NEET Test Series from KOTA - 10 Papers In MS WORD
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WAVES
172199
Assertion: Solids can support both longitudinal and transverse waved but only longitudinal waves can propagate in gases Reason: For the propagation of transverse waves, medium must also necessarily have the property of rigidity.
1 If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
A For the propagation of transverse waves, medium must have the property of rigidity. Because gases have no rigidity, (they do not possess shear elasticity), hence transverse waves cannot be produced is gases. On the other hand, the solids possess both volume and shear elasticity and likewise both the longitudinal and transverse waves can be transmitted through them.
AIIMS-26.05.2018(M)
WAVES
172198
The displacement of a wave is given by $\mathbf{y}=$ $0.001 \sin (100 t+x)$ where $x$ and $y$ are in meter and $t$ is in second. This represents a wave
1 Of Wavelength one meter
2 Travelling with a velocity of $100 \mathrm{~m} / \mathrm{s}$ in the negative $\mathrm{x}$-direction
3 Of frequency $\frac{100}{\pi} \mathrm{Hz}$
4 Travelling with a velocity of $\frac{50}{\pi} \mathrm{m} / \mathrm{s}$ in the positive $\mathrm{x}$-direction
Explanation:
B Given, $y=0.001 \sin (100 t+x)$ Comparing with $\mathrm{y}=\mathrm{a} \sin (\omega \mathrm{t}+\mathrm{kx})$ $\omega=100, \mathrm{k}=1$ $2 \pi \mathrm{f}=100, \quad \mathrm{f}=\frac{50}{\pi} \mathrm{Hz}$ Velocity $(v)=\frac{\omega}{\mathrm{k}}=\frac{100}{1}=100 \mathrm{~m} / \mathrm{s}$ Since, positive sign between $\mathrm{x}$ and $\mathrm{t}$ terms so, wave is travelling in negative $\mathrm{x}$-direction.
COMEDK 2018
WAVES
172200
A progressive wave of frequency $500 \mathrm{~Hz}$ is travelling with a velocity of $360 \mathrm{~ms}^{-1}$. The distance between the two points, having a phase difference of $60^{\circ}$ is
1 $1.2 \mathrm{~m}$
2 $12 \mathrm{~m}$
3 $0.12 \mathrm{~m}$
4 $0.012 \mathrm{~m}$
Explanation:
C Given that, $\mathrm{f}=500 \mathrm{~Hz}, \mathrm{v}=360 \mathrm{~ms}^{-1}$ We know, $\quad \lambda=\frac{\mathrm{v}}{\mathrm{f}}=\frac{360}{500}$ Now, a phase difference of $60^{\circ}$ corresponds to a path difference of $\frac{60}{360} \times \lambda$ So, distance between 2 particles is $\mathrm{d}=\frac{60}{360} \times \lambda=\frac{60}{360} \times \frac{360}{500}=0.12 \mathrm{~m}$
AP EAMCET (23.04.2018) Shift-2
WAVES
172202
A motion is described by $y=4 \mathrm{e}^{x}\left(\mathrm{e}^{-5 t}\right)$, where $y$, $x$ are in metres and $t$ is in second.
1 This represents progressive wave propagating along - x-direction with $5 \mathrm{~m} / \mathrm{s}$
2 This represents progressive wave propagating along $+\mathrm{x}$-direction with $5 \mathrm{~m} / \mathrm{s}$
3 This does not represent progressive wave
4 This represents standing wave
Explanation:
B Given, $y=4 \mathrm{e}^{\mathrm{x}}\left(\mathrm{e}^{-5 \mathrm{t}}\right)$ $=4 \mathrm{e}^{\mathrm{x}-5 \mathrm{t}}$ Since, It is a form of $\mathrm{y}=f(\mathrm{ax} \pm \mathrm{bt})$ So, it represent a progressive wave, propagating in positive $\mathrm{X}$-axis direction because coefficient of $\mathrm{x}$ and coefficient of thave opposite sign. So, Speed of a wave $(\mathrm{v})=\frac{\text { coefficient of } \mathrm{t}}{\text { coefficient of } \mathrm{x}}=\frac{5}{1}=5 \mathrm{~m} / \mathrm{s}$
172199
Assertion: Solids can support both longitudinal and transverse waved but only longitudinal waves can propagate in gases Reason: For the propagation of transverse waves, medium must also necessarily have the property of rigidity.
