QBManager

Electro Magnetic Induction

154514 A square of side $L$ meters lies in the $x - y$ plane in a region, where the magnetic field is given by $\vec{B} = B_{0} (2 \hat{i} + 3 \hat{j} + 4 \hat{k}) T, B_{0}$ is constant. The magnitude of flux passing through the square is

1

2 B_{0} L^{2} Wb

2

3 B_{0} L^{2} Wb

3

4 B_{0} L^{2} Wb

4

\sqrt{29} B_{0} L^{2} Wb

Explanation:

C Given that,
$\vec{A} = L^{2} \hat{k}$ and $\vec{B} = B_{o} (2 \hat{i} + 3 \hat{j} + 4 \hat{k})$
Magnitude of flux $(ϕ) = \vec{B} \vec{A}$
$ϕ = {\vec{B}}_{o} (2 \hat{i} + 3 \hat{j} + 4 \hat{k}) L^{2} \hat{k}$
$ϕ = {\vec{B}}_{o} (4 L^{2}) \hat{K} \cdot \hat{K}$
$ϕ = (4 {\vec{B}}_{0} L^{2}) Wb$

Assam CEE-2019

Electro Magnetic Induction

154517 A coil of surface area $200 {cm}^{2}$ having 25 turns is held perpendicular to the magnetic field of intensity $0.02 \frac{Wb}{m^{2}}$ . The resistance of the coil is $1 Ω$ . If it is removed from the magnetic field in $1 s$ , the induced charge in the coil is C.

1 1

2 0.01

3 0.1

4 0.001

Explanation:

B Given that,
$A = 200 {cm}^{2} = 200 \times 10^{- 4} m^{2}$
$N = 25 turns$
$B_{1} = 0.02 Wb / m^{2}, B_{2} = 0$
$R = 1 Ω$
We know that,
$q = \frac{ϕ_{i} - ϕ_{r}}{R} = \frac{{NB}_{1} A - {NB}_{2} A}{R}$
$q = \frac{25 \times 0.02 \times 200 \times 10^{- 4} - 0}{1}$
$q = 10^{- 2} C = 0.01 C$

GUJCET 2019

Electro Magnetic Induction

154518 A coil of mean area $500 {cm}^{2}$ and having 1000 turns is held with its plane perpendicular to a uniform field of $0.4 G$ . If the coil is turned through $180^{\circ}$ in $\frac{1}{10}$ second, then the average induced emf is (Take, $1 G = 10^{- 4} T$ )

1

0.04 V

2

0.4 V

3

4 V

4

40 V

Explanation:

A Given,
$A = 500 {cm}^{2} = 500 \times 10^{- 4} = 0.05 m^{2}$
Number of turns $(N) = 1000$ turns
Magnetic field $(B) = 0.4 G = 0.4 \times 10^{- 4} T$
Time taken, $Δ T = \frac{1}{10} = 0.1 \sec$
Change in flux $(Δ ϕ) = - 2 NBA$
We know that, average induced emf
$ε_{av} = \frac{2 NBA}{Δ t}$
$ε_{av} = \frac{2 \times 1000 \times 0.4 \times 10^{- 4} \times 0.05}{0.1}$
$ε_{av} = 0.04 V$

AP EAMCET (21.04.2019) Shift-II

Electro Magnetic Induction

154519 A circular coil of area $0.1 m^{2}$ having 200 turns is placed in a magnetic field of $40 T$ . The plane of the coil makes $30^{\circ}$ with the field. If the field is removed for $0.1 s$ then the induced emf in the coil is

1

4000 V

2

4000 \sqrt{3} V

3

2000 V

4

2000 \sqrt{3} V

Explanation:

B Given that,
Area of circular coil $(A) = 0.1 m^{2}$
No of turns in the coil $(N) = 200$ turns
Magnetic field $(B) = 40 T$
We know that,
$ϕ_{1} = NBA \cos θ$
$ϕ_{1} = 200 \times 40 \times 0.1 \times \cos 30^{\circ}$
$ϕ_{1} = 8000 \times 0.1 \times \frac{\sqrt{3}}{2}$
$ϕ_{1} = 4000 \times 0.1 \times \sqrt{3}$
$ϕ_{1} = 400 \sqrt{3}$
When field removed for $0.1 \sec$
Then the flux, $ϕ_{2} = 0$
Net flux $(d ϕ) = ϕ_{1} - ϕ_{2} = 400 \sqrt{3}$
$dt = 0.1 \sec$
Now induced $emf (ε) = \frac{d ϕ}{dt} = \frac{400 \sqrt{3}}{0.1}$
$ε = 4000 \sqrt{3} V$

