28761
The ligands which can get attached to the central metal ion through more than one atom are called
1 Ambident ligands
2 Polydentate ligands
3 Chelate ligands
4 Neutral ligands
Explanation:
It’s obvious.
COORDINATION COMPOUNDS
28762
A strong ligand gives a complex which is generally called
1 High spin
2 High energy
3 Low spin
4 Stable
Explanation:
(c) A strong field ligand produces low spin complexes.
COORDINATION COMPOUNDS
28763
\(C{N^ - }\) is a strong field ligand. This is due to the fact that
1 It can accept electron from metal species
2 It forms high spin complexes with metal species
3 It carries negative charge.
4 It is a pseudohalide
Explanation:
(d)Cyanide ion is strong field ligand because it is a pseudohalide ion pseudohalide ions are stronger coordinating ligand & they have the ability to form \(\sigma \) bond (from the pseudohalide to the metal) and \(\pi \) bond (from the metal to pseudohalide).
COORDINATION COMPOUNDS
28764
Considering \({H_2}O\) as a weak field ligand, the number of unpaired electrons in \({[Mn{({H_2}O)_6}]^{2 + }}\) will be (At. No. of \(Mn = 25\))
1 \(2\)
2 \(4\)
3 \(3\)
4 \(5\)
Explanation:
(d) In presence of weak ligand field, there will be no pairing of electrons. So it will form a high spin complex. i.e. the number of unpaired electrons \( = 5.\)
28761
The ligands which can get attached to the central metal ion through more than one atom are called
1 Ambident ligands
2 Polydentate ligands
3 Chelate ligands
4 Neutral ligands
Explanation:
It’s obvious.
COORDINATION COMPOUNDS
28762
A strong ligand gives a complex which is generally called
1 High spin
2 High energy
3 Low spin
4 Stable
Explanation:
(c) A strong field ligand produces low spin complexes.
COORDINATION COMPOUNDS
28763
\(C{N^ - }\) is a strong field ligand. This is due to the fact that
1 It can accept electron from metal species
2 It forms high spin complexes with metal species
3 It carries negative charge.
4 It is a pseudohalide
Explanation:
(d)Cyanide ion is strong field ligand because it is a pseudohalide ion pseudohalide ions are stronger coordinating ligand & they have the ability to form \(\sigma \) bond (from the pseudohalide to the metal) and \(\pi \) bond (from the metal to pseudohalide).
COORDINATION COMPOUNDS
28764
Considering \({H_2}O\) as a weak field ligand, the number of unpaired electrons in \({[Mn{({H_2}O)_6}]^{2 + }}\) will be (At. No. of \(Mn = 25\))
1 \(2\)
2 \(4\)
3 \(3\)
4 \(5\)
Explanation:
(d) In presence of weak ligand field, there will be no pairing of electrons. So it will form a high spin complex. i.e. the number of unpaired electrons \( = 5.\)
28761
The ligands which can get attached to the central metal ion through more than one atom are called
1 Ambident ligands
2 Polydentate ligands
3 Chelate ligands
4 Neutral ligands
Explanation:
It’s obvious.
COORDINATION COMPOUNDS
28762
A strong ligand gives a complex which is generally called
1 High spin
2 High energy
3 Low spin
4 Stable
Explanation:
(c) A strong field ligand produces low spin complexes.
COORDINATION COMPOUNDS
28763
\(C{N^ - }\) is a strong field ligand. This is due to the fact that
1 It can accept electron from metal species
2 It forms high spin complexes with metal species
3 It carries negative charge.
4 It is a pseudohalide
Explanation:
(d)Cyanide ion is strong field ligand because it is a pseudohalide ion pseudohalide ions are stronger coordinating ligand & they have the ability to form \(\sigma \) bond (from the pseudohalide to the metal) and \(\pi \) bond (from the metal to pseudohalide).
COORDINATION COMPOUNDS
28764
Considering \({H_2}O\) as a weak field ligand, the number of unpaired electrons in \({[Mn{({H_2}O)_6}]^{2 + }}\) will be (At. No. of \(Mn = 25\))
1 \(2\)
2 \(4\)
3 \(3\)
4 \(5\)
Explanation:
(d) In presence of weak ligand field, there will be no pairing of electrons. So it will form a high spin complex. i.e. the number of unpaired electrons \( = 5.\)
28761
The ligands which can get attached to the central metal ion through more than one atom are called
1 Ambident ligands
2 Polydentate ligands
3 Chelate ligands
4 Neutral ligands
Explanation:
It’s obvious.
COORDINATION COMPOUNDS
28762
A strong ligand gives a complex which is generally called
1 High spin
2 High energy
3 Low spin
4 Stable
Explanation:
(c) A strong field ligand produces low spin complexes.
COORDINATION COMPOUNDS
28763
\(C{N^ - }\) is a strong field ligand. This is due to the fact that
1 It can accept electron from metal species
2 It forms high spin complexes with metal species
3 It carries negative charge.
4 It is a pseudohalide
Explanation:
(d)Cyanide ion is strong field ligand because it is a pseudohalide ion pseudohalide ions are stronger coordinating ligand & they have the ability to form \(\sigma \) bond (from the pseudohalide to the metal) and \(\pi \) bond (from the metal to pseudohalide).
COORDINATION COMPOUNDS
28764
Considering \({H_2}O\) as a weak field ligand, the number of unpaired electrons in \({[Mn{({H_2}O)_6}]^{2 + }}\) will be (At. No. of \(Mn = 25\))
1 \(2\)
2 \(4\)
3 \(3\)
4 \(5\)
Explanation:
(d) In presence of weak ligand field, there will be no pairing of electrons. So it will form a high spin complex. i.e. the number of unpaired electrons \( = 5.\)
28761
The ligands which can get attached to the central metal ion through more than one atom are called
1 Ambident ligands
2 Polydentate ligands
3 Chelate ligands
4 Neutral ligands
Explanation:
It’s obvious.
COORDINATION COMPOUNDS
28762
A strong ligand gives a complex which is generally called
1 High spin
2 High energy
3 Low spin
4 Stable
Explanation:
(c) A strong field ligand produces low spin complexes.
COORDINATION COMPOUNDS
28763
\(C{N^ - }\) is a strong field ligand. This is due to the fact that
1 It can accept electron from metal species
2 It forms high spin complexes with metal species
3 It carries negative charge.
4 It is a pseudohalide
Explanation:
(d)Cyanide ion is strong field ligand because it is a pseudohalide ion pseudohalide ions are stronger coordinating ligand & they have the ability to form \(\sigma \) bond (from the pseudohalide to the metal) and \(\pi \) bond (from the metal to pseudohalide).
COORDINATION COMPOUNDS
28764
Considering \({H_2}O\) as a weak field ligand, the number of unpaired electrons in \({[Mn{({H_2}O)_6}]^{2 + }}\) will be (At. No. of \(Mn = 25\))
1 \(2\)
2 \(4\)
3 \(3\)
4 \(5\)
Explanation:
(d) In presence of weak ligand field, there will be no pairing of electrons. So it will form a high spin complex. i.e. the number of unpaired electrons \( = 5.\)