1 If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
A For the propagation of transverse waves, medium must have the property of rigidity. Because gases have no rigidity, (they do not possess shear elasticity), hence transverse waves cannot be produced is gases. On the other hand, the solids possess both volume and shear elasticity and likewise both the longitudinal and transverse waves can be transmitted through them.
AIIMS-26.05.2018(M)
WAVES
172198
The displacement of a wave is given by $\mathbf{y}=$ $0.001 \sin (100 t+x)$ where $x$ and $y$ are in meter and $t$ is in second. This represents a wave
1 Of Wavelength one meter
2 Travelling with a velocity of $100 \mathrm{~m} / \mathrm{s}$ in the negative $\mathrm{x}$-direction
3 Of frequency $\frac{100}{\pi} \mathrm{Hz}$
4 Travelling with a velocity of $\frac{50}{\pi} \mathrm{m} / \mathrm{s}$ in the positive $\mathrm{x}$-direction
Explanation:
B Given, $y=0.001 \sin (100 t+x)$ Comparing with $\mathrm{y}=\mathrm{a} \sin (\omega \mathrm{t}+\mathrm{kx})$ $\omega=100, \mathrm{k}=1$ $2 \pi \mathrm{f}=100, \quad \mathrm{f}=\frac{50}{\pi} \mathrm{Hz}$ Velocity $(v)=\frac{\omega}{\mathrm{k}}=\frac{100}{1}=100 \mathrm{~m} / \mathrm{s}$ Since, positive sign between $\mathrm{x}$ and $\mathrm{t}$ terms so, wave is travelling in negative $\mathrm{x}$-direction.
COMEDK 2018
WAVES
172200
A progressive wave of frequency $500 \mathrm{~Hz}$ is travelling with a velocity of $360 \mathrm{~ms}^{-1}$. The distance between the two points, having a phase difference of $60^{\circ}$ is
1 $1.2 \mathrm{~m}$
2 $12 \mathrm{~m}$
3 $0.12 \mathrm{~m}$
4 $0.012 \mathrm{~m}$
Explanation:
C Given that, $\mathrm{f}=500 \mathrm{~Hz}, \mathrm{v}=360 \mathrm{~ms}^{-1}$ We know, $\quad \lambda=\frac{\mathrm{v}}{\mathrm{f}}=\frac{360}{500}$ Now, a phase difference of $60^{\circ}$ corresponds to a path difference of $\frac{60}{360} \times \lambda$ So, distance between 2 particles is $\mathrm{d}=\frac{60}{360} \times \lambda=\frac{60}{360} \times \frac{360}{500}=0.12 \mathrm{~m}$
AP EAMCET (23.04.2018) Shift-2
WAVES
172202
A motion is described by $y=4 \mathrm{e}^{x}\left(\mathrm{e}^{-5 t}\right)$, where $y$, $x$ are in metres and $t$ is in second.
1 This represents progressive wave propagating along - x-direction with $5 \mathrm{~m} / \mathrm{s}$
2 This represents progressive wave propagating along $+\mathrm{x}$-direction with $5 \mathrm{~m} / \mathrm{s}$
3 This does not represent progressive wave
4 This represents standing wave
Explanation:
B Given, $y=4 \mathrm{e}^{\mathrm{x}}\left(\mathrm{e}^{-5 \mathrm{t}}\right)$ $=4 \mathrm{e}^{\mathrm{x}-5 \mathrm{t}}$ Since, It is a form of $\mathrm{y}=f(\mathrm{ax} \pm \mathrm{bt})$ So, it represent a progressive wave, propagating in positive $\mathrm{X}$-axis direction because coefficient of $\mathrm{x}$ and coefficient of thave opposite sign. So, Speed of a wave $(\mathrm{v})=\frac{\text { coefficient of } \mathrm{t}}{\text { coefficient of } \mathrm{x}}=\frac{5}{1}=5 \mathrm{~m} / \mathrm{s}$
172199
Assertion: Solids can support both longitudinal and transverse waved but only longitudinal waves can propagate in gases Reason: For the propagation of transverse waves, medium must also necessarily have the property of rigidity.
