147373
Assertion (A): Neutrino is chargeless and possesses spin. Reason (R) : Neutrino exists inside the nucleus.
1 Both (A) and (R) are correct and (R) is the correct explanation of (A)
2 Both (A) and (R) are correct but (R) is not the correct explanation of (A)
3 (A) is correct but (R) is not correct
4 Is not correct but (R) is correct
Explanation:
C Neutrino is chargeless and has spin. Neutrino is a very small piece of matter and categorized under Lepton's. Neutrino is similar to an electron. It is outer side of the nucleus.
AP EAMCET-25.04.2018
NUCLEAR PHYSICS
147376
Assertion: Bohr has to postulate that the electrons in stationary orbits around the nucleus do not radiate. Reason: According to classical physics all moving electrons radiate.
1 If both Assertion and Reason are correct and reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion
3 If Assertion is correct but Reason is incorrect
4 If both the Assertion and Reason are incorrect
Explanation:
B According to Bohr's Postulate electrons revolve around the nucleus in certain definite circular path called stationary orbit in which they do not radiate. According to classical physics all accelerating charged particle radiate electromagnetic radiation. So, accelerating electrons will also radiate energy.
AIIMS-2017
NUCLEAR PHYSICS
147379
The wavelength of the $K_{\alpha}$ line for an element of atomic number 43 is $\lambda$. The wavelength of the $K_{\alpha}$ line for an element of atomic number 29 is
1 $\left(\frac{43}{29}\right) \lambda$
2 $\left(\frac{42}{28}\right) \lambda$
3 $\left(\frac{9}{4}\right) \lambda$
4 $\left(\frac{4}{9}\right) \lambda$
Explanation:
C Given that, Atomic number are $Z_{1}=43$ and $Z_{2}=29$ We know that, $\lambda \propto \frac{1}{(Z-1)^{2}}$ Then, ratio of wavelength of $K_{\alpha}$ of atomic number 29 and $43-$ \(\frac{\lambda_2}{\lambda_1}=\left(\frac{Z_1-1}{Z_2-1}\right)^2\) $=\left(\frac{43-1}{29-1}\right)^{2}=\left(\frac{42}{28}\right)^{2}$ $\frac{\lambda_{2}}{\lambda_{1}}=\left(\frac{3}{2}\right)^{2}$ $\text { Or } \quad \lambda_{2}=\frac{9}{4} \lambda_{1}$ $\lambda_{2}=\frac{9}{4} \lambda$ $\left[\therefore \lambda_{1}=\lambda\right]$
Manipal UGET-2013
NUCLEAR PHYSICS
147382
If $10 \mathrm{~g}$ of Uranium-235 is completely destroyed in a reactor, then energy released is
1 $9 \times 10^{14} \mathrm{~J}$
2 $9 \times 10^{15} \mathrm{~J}$
3 $9 \times 10^{16} \mathrm{~J}$
4 $9 \times 10^{18} \mathrm{~J}$
Explanation:
A Given that, Destroyed mass $(\mathrm{m})=10$ gram $=10 \times 10^{-3} \mathrm{~kg}$ Speed of light $(\mathrm{c})=3 \times 10^{8} \mathrm{~m} / \mathrm{s}$ We know that, $\mathrm{E}=\mathrm{mc}^{2}$ $\mathrm{E}=\left(10 \times 10^{-3}\right) \times\left(3 \times 10^{8}\right)^{2}$ $\mathrm{E}=9 \times 10^{14} \mathrm{~J}$
147373
Assertion (A): Neutrino is chargeless and possesses spin. Reason (R) : Neutrino exists inside the nucleus.
1 Both (A) and (R) are correct and (R) is the correct explanation of (A)
2 Both (A) and (R) are correct but (R) is not the correct explanation of (A)
3 (A) is correct but (R) is not correct
4 Is not correct but (R) is correct
Explanation:
C Neutrino is chargeless and has spin. Neutrino is a very small piece of matter and categorized under Lepton's. Neutrino is similar to an electron. It is outer side of the nucleus.
AP EAMCET-25.04.2018
NUCLEAR PHYSICS
147376
Assertion: Bohr has to postulate that the electrons in stationary orbits around the nucleus do not radiate. Reason: According to classical physics all moving electrons radiate.
1 If both Assertion and Reason are correct and reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion
3 If Assertion is correct but Reason is incorrect
4 If both the Assertion and Reason are incorrect
Explanation:
B According to Bohr's Postulate electrons revolve around the nucleus in certain definite circular path called stationary orbit in which they do not radiate. According to classical physics all accelerating charged particle radiate electromagnetic radiation. So, accelerating electrons will also radiate energy.
