28305
\(Y\) \(\mathop {\xleftarrow{{(i)\,N{H_3},\Delta }}}\limits_{(ii)\,KOD,B{r_2}\Delta } \) (image) \(\mathop {\xrightarrow{{(i)\,N{D_3},\Delta }}}\limits_{(ii)\,KOH,B{r_2}\Delta } X,\)What are \(X\) and \(Y\) :
1 \(X\) is (image) ; \(Y\) is (image)
2 \(X\) is (image) ; \(Y\) is (image)
3 both (image)
4 both (image)
Explanation:
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28306
Major end product of the following sequence of reaction is:\(CH_3CH_2CH_2CONH_2\) \(\mathop {\xrightarrow{{Ca{{(OH)}_2},C{l_2}}}}\limits_\Delta X\xrightarrow{{HN{O_2}}}Z\)
\(CH _3 CH _2 CH _2 CONH _2 \frac{ Ca ( OH )_2, Cl _2}{\Delta} CH _3 CH _2 CH _2 NH _2 \stackrel{ HNO _2}{\longrightarrow} CH _3 CH _2 ZH _2 OH\) The first step is the Hoffmann's bromamide reaction in which butanamide gives n-propyl amine which contains one carbon atom less. In the second reaction, nitrous acid reacts with \(n\)-propyl amine to form \(n\) propyl alcohol.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28309
Acetic anhydride and ammonia gives the product :
1 \(CH_3CONH_2\)
2 \(CH_3CONHCH_3\)
3 \(CH_3CN\)
4 \(CH_3COONH_4\)
Explanation:
Acetic anhydride reacts with ammonia to form acetamide \(\left( CH _3 CONH _2\right)\).
28305
\(Y\) \(\mathop {\xleftarrow{{(i)\,N{H_3},\Delta }}}\limits_{(ii)\,KOD,B{r_2}\Delta } \) (image) \(\mathop {\xrightarrow{{(i)\,N{D_3},\Delta }}}\limits_{(ii)\,KOH,B{r_2}\Delta } X,\)What are \(X\) and \(Y\) :
1 \(X\) is (image) ; \(Y\) is (image)
2 \(X\) is (image) ; \(Y\) is (image)
3 both (image)
4 both (image)
Explanation:
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28306
Major end product of the following sequence of reaction is:\(CH_3CH_2CH_2CONH_2\) \(\mathop {\xrightarrow{{Ca{{(OH)}_2},C{l_2}}}}\limits_\Delta X\xrightarrow{{HN{O_2}}}Z\)
\(CH _3 CH _2 CH _2 CONH _2 \frac{ Ca ( OH )_2, Cl _2}{\Delta} CH _3 CH _2 CH _2 NH _2 \stackrel{ HNO _2}{\longrightarrow} CH _3 CH _2 ZH _2 OH\) The first step is the Hoffmann's bromamide reaction in which butanamide gives n-propyl amine which contains one carbon atom less. In the second reaction, nitrous acid reacts with \(n\)-propyl amine to form \(n\) propyl alcohol.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28309
Acetic anhydride and ammonia gives the product :
1 \(CH_3CONH_2\)
2 \(CH_3CONHCH_3\)
3 \(CH_3CN\)
4 \(CH_3COONH_4\)
Explanation:
Acetic anhydride reacts with ammonia to form acetamide \(\left( CH _3 CONH _2\right)\).
28305
\(Y\) \(\mathop {\xleftarrow{{(i)\,N{H_3},\Delta }}}\limits_{(ii)\,KOD,B{r_2}\Delta } \) (image) \(\mathop {\xrightarrow{{(i)\,N{D_3},\Delta }}}\limits_{(ii)\,KOH,B{r_2}\Delta } X,\)What are \(X\) and \(Y\) :
1 \(X\) is (image) ; \(Y\) is (image)
2 \(X\) is (image) ; \(Y\) is (image)
3 both (image)
4 both (image)
Explanation:
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28306
Major end product of the following sequence of reaction is:\(CH_3CH_2CH_2CONH_2\) \(\mathop {\xrightarrow{{Ca{{(OH)}_2},C{l_2}}}}\limits_\Delta X\xrightarrow{{HN{O_2}}}Z\)
\(CH _3 CH _2 CH _2 CONH _2 \frac{ Ca ( OH )_2, Cl _2}{\Delta} CH _3 CH _2 CH _2 NH _2 \stackrel{ HNO _2}{\longrightarrow} CH _3 CH _2 ZH _2 OH\) The first step is the Hoffmann's bromamide reaction in which butanamide gives n-propyl amine which contains one carbon atom less. In the second reaction, nitrous acid reacts with \(n\)-propyl amine to form \(n\) propyl alcohol.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28309
Acetic anhydride and ammonia gives the product :
1 \(CH_3CONH_2\)
2 \(CH_3CONHCH_3\)
3 \(CH_3CN\)
4 \(CH_3COONH_4\)
Explanation:
Acetic anhydride reacts with ammonia to form acetamide \(\left( CH _3 CONH _2\right)\).
