153539 A particle with charge $1.6 \times 10^{-5} \mathrm{C}$ is moving with a velocity of magnitude $3 \mathrm{~m} / \mathrm{s}$ in uniform magnetic field of $2 \mathrm{~T}$. The direction of velocity remains perpendicular to the direction of magnetic field. What is the magnitude of net force on the particle?

153540 A proton moving in perpendicular magnetic field possesses energy ' $E$ '. The magnetic field is increased four times. But the proton is constrained to move in the path of same radius. The kinetic energy will increase

153541 The work done by an uniform magnetic field, on a moving charge is

153542 Assertion: A charge particle is released from rest in magnetic field then it will move in circular path.
Reason: Work done by magnetic field is non zero.

153544 The magnetic force acting on a charged particle of charge $-2 \mu \mathrm{C}$ in a magnetic field of 2 $T$ acting in $y$ direction, when the particle velocity is $(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}) \times 10^{6} \mathrm{~m} \mathrm{~s}^{-1}$, is

153539 A particle with charge $1.6 \times 10^{-5} \mathrm{C}$ is moving with a velocity of magnitude $3 \mathrm{~m} / \mathrm{s}$ in uniform magnetic field of $2 \mathrm{~T}$. The direction of velocity remains perpendicular to the direction of magnetic field. What is the magnitude of net force on the particle?

153540 A proton moving in perpendicular magnetic field possesses energy ' $E$ '. The magnetic field is increased four times. But the proton is constrained to move in the path of same radius. The kinetic energy will increase

153541 The work done by an uniform magnetic field, on a moving charge is

153542 Assertion: A charge particle is released from rest in magnetic field then it will move in circular path.
Reason: Work done by magnetic field is non zero.

153544 The magnetic force acting on a charged particle of charge $-2 \mu \mathrm{C}$ in a magnetic field of 2 $T$ acting in $y$ direction, when the particle velocity is $(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}) \times 10^{6} \mathrm{~m} \mathrm{~s}^{-1}$, is

153539 A particle with charge $1.6 \times 10^{-5} \mathrm{C}$ is moving with a velocity of magnitude $3 \mathrm{~m} / \mathrm{s}$ in uniform magnetic field of $2 \mathrm{~T}$. The direction of velocity remains perpendicular to the direction of magnetic field. What is the magnitude of net force on the particle?

153540 A proton moving in perpendicular magnetic field possesses energy ' $E$ '. The magnetic field is increased four times. But the proton is constrained to move in the path of same radius. The kinetic energy will increase

153541 The work done by an uniform magnetic field, on a moving charge is

153542 Assertion: A charge particle is released from rest in magnetic field then it will move in circular path.
Reason: Work done by magnetic field is non zero.

153544 The magnetic force acting on a charged particle of charge $-2 \mu \mathrm{C}$ in a magnetic field of 2 $T$ acting in $y$ direction, when the particle velocity is $(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}) \times 10^{6} \mathrm{~m} \mathrm{~s}^{-1}$, is

153539 A particle with charge $1.6 \times 10^{-5} \mathrm{C}$ is moving with a velocity of magnitude $3 \mathrm{~m} / \mathrm{s}$ in uniform magnetic field of $2 \mathrm{~T}$. The direction of velocity remains perpendicular to the direction of magnetic field. What is the magnitude of net force on the particle?

153540 A proton moving in perpendicular magnetic field possesses energy ' $E$ '. The magnetic field is increased four times. But the proton is constrained to move in the path of same radius. The kinetic energy will increase

153541 The work done by an uniform magnetic field, on a moving charge is

153542 Assertion: A charge particle is released from rest in magnetic field then it will move in circular path.
Reason: Work done by magnetic field is non zero.

153544 The magnetic force acting on a charged particle of charge $-2 \mu \mathrm{C}$ in a magnetic field of 2 $T$ acting in $y$ direction, when the particle velocity is $(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}) \times 10^{6} \mathrm{~m} \mathrm{~s}^{-1}$, is

153539 A particle with charge $1.6 \times 10^{-5} \mathrm{C}$ is moving with a velocity of magnitude $3 \mathrm{~m} / \mathrm{s}$ in uniform magnetic field of $2 \mathrm{~T}$. The direction of velocity remains perpendicular to the direction of magnetic field. What is the magnitude of net force on the particle?

153540 A proton moving in perpendicular magnetic field possesses energy ' $E$ '. The magnetic field is increased four times. But the proton is constrained to move in the path of same radius. The kinetic energy will increase

153541 The work done by an uniform magnetic field, on a moving charge is

153542 Assertion: A charge particle is released from rest in magnetic field then it will move in circular path.
Reason: Work done by magnetic field is non zero.

153544 The magnetic force acting on a charged particle of charge $-2 \mu \mathrm{C}$ in a magnetic field of 2 $T$ acting in $y$ direction, when the particle velocity is $(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}) \times 10^{6} \mathrm{~m} \mathrm{~s}^{-1}$, is