AP EAMCET (22.04.2019) Shift-II

Electro Magnetic Induction

154514 A square of side $L$ meters lies in the $x - y$ plane in a region, where the magnetic field is given by $\vec{B} = B_{0} (2 \hat{i} + 3 \hat{j} + 4 \hat{k}) T, B_{0}$ is constant. The magnitude of flux passing through the square is

1

2 B_{0} L^{2} Wb

2

3 B_{0} L^{2} Wb

3

4 B_{0} L^{2} Wb

4

\sqrt{29} B_{0} L^{2} Wb

Explanation:

C Given that,
$\vec{A} = L^{2} \hat{k}$ and $\vec{B} = B_{o} (2 \hat{i} + 3 \hat{j} + 4 \hat{k})$
Magnitude of flux $(ϕ) = \vec{B} \vec{A}$
$ϕ = {\vec{B}}_{o} (2 \hat{i} + 3 \hat{j} + 4 \hat{k}) L^{2} \hat{k}$
$ϕ = {\vec{B}}_{o} (4 L^{2}) \hat{K} \cdot \hat{K}$
$ϕ = (4 {\vec{B}}_{0} L^{2}) Wb$

Assam CEE-2019

Electro Magnetic Induction

154517 A coil of surface area $200 {cm}^{2}$ having 25 turns is held perpendicular to the magnetic field of intensity $0.02 \frac{Wb}{m^{2}}$ . The resistance of the coil is $1 Ω$ . If it is removed from the magnetic field in $1 s$ , the induced charge in the coil is C.

1 1

2 0.01

3 0.1

4 0.001

Explanation:

B Given that,
$A = 200 {cm}^{2} = 200 \times 10^{- 4} m^{2}$
$N = 25 turns$
$B_{1} = 0.02 Wb / m^{2}, B_{2} = 0$
$R = 1 Ω$
We know that,
$q = \frac{ϕ_{i} - ϕ_{r}}{R} = \frac{{NB}_{1} A - {NB}_{2} A}{R}$
$q = \frac{25 \times 0.02 \times 200 \times 10^{- 4} - 0}{1}$
$q = 10^{- 2} C = 0.01 C$

GUJCET 2019

Electro Magnetic Induction

154518 A coil of mean area $500 {cm}^{2}$ and having 1000 turns is held with its plane perpendicular to a uniform field of $0.4 G$ . If the coil is turned through $180^{\circ}$ in $\frac{1}{10}$ second, then the average induced emf is (Take, $1 G = 10^{- 4} T$ )

1

0.04 V

2

0.4 V

3

4 V

4

40 V

Explanation:

A Given,
$A = 500 {cm}^{2} = 500 \times 10^{- 4} = 0.05 m^{2}$
Number of turns $(N) = 1000$ turns
Magnetic field $(B) = 0.4 G = 0.4 \times 10^{- 4} T$
Time taken, $Δ T = \frac{1}{10} = 0.1 \sec$
Change in flux $(Δ ϕ) = - 2 NBA$
We know that, average induced emf
$ε_{av} = \frac{2 NBA}{Δ t}$
$ε_{av} = \frac{2 \times 1000 \times 0.4 \times 10^{- 4} \times 0.05}{0.1}$
$ε_{av} = 0.04 V$

AP EAMCET (21.04.2019) Shift-II

Electro Magnetic Induction

154519 A circular coil of area $0.1 m^{2}$ having 200 turns is placed in a magnetic field of $40 T$ . The plane of the coil makes $30^{\circ}$ with the field. If the field is removed for $0.1 s$ then the induced emf in the coil is

1

4000 V

2

4000 \sqrt{3} V

3

2000 V

4

2000 \sqrt{3} V

Explanation:

B Given that,
Area of circular coil $(A) = 0.1 m^{2}$
No of turns in the coil $(N) = 200$ turns
Magnetic field $(B) = 40 T$
We know that,
$ϕ_{1} = NBA \cos θ$
$ϕ_{1} = 200 \times 40 \times 0.1 \times \cos 30^{\circ}$
$ϕ_{1} = 8000 \times 0.1 \times \frac{\sqrt{3}}{2}$
$ϕ_{1} = 4000 \times 0.1 \times \sqrt{3}$
$ϕ_{1} = 400 \sqrt{3}$
When field removed for $0.1 \sec$
Then the flux, $ϕ_{2} = 0$
Net flux $(d ϕ) = ϕ_{1} - ϕ_{2} = 400 \sqrt{3}$
$dt = 0.1 \sec$
Now induced $emf (ε) = \frac{d ϕ}{dt} = \frac{400 \sqrt{3}}{0.1}$
$ε = 4000 \sqrt{3} V$