28305
\(Y\) \(\mathop {\xleftarrow{{(i)\,N{H_3},\Delta }}}\limits_{(ii)\,KOD,B{r_2}\Delta } \) (image) \(\mathop {\xrightarrow{{(i)\,N{D_3},\Delta }}}\limits_{(ii)\,KOH,B{r_2}\Delta } X,\)What are \(X\) and \(Y\) :
1 \(X\) is (image) ; \(Y\) is (image)
2 \(X\) is (image) ; \(Y\) is (image)
3 both (image)
4 both (image)
Explanation:
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28306
Major end product of the following sequence of reaction is:\(CH_3CH_2CH_2CONH_2\) \(\mathop {\xrightarrow{{Ca{{(OH)}_2},C{l_2}}}}\limits_\Delta X\xrightarrow{{HN{O_2}}}Z\)
\(CH _3 CH _2 CH _2 CONH _2 \frac{ Ca ( OH )_2, Cl _2}{\Delta} CH _3 CH _2 CH _2 NH _2 \stackrel{ HNO _2}{\longrightarrow} CH _3 CH _2 ZH _2 OH\) The first step is the Hoffmann's bromamide reaction in which butanamide gives n-propyl amine which contains one carbon atom less. In the second reaction, nitrous acid reacts with \(n\)-propyl amine to form \(n\) propyl alcohol.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28309
Acetic anhydride and ammonia gives the product :
1 \(CH_3CONH_2\)
2 \(CH_3CONHCH_3\)
3 \(CH_3CN\)
4 \(CH_3COONH_4\)
Explanation:
Acetic anhydride reacts with ammonia to form acetamide \(\left( CH _3 CONH _2\right)\).
28305
\(Y\) \(\mathop {\xleftarrow{{(i)\,N{H_3},\Delta }}}\limits_{(ii)\,KOD,B{r_2}\Delta } \) (image) \(\mathop {\xrightarrow{{(i)\,N{D_3},\Delta }}}\limits_{(ii)\,KOH,B{r_2}\Delta } X,\)What are \(X\) and \(Y\) :
1 \(X\) is (image) ; \(Y\) is (image)
2 \(X\) is (image) ; \(Y\) is (image)
3 both (image)
4 both (image)
Explanation:
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28306
Major end product of the following sequence of reaction is:\(CH_3CH_2CH_2CONH_2\) \(\mathop {\xrightarrow{{Ca{{(OH)}_2},C{l_2}}}}\limits_\Delta X\xrightarrow{{HN{O_2}}}Z\)
\(CH _3 CH _2 CH _2 CONH _2 \frac{ Ca ( OH )_2, Cl _2}{\Delta} CH _3 CH _2 CH _2 NH _2 \stackrel{ HNO _2}{\longrightarrow} CH _3 CH _2 ZH _2 OH\) The first step is the Hoffmann's bromamide reaction in which butanamide gives n-propyl amine which contains one carbon atom less. In the second reaction, nitrous acid reacts with \(n\)-propyl amine to form \(n\) propyl alcohol.
ALDEHYDES, KETONES AND CARBOXYLIC ACID
28309
Acetic anhydride and ammonia gives the product :
1 \(CH_3CONH_2\)
2 \(CH_3CONHCH_3\)
3 \(CH_3CN\)
4 \(CH_3COONH_4\)
Explanation:
Acetic anhydride reacts with ammonia to form acetamide \(\left( CH _3 CONH _2\right)\).