QBManager

Current Electricity

152170 A certain electrical conductor has a square cross-section, $2.0 mm$ on side, and is $12 m$ long. The resistance between its ends is $0.072 Ω$ . The resistivity of its material is equal to :

1

2.4 \times 10^{- 6} Ω m

2

1.2 \times 10^{- 6} Ω m

3

1.2 \times 10^{- 8} Ω m

4

2.4 \times 10^{- 8} Ω m

Explanation:

D Given that,
$R = 0.072 Ω$
$A = (2 \times 2) {mm}^{2} = 4 \times 10^{- 6} m^{2}$
$l = 12 m .$
We know that,
Resistance of a conductor is given by,
$R = ρ \frac{l}{A}$
$ρ = \frac{RA}{l}$
$ρ = \frac{0.072 \times 4 \times 10^{- 6}}{12}$
$ρ = 2.4 \times 10^{- 8} Ω m$

BCECE-2006

Current Electricity

152156 The heating element of a heater should be made of material which should have

1 high resistivity and high melting point

2 high resistivity and low melting point

3 low resistivity and low melting point

4 low resistivity and high melting point

Explanation:

A We know that,
Resistance $(R) = \frac{ρ l}{A}$
$ρ = \frac{RA}{l}$
So, we can say that the heating elements resistivity is directly proportional to its resistance. High resistivity is the desirable property of a heating element.
Therefore, the heating element of a heater should be made of material which should have high resistivity and high melting point.

J and K CET- 1998

Current Electricity

152142 When the temperature of a metallic resistor is increased, the product of its resistivity and conductivity

1 increases

2 decreases

3 remains constant

4 may increases of decrease

Explanation:

C We know that,
$Resistivity (ρ) = \frac{1}{Conductivity (σ)}$
$∵$ The product of resistivity and conductivity is constant.
Resistivity $\times$ Conductivity $=$ Constant.
Conductivity is measure of how easily electricity flows, electrical resistivity measure how much a material resists the flow of electricity.

CG PET- 2012

Current Electricity

152149 Which of the following quantities do not change when a resistor connected to a battery is heated due to the current?

1 Drift speed

2 Resistivity

3 Resistance

4 Number of free electrons

BITSAT-2010

Current Electricity

152151 Fractional increase in resistivity per unit increase in temperature is defined as

1 resistivity

2 temperature coefficient of resistivity

3 conductivity

4 drift velocity

Explanation:

B Fractional increase in resistivity per unit increase in temperature is defined as temperature coefficient of resistivity.
$R = R_{0} (1 + α Δ T)$
Where, $α \to$ Temperature coefficient of resistivity

J and K CET- 2011

Current Electricity

152170 A certain electrical conductor has a square cross-section, $2.0 mm$ on side, and is $12 m$ long. The resistance between its ends is $0.072 Ω$ . The resistivity of its material is equal to :

1

2.4 \times 10^{- 6} Ω m

2

1.2 \times 10^{- 6} Ω m

3

1.2 \times 10^{- 8} Ω m

4

2.4 \times 10^{- 8} Ω m

Explanation:

D Given that,
$R = 0.072 Ω$
$A = (2 \times 2) {mm}^{2} = 4 \times 10^{- 6} m^{2}$
$l = 12 m .$
We know that,
Resistance of a conductor is given by,
$R = ρ \frac{l}{A}$
$ρ = \frac{RA}{l}$
$ρ = \frac{0.072 \times 4 \times 10^{- 6}}{12}$
$ρ = 2.4 \times 10^{- 8} Ω m$

BCECE-2006

Current Electricity

152156 The heating element of a heater should be made of material which should have

1 high resistivity and high melting point

2 high resistivity and low melting point

3 low resistivity and low melting point

4 low resistivity and high melting point

Explanation:

A We know that,
Resistance $(R) = \frac{ρ l}{A}$
$ρ = \frac{RA}{l}$
So, we can say that the heating elements resistivity is directly proportional to its resistance. High resistivity is the desirable property of a heating element.
Therefore, the heating element of a heater should be made of material which should have high resistivity and high melting point.

J and K CET- 1998

Current Electricity

152142 When the temperature of a metallic resistor is increased, the product of its resistivity and conductivity

1 increases

2 decreases

3 remains constant

4 may increases of decrease

Explanation:

C We know that,
$Resistivity (ρ) = \frac{1}{Conductivity (σ)}$
$∵$ The product of resistivity and conductivity is constant.
Resistivity $\times$ Conductivity $=$ Constant.
Conductivity is measure of how easily electricity flows, electrical resistivity measure how much a material resists the flow of electricity.

