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COORDINATION COMPOUNDS

28760 The neutral ligand is

1 Chloro

2 Hydroxo

3 Ammine

4 Oxalato

Explanation:

(c) Ammine $(N H_{2})$ is neutral ligand.

COORDINATION COMPOUNDS

28761 The ligands which can get attached to the central metal ion through more than one atom are called

1 Ambident ligands

2 Polydentate ligands

3 Chelate ligands

4 Neutral ligands

COORDINATION COMPOUNDS

28762 A strong ligand gives a complex which is generally called

1 High spin

2 High energy

3 Low spin

4 Stable

COORDINATION COMPOUNDS

28763 $C N^{-}$ is a strong field ligand. This is due to the fact that

1 It can accept electron from metal species

2 It forms high spin complexes with metal species

3 It carries negative charge.

4 It is a pseudohalide

Explanation:

(d)Cyanide ion is strong field ligand because it is a pseudohalide ion pseudohalide ions are stronger coordinating ligand & they have the ability to form $σ$ bond (from the pseudohalide to the metal) and $π$ bond (from the metal to pseudohalide).

COORDINATION COMPOUNDS

28764 Considering $H_{2} O$ as a weak field ligand, the number of unpaired electrons in $[M n (H_{2} O)_{6}]^{2 +}$ will be (At. No. of $M n = 25$ )

1

2

2

4

3

3

4

5

Explanation:

(d) In presence of weak ligand field, there will be no pairing of electrons. So it will form a high spin complex. i.e. the number of unpaired electrons $= 5.$ 342-s39

COORDINATION COMPOUNDS

28760 The neutral ligand is

1 Chloro

2 Hydroxo

3 Ammine

4 Oxalato

Explanation:

(c) Ammine $(N H_{2})$ is neutral ligand.

COORDINATION COMPOUNDS

28761 The ligands which can get attached to the central metal ion through more than one atom are called

1 Ambident ligands

2 Polydentate ligands

3 Chelate ligands

4 Neutral ligands

COORDINATION COMPOUNDS

28762 A strong ligand gives a complex which is generally called

1 High spin

2 High energy

3 Low spin

4 Stable

COORDINATION COMPOUNDS

28763 $C N^{-}$ is a strong field ligand. This is due to the fact that

1 It can accept electron from metal species

2 It forms high spin complexes with metal species

3 It carries negative charge.

4 It is a pseudohalide

Explanation:

(d)Cyanide ion is strong field ligand because it is a pseudohalide ion pseudohalide ions are stronger coordinating ligand & they have the ability to form $σ$ bond (from the pseudohalide to the metal) and $π$ bond (from the metal to pseudohalide).

COORDINATION COMPOUNDS

28764 Considering $H_{2} O$ as a weak field ligand, the number of unpaired electrons in $[M n (H_{2} O)_{6}]^{2 +}$ will be (At. No. of $M n = 25$ )

1

2

2

4

3

3

4

5

Explanation:

(d) In presence of weak ligand field, there will be no pairing of electrons. So it will form a high spin complex. i.e. the number of unpaired electrons $= 5.$ 342-s39

COORDINATION COMPOUNDS

28760 The neutral ligand is

1 Chloro

2 Hydroxo

3 Ammine

4 Oxalato

Explanation:

(c) Ammine $(N H_{2})$ is neutral ligand.

COORDINATION COMPOUNDS

28761 The ligands which can get attached to the central metal ion through more than one atom are called

1 Ambident ligands

2 Polydentate ligands

3 Chelate ligands

4 Neutral ligands

COORDINATION COMPOUNDS

28762 A strong ligand gives a complex which is generally called

1 High spin

2 High energy

3 Low spin

4 Stable

COORDINATION COMPOUNDS

28763 $C N^{-}$ is a strong field ligand. This is due to the fact that

1 It can accept electron from metal species

2 It forms high spin complexes with metal species

3 It carries negative charge.

4 It is a pseudohalide

Explanation:

(d)Cyanide ion is strong field ligand because it is a pseudohalide ion pseudohalide ions are stronger coordinating ligand & they have the ability to form $σ$ bond (from the pseudohalide to the metal) and $π$ bond (from the metal to pseudohalide).

