06. Measuring Instrument (Meter Bridge, Galvanometer, Ammeter, Voltmeter, Potentiometer)
Current Electricity

152842 A galvanometer of resistance $20 \Omega$ gives a full scale deflection when a current of $0.04 \mathrm{~A}$ is passed through it. To convert it into an ammeter of range $20 \mathrm{~A}$, the resistance that must be connected in series with the coil of the galvanometer is (Galvanometer is shunted by $0.05 \Omega$ )

1 $4.95 \Omega$
2 $9.45 \Omega$
3 $5.94 \Omega$
4 $12.62 \Omega$
Current Electricity

152845 Two wires ' $A$ ' and ' $B$ ' of equal lengths are connected in left and right gaps, of meter bridge, respectively. The null point is obtained at $40 \mathrm{~cm}$ from left end. Diameters of the wires ' $A$ ' and ' $B$ ' are in the ratio $3: 1$, the ratio of specific of ' $A$ ' to that of ' $B$ ' is

1 $6: 1$
2 $3: 1$
3 $9: 1$
4 $1: 1$
Current Electricity

152847 If only $2 \%$ of the total current passes through an ammeter having coil of resistance ' $R$ ' then the resistance of the shunt of an ammeter is

1 $\frac{\mathrm{R}}{49}$
2 $49 \mathrm{R}$
3 $50 \mathrm{R}$
4 $\frac{\mathrm{R}}{50}$
Current Electricity

152848 In potentiometer experiment, the balancing length with a cell $E_{1}$ of unknown e.m.f. is ' $\ell_{1}$ ' $\mathrm{cm}$. By shunting the cell with resistance $\mathrm{R} \Omega$, the balancing length becomes $\frac{\ell_{1}}{2} \mathrm{~cm}$. the internal resistance $(r)$ of a cell is

1 $r=2 R$
2 $r=0$
3 $r=\frac{R}{2}$
4 $r=R$
Current Electricity

152842 A galvanometer of resistance $20 \Omega$ gives a full scale deflection when a current of $0.04 \mathrm{~A}$ is passed through it. To convert it into an ammeter of range $20 \mathrm{~A}$, the resistance that must be connected in series with the coil of the galvanometer is (Galvanometer is shunted by $0.05 \Omega$ )

1 $4.95 \Omega$
2 $9.45 \Omega$
3 $5.94 \Omega$
4 $12.62 \Omega$
Current Electricity

152845 Two wires ' $A$ ' and ' $B$ ' of equal lengths are connected in left and right gaps, of meter bridge, respectively. The null point is obtained at $40 \mathrm{~cm}$ from left end. Diameters of the wires ' $A$ ' and ' $B$ ' are in the ratio $3: 1$, the ratio of specific of ' $A$ ' to that of ' $B$ ' is

1 $6: 1$
2 $3: 1$
3 $9: 1$
4 $1: 1$
Current Electricity

152847 If only $2 \%$ of the total current passes through an ammeter having coil of resistance ' $R$ ' then the resistance of the shunt of an ammeter is

1 $\frac{\mathrm{R}}{49}$
2 $49 \mathrm{R}$
3 $50 \mathrm{R}$
4 $\frac{\mathrm{R}}{50}$
Current Electricity

152848 In potentiometer experiment, the balancing length with a cell $E_{1}$ of unknown e.m.f. is ' $\ell_{1}$ ' $\mathrm{cm}$. By shunting the cell with resistance $\mathrm{R} \Omega$, the balancing length becomes $\frac{\ell_{1}}{2} \mathrm{~cm}$. the internal resistance $(r)$ of a cell is

1 $r=2 R$
2 $r=0$
3 $r=\frac{R}{2}$
4 $r=R$
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
Current Electricity

152842 A galvanometer of resistance $20 \Omega$ gives a full scale deflection when a current of $0.04 \mathrm{~A}$ is passed through it. To convert it into an ammeter of range $20 \mathrm{~A}$, the resistance that must be connected in series with the coil of the galvanometer is (Galvanometer is shunted by $0.05 \Omega$ )

1 $4.95 \Omega$
2 $9.45 \Omega$
3 $5.94 \Omega$
4 $12.62 \Omega$
Current Electricity

152845 Two wires ' $A$ ' and ' $B$ ' of equal lengths are connected in left and right gaps, of meter bridge, respectively. The null point is obtained at $40 \mathrm{~cm}$ from left end. Diameters of the wires ' $A$ ' and ' $B$ ' are in the ratio $3: 1$, the ratio of specific of ' $A$ ' to that of ' $B$ ' is

1 $6: 1$
2 $3: 1$
3 $9: 1$
4 $1: 1$
Current Electricity

152847 If only $2 \%$ of the total current passes through an ammeter having coil of resistance ' $R$ ' then the resistance of the shunt of an ammeter is

1 $\frac{\mathrm{R}}{49}$
2 $49 \mathrm{R}$
3 $50 \mathrm{R}$
4 $\frac{\mathrm{R}}{50}$
Current Electricity

152848 In potentiometer experiment, the balancing length with a cell $E_{1}$ of unknown e.m.f. is ' $\ell_{1}$ ' $\mathrm{cm}$. By shunting the cell with resistance $\mathrm{R} \Omega$, the balancing length becomes $\frac{\ell_{1}}{2} \mathrm{~cm}$. the internal resistance $(r)$ of a cell is

1 $r=2 R$
2 $r=0$
3 $r=\frac{R}{2}$
4 $r=R$
Current Electricity

152842 A galvanometer of resistance $20 \Omega$ gives a full scale deflection when a current of $0.04 \mathrm{~A}$ is passed through it. To convert it into an ammeter of range $20 \mathrm{~A}$, the resistance that must be connected in series with the coil of the galvanometer is (Galvanometer is shunted by $0.05 \Omega$ )

1 $4.95 \Omega$
2 $9.45 \Omega$
3 $5.94 \Omega$
4 $12.62 \Omega$
Current Electricity

152845 Two wires ' $A$ ' and ' $B$ ' of equal lengths are connected in left and right gaps, of meter bridge, respectively. The null point is obtained at $40 \mathrm{~cm}$ from left end. Diameters of the wires ' $A$ ' and ' $B$ ' are in the ratio $3: 1$, the ratio of specific of ' $A$ ' to that of ' $B$ ' is

1 $6: 1$
2 $3: 1$
3 $9: 1$
4 $1: 1$
Current Electricity

152847 If only $2 \%$ of the total current passes through an ammeter having coil of resistance ' $R$ ' then the resistance of the shunt of an ammeter is

1 $\frac{\mathrm{R}}{49}$
2 $49 \mathrm{R}$
3 $50 \mathrm{R}$
4 $\frac{\mathrm{R}}{50}$
Current Electricity

152848 In potentiometer experiment, the balancing length with a cell $E_{1}$ of unknown e.m.f. is ' $\ell_{1}$ ' $\mathrm{cm}$. By shunting the cell with resistance $\mathrm{R} \Omega$, the balancing length becomes $\frac{\ell_{1}}{2} \mathrm{~cm}$. the internal resistance $(r)$ of a cell is

1 $r=2 R$
2 $r=0$
3 $r=\frac{R}{2}$
4 $r=R$