Explanation:
Ethane is obtained by electrolysis of dipotassium succinate as follows
$\underset{Dipot.\,\,succinate}{\mathop{\begin{matrix}
C{{H}_{2}}COOK \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{2}}COOK \\
\end{matrix}}}\,$ $\xrightarrow{ionization}$ $\begin{matrix}
C{{H}_{2}}CO{{O}^{-}} \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{2}}CO{{O}^{-}} \\
\end{matrix}$ $+2K^+$
\(2{{H}_{2}}O\,\overset{ionization}{\longleftrightarrow}2O{{H}^{-\,}}+\,2{{H}^{+}}\)
At anode :
$\begin{matrix}
C{{H}_{2}}CO{{O}^{-}} \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{2}}CO{{O}^{-}} \\
\end{matrix}$ $\xrightarrow{2{{e}^{-}}}$ $\underset{Unstable}{\mathop{\left[ \begin{matrix}
C{{H}_{2}}COO \\
|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{2}}COO \\
\end{matrix} \right]}}\,$ $\to $ $\begin{matrix}
C{{H}_{2}} \\
||\,\,\,\,\,\, \\
C{{H}_{2}} \\
\end{matrix}$ $+\,2CO_2$
At cathode :
\(2H^+ + 2e^-\to [2H]\to H_2\)
