Wave Nature Of Light Of Matter (de-Broglie)
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Dual nature of radiation and Matter

142452 The energy of an electron having de-Broglic wavelength ' $\lambda$ ' is $(h=$ Plank's constant, $m=$ mass of electron)

1 $\frac{\mathrm{h}}{2 \mathrm{~m} \lambda}$
2 $\frac{h^{2}}{2 m \lambda^{2}}$
3 $\frac{h^{2}}{2 m^{2} \lambda^{2}}$
4 $\frac{\mathrm{h}^{2}}{2 \mathrm{~m}^{2} \lambda}$
MHT-CET 2018
Dual nature of radiation and Matter

142453 The masses of two particles having same kinetic energies are in the ratio 2:1. Then their de-Broglie wavelengths are in the ratio

1 $2: 1$
2 $1: 2$
3 $\sqrt{2}: 1$
4 $1: \sqrt{2}$
COMEDK 2018
Dual nature of radiation and Matter

142455 Two particles $A$ and $B$ of same mass have their total energies $E_{A}$ and $E_{B}$ in the ratio $E_{A}: E_{B}$ $=1: 2$ Their potential energies $U_{A}$ and $U_{B}$ are in the ratio $U_{A}: U_{B}=1: 2$. If $\lambda_{A}$ and $\lambda_{B}$ are there de-Broglie wavelengths, then $\lambda_{A}: \lambda_{B}$ is

1 $1: 2$
2 $2: 1$
3 $1: \sqrt{2}$
4 $\sqrt{2}: 1$
5 $1: 1$
Kerala CEE -2018
Dual nature of radiation and Matter

142456 If $\lambda_{1}$ and $\lambda_{2}$ denote the de-Broglie wavelengths of two particles with same masses but charges in the ratio of 1:2 after they are accelerated from rest through the same potential difference, then

1 $\lambda_{1}=\lambda_{2}$
2 $\lambda_{1} \lt \lambda_{2}$
3 $\lambda_{1}>\lambda_{2}$
4 None of these
UPSEE - 2018
For More Updates join with Us
Dual nature of radiation and Matter

142452 The energy of an electron having de-Broglic wavelength ' $\lambda$ ' is $(h=$ Plank's constant, $m=$ mass of electron)

1 $\frac{\mathrm{h}}{2 \mathrm{~m} \lambda}$
2 $\frac{h^{2}}{2 m \lambda^{2}}$
3 $\frac{h^{2}}{2 m^{2} \lambda^{2}}$
4 $\frac{\mathrm{h}^{2}}{2 \mathrm{~m}^{2} \lambda}$
MHT-CET 2018
Dual nature of radiation and Matter

142453 The masses of two particles having same kinetic energies are in the ratio 2:1. Then their de-Broglie wavelengths are in the ratio

1 $2: 1$
2 $1: 2$
3 $\sqrt{2}: 1$
4 $1: \sqrt{2}$
COMEDK 2018
Dual nature of radiation and Matter

142455 Two particles $A$ and $B$ of same mass have their total energies $E_{A}$ and $E_{B}$ in the ratio $E_{A}: E_{B}$ $=1: 2$ Their potential energies $U_{A}$ and $U_{B}$ are in the ratio $U_{A}: U_{B}=1: 2$. If $\lambda_{A}$ and $\lambda_{B}$ are there de-Broglie wavelengths, then $\lambda_{A}: \lambda_{B}$ is

1 $1: 2$
2 $2: 1$
3 $1: \sqrt{2}$
4 $\sqrt{2}: 1$
5 $1: 1$
Kerala CEE -2018
Dual nature of radiation and Matter

142456 If $\lambda_{1}$ and $\lambda_{2}$ denote the de-Broglie wavelengths of two particles with same masses but charges in the ratio of 1:2 after they are accelerated from rest through the same potential difference, then

1 $\lambda_{1}=\lambda_{2}$
2 $\lambda_{1} \lt \lambda_{2}$
3 $\lambda_{1}>\lambda_{2}$
4 None of these
UPSEE - 2018
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Dual nature of radiation and Matter