AIIMS-2017
NUCLEAR PHYSICS
147379
The wavelength of the $K_{\alpha}$ line for an element of atomic number 43 is $\lambda$. The wavelength of the $K_{\alpha}$ line for an element of atomic number 29 is
1 $\left(\frac{43}{29}\right) \lambda$
2 $\left(\frac{42}{28}\right) \lambda$
3 $\left(\frac{9}{4}\right) \lambda$
4 $\left(\frac{4}{9}\right) \lambda$
Explanation:
C Given that, Atomic number are $Z_{1}=43$ and $Z_{2}=29$ We know that, $\lambda \propto \frac{1}{(Z-1)^{2}}$ Then, ratio of wavelength of $K_{\alpha}$ of atomic number 29 and $43-$ \(\frac{\lambda_2}{\lambda_1}=\left(\frac{Z_1-1}{Z_2-1}\right)^2\) $=\left(\frac{43-1}{29-1}\right)^{2}=\left(\frac{42}{28}\right)^{2}$ $\frac{\lambda_{2}}{\lambda_{1}}=\left(\frac{3}{2}\right)^{2}$ $\text { Or } \quad \lambda_{2}=\frac{9}{4} \lambda_{1}$ $\lambda_{2}=\frac{9}{4} \lambda$ $\left[\therefore \lambda_{1}=\lambda\right]$
Manipal UGET-2013
NUCLEAR PHYSICS
147382
If $10 \mathrm{~g}$ of Uranium-235 is completely destroyed in a reactor, then energy released is
1 $9 \times 10^{14} \mathrm{~J}$
2 $9 \times 10^{15} \mathrm{~J}$
3 $9 \times 10^{16} \mathrm{~J}$
4 $9 \times 10^{18} \mathrm{~J}$
Explanation:
A Given that, Destroyed mass $(\mathrm{m})=10$ gram $=10 \times 10^{-3} \mathrm{~kg}$ Speed of light $(\mathrm{c})=3 \times 10^{8} \mathrm{~m} / \mathrm{s}$ We know that, $\mathrm{E}=\mathrm{mc}^{2}$ $\mathrm{E}=\left(10 \times 10^{-3}\right) \times\left(3 \times 10^{8}\right)^{2}$ $\mathrm{E}=9 \times 10^{14} \mathrm{~J}$
147373
Assertion (A): Neutrino is chargeless and possesses spin. Reason (R) : Neutrino exists inside the nucleus.
1 Both (A) and (R) are correct and (R) is the correct explanation of (A)
2 Both (A) and (R) are correct but (R) is not the correct explanation of (A)
3 (A) is correct but (R) is not correct
4 Is not correct but (R) is correct
Explanation:
C Neutrino is chargeless and has spin. Neutrino is a very small piece of matter and categorized under Lepton's. Neutrino is similar to an electron. It is outer side of the nucleus.
AP EAMCET-25.04.2018
NUCLEAR PHYSICS
147376
Assertion: Bohr has to postulate that the electrons in stationary orbits around the nucleus do not radiate. Reason: According to classical physics all moving electrons radiate.
1 If both Assertion and Reason are correct and reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion
3 If Assertion is correct but Reason is incorrect
4 If both the Assertion and Reason are incorrect
Explanation:
B According to Bohr's Postulate electrons revolve around the nucleus in certain definite circular path called stationary orbit in which they do not radiate. According to classical physics all accelerating charged particle radiate electromagnetic radiation. So, accelerating electrons will also radiate energy.
