118968
In how many ways 7 men and 7 women can be seated around a round table such that no two women can sit together
#[Qdiff: Hard, QCat: Numerical Based, examname: Now, [MHT CET-2021], no two women are to sit together as such the 7 women are to be arranged in seven empty seats between two consecutive men and number of arrangement will be 7 Hence, by fundamental theorem the total number ways \(=7 ! \times 6 !\), 65. A committee of 4 is to selected from 4 Engineers, 6 Doctors and 5 Lawyers. The number of ways in which there is at least one from each profession is,
118968
In how many ways 7 men and 7 women can be seated around a round table such that no two women can sit together
#[Qdiff: Hard, QCat: Numerical Based, examname: Now, [MHT CET-2021], no two women are to sit together as such the 7 women are to be arranged in seven empty seats between two consecutive men and number of arrangement will be 7 Hence, by fundamental theorem the total number ways \(=7 ! \times 6 !\), 65. A committee of 4 is to selected from 4 Engineers, 6 Doctors and 5 Lawyers. The number of ways in which there is at least one from each profession is,
118968
In how many ways 7 men and 7 women can be seated around a round table such that no two women can sit together
#[Qdiff: Hard, QCat: Numerical Based, examname: Now, [MHT CET-2021], no two women are to sit together as such the 7 women are to be arranged in seven empty seats between two consecutive men and number of arrangement will be 7 Hence, by fundamental theorem the total number ways \(=7 ! \times 6 !\), 65. A committee of 4 is to selected from 4 Engineers, 6 Doctors and 5 Lawyers. The number of ways in which there is at least one from each profession is,
118968
In how many ways 7 men and 7 women can be seated around a round table such that no two women can sit together
#[Qdiff: Hard, QCat: Numerical Based, examname: Now, [MHT CET-2021], no two women are to sit together as such the 7 women are to be arranged in seven empty seats between two consecutive men and number of arrangement will be 7 Hence, by fundamental theorem the total number ways \(=7 ! \times 6 !\), 65. A committee of 4 is to selected from 4 Engineers, 6 Doctors and 5 Lawyers. The number of ways in which there is at least one from each profession is,