1 If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
A For the propagation of transverse waves, medium must have the property of rigidity. Because gases have no rigidity, (they do not possess shear elasticity), hence transverse waves cannot be produced is gases. On the other hand, the solids possess both volume and shear elasticity and likewise both the longitudinal and transverse waves can be transmitted through them.
AIIMS-26.05.2018(M)
WAVES
172198
The displacement of a wave is given by $\mathbf{y}=$ $0.001 \sin (100 t+x)$ where $x$ and $y$ are in meter and $t$ is in second. This represents a wave
1 Of Wavelength one meter
2 Travelling with a velocity of $100 \mathrm{~m} / \mathrm{s}$ in the negative $\mathrm{x}$-direction
3 Of frequency $\frac{100}{\pi} \mathrm{Hz}$
4 Travelling with a velocity of $\frac{50}{\pi} \mathrm{m} / \mathrm{s}$ in the positive $\mathrm{x}$-direction
Explanation:
B Given, $y=0.001 \sin (100 t+x)$ Comparing with $\mathrm{y}=\mathrm{a} \sin (\omega \mathrm{t}+\mathrm{kx})$ $\omega=100, \mathrm{k}=1$ $2 \pi \mathrm{f}=100, \quad \mathrm{f}=\frac{50}{\pi} \mathrm{Hz}$ Velocity $(v)=\frac{\omega}{\mathrm{k}}=\frac{100}{1}=100 \mathrm{~m} / \mathrm{s}$ Since, positive sign between $\mathrm{x}$ and $\mathrm{t}$ terms so, wave is travelling in negative $\mathrm{x}$-direction.
COMEDK 2018
WAVES
172200
A progressive wave of frequency $500 \mathrm{~Hz}$ is travelling with a velocity of $360 \mathrm{~ms}^{-1}$. The distance between the two points, having a phase difference of $60^{\circ}$ is
1 $1.2 \mathrm{~m}$
2 $12 \mathrm{~m}$
3 $0.12 \mathrm{~m}$
4 $0.012 \mathrm{~m}$
Explanation:
C Given that, $\mathrm{f}=500 \mathrm{~Hz}, \mathrm{v}=360 \mathrm{~ms}^{-1}$ We know, $\quad \lambda=\frac{\mathrm{v}}{\mathrm{f}}=\frac{360}{500}$ Now, a phase difference of $60^{\circ}$ corresponds to a path difference of $\frac{60}{360} \times \lambda$ So, distance between 2 particles is $\mathrm{d}=\frac{60}{360} \times \lambda=\frac{60}{360} \times \frac{360}{500}=0.12 \mathrm{~m}$
AP EAMCET (23.04.2018) Shift-2
WAVES
172202
A motion is described by $y=4 \mathrm{e}^{x}\left(\mathrm{e}^{-5 t}\right)$, where $y$, $x$ are in metres and $t$ is in second.
1 This represents progressive wave propagating along - x-direction with $5 \mathrm{~m} / \mathrm{s}$
2 This represents progressive wave propagating along $+\mathrm{x}$-direction with $5 \mathrm{~m} / \mathrm{s}$
3 This does not represent progressive wave
4 This represents standing wave
Explanation:
B Given, $y=4 \mathrm{e}^{\mathrm{x}}\left(\mathrm{e}^{-5 \mathrm{t}}\right)$ $=4 \mathrm{e}^{\mathrm{x}-5 \mathrm{t}}$ Since, It is a form of $\mathrm{y}=f(\mathrm{ax} \pm \mathrm{bt})$ So, it represent a progressive wave, propagating in positive $\mathrm{X}$-axis direction because coefficient of $\mathrm{x}$ and coefficient of thave opposite sign. So, Speed of a wave $(\mathrm{v})=\frac{\text { coefficient of } \mathrm{t}}{\text { coefficient of } \mathrm{x}}=\frac{5}{1}=5 \mathrm{~m} / \mathrm{s}$
172199
Assertion: Solids can support both longitudinal and transverse waved but only longitudinal waves can propagate in gases Reason: For the propagation of transverse waves, medium must also necessarily have the property of rigidity.
