172166
The equation of a running wave is $y=\sin \left(7 \pi t-0.04 x+\frac{\pi}{3}\right)$, where $y$ and $x$ are in meter and $t$ is in seconds. The velocity of this wave is
1 $175 \pi \mathrm{m} / \mathrm{s}$
2 $49 \pi \mathrm{m} / \mathrm{s}$
3 $49 / \pi \mathrm{ms}$
4 $1.75 \pi \mathrm{m} / \mathrm{s}$
Explanation:
A Given, equation $\mathrm{y}=\sin \left(7 \pi \mathrm{t}-0.04 \mathrm{x}+\frac{\pi}{3}\right)$ Above equation compare with standard equation $\mathrm{y}=A \sin \left(\omega \mathrm{t}-\mathrm{kx}+\phi_{0}\right)$ $\mathrm{v}_{\text {wave }}=\frac{\omega}{\mathrm{k}}$ In above given equation Value of, $\omega=7 \pi$ and $\mathrm{k}=0.04$ $\text { So } \mathrm{v}_{\text {wave }}=\frac{\omega}{\mathrm{k}}=\frac{7 \pi}{0.04}=175 \pi \mathrm{m} / \mathrm{sec}$
Tripura-2021
WAVES
172167
A wave is represented by the equation $\mathrm{y}=\mathbf{( 0 . 0 2}$ m) $\sin (5 \pi x-20 t)$. The minimum distance between the two particles always having the same speed is. (Assume $x$ and $t$ are in SI units)
1 $0.02 \mathrm{~m}$
2 $0.4 \mathrm{~m}$
3 $0.8 \mathrm{~m}$
4 $0.2 \mathrm{~m}$
Explanation:
D By question, $\mathrm{y}=0.02 \sin (5 \pi \mathrm{x}-20 \mathrm{t})$ $\quad \mathrm{y}=\mathrm{a} \sin (\mathrm{kx}-\omega \mathrm{t})$ $\mathrm{k}=5 \pi$ $\frac{2 \pi}{\lambda}=5 \pi$ $\lambda=\frac{2}{5}$ The minimum distance between the two particles $\frac{\lambda}{2}=\frac{\frac{2}{5}}{2}=\frac{1}{5}=0.2 \mathrm{~m}$
TS EAMCET 04.08.2021
WAVES
172168
The distance between the successive node and anti-node is
1 $\lambda$
2 $\frac{\lambda}{2}$
3 $\frac{\lambda}{4}$
4 $\frac{3 \lambda}{4}$
Explanation:
C Stationary waves: Standing wave also called as a stationary wave is combination of two wave moving in opposite directions, each having the same amplitude and frequency. - Nodes (N): The points where amplitude is minimum are called Nodes. - The distance between two successive node is $\frac{\lambda}{2}$. - Nodes are at permanent rest. - At nodes air pressure and density both are high Antinodes (A): Points of maximum amplitudes are called antinodes. - The distance between two successive nodes or antinodes is $\frac{\lambda}{2}$. - At antinodes air pressure and density both are low. - The distance between a Node $(\mathrm{N})$ and Antinodes (A) in a stationary wave is $\lambda / 4$.
AP EAMCET (18.09.2020) Shift-II]**#SRM JEE-2018
WAVES
172169
What is the phase difference between two particles $25 \mathrm{~m}$ apart in a wave represented by equation $y=0.03 \sin (\pi[2 t-0.01 x])$ s travelling in a medium?