CG PET- 2012

Current Electricity

152149 Which of the following quantities do not change when a resistor connected to a battery is heated due to the current?

1 Drift speed

2 Resistivity

3 Resistance

4 Number of free electrons

BITSAT-2010

Current Electricity

152151 Fractional increase in resistivity per unit increase in temperature is defined as

1 resistivity

2 temperature coefficient of resistivity

3 conductivity

4 drift velocity

Explanation:

B Fractional increase in resistivity per unit increase in temperature is defined as temperature coefficient of resistivity.
$R = R_{0} (1 + α Δ T)$
Where, $α \to$ Temperature coefficient of resistivity

J and K CET- 2011

Current Electricity

152170 A certain electrical conductor has a square cross-section, $2.0 mm$ on side, and is $12 m$ long. The resistance between its ends is $0.072 Ω$ . The resistivity of its material is equal to :

1

2.4 \times 10^{- 6} Ω m

2

1.2 \times 10^{- 6} Ω m

3

1.2 \times 10^{- 8} Ω m

4

2.4 \times 10^{- 8} Ω m

Explanation:

D Given that,
$R = 0.072 Ω$
$A = (2 \times 2) {mm}^{2} = 4 \times 10^{- 6} m^{2}$
$l = 12 m .$
We know that,
Resistance of a conductor is given by,
$R = ρ \frac{l}{A}$
$ρ = \frac{RA}{l}$
$ρ = \frac{0.072 \times 4 \times 10^{- 6}}{12}$
$ρ = 2.4 \times 10^{- 8} Ω m$

BCECE-2006

Current Electricity

152156 The heating element of a heater should be made of material which should have

1 high resistivity and high melting point

2 high resistivity and low melting point

3 low resistivity and low melting point

4 low resistivity and high melting point

Explanation:

A We know that,
Resistance $(R) = \frac{ρ l}{A}$
$ρ = \frac{RA}{l}$
So, we can say that the heating elements resistivity is directly proportional to its resistance. High resistivity is the desirable property of a heating element.
Therefore, the heating element of a heater should be made of material which should have high resistivity and high melting point.

J and K CET- 1998

Current Electricity

152142 When the temperature of a metallic resistor is increased, the product of its resistivity and conductivity

1 increases

2 decreases

3 remains constant

4 may increases of decrease

Explanation:

C We know that,
$Resistivity (ρ) = \frac{1}{Conductivity (σ)}$
$∵$ The product of resistivity and conductivity is constant.
Resistivity $\times$ Conductivity $=$ Constant.
Conductivity is measure of how easily electricity flows, electrical resistivity measure how much a material resists the flow of electricity.

CG PET- 2012

Current Electricity

152149 Which of the following quantities do not change when a resistor connected to a battery is heated due to the current?

1 Drift speed

2 Resistivity

3 Resistance

4 Number of free electrons

BITSAT-2010

Current Electricity

152151 Fractional increase in resistivity per unit increase in temperature is defined as

1 resistivity

2 temperature coefficient of resistivity

3 conductivity

4 drift velocity

Explanation:

B Fractional increase in resistivity per unit increase in temperature is defined as temperature coefficient of resistivity.
$R = R_{0} (1 + α Δ T)$
Where, $α \to$ Temperature coefficient of resistivity

J and K CET- 2011

Current Electricity

152170 A certain electrical conductor has a square cross-section, $2.0 mm$ on side, and is $12 m$ long. The resistance between its ends is $0.072 Ω$ . The resistivity of its material is equal to :

1

2.4 \times 10^{- 6} Ω m

2

1.2 \times 10^{- 6} Ω m

3

1.2 \times 10^{- 8} Ω m

4

2.4 \times 10^{- 8} Ω m

Explanation:

D Given that,
$R = 0.072 Ω$
$A = (2 \times 2) {mm}^{2} = 4 \times 10^{- 6} m^{2}$
$l = 12 m .$
We know that,
Resistance of a conductor is given by,
$R = ρ \frac{l}{A}$
$ρ = \frac{RA}{l}$
$ρ = \frac{0.072 \times 4 \times 10^{- 6}}{12}$
$ρ = 2.4 \times 10^{- 8} Ω m$

BCECE-2006

Current Electricity

152156 The heating element of a heater should be made of material which should have

1 high resistivity and high melting point

2 high resistivity and low melting point

3 low resistivity and low melting point

4 low resistivity and high melting point

Explanation:

A We know that,
Resistance $(R) = \frac{ρ l}{A}$
$ρ = \frac{RA}{l}$
So, we can say that the heating elements resistivity is directly proportional to its resistance. High resistivity is the desirable property of a heating element.
Therefore, the heating element of a heater should be made of material which should have high resistivity and high melting point.