COORDINATION COMPOUNDS

28764 Considering $H_{2} O$ as a weak field ligand, the number of unpaired electrons in $[M n (H_{2} O)_{6}]^{2 +}$ will be (At. No. of $M n = 25$ )

1

2

2

4

3

3

4

5

Explanation:

(d) In presence of weak ligand field, there will be no pairing of electrons. So it will form a high spin complex. i.e. the number of unpaired electrons $= 5.$ 342-s39

COORDINATION COMPOUNDS

28760 The neutral ligand is

1 Chloro

2 Hydroxo

3 Ammine

4 Oxalato

Explanation:

(c) Ammine $(N H_{2})$ is neutral ligand.

COORDINATION COMPOUNDS

28761 The ligands which can get attached to the central metal ion through more than one atom are called

1 Ambident ligands

2 Polydentate ligands

3 Chelate ligands

4 Neutral ligands

COORDINATION COMPOUNDS

28762 A strong ligand gives a complex which is generally called

1 High spin

2 High energy

3 Low spin

4 Stable

COORDINATION COMPOUNDS

28763 $C N^{-}$ is a strong field ligand. This is due to the fact that

1 It can accept electron from metal species

2 It forms high spin complexes with metal species

3 It carries negative charge.

4 It is a pseudohalide

Explanation:

(d)Cyanide ion is strong field ligand because it is a pseudohalide ion pseudohalide ions are stronger coordinating ligand & they have the ability to form $σ$ bond (from the pseudohalide to the metal) and $π$ bond (from the metal to pseudohalide).

COORDINATION COMPOUNDS

28764 Considering $H_{2} O$ as a weak field ligand, the number of unpaired electrons in $[M n (H_{2} O)_{6}]^{2 +}$ will be (At. No. of $M n = 25$ )

1

2

2

4

3

3

4

5

Explanation:

(d) In presence of weak ligand field, there will be no pairing of electrons. So it will form a high spin complex. i.e. the number of unpaired electrons $= 5.$ 342-s39

COORDINATION COMPOUNDS

28760 The neutral ligand is

1 Chloro

2 Hydroxo

3 Ammine

4 Oxalato

Explanation:

(c) Ammine $(N H_{2})$ is neutral ligand.

COORDINATION COMPOUNDS

28761 The ligands which can get attached to the central metal ion through more than one atom are called

1 Ambident ligands

2 Polydentate ligands

3 Chelate ligands

4 Neutral ligands

COORDINATION COMPOUNDS

28762 A strong ligand gives a complex which is generally called

1 High spin

2 High energy

3 Low spin

4 Stable

COORDINATION COMPOUNDS

28763 $C N^{-}$ is a strong field ligand. This is due to the fact that

1 It can accept electron from metal species

2 It forms high spin complexes with metal species

3 It carries negative charge.

4 It is a pseudohalide

Explanation:

(d)Cyanide ion is strong field ligand because it is a pseudohalide ion pseudohalide ions are stronger coordinating ligand & they have the ability to form $σ$ bond (from the pseudohalide to the metal) and $π$ bond (from the metal to pseudohalide).

COORDINATION COMPOUNDS

28764 Considering $H_{2} O$ as a weak field ligand, the number of unpaired electrons in $[M n (H_{2} O)_{6}]^{2 +}$ will be (At. No. of $M n = 25$ )

1

2

2

4

3

3

4

5

Explanation:

(d) In presence of weak ligand field, there will be no pairing of electrons. So it will form a high spin complex. i.e. the number of unpaired electrons $= 5.$ 342-s39

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