172170
Two progressive waves are travelling towards each other with velocity $50 \mathrm{~m} / \mathrm{s}$ and frequency $200 \mathrm{~Hz}$. The distance between two consecutive antinodes is
1 $0.125 \mathrm{~m}$
2 $0.031 \mathrm{~m}$
3 $0.250 \mathrm{~m}$
4 $0.0625 \mathrm{~m}$
Explanation:
A Given, Velocity $(\mathrm{v})=50 \mathrm{~m} / \mathrm{s}$ Frequency $(\mathrm{n})=200 \mathrm{~Hz}$ We know, $\mathrm{v}=\mathrm{n} \lambda$ $\lambda=\frac{\mathrm{v}}{\mathrm{n}}=\frac{50}{200}=0.25 \mathrm{~m}$ $\lambda=0.25 \mathrm{~m}$ So, distance between two nodes $=\frac{\lambda}{2}=\frac{0.25}{2}=0.125 \mathrm{~m}$
172166
The equation of a running wave is $y=\sin \left(7 \pi t-0.04 x+\frac{\pi}{3}\right)$, where $y$ and $x$ are in meter and $t$ is in seconds. The velocity of this wave is
1 $175 \pi \mathrm{m} / \mathrm{s}$
2 $49 \pi \mathrm{m} / \mathrm{s}$
3 $49 / \pi \mathrm{ms}$
4 $1.75 \pi \mathrm{m} / \mathrm{s}$
Explanation:
A Given, equation $\mathrm{y}=\sin \left(7 \pi \mathrm{t}-0.04 \mathrm{x}+\frac{\pi}{3}\right)$ Above equation compare with standard equation $\mathrm{y}=A \sin \left(\omega \mathrm{t}-\mathrm{kx}+\phi_{0}\right)$ $\mathrm{v}_{\text {wave }}=\frac{\omega}{\mathrm{k}}$ In above given equation Value of, $\omega=7 \pi$ and $\mathrm{k}=0.04$ $\text { So } \mathrm{v}_{\text {wave }}=\frac{\omega}{\mathrm{k}}=\frac{7 \pi}{0.04}=175 \pi \mathrm{m} / \mathrm{sec}$
Tripura-2021
WAVES
172167
A wave is represented by the equation $\mathrm{y}=\mathbf{( 0 . 0 2}$ m) $\sin (5 \pi x-20 t)$. The minimum distance between the two particles always having the same speed is. (Assume $x$ and $t$ are in SI units)
1 $0.02 \mathrm{~m}$
2 $0.4 \mathrm{~m}$
3 $0.8 \mathrm{~m}$
4 $0.2 \mathrm{~m}$
Explanation:
D By question, $\mathrm{y}=0.02 \sin (5 \pi \mathrm{x}-20 \mathrm{t})$ $\quad \mathrm{y}=\mathrm{a} \sin (\mathrm{kx}-\omega \mathrm{t})$ $\mathrm{k}=5 \pi$ $\frac{2 \pi}{\lambda}=5 \pi$ $\lambda=\frac{2}{5}$ The minimum distance between the two particles $\frac{\lambda}{2}=\frac{\frac{2}{5}}{2}=\frac{1}{5}=0.2 \mathrm{~m}$
TS EAMCET 04.08.2021
WAVES
172168
The distance between the successive node and anti-node is
1 $\lambda$
2 $\frac{\lambda}{2}$
3 $\frac{\lambda}{4}$
4 $\frac{3 \lambda}{4}$
Explanation:
C Stationary waves: Standing wave also called as a stationary wave is combination of two wave moving in opposite directions, each having the same amplitude and frequency. - Nodes (N): The points where amplitude is minimum are called Nodes. - The distance between two successive node is $\frac{\lambda}{2}$. - Nodes are at permanent rest. - At nodes air pressure and density both are high Antinodes (A): Points of maximum amplitudes are called antinodes. - The distance between two successive nodes or antinodes is $\frac{\lambda}{2}$. - At antinodes air pressure and density both are low. - The distance between a Node $(\mathrm{N})$ and Antinodes (A) in a stationary wave is $\lambda / 4$.
AP EAMCET (18.09.2020) Shift-II]**#SRM JEE-2018
WAVES
172169
What is the phase difference between two particles $25 \mathrm{~m}$ apart in a wave represented by equation $y=0.03 \sin (\pi[2 t-0.01 x])$ s travelling in a medium?