AP EAMCET (22.04.2019) Shift-II

Electro Magnetic Induction

154514 A square of side $L$ meters lies in the $x - y$ plane in a region, where the magnetic field is given by $\vec{B} = B_{0} (2 \hat{i} + 3 \hat{j} + 4 \hat{k}) T, B_{0}$ is constant. The magnitude of flux passing through the square is

1

2 B_{0} L^{2} Wb

2

3 B_{0} L^{2} Wb

3

4 B_{0} L^{2} Wb

4

\sqrt{29} B_{0} L^{2} Wb

Explanation:

C Given that,
$\vec{A} = L^{2} \hat{k}$ and $\vec{B} = B_{o} (2 \hat{i} + 3 \hat{j} + 4 \hat{k})$
Magnitude of flux $(ϕ) = \vec{B} \vec{A}$
$ϕ = {\vec{B}}_{o} (2 \hat{i} + 3 \hat{j} + 4 \hat{k}) L^{2} \hat{k}$
$ϕ = {\vec{B}}_{o} (4 L^{2}) \hat{K} \cdot \hat{K}$
$ϕ = (4 {\vec{B}}_{0} L^{2}) Wb$

Assam CEE-2019

Electro Magnetic Induction

154517 A coil of surface area $200 {cm}^{2}$ having 25 turns is held perpendicular to the magnetic field of intensity $0.02 \frac{Wb}{m^{2}}$ . The resistance of the coil is $1 Ω$ . If it is removed from the magnetic field in $1 s$ , the induced charge in the coil is C.

1 1

2 0.01

3 0.1

4 0.001

Explanation:

B Given that,
$A = 200 {cm}^{2} = 200 \times 10^{- 4} m^{2}$
$N = 25 turns$
$B_{1} = 0.02 Wb / m^{2}, B_{2} = 0$
$R = 1 Ω$
We know that,
$q = \frac{ϕ_{i} - ϕ_{r}}{R} = \frac{{NB}_{1} A - {NB}_{2} A}{R}$
$q = \frac{25 \times 0.02 \times 200 \times 10^{- 4} - 0}{1}$
$q = 10^{- 2} C = 0.01 C$

GUJCET 2019

Electro Magnetic Induction

154518 A coil of mean area $500 {cm}^{2}$ and having 1000 turns is held with its plane perpendicular to a uniform field of $0.4 G$ . If the coil is turned through $180^{\circ}$ in $\frac{1}{10}$ second, then the average induced emf is (Take, $1 G = 10^{- 4} T$ )

1

0.04 V

2

0.4 V

3

4 V

4

40 V

Explanation:

A Given,
$A = 500 {cm}^{2} = 500 \times 10^{- 4} = 0.05 m^{2}$
Number of turns $(N) = 1000$ turns
Magnetic field $(B) = 0.4 G = 0.4 \times 10^{- 4} T$
Time taken, $Δ T = \frac{1}{10} = 0.1 \sec$
Change in flux $(Δ ϕ) = - 2 NBA$
We know that, average induced emf
$ε_{av} = \frac{2 NBA}{Δ t}$
$ε_{av} = \frac{2 \times 1000 \times 0.4 \times 10^{- 4} \times 0.05}{0.1}$
$ε_{av} = 0.04 V$

AP EAMCET (21.04.2019) Shift-II

Electro Magnetic Induction

154519 A circular coil of area $0.1 m^{2}$ having 200 turns is placed in a magnetic field of $40 T$ . The plane of the coil makes $30^{\circ}$ with the field. If the field is removed for $0.1 s$ then the induced emf in the coil is

1

4000 V

2

4000 \sqrt{3} V

3

2000 V

4

2000 \sqrt{3} V

Explanation:

B Given that,
Area of circular coil $(A) = 0.1 m^{2}$
No of turns in the coil $(N) = 200$ turns
Magnetic field $(B) = 40 T$
We know that,
$ϕ_{1} = NBA \cos θ$
$ϕ_{1} = 200 \times 40 \times 0.1 \times \cos 30^{\circ}$
$ϕ_{1} = 8000 \times 0.1 \times \frac{\sqrt{3}}{2}$
$ϕ_{1} = 4000 \times 0.1 \times \sqrt{3}$
$ϕ_{1} = 400 \sqrt{3}$
When field removed for $0.1 \sec$
Then the flux, $ϕ_{2} = 0$
Net flux $(d ϕ) = ϕ_{1} - ϕ_{2} = 400 \sqrt{3}$
$dt = 0.1 \sec$
Now induced $emf (ε) = \frac{d ϕ}{dt} = \frac{400 \sqrt{3}}{0.1}$
$ε = 4000 \sqrt{3} V$

