120248
If a normal chord at a point on the parabola subtends a right angle at its vertex, then
1
2
3
4
Explanation:
D Equation of given parabola is
Equation o normal chord at point on the parabola (i) is -
The chord (ii) subtends a right angle at vertex of parabola so first homogenise the parabola (i) with the help of line (ii), we get -
The sum of the coefficients of and terms should be zero.
So,
AP EAMCET-20.04.2019
Parabola
120249
The locus of the points intersections of perpendicular normal's to the parabola 4ax, is
1
2
3
4
Explanation:
D Given, parabola Let the equation contain slope to the parabola is which passes through point Then,
Let the roots be and then
Due to perpendicular normal Now, taking locus we can get -
AP EAMCET-20.04.2019
Parabola
120250
If is a normal to the parabola then the condition is
1
2
3
4
Explanation:
C Given, is normal to then,
Slope, , constant, Now,
AP EAMCET-04.07.2021
Parabola
120251
If and the origin are the points of intersection of the parabolas and ; and if is the acute angle between these curves at , then
1 2
2
3
4 3
Explanation:
C Given,
Differentiate w.r.tx
Differentiate w. r.t. Now, Hence, Now,
AP EAMCET-24.04.2018
Parabola
120252
The angle between the tangents drawn from the point to the parabola , is:
1
2
3
4
Explanation:
D We know that, equation of tangent on is As it passes through then,
Let, the roots and
120248
If a normal chord at a point on the parabola subtends a right angle at its vertex, then
1
2
3
4
Explanation:
D Equation of given parabola is
Equation o normal chord at point on the parabola (i) is -
The chord (ii) subtends a right angle at vertex of parabola so first homogenise the parabola (i) with the help of line (ii), we get -
The sum of the coefficients of and terms should be zero.
So,
AP EAMCET-20.04.2019
Parabola
120249
The locus of the points intersections of perpendicular normal's to the parabola 4ax, is
1
2
3
4
Explanation:
D Given, parabola Let the equation contain slope to the parabola is which passes through point Then,
Let the roots be and then
Due to perpendicular normal Now, taking locus we can get -
AP EAMCET-20.04.2019
Parabola
120250
If is a normal to the parabola then the condition is
1
2
3
4
Explanation:
C Given, is normal to then,
Slope, , constant, Now,
AP EAMCET-04.07.2021
Parabola
120251
If and the origin are the points of intersection of the parabolas and ; and if is the acute angle between these curves at , then
1 2
2
3
4 3
Explanation:
C Given,
Differentiate w.r.tx
Differentiate w. r.t. Now, Hence, Now,
AP EAMCET-24.04.2018
Parabola
120252
The angle between the tangents drawn from the point to the parabola , is:
1
2
3
4
Explanation:
D We know that, equation of tangent on is As it passes through then,
Let, the roots and
120248
If a normal chord at a point on the parabola subtends a right angle at its vertex, then
1
2
3
4
Explanation:
D Equation of given parabola is
Equation o normal chord at point on the parabola (i) is -
The chord (ii) subtends a right angle at vertex of parabola so first homogenise the parabola (i) with the help of line (ii), we get -
The sum of the coefficients of and terms should be zero.
So,
AP EAMCET-20.04.2019
Parabola
120249
The locus of the points intersections of perpendicular normal's to the parabola 4ax, is
1
2
3
4
Explanation:
D Given, parabola Let the equation contain slope to the parabola is which passes through point Then,
Let the roots be and then
Due to perpendicular normal Now, taking locus we can get -
AP EAMCET-20.04.2019
Parabola
120250
If is a normal to the parabola then the condition is
1
2
3
4
Explanation:
C Given, is normal to then,
Slope, , constant, Now,
AP EAMCET-04.07.2021
Parabola
120251
If and the origin are the points of intersection of the parabolas and ; and if is the acute angle between these curves at , then
1 2
2
3
4 3
Explanation:
C Given,
Differentiate w.r.tx
Differentiate w. r.t. Now, Hence, Now,
AP EAMCET-24.04.2018
Parabola
120252
The angle between the tangents drawn from the point to the parabola , is:
1
2
3
4
Explanation:
D We know that, equation of tangent on is As it passes through then,
Let, the roots and
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Parabola
120248
If a normal chord at a point on the parabola subtends a right angle at its vertex, then
1
2
3
4
Explanation:
D Equation of given parabola is
Equation o normal chord at point on the parabola (i) is -
The chord (ii) subtends a right angle at vertex of parabola so first homogenise the parabola (i) with the help of line (ii), we get -
The sum of the coefficients of and terms should be zero.
So,
AP EAMCET-20.04.2019
Parabola
120249
The locus of the points intersections of perpendicular normal's to the parabola 4ax, is
1
2
3
4
Explanation:
D Given, parabola Let the equation contain slope to the parabola is which passes through point Then,
Let the roots be and then
Due to perpendicular normal Now, taking locus we can get -
AP EAMCET-20.04.2019
Parabola
120250
If is a normal to the parabola then the condition is
1
2
3
4
Explanation:
C Given, is normal to then,
Slope, , constant, Now,
AP EAMCET-04.07.2021
Parabola
120251
If and the origin are the points of intersection of the parabolas and ; and if is the acute angle between these curves at , then
1 2
2
3
4 3
Explanation:
C Given,
Differentiate w.r.tx
Differentiate w. r.t. Now, Hence, Now,
AP EAMCET-24.04.2018
Parabola
120252
The angle between the tangents drawn from the point to the parabola , is:
1
2
3
4
Explanation:
D We know that, equation of tangent on is As it passes through then,
Let, the roots and
120248
If a normal chord at a point on the parabola subtends a right angle at its vertex, then
1
2
3
4
Explanation:
D Equation of given parabola is
Equation o normal chord at point on the parabola (i) is -
The chord (ii) subtends a right angle at vertex of parabola so first homogenise the parabola (i) with the help of line (ii), we get -
The sum of the coefficients of and terms should be zero.
So,
AP EAMCET-20.04.2019
Parabola
120249
The locus of the points intersections of perpendicular normal's to the parabola 4ax, is
1
2
3
4
Explanation:
D Given, parabola Let the equation contain slope to the parabola is which passes through point Then,
Let the roots be and then
Due to perpendicular normal Now, taking locus we can get -
AP EAMCET-20.04.2019
Parabola
120250
If is a normal to the parabola then the condition is
1
2
3
4
Explanation:
C Given, is normal to then,
Slope, , constant, Now,
AP EAMCET-04.07.2021
Parabola
120251
If and the origin are the points of intersection of the parabolas and ; and if is the acute angle between these curves at , then
1 2
2
3
4 3
Explanation:
C Given,
Differentiate w.r.tx
Differentiate w. r.t. Now, Hence, Now,
AP EAMCET-24.04.2018
Parabola
120252
The angle between the tangents drawn from the point to the parabola , is:
1
2
3
4
Explanation:
D We know that, equation of tangent on is As it passes through then,
Let, the roots and