172170
Two progressive waves are travelling towards each other with velocity $50 \mathrm{~m} / \mathrm{s}$ and frequency $200 \mathrm{~Hz}$. The distance between two consecutive antinodes is
1 $0.125 \mathrm{~m}$
2 $0.031 \mathrm{~m}$
3 $0.250 \mathrm{~m}$
4 $0.0625 \mathrm{~m}$
Explanation:
A Given, Velocity $(\mathrm{v})=50 \mathrm{~m} / \mathrm{s}$ Frequency $(\mathrm{n})=200 \mathrm{~Hz}$ We know, $\mathrm{v}=\mathrm{n} \lambda$ $\lambda=\frac{\mathrm{v}}{\mathrm{n}}=\frac{50}{200}=0.25 \mathrm{~m}$ $\lambda=0.25 \mathrm{~m}$ So, distance between two nodes $=\frac{\lambda}{2}=\frac{0.25}{2}=0.125 \mathrm{~m}$
172166
The equation of a running wave is $y=\sin \left(7 \pi t-0.04 x+\frac{\pi}{3}\right)$, where $y$ and $x$ are in meter and $t$ is in seconds. The velocity of this wave is
1 $175 \pi \mathrm{m} / \mathrm{s}$
2 $49 \pi \mathrm{m} / \mathrm{s}$
3 $49 / \pi \mathrm{ms}$
4 $1.75 \pi \mathrm{m} / \mathrm{s}$
Explanation:
A Given, equation $\mathrm{y}=\sin \left(7 \pi \mathrm{t}-0.04 \mathrm{x}+\frac{\pi}{3}\right)$ Above equation compare with standard equation $\mathrm{y}=A \sin \left(\omega \mathrm{t}-\mathrm{kx}+\phi_{0}\right)$ $\mathrm{v}_{\text {wave }}=\frac{\omega}{\mathrm{k}}$ In above given equation Value of, $\omega=7 \pi$ and $\mathrm{k}=0.04$ $\text { So } \mathrm{v}_{\text {wave }}=\frac{\omega}{\mathrm{k}}=\frac{7 \pi}{0.04}=175 \pi \mathrm{m} / \mathrm{sec}$
Tripura-2021
WAVES
172167
A wave is represented by the equation $\mathrm{y}=\mathbf{( 0 . 0 2}$ m) $\sin (5 \pi x-20 t)$. The minimum distance between the two particles always having the same speed is. (Assume $x$ and $t$ are in SI units)
1 $0.02 \mathrm{~m}$
2 $0.4 \mathrm{~m}$
3 $0.8 \mathrm{~m}$
4 $0.2 \mathrm{~m}$
Explanation:
D By question, $\mathrm{y}=0.02 \sin (5 \pi \mathrm{x}-20 \mathrm{t})$ $\quad \mathrm{y}=\mathrm{a} \sin (\mathrm{kx}-\omega \mathrm{t})$ $\mathrm{k}=5 \pi$ $\frac{2 \pi}{\lambda}=5 \pi$ $\lambda=\frac{2}{5}$ The minimum distance between the two particles $\frac{\lambda}{2}=\frac{\frac{2}{5}}{2}=\frac{1}{5}=0.2 \mathrm{~m}$
TS EAMCET 04.08.2021
WAVES
172168
The distance between the successive node and anti-node is
1 $\lambda$
2 $\frac{\lambda}{2}$
3 $\frac{\lambda}{4}$
4 $\frac{3 \lambda}{4}$
Explanation:
C Stationary waves: Standing wave also called as a stationary wave is combination of two wave moving in opposite directions, each having the same amplitude and frequency. - Nodes (N): The points where amplitude is minimum are called Nodes. - The distance between two successive node is $\frac{\lambda}{2}$. - Nodes are at permanent rest. - At nodes air pressure and density both are high Antinodes (A): Points of maximum amplitudes are called antinodes. - The distance between two successive nodes or antinodes is $\frac{\lambda}{2}$. - At antinodes air pressure and density both are low. - The distance between a Node $(\mathrm{N})$ and Antinodes (A) in a stationary wave is $\lambda / 4$.
AP EAMCET (18.09.2020) Shift-II]**#SRM JEE-2018
WAVES
172169
What is the phase difference between two particles $25 \mathrm{~m}$ apart in a wave represented by equation $y=0.03 \sin (\pi[2 t-0.01 x])$ s travelling in a medium?
