Permutation as an Arrangement
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Permutation and Combination

118968 In how many ways 7 men and 7 women can be seated around a round table such that no two women can sit together
#[Qdiff: Hard, QCat: Numerical Based, examname: Now, [MHT CET-2021], no two women are to sit together as such the 7 women are to be arranged in seven empty seats between two consecutive men and number of arrangement will be 7 Hence, by fundamental theorem the total number ways \(=7 ! \times 6 !\), 65. A committee of 4 is to selected from 4 Engineers, 6 Doctors and 5 Lawyers. The number of ways in which there is at least one from each profession is,

1 \((7 !)^2\)
2 \(7 ! \times 6\) !
3 \((6 !)^2\)
4 7 !
Permutation and Combination

118973 The number of ways in which the letters \(x_1\), \(\mathrm{x}_2, \ldots \mathrm{x}_{10,} \mathrm{y}_1, \mathrm{y}_2, \ldots \mathrm{y}_{15}\) can be arranged in a line such that the suffixes of \(x\) and those of \(y\) are in ascending order of magnitude is

1 \({ }^{25} \mathrm{C}_{10} 10 ! 5\) !
2 \({ }^{25} \mathrm{C}_{15}\)
3 \({ }^{25} \mathrm{P}_{10}\)
4 None of these
Permutation and Combination

118974 In a polygon no three diagonals are concurrent. If the total number of points of intersection of diagonals interior to the polygon be 70 , then the number of diagonals of the polygon, is

1 8
2 20
3 28
4 none of these
Permutation and Combination

118975 Let \(\mathbf{T}_{\mathbf{n}}\) denote the number of triangles which can be formed using the vertices of a regular polygon of \(n\) sides. If \(T_{n+1}-T_n=21\), then \(n\) equals to

1 5
2 7
3 6
4 4
Permutation and Combination

118968 In how many ways 7 men and 7 women can be seated around a round table such that no two women can sit together
#[Qdiff: Hard, QCat: Numerical Based, examname: Now, [MHT CET-2021], no two women are to sit together as such the 7 women are to be arranged in seven empty seats between two consecutive men and number of arrangement will be 7 Hence, by fundamental theorem the total number ways \(=7 ! \times 6 !\), 65. A committee of 4 is to selected from 4 Engineers, 6 Doctors and 5 Lawyers. The number of ways in which there is at least one from each profession is,

1 \((7 !)^2\)
2 \(7 ! \times 6\) !
3 \((6 !)^2\)
4 7 !
Permutation and Combination

118973 The number of ways in which the letters \(x_1\), \(\mathrm{x}_2, \ldots \mathrm{x}_{10,} \mathrm{y}_1, \mathrm{y}_2, \ldots \mathrm{y}_{15}\) can be arranged in a line such that the suffixes of \(x\) and those of \(y\) are in ascending order of magnitude is

1 \({ }^{25} \mathrm{C}_{10} 10 ! 5\) !
2 \({ }^{25} \mathrm{C}_{15}\)
3 \({ }^{25} \mathrm{P}_{10}\)
4 None of these
Permutation and Combination

118974 In a polygon no three diagonals are concurrent. If the total number of points of intersection of diagonals interior to the polygon be 70 , then the number of diagonals of the polygon, is

1 8
2 20
3 28
4 none of these
Permutation and Combination

118975 Let \(\mathbf{T}_{\mathbf{n}}\) denote the number of triangles which can be formed using the vertices of a regular polygon of \(n\) sides. If \(T_{n+1}-T_n=21\), then \(n\) equals to

1 5
2 7
3 6
4 4
Permutation and Combination

118968 In how many ways 7 men and 7 women can be seated around a round table such that no two women can sit together
#[Qdiff: Hard, QCat: Numerical Based, examname: Now, [MHT CET-2021], no two women are to sit together as such the 7 women are to be arranged in seven empty seats between two consecutive men and number of arrangement will be 7 Hence, by fundamental theorem the total number ways \(=7 ! \times 6 !\), 65. A committee of 4 is to selected from 4 Engineers, 6 Doctors and 5 Lawyers. The number of ways in which there is at least one from each profession is,

1 \((7 !)^2\)
2 \(7 ! \times 6\) !
3 \((6 !)^2\)
4 7 !
Permutation and Combination

118973 The number of ways in which the letters \(x_1\), \(\mathrm{x}_2, \ldots \mathrm{x}_{10,} \mathrm{y}_1, \mathrm{y}_2, \ldots \mathrm{y}_{15}\) can be arranged in a line such that the suffixes of \(x\) and those of \(y\) are in ascending order of magnitude is

1 \({ }^{25} \mathrm{C}_{10} 10 ! 5\) !
2 \({ }^{25} \mathrm{C}_{15}\)
3 \({ }^{25} \mathrm{P}_{10}\)
4 None of these
Permutation and Combination

118974 In a polygon no three diagonals are concurrent. If the total number of points of intersection of diagonals interior to the polygon be 70 , then the number of diagonals of the polygon, is

1 8
2 20
3 28
4 none of these
Permutation and Combination

118975 Let \(\mathbf{T}_{\mathbf{n}}\) denote the number of triangles which can be formed using the vertices of a regular polygon of \(n\) sides. If \(T_{n+1}-T_n=21\), then \(n\) equals to

1 5
2 7
3 6
4 4
Permutation and Combination

118968 In how many ways 7 men and 7 women can be seated around a round table such that no two women can sit together
#[Qdiff: Hard, QCat: Numerical Based, examname: Now, [MHT CET-2021], no two women are to sit together as such the 7 women are to be arranged in seven empty seats between two consecutive men and number of arrangement will be 7 Hence, by fundamental theorem the total number ways \(=7 ! \times 6 !\), 65. A committee of 4 is to selected from 4 Engineers, 6 Doctors and 5 Lawyers. The number of ways in which there is at least one from each profession is,

1 \((7 !)^2\)
2 \(7 ! \times 6\) !
3 \((6 !)^2\)
4 7 !
Permutation and Combination

118973 The number of ways in which the letters \(x_1\), \(\mathrm{x}_2, \ldots \mathrm{x}_{10,} \mathrm{y}_1, \mathrm{y}_2, \ldots \mathrm{y}_{15}\) can be arranged in a line such that the suffixes of \(x\) and those of \(y\) are in ascending order of magnitude is

1 \({ }^{25} \mathrm{C}_{10} 10 ! 5\) !
2 \({ }^{25} \mathrm{C}_{15}\)
3 \({ }^{25} \mathrm{P}_{10}\)
4 None of these
Permutation and Combination

118974 In a polygon no three diagonals are concurrent. If the total number of points of intersection of diagonals interior to the polygon be 70 , then the number of diagonals of the polygon, is

1 8
2 20
3 28
4 none of these
Permutation and Combination

118975 Let \(\mathbf{T}_{\mathbf{n}}\) denote the number of triangles which can be formed using the vertices of a regular polygon of \(n\) sides. If \(T_{n+1}-T_n=21\), then \(n\) equals to

1 5
2 7
3 6
4 4