difference of $800 \mathrm{~V}$ are $2 \mathrm{~cm}$ apart. It is found that a particle of mass $1.96 \times 10^{-15} \mathrm{~kg}$ remains suspended in the region between the plates. The charge on the particle must be ( $e=$ elementary charge)

1 $2 \mathrm{e}$
2 $3 \mathrm{e}$
3 $6 \mathrm{e}$
4 $8 \mathrm{e}$
Capacitance

165601 Capacity of parallel plate capacitor is $10 \mu \mathrm{F}$, when gap between plates is $8 \mathrm{~cm}$, then what will be its capacity if gap is reduced to $4 \mathrm{~cm}$ ?

1 $10 \mu \mathrm{F}$
2 $40 \mu \mathrm{F}$
3 $20 \mu \mathrm{F}$
4 $30 \mu \mathrm{F}$
Capacitance

165602 Two metal spheres of capacitance $C_{1}$ and $C_{2}$ carry some charges. They are put in contact and then separated. The final charges $Q_{1}$ and $Q_{2}$ on them will satisfy

1 $\frac{Q_{1}}{Q_{2}}<\frac{C_{1}}{C_{2}}$
2 $\frac{\mathrm{Q}_{1}}{\mathrm{Q}_{2}}=\frac{\mathrm{C}_{1}}{\mathrm{C}_{2}}$
3 $\frac{Q_{1}}{Q_{2}}>\frac{C_{1}}{C_{2}}$
4 $\frac{\mathrm{Q}_{1}}{\mathrm{Q}_{2}}=\frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}$
Capacitance

165603 A parallel plate capacitor with air between the plates has a capacitance of $9 \mathrm{pF}$. The separation between the plates is $d$. The space between the plates is now filled with two dielectrics constant $K_{1}=3$ and thickness $d / 3$ while the other one has dielectric constant $K_{2}=$ 6 and thickness 2d/3. Capacitance of the capacitor is now

1 $1.8 \mathrm{pF}$
2 $45 \mathrm{pF}$
3 $40.5 \mathrm{pF}$
4 $20.25 \mathrm{pF}$
Capacitance

165604 Two metal plates having potential difference of $800 \mathrm{~V}$ are $2 \mathrm{~cm}$ apart. It is found that a particle of mass $1.96 \times 10^{-15} \mathrm{~kg}$ remains suspended in the region between the plates. The charge on the particle must be ( $e=$ elementary charge)

1 $2 \mathrm{e}$
2 $3 \mathrm{e}$
3 $6 \mathrm{e}$
4 $8 \mathrm{e}$
Capacitance

165601 Capacity of parallel plate capacitor is $10 \mu \mathrm{F}$, when gap between plates is $8 \mathrm{~cm}$, then what will be its capacity if gap is reduced to $4 \mathrm{~cm}$ ?

1 $10 \mu \mathrm{F}$
2 $40 \mu \mathrm{F}$
3 $20 \mu \mathrm{F}$
4 $30 \mu \mathrm{F}$
Capacitance

165602 Two metal spheres of capacitance $C_{1}$ and $C_{2}$ carry some charges. They are put in contact and then separated. The final charges $Q_{1}$ and $Q_{2}$ on them will satisfy

1 $\frac{Q_{1}}{Q_{2}}<\frac{C_{1}}{C_{2}}$
2 $\frac{\mathrm{Q}_{1}}{\mathrm{Q}_{2}}=\frac{\mathrm{C}_{1}}{\mathrm{C}_{2}}$
3 $\frac{Q_{1}}{Q_{2}}>\frac{C_{1}}{C_{2}}$
4 $\frac{\mathrm{Q}_{1}}{\mathrm{Q}_{2}}=\frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}$
Capacitance

165603 A parallel plate capacitor with air between the plates has a capacitance of $9 \mathrm{pF}$. The separation between the plates is $d$. The space between the plates is now filled with two dielectrics constant $K_{1}=3$ and thickness $d / 3$ while the other one has dielectric constant $K_{2}=$ 6 and thickness 2d/3. Capacitance of the capacitor is now

1 $1.8 \mathrm{pF}$
2 $45 \mathrm{pF}$
3 $40.5 \mathrm{pF}$
4 $20.25 \mathrm{pF}$
Capacitance

165604 Two metal plates having potential difference of $800 \mathrm{~V}$ are $2 \mathrm{~cm}$ apart. It is found that a particle of mass $1.96 \times 10^{-15} \mathrm{~kg}$ remains suspended in the region between the plates. The charge on the particle must be ( $e=$ elementary charge)

1 $2 \mathrm{e}$
2 $3 \mathrm{e}$
3 $6 \mathrm{e}$
4 $8 \mathrm{e}$
Capacitance

165601 Capacity of parallel plate capacitor is $10 \mu \mathrm{F}$, when gap between plates is $8 \mathrm{~cm}$, then what will be its capacity if gap is reduced to $4 \mathrm{~cm}$ ?

1 $10 \mu \mathrm{F}$
2 $40 \mu \mathrm{F}$
3 $20 \mu \mathrm{F}$
4 $30 \mu \mathrm{F}$
Capacitance

165602 Two metal spheres of capacitance $C_{1}$ and $C_{2}$ carry some charges. They are put in contact and then separated. The final charges $Q_{1}$ and $Q_{2}$ on them will satisfy

1 $\frac{Q_{1}}{Q_{2}}<\frac{C_{1}}{C_{2}}$
2 $\frac{\mathrm{Q}_{1}}{\mathrm{Q}_{2}}=\frac{\mathrm{C}_{1}}{\mathrm{C}_{2}}$
3 $\frac{Q_{1}}{Q_{2}}>\frac{C_{1}}{C_{2}}$
4 $\frac{\mathrm{Q}_{1}}{\mathrm{Q}_{2}}=\frac{\mathrm{C}_{2}}{\mathrm{C}_{1}}$
Capacitance

165603 A parallel plate capacitor with air between the plates has a capacitance of $9 \mathrm{pF}$. The separation between the plates is $d$. The space between the plates is now filled with two dielectrics constant $K_{1}=3$ and thickness $d / 3$ while the other one has dielectric constant $K_{2}=$ 6 and thickness 2d/3. Capacitance of the capacitor is now

1 $1.8 \mathrm{pF}$
2 $45 \mathrm{pF}$
3 $40.5 \mathrm{pF}$
4 $20.25 \mathrm{pF}$
Capacitance

165604 Two metal plates having potential difference of $800 \mathrm{~V}$ are $2 \mathrm{~cm}$ apart. It is found that a particle of mass $1.96 \times 10^{-15} \mathrm{~kg}$ remains suspended in the region between the plates. The charge on the particle must be ( $e=$ elementary charge)

1 $2 \mathrm{e}$
2 $3 \mathrm{e}$
3 $6 \mathrm{e}$
4 $8 \mathrm{e}$