172170
Two progressive waves are travelling towards each other with velocity $50 \mathrm{~m} / \mathrm{s}$ and frequency $200 \mathrm{~Hz}$. The distance between two consecutive antinodes is
1 $0.125 \mathrm{~m}$
2 $0.031 \mathrm{~m}$
3 $0.250 \mathrm{~m}$
4 $0.0625 \mathrm{~m}$
Explanation:
A Given, Velocity $(\mathrm{v})=50 \mathrm{~m} / \mathrm{s}$ Frequency $(\mathrm{n})=200 \mathrm{~Hz}$ We know, $\mathrm{v}=\mathrm{n} \lambda$ $\lambda=\frac{\mathrm{v}}{\mathrm{n}}=\frac{50}{200}=0.25 \mathrm{~m}$ $\lambda=0.25 \mathrm{~m}$ So, distance between two nodes $=\frac{\lambda}{2}=\frac{0.25}{2}=0.125 \mathrm{~m}$
172166
The equation of a running wave is $y=\sin \left(7 \pi t-0.04 x+\frac{\pi}{3}\right)$, where $y$ and $x$ are in meter and $t$ is in seconds. The velocity of this wave is
1 $175 \pi \mathrm{m} / \mathrm{s}$
2 $49 \pi \mathrm{m} / \mathrm{s}$
3 $49 / \pi \mathrm{ms}$
4 $1.75 \pi \mathrm{m} / \mathrm{s}$
Explanation:
A Given, equation $\mathrm{y}=\sin \left(7 \pi \mathrm{t}-0.04 \mathrm{x}+\frac{\pi}{3}\right)$ Above equation compare with standard equation $\mathrm{y}=A \sin \left(\omega \mathrm{t}-\mathrm{kx}+\phi_{0}\right)$ $\mathrm{v}_{\text {wave }}=\frac{\omega}{\mathrm{k}}$ In above given equation Value of, $\omega=7 \pi$ and $\mathrm{k}=0.04$ $\text { So } \mathrm{v}_{\text {wave }}=\frac{\omega}{\mathrm{k}}=\frac{7 \pi}{0.04}=175 \pi \mathrm{m} / \mathrm{sec}$
Tripura-2021
WAVES
172167
A wave is represented by the equation $\mathrm{y}=\mathbf{( 0 . 0 2}$ m) $\sin (5 \pi x-20 t)$. The minimum distance between the two particles always having the same speed is. (Assume $x$ and $t$ are in SI units)
1 $0.02 \mathrm{~m}$
2 $0.4 \mathrm{~m}$
3 $0.8 \mathrm{~m}$
4 $0.2 \mathrm{~m}$
Explanation:
D By question, $\mathrm{y}=0.02 \sin (5 \pi \mathrm{x}-20 \mathrm{t})$ $\quad \mathrm{y}=\mathrm{a} \sin (\mathrm{kx}-\omega \mathrm{t})$ $\mathrm{k}=5 \pi$ $\frac{2 \pi}{\lambda}=5 \pi$ $\lambda=\frac{2}{5}$ The minimum distance between the two particles $\frac{\lambda}{2}=\frac{\frac{2}{5}}{2}=\frac{1}{5}=0.2 \mathrm{~m}$
TS EAMCET 04.08.2021
WAVES
172168
The distance between the successive node and anti-node is
1 $\lambda$
2 $\frac{\lambda}{2}$
3 $\frac{\lambda}{4}$
4 $\frac{3 \lambda}{4}$
Explanation:
C Stationary waves: Standing wave also called as a stationary wave is combination of two wave moving in opposite directions, each having the same amplitude and frequency. - Nodes (N): The points where amplitude is minimum are called Nodes. - The distance between two successive node is $\frac{\lambda}{2}$. - Nodes are at permanent rest. - At nodes air pressure and density both are high Antinodes (A): Points of maximum amplitudes are called antinodes. - The distance between two successive nodes or antinodes is $\frac{\lambda}{2}$. - At antinodes air pressure and density both are low. - The distance between a Node $(\mathrm{N})$ and Antinodes (A) in a stationary wave is $\lambda / 4$.
AP EAMCET (18.09.2020) Shift-II]**#SRM JEE-2018
WAVES
172169
What is the phase difference between two particles $25 \mathrm{~m}$ apart in a wave represented by equation $y=0.03 \sin (\pi[2 t-0.01 x])$ s travelling in a medium?