J and K CET- 1998

Current Electricity

152142 When the temperature of a metallic resistor is increased, the product of its resistivity and conductivity

1 increases

2 decreases

3 remains constant

4 may increases of decrease

Explanation:

C We know that,
$Resistivity (ρ) = \frac{1}{Conductivity (σ)}$
$∵$ The product of resistivity and conductivity is constant.
Resistivity $\times$ Conductivity $=$ Constant.
Conductivity is measure of how easily electricity flows, electrical resistivity measure how much a material resists the flow of electricity.

CG PET- 2012

Current Electricity

152149 Which of the following quantities do not change when a resistor connected to a battery is heated due to the current?

1 Drift speed

2 Resistivity

3 Resistance

4 Number of free electrons

BITSAT-2010

Current Electricity

152151 Fractional increase in resistivity per unit increase in temperature is defined as

1 resistivity

2 temperature coefficient of resistivity

3 conductivity

4 drift velocity

Explanation:

B Fractional increase in resistivity per unit increase in temperature is defined as temperature coefficient of resistivity.
$R = R_{0} (1 + α Δ T)$
Where, $α \to$ Temperature coefficient of resistivity

J and K CET- 2011

Current Electricity

152170 A certain electrical conductor has a square cross-section, $2.0 mm$ on side, and is $12 m$ long. The resistance between its ends is $0.072 Ω$ . The resistivity of its material is equal to :

1

2.4 \times 10^{- 6} Ω m

2

1.2 \times 10^{- 6} Ω m

3

1.2 \times 10^{- 8} Ω m

4

2.4 \times 10^{- 8} Ω m

Explanation:

D Given that,
$R = 0.072 Ω$
$A = (2 \times 2) {mm}^{2} = 4 \times 10^{- 6} m^{2}$
$l = 12 m .$
We know that,
Resistance of a conductor is given by,
$R = ρ \frac{l}{A}$
$ρ = \frac{RA}{l}$
$ρ = \frac{0.072 \times 4 \times 10^{- 6}}{12}$
$ρ = 2.4 \times 10^{- 8} Ω m$

BCECE-2006

Current Electricity

152156 The heating element of a heater should be made of material which should have

1 high resistivity and high melting point

2 high resistivity and low melting point

3 low resistivity and low melting point

4 low resistivity and high melting point

Explanation:

A We know that,
Resistance $(R) = \frac{ρ l}{A}$
$ρ = \frac{RA}{l}$
So, we can say that the heating elements resistivity is directly proportional to its resistance. High resistivity is the desirable property of a heating element.
Therefore, the heating element of a heater should be made of material which should have high resistivity and high melting point.

J and K CET- 1998

Current Electricity

152142 When the temperature of a metallic resistor is increased, the product of its resistivity and conductivity

1 increases

2 decreases

3 remains constant

4 may increases of decrease

Explanation:

C We know that,
$Resistivity (ρ) = \frac{1}{Conductivity (σ)}$
$∵$ The product of resistivity and conductivity is constant.
Resistivity $\times$ Conductivity $=$ Constant.
Conductivity is measure of how easily electricity flows, electrical resistivity measure how much a material resists the flow of electricity.

CG PET- 2012

Current Electricity

152149 Which of the following quantities do not change when a resistor connected to a battery is heated due to the current?

1 Drift speed

2 Resistivity

3 Resistance

4 Number of free electrons

BITSAT-2010

Current Electricity

152151 Fractional increase in resistivity per unit increase in temperature is defined as

1 resistivity

2 temperature coefficient of resistivity

3 conductivity

4 drift velocity

Explanation:

B Fractional increase in resistivity per unit increase in temperature is defined as temperature coefficient of resistivity.
$R = R_{0} (1 + α Δ T)$
Where, $α \to$ Temperature coefficient of resistivity

J and K CET- 2011

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