118001 If \(\mathrm{z}_{\mathrm{k}}=\cos \alpha_{\mathrm{k}}+i \quad \sin \alpha_{\mathrm{k}} \quad\) and \(\sum_{k=1}^n z_k=0\), then \(\sum_{k=1}^n z_k^{-1}\) equals

118003 Let \(\mathrm{n}\) be a positive integer such that \(\sin \frac{\pi}{2 n}+\cos \frac{\pi}{2 n}=\frac{\sqrt{n}}{2}\), then

118004 \((-1+i \sqrt{3})^{60}=\)

118005 \(\sum_{\mathrm{k}=1}^6\left(\sin \frac{2 \pi \mathrm{k}}{7}-i \cos \frac{2 \pi \mathrm{k}}{7}\right)=\)

118006 \(\frac{(1+i)^{2016}}{(1-i)^{2014}}=\)

118001 If \(\mathrm{z}_{\mathrm{k}}=\cos \alpha_{\mathrm{k}}+i \quad \sin \alpha_{\mathrm{k}} \quad\) and \(\sum_{k=1}^n z_k=0\), then \(\sum_{k=1}^n z_k^{-1}\) equals

118003 Let \(\mathrm{n}\) be a positive integer such that \(\sin \frac{\pi}{2 n}+\cos \frac{\pi}{2 n}=\frac{\sqrt{n}}{2}\), then

118004 \((-1+i \sqrt{3})^{60}=\)

118005 \(\sum_{\mathrm{k}=1}^6\left(\sin \frac{2 \pi \mathrm{k}}{7}-i \cos \frac{2 \pi \mathrm{k}}{7}\right)=\)

118006 \(\frac{(1+i)^{2016}}{(1-i)^{2014}}=\)

118001 If \(\mathrm{z}_{\mathrm{k}}=\cos \alpha_{\mathrm{k}}+i \quad \sin \alpha_{\mathrm{k}} \quad\) and \(\sum_{k=1}^n z_k=0\), then \(\sum_{k=1}^n z_k^{-1}\) equals

118003 Let \(\mathrm{n}\) be a positive integer such that \(\sin \frac{\pi}{2 n}+\cos \frac{\pi}{2 n}=\frac{\sqrt{n}}{2}\), then

118004 \((-1+i \sqrt{3})^{60}=\)

118005 \(\sum_{\mathrm{k}=1}^6\left(\sin \frac{2 \pi \mathrm{k}}{7}-i \cos \frac{2 \pi \mathrm{k}}{7}\right)=\)

118006 \(\frac{(1+i)^{2016}}{(1-i)^{2014}}=\)

118001 If \(\mathrm{z}_{\mathrm{k}}=\cos \alpha_{\mathrm{k}}+i \quad \sin \alpha_{\mathrm{k}} \quad\) and \(\sum_{k=1}^n z_k=0\), then \(\sum_{k=1}^n z_k^{-1}\) equals

118003 Let \(\mathrm{n}\) be a positive integer such that \(\sin \frac{\pi}{2 n}+\cos \frac{\pi}{2 n}=\frac{\sqrt{n}}{2}\), then

118004 \((-1+i \sqrt{3})^{60}=\)

118005 \(\sum_{\mathrm{k}=1}^6\left(\sin \frac{2 \pi \mathrm{k}}{7}-i \cos \frac{2 \pi \mathrm{k}}{7}\right)=\)

118006 \(\frac{(1+i)^{2016}}{(1-i)^{2014}}=\)

118001 If \(\mathrm{z}_{\mathrm{k}}=\cos \alpha_{\mathrm{k}}+i \quad \sin \alpha_{\mathrm{k}} \quad\) and \(\sum_{k=1}^n z_k=0\), then \(\sum_{k=1}^n z_k^{-1}\) equals

118003 Let \(\mathrm{n}\) be a positive integer such that \(\sin \frac{\pi}{2 n}+\cos \frac{\pi}{2 n}=\frac{\sqrt{n}}{2}\), then

118004 \((-1+i \sqrt{3})^{60}=\)

118005 \(\sum_{\mathrm{k}=1}^6\left(\sin \frac{2 \pi \mathrm{k}}{7}-i \cos \frac{2 \pi \mathrm{k}}{7}\right)=\)

118006 \(\frac{(1+i)^{2016}}{(1-i)^{2014}}=\)