154094 A vibration magnetometer is used at two different places $A$ and $B$ on the earth. The time period of a magnet suspended freely in the magnetometer at $A$ is twice that at $B$. If the horizontal component of the earth's magnetic field at $B$ is $32 \times 10^{-6} \mathrm{~T}$, then its value at $A$ is

154095 If a bar magnet is cut along the dotted line as shown in the figure and the two pieces are held separated by a small distance as they are, then

154096 On the magnetic meridian at some place of the Earth's surface the vertical component of the earth's magnetic field is $0.433 \mathrm{G}$ and the dip angle is $60^{\circ}$. Then the magnetic field of the earth at this place is

154097 A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at $30^{\circ}$ with the horizontal. The horizontal component of the earth's magnetic field at the place is $0.3 \mathrm{G}$. Then the magnitude of the earth's magnetic field at the location is

154099 The vertical component of the earth's magnetic field is $6 \times 10^{-5} \mathrm{~T}$ at any place where the angle of dip is $37^{\circ}$. The earth's resultant magnetic field at that place will be (Given $\tan 37^{\circ}=\frac{\mathbf{3}}{\mathbf{4}}$ )

154094 A vibration magnetometer is used at two different places $A$ and $B$ on the earth. The time period of a magnet suspended freely in the magnetometer at $A$ is twice that at $B$. If the horizontal component of the earth's magnetic field at $B$ is $32 \times 10^{-6} \mathrm{~T}$, then its value at $A$ is

154095 If a bar magnet is cut along the dotted line as shown in the figure and the two pieces are held separated by a small distance as they are, then

154096 On the magnetic meridian at some place of the Earth's surface the vertical component of the earth's magnetic field is $0.433 \mathrm{G}$ and the dip angle is $60^{\circ}$. Then the magnetic field of the earth at this place is

154097 A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at $30^{\circ}$ with the horizontal. The horizontal component of the earth's magnetic field at the place is $0.3 \mathrm{G}$. Then the magnitude of the earth's magnetic field at the location is

154099 The vertical component of the earth's magnetic field is $6 \times 10^{-5} \mathrm{~T}$ at any place where the angle of dip is $37^{\circ}$. The earth's resultant magnetic field at that place will be (Given $\tan 37^{\circ}=\frac{\mathbf{3}}{\mathbf{4}}$ )

154094 A vibration magnetometer is used at two different places $A$ and $B$ on the earth. The time period of a magnet suspended freely in the magnetometer at $A$ is twice that at $B$. If the horizontal component of the earth's magnetic field at $B$ is $32 \times 10^{-6} \mathrm{~T}$, then its value at $A$ is

154095 If a bar magnet is cut along the dotted line as shown in the figure and the two pieces are held separated by a small distance as they are, then

154096 On the magnetic meridian at some place of the Earth's surface the vertical component of the earth's magnetic field is $0.433 \mathrm{G}$ and the dip angle is $60^{\circ}$. Then the magnetic field of the earth at this place is

154097 A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at $30^{\circ}$ with the horizontal. The horizontal component of the earth's magnetic field at the place is $0.3 \mathrm{G}$. Then the magnitude of the earth's magnetic field at the location is

154099 The vertical component of the earth's magnetic field is $6 \times 10^{-5} \mathrm{~T}$ at any place where the angle of dip is $37^{\circ}$. The earth's resultant magnetic field at that place will be (Given $\tan 37^{\circ}=\frac{\mathbf{3}}{\mathbf{4}}$ )

154094 A vibration magnetometer is used at two different places $A$ and $B$ on the earth. The time period of a magnet suspended freely in the magnetometer at $A$ is twice that at $B$. If the horizontal component of the earth's magnetic field at $B$ is $32 \times 10^{-6} \mathrm{~T}$, then its value at $A$ is

154095 If a bar magnet is cut along the dotted line as shown in the figure and the two pieces are held separated by a small distance as they are, then

154096 On the magnetic meridian at some place of the Earth's surface the vertical component of the earth's magnetic field is $0.433 \mathrm{G}$ and the dip angle is $60^{\circ}$. Then the magnetic field of the earth at this place is

154097 A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at $30^{\circ}$ with the horizontal. The horizontal component of the earth's magnetic field at the place is $0.3 \mathrm{G}$. Then the magnitude of the earth's magnetic field at the location is

154099 The vertical component of the earth's magnetic field is $6 \times 10^{-5} \mathrm{~T}$ at any place where the angle of dip is $37^{\circ}$. The earth's resultant magnetic field at that place will be (Given $\tan 37^{\circ}=\frac{\mathbf{3}}{\mathbf{4}}$ )

154094 A vibration magnetometer is used at two different places $A$ and $B$ on the earth. The time period of a magnet suspended freely in the magnetometer at $A$ is twice that at $B$. If the horizontal component of the earth's magnetic field at $B$ is $32 \times 10^{-6} \mathrm{~T}$, then its value at $A$ is

154095 If a bar magnet is cut along the dotted line as shown in the figure and the two pieces are held separated by a small distance as they are, then

154096 On the magnetic meridian at some place of the Earth's surface the vertical component of the earth's magnetic field is $0.433 \mathrm{G}$ and the dip angle is $60^{\circ}$. Then the magnetic field of the earth at this place is

154097 A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip pointing down at $30^{\circ}$ with the horizontal. The horizontal component of the earth's magnetic field at the place is $0.3 \mathrm{G}$. Then the magnitude of the earth's magnetic field at the location is

154099 The vertical component of the earth's magnetic field is $6 \times 10^{-5} \mathrm{~T}$ at any place where the angle of dip is $37^{\circ}$. The earth's resultant magnetic field at that place will be (Given $\tan 37^{\circ}=\frac{\mathbf{3}}{\mathbf{4}}$ )