Equation of Parabola with Given Focus and Directrix
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NEET DIGITAL LIBRARY
Parabola

120953 The distance between the vertex and the focus to the parabola \(x^2-2 x-3 y-2=0\) is

1 \(\frac{4}{5}\)
2 \(\frac{3}{4}\)
3 \(\frac{1}{2}\)
4 \(\frac{5}{6}\)
AP EAMCET-2016
Parabola

120954 The locus of the mid-points of all chords of the parabola \(y^2=4\) ax through its vertex is another parabola with directrix

1 \(x=-a\)
2 \(x=a\)
3 \(x=0\)
4 \(x=-\frac{a}{2}\)
WB JEE-2016
Parabola

120955 The length of the latus rectum of the parabola \(20\left(x^2+y^2-6 x-2 y+10\right)=(4 x-2 y-5)^2\), is

1 \(\frac{\sqrt{5}}{2}\)
2 \(2 \sqrt{5}\)
3 \(\sqrt{5}\)
4 \(4 \sqrt{5}\)
AP EAMCET-22.04.2019
Parabola

120956 The equation of the latus rectum of a parabola is \(x+y=8\) and the equation of the tangent at the vertex is \(x+y=12\). Then, the length of the latus rectum is

1 \(4 \sqrt{2}\) units
2 \(2 \sqrt{2}\) units
3 8 units
4 \(8 \sqrt{2}\) units
WB JEE-2020
Join With Us for More Updates
Parabola

120953 The distance between the vertex and the focus to the parabola \(x^2-2 x-3 y-2=0\) is

1 \(\frac{4}{5}\)
2 \(\frac{3}{4}\)
3 \(\frac{1}{2}\)
4 \(\frac{5}{6}\)
AP EAMCET-2016
Parabola

120954 The locus of the mid-points of all chords of the parabola \(y^2=4\) ax through its vertex is another parabola with directrix

1 \(x=-a\)
2 \(x=a\)
3 \(x=0\)
4 \(x=-\frac{a}{2}\)
WB JEE-2016
Parabola

120955 The length of the latus rectum of the parabola \(20\left(x^2+y^2-6 x-2 y+10\right)=(4 x-2 y-5)^2\), is

1 \(\frac{\sqrt{5}}{2}\)
2 \(2 \sqrt{5}\)
3 \(\sqrt{5}\)
4 \(4 \sqrt{5}\)
AP EAMCET-22.04.2019
Parabola

120956 The equation of the latus rectum of a parabola is \(x+y=8\) and the equation of the tangent at the vertex is \(x+y=12\). Then, the length of the latus rectum is

1 \(4 \sqrt{2}\) units
2 \(2 \sqrt{2}\) units
3 8 units
4 \(8 \sqrt{2}\) units
WB JEE-2020
For More Updates join with Us
Parabola

120953 The distance between the vertex and the focus to the parabola \(x^2-2 x-3 y-2=0\) is

1 \(\frac{4}{5}\)
2 \(\frac{3}{4}\)
3 \(\frac{1}{2}\)
4 \(\frac{5}{6}\)
AP EAMCET-2016
Parabola

120954 The locus of the mid-points of all chords of the parabola \(y^2=4\) ax through its vertex is another parabola with directrix

1 \(x=-a\)
2 \(x=a\)
3 \(x=0\)
4 \(x=-\frac{a}{2}\)
WB JEE-2016
Parabola

120955 The length of the latus rectum of the parabola \(20\left(x^2+y^2-6 x-2 y+10\right)=(4 x-2 y-5)^2\), is

1 \(\frac{\sqrt{5}}{2}\)
2 \(2 \sqrt{5}\)
3 \(\sqrt{5}\)
4 \(4 \sqrt{5}\)
AP EAMCET-22.04.2019
Parabola

120956 The equation of the latus rectum of a parabola is \(x+y=8\) and the equation of the tangent at the vertex is \(x+y=12\). Then, the length of the latus rectum is

1 \(4 \sqrt{2}\) units
2 \(2 \sqrt{2}\) units
3 8 units
4 \(8 \sqrt{2}\) units
WB JEE-2020
NEET DIGITAL LIBRARY
Parabola

120953 The distance between the vertex and the focus to the parabola \(x^2-2 x-3 y-2=0\) is

1 \(\frac{4}{5}\)
2 \(\frac{3}{4}\)
3 \(\frac{1}{2}\)
4 \(\frac{5}{6}\)
AP EAMCET-2016
Parabola

120954 The locus of the mid-points of all chords of the parabola \(y^2=4\) ax through its vertex is another parabola with directrix

1 \(x=-a\)
2 \(x=a\)
3 \(x=0\)
4 \(x=-\frac{a}{2}\)
WB JEE-2016
Parabola

120955 The length of the latus rectum of the parabola \(20\left(x^2+y^2-6 x-2 y+10\right)=(4 x-2 y-5)^2\), is

1 \(\frac{\sqrt{5}}{2}\)
2 \(2 \sqrt{5}\)
3 \(\sqrt{5}\)
4 \(4 \sqrt{5}\)
AP EAMCET-22.04.2019
Parabola

120956 The equation of the latus rectum of a parabola is \(x+y=8\) and the equation of the tangent at the vertex is \(x+y=12\). Then, the length of the latus rectum is

1 \(4 \sqrt{2}\) units
2 \(2 \sqrt{2}\) units
3 8 units
4 \(8 \sqrt{2}\) units
WB JEE-2020
Join With Us for More Updates