152832 A potentiometer wire of length $100 \mathrm{~cm}$ and resistance $3 \Omega$ is connected in series with resistance of $8 \Omega$ and an accumulator of 4 volt whose internal resistance is $1 \Omega$.
A cell of e.m.f. ' $E$ ' is balanced by $50 \mathrm{~cm}$ length of the wire. The e.m.f. of the cell is

152833 In meter-bridge experiment a resistance of 18 $\Omega$ is connected in left gap and an unknown resistance $R$ is connected in right gap. The null point is obtained at ' $\ell_{1}$ ' from left end. If unknown resistance is replaced by $\left(\frac{R}{3}\right) \Omega$, the null point is obtained at $1.5 \ell_{1}$. The unknown resistance is

152834 When a resistance of $200 \Omega$ is connected in series with a galvanometer of resistance ' $G$ ', its range is ' $V$ '. To triple its range, a resistance of $2000\Omega$ is connected in series. The value of $G$ is

152836 The length of a potentiometer wire is ' $L$ '. A cell of e.m.f. ' $E$ ' is balanced at a length $\frac{{ }^{\prime} L}{5}$ from the positive end of the wire. If the length of the wire is increased by \(\frac{L}{2}\), at what distance will the same cell give a balance point?

152837 A galvanometer of resistance $100 \Omega$ requires 10 $\mu \mathrm{A}$ current for full scale deflection. Now a resistance of $1 \Omega$ is connected to convert it into an ammeter. The minimum current required to obtain full scale deflection is
1098. Scale of galvanometer divided into 100 equal divisions has a current sensitivity $10 \mathrm{div} . / \mathrm{mA}$ and voltage sensitivity $4 \mathrm{div} . / \mathrm{mV}$. The resistance of galvanometer is

152832 A potentiometer wire of length $100 \mathrm{~cm}$ and resistance $3 \Omega$ is connected in series with resistance of $8 \Omega$ and an accumulator of 4 volt whose internal resistance is $1 \Omega$.
A cell of e.m.f. ' $E$ ' is balanced by $50 \mathrm{~cm}$ length of the wire. The e.m.f. of the cell is

152833 In meter-bridge experiment a resistance of 18 $\Omega$ is connected in left gap and an unknown resistance $R$ is connected in right gap. The null point is obtained at ' $\ell_{1}$ ' from left end. If unknown resistance is replaced by $\left(\frac{R}{3}\right) \Omega$, the null point is obtained at $1.5 \ell_{1}$. The unknown resistance is

152834 When a resistance of $200 \Omega$ is connected in series with a galvanometer of resistance ' $G$ ', its range is ' $V$ '. To triple its range, a resistance of $2000\Omega$ is connected in series. The value of $G$ is

152836 The length of a potentiometer wire is ' $L$ '. A cell of e.m.f. ' $E$ ' is balanced at a length $\frac{{ }^{\prime} L}{5}$ from the positive end of the wire. If the length of the wire is increased by \(\frac{L}{2}\), at what distance will the same cell give a balance point?

152837 A galvanometer of resistance $100 \Omega$ requires 10 $\mu \mathrm{A}$ current for full scale deflection. Now a resistance of $1 \Omega$ is connected to convert it into an ammeter. The minimum current required to obtain full scale deflection is
1098. Scale of galvanometer divided into 100 equal divisions has a current sensitivity $10 \mathrm{div} . / \mathrm{mA}$ and voltage sensitivity $4 \mathrm{div} . / \mathrm{mV}$. The resistance of galvanometer is

152832 A potentiometer wire of length $100 \mathrm{~cm}$ and resistance $3 \Omega$ is connected in series with resistance of $8 \Omega$ and an accumulator of 4 volt whose internal resistance is $1 \Omega$.
A cell of e.m.f. ' $E$ ' is balanced by $50 \mathrm{~cm}$ length of the wire. The e.m.f. of the cell is

152833 In meter-bridge experiment a resistance of 18 $\Omega$ is connected in left gap and an unknown resistance $R$ is connected in right gap. The null point is obtained at ' $\ell_{1}$ ' from left end. If unknown resistance is replaced by $\left(\frac{R}{3}\right) \Omega$, the null point is obtained at $1.5 \ell_{1}$. The unknown resistance is

152834 When a resistance of $200 \Omega$ is connected in series with a galvanometer of resistance ' $G$ ', its range is ' $V$ '. To triple its range, a resistance of $2000\Omega$ is connected in series. The value of $G$ is

152836 The length of a potentiometer wire is ' $L$ '. A cell of e.m.f. ' $E$ ' is balanced at a length $\frac{{ }^{\prime} L}{5}$ from the positive end of the wire. If the length of the wire is increased by \(\frac{L}{2}\), at what distance will the same cell give a balance point?

