Explanation:
D Given that,
\(\text { Equation of circle }=x^2+y^2-8 x-4 y+c=0\)
\(\text { The centre of the given circle is } \mathrm{C} \equiv(4,2)\)
\(\text { Let, Point } \mathrm{A} \equiv(-3,2)\)
\(\text { If }(\alpha, \beta) \text { are the coordinates of }\)
\(\text { he other end of the diameter, }\)
\(\text { then, as the middle point of the }\)
diameter is the centre,
\(\therefore \frac{\alpha-3}{2}=4, \frac{\beta+2}{2}=2\)
\(\alpha=11, \beta=2\)

Thus, the coordinates of the other end of diameter are \((11,2)\)