AP EAMCET (22.04.2019) Shift-II

Electro Magnetic Induction

154514 A square of side $L$ meters lies in the $x - y$ plane in a region, where the magnetic field is given by $\vec{B} = B_{0} (2 \hat{i} + 3 \hat{j} + 4 \hat{k}) T, B_{0}$ is constant. The magnitude of flux passing through the square is

1

2 B_{0} L^{2} Wb

2

3 B_{0} L^{2} Wb

3

4 B_{0} L^{2} Wb

4

\sqrt{29} B_{0} L^{2} Wb

Explanation:

C Given that,
$\vec{A} = L^{2} \hat{k}$ and $\vec{B} = B_{o} (2 \hat{i} + 3 \hat{j} + 4 \hat{k})$
Magnitude of flux $(ϕ) = \vec{B} \vec{A}$
$ϕ = {\vec{B}}_{o} (2 \hat{i} + 3 \hat{j} + 4 \hat{k}) L^{2} \hat{k}$
$ϕ = {\vec{B}}_{o} (4 L^{2}) \hat{K} \cdot \hat{K}$
$ϕ = (4 {\vec{B}}_{0} L^{2}) Wb$

Assam CEE-2019

Electro Magnetic Induction

154517 A coil of surface area $200 {cm}^{2}$ having 25 turns is held perpendicular to the magnetic field of intensity $0.02 \frac{Wb}{m^{2}}$ . The resistance of the coil is $1 Ω$ . If it is removed from the magnetic field in $1 s$ , the induced charge in the coil is C.

1 1

2 0.01

3 0.1

4 0.001

Explanation:

B Given that,
$A = 200 {cm}^{2} = 200 \times 10^{- 4} m^{2}$
$N = 25 turns$
$B_{1} = 0.02 Wb / m^{2}, B_{2} = 0$
$R = 1 Ω$
We know that,
$q = \frac{ϕ_{i} - ϕ_{r}}{R} = \frac{{NB}_{1} A - {NB}_{2} A}{R}$
$q = \frac{25 \times 0.02 \times 200 \times 10^{- 4} - 0}{1}$
$q = 10^{- 2} C = 0.01 C$

GUJCET 2019

Electro Magnetic Induction

154518 A coil of mean area $500 {cm}^{2}$ and having 1000 turns is held with its plane perpendicular to a uniform field of $0.4 G$ . If the coil is turned through $180^{\circ}$ in $\frac{1}{10}$ second, then the average induced emf is (Take, $1 G = 10^{- 4} T$ )

1

0.04 V

2

0.4 V

3

4 V

4

40 V

Explanation:

A Given,
$A = 500 {cm}^{2} = 500 \times 10^{- 4} = 0.05 m^{2}$
Number of turns $(N) = 1000$ turns
Magnetic field $(B) = 0.4 G = 0.4 \times 10^{- 4} T$
Time taken, $Δ T = \frac{1}{10} = 0.1 \sec$
Change in flux $(Δ ϕ) = - 2 NBA$
We know that, average induced emf
$ε_{av} = \frac{2 NBA}{Δ t}$
$ε_{av} = \frac{2 \times 1000 \times 0.4 \times 10^{- 4} \times 0.05}{0.1}$
$ε_{av} = 0.04 V$

AP EAMCET (21.04.2019) Shift-II

Electro Magnetic Induction

154519 A circular coil of area $0.1 m^{2}$ having 200 turns is placed in a magnetic field of $40 T$ . The plane of the coil makes $30^{\circ}$ with the field. If the field is removed for $0.1 s$ then the induced emf in the coil is

1

4000 V

2

4000 \sqrt{3} V

3

2000 V

4

2000 \sqrt{3} V

Explanation:

B Given that,
Area of circular coil $(A) = 0.1 m^{2}$
No of turns in the coil $(N) = 200$ turns
Magnetic field $(B) = 40 T$
We know that,
$ϕ_{1} = NBA \cos θ$
$ϕ_{1} = 200 \times 40 \times 0.1 \times \cos 30^{\circ}$
$ϕ_{1} = 8000 \times 0.1 \times \frac{\sqrt{3}}{2}$
$ϕ_{1} = 4000 \times 0.1 \times \sqrt{3}$
$ϕ_{1} = 400 \sqrt{3}$
When field removed for $0.1 \sec$
Then the flux, $ϕ_{2} = 0$
Net flux $(d ϕ) = ϕ_{1} - ϕ_{2} = 400 \sqrt{3}$
$dt = 0.1 \sec$
Now induced $emf (ε) = \frac{d ϕ}{dt} = \frac{400 \sqrt{3}}{0.1}$
$ε = 4000 \sqrt{3} V$

AP EAMCET (22.04.2019) Shift-II

Explanation:

Explanation:

Explanation:

Explanation:

Question Bank Series

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Question Bank Series