1 If both Assertion and Reason are correct and Reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
3 If Assertion is correct but Reason is incorrect.
4 If both the Assertion and Reason are incorrect.
Explanation:
A For the propagation of transverse waves, medium must have the property of rigidity. Because gases have no rigidity, (they do not possess shear elasticity), hence transverse waves cannot be produced is gases. On the other hand, the solids possess both volume and shear elasticity and likewise both the longitudinal and transverse waves can be transmitted through them.
AIIMS-26.05.2018(M)
WAVES
172198
The displacement of a wave is given by $\mathbf{y}=$ $0.001 \sin (100 t+x)$ where $x$ and $y$ are in meter and $t$ is in second. This represents a wave
1 Of Wavelength one meter
2 Travelling with a velocity of $100 \mathrm{~m} / \mathrm{s}$ in the negative $\mathrm{x}$-direction
3 Of frequency $\frac{100}{\pi} \mathrm{Hz}$
4 Travelling with a velocity of $\frac{50}{\pi} \mathrm{m} / \mathrm{s}$ in the positive $\mathrm{x}$-direction
Explanation:
B Given, $y=0.001 \sin (100 t+x)$ Comparing with $\mathrm{y}=\mathrm{a} \sin (\omega \mathrm{t}+\mathrm{kx})$ $\omega=100, \mathrm{k}=1$ $2 \pi \mathrm{f}=100, \quad \mathrm{f}=\frac{50}{\pi} \mathrm{Hz}$ Velocity $(v)=\frac{\omega}{\mathrm{k}}=\frac{100}{1}=100 \mathrm{~m} / \mathrm{s}$ Since, positive sign between $\mathrm{x}$ and $\mathrm{t}$ terms so, wave is travelling in negative $\mathrm{x}$-direction.
COMEDK 2018
WAVES
172200
A progressive wave of frequency $500 \mathrm{~Hz}$ is travelling with a velocity of $360 \mathrm{~ms}^{-1}$. The distance between the two points, having a phase difference of $60^{\circ}$ is
1 $1.2 \mathrm{~m}$
2 $12 \mathrm{~m}$
3 $0.12 \mathrm{~m}$
4 $0.012 \mathrm{~m}$
Explanation:
C Given that, $\mathrm{f}=500 \mathrm{~Hz}, \mathrm{v}=360 \mathrm{~ms}^{-1}$ We know, $\quad \lambda=\frac{\mathrm{v}}{\mathrm{f}}=\frac{360}{500}$ Now, a phase difference of $60^{\circ}$ corresponds to a path difference of $\frac{60}{360} \times \lambda$ So, distance between 2 particles is $\mathrm{d}=\frac{60}{360} \times \lambda=\frac{60}{360} \times \frac{360}{500}=0.12 \mathrm{~m}$
AP EAMCET (23.04.2018) Shift-2
WAVES
172202
A motion is described by $y=4 \mathrm{e}^{x}\left(\mathrm{e}^{-5 t}\right)$, where $y$, $x$ are in metres and $t$ is in second.
1 This represents progressive wave propagating along - x-direction with $5 \mathrm{~m} / \mathrm{s}$
2 This represents progressive wave propagating along $+\mathrm{x}$-direction with $5 \mathrm{~m} / \mathrm{s}$
3 This does not represent progressive wave
4 This represents standing wave
Explanation:
B Given, $y=4 \mathrm{e}^{\mathrm{x}}\left(\mathrm{e}^{-5 \mathrm{t}}\right)$ $=4 \mathrm{e}^{\mathrm{x}-5 \mathrm{t}}$ Since, It is a form of $\mathrm{y}=f(\mathrm{ax} \pm \mathrm{bt})$ So, it represent a progressive wave, propagating in positive $\mathrm{X}$-axis direction because coefficient of $\mathrm{x}$ and coefficient of thave opposite sign. So, Speed of a wave $(\mathrm{v})=\frac{\text { coefficient of } \mathrm{t}}{\text { coefficient of } \mathrm{x}}=\frac{5}{1}=5 \mathrm{~m} / \mathrm{s}$
