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Permutation and Combination

119212 If a person has 3 coins of different denominations, the number of different sums can be formed is

1 3

2 7

3 8

4 3 !

Explanation:

B : Given, number of coins $= 3$
The no. of different sums are
$=^{3} C_{1} +^{3} C_{2} +^{3} C_{3}$
$= 3 + 3 + 1 = 7$

AP EAMCET-19.08.2021

Permutation and Combination

119220 The number of ways of distributing 500 dissimilar boxes equally among ' 50 ' persons is

1

500! (10!)^{50} / 50

!

2

500! (50!)^{10} / 10

!

3

500! / (50!)^{10}

4

500! / (10!)^{50}

Explanation:

D If 500 dissimilar boxes is distributed among 50 person, then each person will get -
$\frac{500}{50} = 10 boxes$
Number of ways of distributing them,
$= \frac{500!}{(10!) (10!) (10!) \dots . (50 times)} = \frac{500!}{(10!)^{50}}$

AP EAMCET-06.07.2022

Permutation and Combination

119232 The total number of 7 digit positive integral numbers with distinct digits that can be formed using the digits $4, 3, 7, 2, 1, 0, 5$ is

1 4320

2 4340

3 4310

4 4230

5 4220

Explanation:

A Given digits are 4, 3, 7, 2, 1, 0, 5
Total number of ways $= 6 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 4320$

Kerala CEE-2016

Permutation and Combination

119212 If a person has 3 coins of different denominations, the number of different sums can be formed is

1 3

2 7

3 8

4 3 !

Explanation:

B : Given, number of coins $= 3$
The no. of different sums are
$=^{3} C_{1} +^{3} C_{2} +^{3} C_{3}$
$= 3 + 3 + 1 = 7$

AP EAMCET-19.08.2021

Permutation and Combination

119220 The number of ways of distributing 500 dissimilar boxes equally among ' 50 ' persons is

1

500! (10!)^{50} / 50

!

2

500! (50!)^{10} / 10

!

3

500! / (50!)^{10}

4

500! / (10!)^{50}

Explanation:

D If 500 dissimilar boxes is distributed among 50 person, then each person will get -
$\frac{500}{50} = 10 boxes$
Number of ways of distributing them,
$= \frac{500!}{(10!) (10!) (10!) \dots . (50 times)} = \frac{500!}{(10!)^{50}}$

AP EAMCET-06.07.2022

Permutation and Combination

119232 The total number of 7 digit positive integral numbers with distinct digits that can be formed using the digits $4, 3, 7, 2, 1, 0, 5$ is

1 4320

2 4340

3 4310

4 4230

5 4220

Explanation:

A Given digits are 4, 3, 7, 2, 1, 0, 5
Total number of ways $= 6 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 4320$

Kerala CEE-2016

Permutation and Combination

119212 If a person has 3 coins of different denominations, the number of different sums can be formed is

1 3

2 7

3 8

4 3 !

Explanation:

B : Given, number of coins $= 3$
The no. of different sums are
$=^{3} C_{1} +^{3} C_{2} +^{3} C_{3}$
$= 3 + 3 + 1 = 7$

AP EAMCET-19.08.2021

Permutation and Combination

119220 The number of ways of distributing 500 dissimilar boxes equally among ' 50 ' persons is

1

500! (10!)^{50} / 50

!

2

500! (50!)^{10} / 10

!

3

500! / (50!)^{10}

4

500! / (10!)^{50}

Explanation:

D If 500 dissimilar boxes is distributed among 50 person, then each person will get -
$\frac{500}{50} = 10 boxes$
Number of ways of distributing them,
$= \frac{500!}{(10!) (10!) (10!) \dots . (50 times)} = \frac{500!}{(10!)^{50}}$

AP EAMCET-06.07.2022

Permutation and Combination

119232 The total number of 7 digit positive integral numbers with distinct digits that can be formed using the digits $4, 3, 7, 2, 1, 0, 5$ is

1 4320

2 4340

3 4310

4 4230

5 4220

Explanation:

A Given digits are 4, 3, 7, 2, 1, 0, 5
Total number of ways $= 6 \times 6 \times 5 \times 4 \times 3 \times 2 \times 1 = 4320$

Kerala CEE-2016