152837 A galvanometer of resistance $100 \Omega$ requires 10 $\mu \mathrm{A}$ current for full scale deflection. Now a resistance of $1 \Omega$ is connected to convert it into an ammeter. The minimum current required to obtain full scale deflection is
1098. Scale of galvanometer divided into 100 equal divisions has a current sensitivity $10 \mathrm{div} . / \mathrm{mA}$ and voltage sensitivity $4 \mathrm{div} . / \mathrm{mV}$. The resistance of galvanometer is

152832 A potentiometer wire of length $100 \mathrm{~cm}$ and resistance $3 \Omega$ is connected in series with resistance of $8 \Omega$ and an accumulator of 4 volt whose internal resistance is $1 \Omega$.
A cell of e.m.f. ' $E$ ' is balanced by $50 \mathrm{~cm}$ length of the wire. The e.m.f. of the cell is

152833 In meter-bridge experiment a resistance of 18 $\Omega$ is connected in left gap and an unknown resistance $R$ is connected in right gap. The null point is obtained at ' $\ell_{1}$ ' from left end. If unknown resistance is replaced by $\left(\frac{R}{3}\right) \Omega$, the null point is obtained at $1.5 \ell_{1}$. The unknown resistance is

152834 When a resistance of $200 \Omega$ is connected in series with a galvanometer of resistance ' $G$ ', its range is ' $V$ '. To triple its range, a resistance of $2000\Omega$ is connected in series. The value of $G$ is

152836 The length of a potentiometer wire is ' $L$ '. A cell of e.m.f. ' $E$ ' is balanced at a length $\frac{{ }^{\prime} L}{5}$ from the positive end of the wire. If the length of the wire is increased by \(\frac{L}{2}\), at what distance will the same cell give a balance point?

152837 A galvanometer of resistance $100 \Omega$ requires 10 $\mu \mathrm{A}$ current for full scale deflection. Now a resistance of $1 \Omega$ is connected to convert it into an ammeter. The minimum current required to obtain full scale deflection is
1098. Scale of galvanometer divided into 100 equal divisions has a current sensitivity $10 \mathrm{div} . / \mathrm{mA}$ and voltage sensitivity $4 \mathrm{div} . / \mathrm{mV}$. The resistance of galvanometer is

152832 A potentiometer wire of length $100 \mathrm{~cm}$ and resistance $3 \Omega$ is connected in series with resistance of $8 \Omega$ and an accumulator of 4 volt whose internal resistance is $1 \Omega$.
A cell of e.m.f. ' $E$ ' is balanced by $50 \mathrm{~cm}$ length of the wire. The e.m.f. of the cell is

152833 In meter-bridge experiment a resistance of 18 $\Omega$ is connected in left gap and an unknown resistance $R$ is connected in right gap. The null point is obtained at ' $\ell_{1}$ ' from left end. If unknown resistance is replaced by $\left(\frac{R}{3}\right) \Omega$, the null point is obtained at $1.5 \ell_{1}$. The unknown resistance is

152834 When a resistance of $200 \Omega$ is connected in series with a galvanometer of resistance ' $G$ ', its range is ' $V$ '. To triple its range, a resistance of $2000\Omega$ is connected in series. The value of $G$ is

152836 The length of a potentiometer wire is ' $L$ '. A cell of e.m.f. ' $E$ ' is balanced at a length $\frac{{ }^{\prime} L}{5}$ from the positive end of the wire. If the length of the wire is increased by \(\frac{L}{2}\), at what distance will the same cell give a balance point?

152837 A galvanometer of resistance $100 \Omega$ requires 10 $\mu \mathrm{A}$ current for full scale deflection. Now a resistance of $1 \Omega$ is connected to convert it into an ammeter. The minimum current required to obtain full scale deflection is
1098. Scale of galvanometer divided into 100 equal divisions has a current sensitivity $10 \mathrm{div} . / \mathrm{mA}$ and voltage sensitivity $4 \mathrm{div} . / \mathrm{mV}$. The resistance of galvanometer is