119311
If \(5^{97}\) is divided by 52 , the remainder obtained is
1 3
2 5
3 4
4 0
5 1
Explanation:
B \(5^{97}=5^{96} \times 5 =\left(5^4\right)^{24} \times 5\) \(=(625)^{24} \times 5\) \(\therefore \quad \frac{5^{97}}{52}=\frac{(625)^{24} \times 5}{52}\) If we divide, 625 by 52 , Then remainder is 1 \(\therefore\) remainder when \((625)^{24} \times 5\) divided by 52 is 5 .
Kerala CEE-2018
Permutation and Combination
119312
The number of diagonals in a hexagon is
1 8
2 9
3 10
4 11
5 12
Explanation:
B Given Side of Hexagon, \(n=6\) \(\text { Number of diagonals } =\frac{\mathrm{n}(\mathrm{n}-3)}{2}\) \(=\frac{6(6-3)}{2}\) \(=3 \times 3=9\)
Kerala CEE-2017
Permutation and Combination
119313
The sum \(S=1 / 9 !+1 / 3 ! 7 !+1 / 5 ! 5 !+1 / 7 ! 3 !+1 / 9\) ! is equal to
119311
If \(5^{97}\) is divided by 52 , the remainder obtained is
1 3
2 5
3 4
4 0
5 1
Explanation:
B \(5^{97}=5^{96} \times 5 =\left(5^4\right)^{24} \times 5\) \(=(625)^{24} \times 5\) \(\therefore \quad \frac{5^{97}}{52}=\frac{(625)^{24} \times 5}{52}\) If we divide, 625 by 52 , Then remainder is 1 \(\therefore\) remainder when \((625)^{24} \times 5\) divided by 52 is 5 .
Kerala CEE-2018
Permutation and Combination
119312
The number of diagonals in a hexagon is
1 8
2 9
3 10
4 11
5 12
Explanation:
B Given Side of Hexagon, \(n=6\) \(\text { Number of diagonals } =\frac{\mathrm{n}(\mathrm{n}-3)}{2}\) \(=\frac{6(6-3)}{2}\) \(=3 \times 3=9\)
Kerala CEE-2017
Permutation and Combination
119313
The sum \(S=1 / 9 !+1 / 3 ! 7 !+1 / 5 ! 5 !+1 / 7 ! 3 !+1 / 9\) ! is equal to
119311
If \(5^{97}\) is divided by 52 , the remainder obtained is
1 3
2 5
3 4
4 0
5 1
Explanation:
B \(5^{97}=5^{96} \times 5 =\left(5^4\right)^{24} \times 5\) \(=(625)^{24} \times 5\) \(\therefore \quad \frac{5^{97}}{52}=\frac{(625)^{24} \times 5}{52}\) If we divide, 625 by 52 , Then remainder is 1 \(\therefore\) remainder when \((625)^{24} \times 5\) divided by 52 is 5 .
Kerala CEE-2018
Permutation and Combination
119312
The number of diagonals in a hexagon is
1 8
2 9
3 10
4 11
5 12
Explanation:
B Given Side of Hexagon, \(n=6\) \(\text { Number of diagonals } =\frac{\mathrm{n}(\mathrm{n}-3)}{2}\) \(=\frac{6(6-3)}{2}\) \(=3 \times 3=9\)
Kerala CEE-2017
Permutation and Combination
119313
The sum \(S=1 / 9 !+1 / 3 ! 7 !+1 / 5 ! 5 !+1 / 7 ! 3 !+1 / 9\) ! is equal to
119311
If \(5^{97}\) is divided by 52 , the remainder obtained is
1 3
2 5
3 4
4 0
5 1
Explanation:
B \(5^{97}=5^{96} \times 5 =\left(5^4\right)^{24} \times 5\) \(=(625)^{24} \times 5\) \(\therefore \quad \frac{5^{97}}{52}=\frac{(625)^{24} \times 5}{52}\) If we divide, 625 by 52 , Then remainder is 1 \(\therefore\) remainder when \((625)^{24} \times 5\) divided by 52 is 5 .
Kerala CEE-2018
Permutation and Combination
119312
The number of diagonals in a hexagon is
1 8
2 9
3 10
4 11
5 12
Explanation:
B Given Side of Hexagon, \(n=6\) \(\text { Number of diagonals } =\frac{\mathrm{n}(\mathrm{n}-3)}{2}\) \(=\frac{6(6-3)}{2}\) \(=3 \times 3=9\)
Kerala CEE-2017
Permutation and Combination
119313
The sum \(S=1 / 9 !+1 / 3 ! 7 !+1 / 5 ! 5 !+1 / 7 ! 3 !+1 / 9\) ! is equal to
119311
If \(5^{97}\) is divided by 52 , the remainder obtained is
1 3
2 5
3 4
4 0
5 1
Explanation:
B \(5^{97}=5^{96} \times 5 =\left(5^4\right)^{24} \times 5\) \(=(625)^{24} \times 5\) \(\therefore \quad \frac{5^{97}}{52}=\frac{(625)^{24} \times 5}{52}\) If we divide, 625 by 52 , Then remainder is 1 \(\therefore\) remainder when \((625)^{24} \times 5\) divided by 52 is 5 .
Kerala CEE-2018
Permutation and Combination
119312
The number of diagonals in a hexagon is
1 8
2 9
3 10
4 11
5 12
Explanation:
B Given Side of Hexagon, \(n=6\) \(\text { Number of diagonals } =\frac{\mathrm{n}(\mathrm{n}-3)}{2}\) \(=\frac{6(6-3)}{2}\) \(=3 \times 3=9\)
Kerala CEE-2017
Permutation and Combination
119313
The sum \(S=1 / 9 !+1 / 3 ! 7 !+1 / 5 ! 5 !+1 / 7 ! 3 !+1 / 9\) ! is equal to