AIIMS-2017
NUCLEAR PHYSICS
147379
The wavelength of the $K_{\alpha}$ line for an element of atomic number 43 is $\lambda$. The wavelength of the $K_{\alpha}$ line for an element of atomic number 29 is
1 $\left(\frac{43}{29}\right) \lambda$
2 $\left(\frac{42}{28}\right) \lambda$
3 $\left(\frac{9}{4}\right) \lambda$
4 $\left(\frac{4}{9}\right) \lambda$
Explanation:
C Given that, Atomic number are $Z_{1}=43$ and $Z_{2}=29$ We know that, $\lambda \propto \frac{1}{(Z-1)^{2}}$ Then, ratio of wavelength of $K_{\alpha}$ of atomic number 29 and $43-$ \(\frac{\lambda_2}{\lambda_1}=\left(\frac{Z_1-1}{Z_2-1}\right)^2\) $=\left(\frac{43-1}{29-1}\right)^{2}=\left(\frac{42}{28}\right)^{2}$ $\frac{\lambda_{2}}{\lambda_{1}}=\left(\frac{3}{2}\right)^{2}$ $\text { Or } \quad \lambda_{2}=\frac{9}{4} \lambda_{1}$ $\lambda_{2}=\frac{9}{4} \lambda$ $\left[\therefore \lambda_{1}=\lambda\right]$
Manipal UGET-2013
NUCLEAR PHYSICS
147382
If $10 \mathrm{~g}$ of Uranium-235 is completely destroyed in a reactor, then energy released is
1 $9 \times 10^{14} \mathrm{~J}$
2 $9 \times 10^{15} \mathrm{~J}$
3 $9 \times 10^{16} \mathrm{~J}$
4 $9 \times 10^{18} \mathrm{~J}$
Explanation:
A Given that, Destroyed mass $(\mathrm{m})=10$ gram $=10 \times 10^{-3} \mathrm{~kg}$ Speed of light $(\mathrm{c})=3 \times 10^{8} \mathrm{~m} / \mathrm{s}$ We know that, $\mathrm{E}=\mathrm{mc}^{2}$ $\mathrm{E}=\left(10 \times 10^{-3}\right) \times\left(3 \times 10^{8}\right)^{2}$ $\mathrm{E}=9 \times 10^{14} \mathrm{~J}$
147373
Assertion (A): Neutrino is chargeless and possesses spin. Reason (R) : Neutrino exists inside the nucleus.
1 Both (A) and (R) are correct and (R) is the correct explanation of (A)
2 Both (A) and (R) are correct but (R) is not the correct explanation of (A)
3 (A) is correct but (R) is not correct
4 Is not correct but (R) is correct
Explanation:
C Neutrino is chargeless and has spin. Neutrino is a very small piece of matter and categorized under Lepton's. Neutrino is similar to an electron. It is outer side of the nucleus.
AP EAMCET-25.04.2018
NUCLEAR PHYSICS
147376
Assertion: Bohr has to postulate that the electrons in stationary orbits around the nucleus do not radiate. Reason: According to classical physics all moving electrons radiate.
1 If both Assertion and Reason are correct and reason is the correct explanation of Assertion.
2 If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion
3 If Assertion is correct but Reason is incorrect
4 If both the Assertion and Reason are incorrect
Explanation:
B According to Bohr's Postulate electrons revolve around the nucleus in certain definite circular path called stationary orbit in which they do not radiate. According to classical physics all accelerating charged particle radiate electromagnetic radiation. So, accelerating electrons will also radiate energy.
AIIMS-2017
NUCLEAR PHYSICS
147379
The wavelength of the $K_{\alpha}$ line for an element of atomic number 43 is $\lambda$. The wavelength of the $K_{\alpha}$ line for an element of atomic number 29 is
1 $\left(\frac{43}{29}\right) \lambda$
2 $\left(\frac{42}{28}\right) \lambda$
3 $\left(\frac{9}{4}\right) \lambda$
4 $\left(\frac{4}{9}\right) \lambda$
Explanation:
C Given that, Atomic number are $Z_{1}=43$ and $Z_{2}=29$ We know that, $\lambda \propto \frac{1}{(Z-1)^{2}}$ Then, ratio of wavelength of $K_{\alpha}$ of atomic number 29 and $43-$ \(\frac{\lambda_2}{\lambda_1}=\left(\frac{Z_1-1}{Z_2-1}\right)^2\) $=\left(\frac{43-1}{29-1}\right)^{2}=\left(\frac{42}{28}\right)^{2}$ $\frac{\lambda_{2}}{\lambda_{1}}=\left(\frac{3}{2}\right)^{2}$ $\text { Or } \quad \lambda_{2}=\frac{9}{4} \lambda_{1}$ $\lambda_{2}=\frac{9}{4} \lambda$ $\left[\therefore \lambda_{1}=\lambda\right]$
Manipal UGET-2013
NUCLEAR PHYSICS
147382
If $10 \mathrm{~g}$ of Uranium-235 is completely destroyed in a reactor, then energy released is
1 $9 \times 10^{14} \mathrm{~J}$
2 $9 \times 10^{15} \mathrm{~J}$
3 $9 \times 10^{16} \mathrm{~J}$
4 $9 \times 10^{18} \mathrm{~J}$
Explanation:
A Given that, Destroyed mass $(\mathrm{m})=10$ gram $=10 \times 10^{-3} \mathrm{~kg}$ Speed of light $(\mathrm{c})=3 \times 10^{8} \mathrm{~m} / \mathrm{s}$ We know that, $\mathrm{E}=\mathrm{mc}^{2}$ $\mathrm{E}=\left(10 \times 10^{-3}\right) \times\left(3 \times 10^{8}\right)^{2}$ $\mathrm{E}=9 \times 10^{14} \mathrm{~J}$