172170
Two progressive waves are travelling towards each other with velocity $50 \mathrm{~m} / \mathrm{s}$ and frequency $200 \mathrm{~Hz}$. The distance between two consecutive antinodes is
1 $0.125 \mathrm{~m}$
2 $0.031 \mathrm{~m}$
3 $0.250 \mathrm{~m}$
4 $0.0625 \mathrm{~m}$
Explanation:
A Given, Velocity $(\mathrm{v})=50 \mathrm{~m} / \mathrm{s}$ Frequency $(\mathrm{n})=200 \mathrm{~Hz}$ We know, $\mathrm{v}=\mathrm{n} \lambda$ $\lambda=\frac{\mathrm{v}}{\mathrm{n}}=\frac{50}{200}=0.25 \mathrm{~m}$ $\lambda=0.25 \mathrm{~m}$ So, distance between two nodes $=\frac{\lambda}{2}=\frac{0.25}{2}=0.125 \mathrm{~m}$
172166
The equation of a running wave is $y=\sin \left(7 \pi t-0.04 x+\frac{\pi}{3}\right)$, where $y$ and $x$ are in meter and $t$ is in seconds. The velocity of this wave is
1 $175 \pi \mathrm{m} / \mathrm{s}$
2 $49 \pi \mathrm{m} / \mathrm{s}$
3 $49 / \pi \mathrm{ms}$
4 $1.75 \pi \mathrm{m} / \mathrm{s}$
Explanation:
A Given, equation $\mathrm{y}=\sin \left(7 \pi \mathrm{t}-0.04 \mathrm{x}+\frac{\pi}{3}\right)$ Above equation compare with standard equation $\mathrm{y}=A \sin \left(\omega \mathrm{t}-\mathrm{kx}+\phi_{0}\right)$ $\mathrm{v}_{\text {wave }}=\frac{\omega}{\mathrm{k}}$ In above given equation Value of, $\omega=7 \pi$ and $\mathrm{k}=0.04$ $\text { So } \mathrm{v}_{\text {wave }}=\frac{\omega}{\mathrm{k}}=\frac{7 \pi}{0.04}=175 \pi \mathrm{m} / \mathrm{sec}$
Tripura-2021
WAVES
172167
A wave is represented by the equation $\mathrm{y}=\mathbf{( 0 . 0 2}$ m) $\sin (5 \pi x-20 t)$. The minimum distance between the two particles always having the same speed is. (Assume $x$ and $t$ are in SI units)
1 $0.02 \mathrm{~m}$
2 $0.4 \mathrm{~m}$
3 $0.8 \mathrm{~m}$
4 $0.2 \mathrm{~m}$
Explanation:
D By question, $\mathrm{y}=0.02 \sin (5 \pi \mathrm{x}-20 \mathrm{t})$ $\quad \mathrm{y}=\mathrm{a} \sin (\mathrm{kx}-\omega \mathrm{t})$ $\mathrm{k}=5 \pi$ $\frac{2 \pi}{\lambda}=5 \pi$ $\lambda=\frac{2}{5}$ The minimum distance between the two particles $\frac{\lambda}{2}=\frac{\frac{2}{5}}{2}=\frac{1}{5}=0.2 \mathrm{~m}$
TS EAMCET 04.08.2021
WAVES
172168
The distance between the successive node and anti-node is
1 $\lambda$
2 $\frac{\lambda}{2}$
3 $\frac{\lambda}{4}$
4 $\frac{3 \lambda}{4}$
Explanation:
C Stationary waves: Standing wave also called as a stationary wave is combination of two wave moving in opposite directions, each having the same amplitude and frequency. - Nodes (N): The points where amplitude is minimum are called Nodes. - The distance between two successive node is $\frac{\lambda}{2}$. - Nodes are at permanent rest. - At nodes air pressure and density both are high Antinodes (A): Points of maximum amplitudes are called antinodes. - The distance between two successive nodes or antinodes is $\frac{\lambda}{2}$. - At antinodes air pressure and density both are low. - The distance between a Node $(\mathrm{N})$ and Antinodes (A) in a stationary wave is $\lambda / 4$.
AP EAMCET (18.09.2020) Shift-II]**#SRM JEE-2018
WAVES
172169
What is the phase difference between two particles $25 \mathrm{~m}$ apart in a wave represented by equation $y=0.03 \sin (\pi[2 t-0.01 x])$ s travelling in a medium?
172170
Two progressive waves are travelling towards each other with velocity $50 \mathrm{~m} / \mathrm{s}$ and frequency $200 \mathrm{~Hz}$. The distance between two consecutive antinodes is
1 $0.125 \mathrm{~m}$
2 $0.031 \mathrm{~m}$
3 $0.250 \mathrm{~m}$
4 $0.0625 \mathrm{~m}$
Explanation:
A Given, Velocity $(\mathrm{v})=50 \mathrm{~m} / \mathrm{s}$ Frequency $(\mathrm{n})=200 \mathrm{~Hz}$ We know, $\mathrm{v}=\mathrm{n} \lambda$ $\lambda=\frac{\mathrm{v}}{\mathrm{n}}=\frac{50}{200}=0.25 \mathrm{~m}$ $\lambda=0.25 \mathrm{~m}$ So, distance between two nodes $=\frac{\lambda}{2}=\frac{0.25}{2}=0.125 \mathrm{~m}$