142452 The energy of an electron having de-Broglic wavelength ' $\lambda$ ' is $(h=$ Plank's constant, $m=$ mass of electron)

1 $\frac{\mathrm{h}}{2 \mathrm{~m} \lambda}$
2 $\frac{h^{2}}{2 m \lambda^{2}}$
3 $\frac{h^{2}}{2 m^{2} \lambda^{2}}$
4 $\frac{\mathrm{h}^{2}}{2 \mathrm{~m}^{2} \lambda}$
MHT-CET 2018
Dual nature of radiation and Matter

142453 The masses of two particles having same kinetic energies are in the ratio 2:1. Then their de-Broglie wavelengths are in the ratio

1 $2: 1$
2 $1: 2$
3 $\sqrt{2}: 1$
4 $1: \sqrt{2}$
COMEDK 2018
Dual nature of radiation and Matter

142455 Two particles $A$ and $B$ of same mass have their total energies $E_{A}$ and $E_{B}$ in the ratio $E_{A}: E_{B}$ $=1: 2$ Their potential energies $U_{A}$ and $U_{B}$ are in the ratio $U_{A}: U_{B}=1: 2$. If $\lambda_{A}$ and $\lambda_{B}$ are there de-Broglie wavelengths, then $\lambda_{A}: \lambda_{B}$ is

1 $1: 2$
2 $2: 1$
3 $1: \sqrt{2}$
4 $\sqrt{2}: 1$
5 $1: 1$
Kerala CEE -2018
Dual nature of radiation and Matter

142456 If $\lambda_{1}$ and $\lambda_{2}$ denote the de-Broglie wavelengths of two particles with same masses but charges in the ratio of 1:2 after they are accelerated from rest through the same potential difference, then

1 $\lambda_{1}=\lambda_{2}$
2 $\lambda_{1} \lt \lambda_{2}$
3 $\lambda_{1}>\lambda_{2}$
4 None of these
UPSEE - 2018
Join With Us for More Updates
Dual nature of radiation and Matter

142452 The energy of an electron having de-Broglic wavelength ' $\lambda$ ' is $(h=$ Plank's constant, $m=$ mass of electron)

1 $\frac{\mathrm{h}}{2 \mathrm{~m} \lambda}$
2 $\frac{h^{2}}{2 m \lambda^{2}}$
3 $\frac{h^{2}}{2 m^{2} \lambda^{2}}$
4 $\frac{\mathrm{h}^{2}}{2 \mathrm{~m}^{2} \lambda}$
MHT-CET 2018
Dual nature of radiation and Matter

142453 The masses of two particles having same kinetic energies are in the ratio 2:1. Then their de-Broglie wavelengths are in the ratio

1 $2: 1$
2 $1: 2$
3 $\sqrt{2}: 1$
4 $1: \sqrt{2}$
COMEDK 2018
Dual nature of radiation and Matter

142455 Two particles $A$ and $B$ of same mass have their total energies $E_{A}$ and $E_{B}$ in the ratio $E_{A}: E_{B}$ $=1: 2$ Their potential energies $U_{A}$ and $U_{B}$ are in the ratio $U_{A}: U_{B}=1: 2$. If $\lambda_{A}$ and $\lambda_{B}$ are there de-Broglie wavelengths, then $\lambda_{A}: \lambda_{B}$ is

1 $1: 2$
2 $2: 1$
3 $1: \sqrt{2}$
4 $\sqrt{2}: 1$
5 $1: 1$
Kerala CEE -2018
Dual nature of radiation and Matter

142456 If $\lambda_{1}$ and $\lambda_{2}$ denote the de-Broglie wavelengths of two particles with same masses but charges in the ratio of 1:2 after they are accelerated from rest through the same potential difference, then

1 $\lambda_{1}=\lambda_{2}$
2 $\lambda_{1} \lt \lambda_{2}$
3 $\lambda_{1}>\lambda_{2}$
4 None of these
UPSEE - 2018
For More Updates join with Us
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